I have a table with a varchar type column. I want to select values from this column which start with a capital letter only.
For example
MyTable
Col1 Col2
Argentina 2
Brasil 3
uruguay 4
I want my select query to return:
Argentina
Brasil
This is a bit of a pain. You can use ASCII() or COLLATE, but these depend on how the data is stored. For varchar() and char(), this will work:
where ASCII(left(col1, 1)) between ASCII('A') and ASCII('Z')
With TestData As
(
Select '012324' As Name
Union All Select 'ABC'
Union All Select 'abc'
Union All Select 'aBc'
Union All Select 'ABé'
Union All Select 'ABÉ'
)
Select *
From TestData
Where Name = UPPER(Name) Collate SQL_Latin1_General_CP1_CS_AS
hope this will help
You Can Use UPPER AND COLLATE Functions to do this.
For E.g:
create table #a (text varchar(10))
insert into #a values ('HAI'),('Hai'),('hai'),('44A')
select *from #a where substring([text],1,1) = substring(Upper([text]),1,1) collate SQL_Latin1_General_CP1_CS_AS
AND substring([text],1,1) like '[A-Z]%'
select Col1 from MyTable where Col1 like '[A-Z]%'
Related
Query:
SELECT [Name]
FROM [dbo].[City]
where name like '%laus%'
Results:
How to order so records with leading wildcard (3,4) are first?
Your may try, but best way use full-text-search
SELECT [Name]
FROM [City]
where name like '%laus%'
ORDER BY
CHARINDEX('laus',name)
Try This
;WITH CTE(name )
AS
(
SELECT 'Berlin' UNION ALL
SELECT 'Laura' UNION ALL
SELECT 'Losangels' UNION ALL
SELECT 'Lausanne' UNION ALL
SELECT 'Lausen' UNION ALL
SELECT 'Roamanel' UNION ALL
SELECT 'Sankt Niklaus' UNION ALL
SELECT 'Vennes sur-Lausanne'
)
SELECT * FROM CTE
ORDER BY (CASE WHEN name like 'Laus%' THEN 1 END ) DESC
Result
name
--------
Lausanne
Lausen
Losangels
Laura
Roamanel
Sankt Niklaus
Vennes sur-Lausanne
Berlin
DECLARE #City TABLE(Name VARCHAR(32))
INSERT #City VALUES
('Belmont-sur-Lausanne'),
('Lausanne'),
('Lausen'),
('Le Mont-sur-Lausanne'),
('Berlin')
SELECT [Name]
FROM #City
--where name like '%laus%'
order by CASE WHEN PATINDEX('%laus%', name) = 0
THEN LEN(name)
ELSE PATINDEX('%laus%', name)
END
,name
May someone please help me for this strange scenario. i have a data as given below.
DECLARE #TABLE TABLE
(
ID INT,
PHONE001 VARCHAR(500)
)
INSERT TEST
SELECT 1,'01323840261,01323844711' UNION ALL
SELECT 2,'' UNION ALL
SELECT 3,',01476862000' UNION ALL
SELECT 4,'01233625418,1223822583,125985' UNION ALL
SELECT 5,'2089840022,9.99021E+13'
and i am trying to put in seperate column for each comma value. the max number of column depends on the largest comma seperated string.
Expected Output
1|01323840261|01323844711|''
2|''|''|''
3|01476862000|''|''|
4|01233625418|1223822583|125985|
5|2089840022|9.99021E+13|''|
try
select id,T.c.value('t[1]','varchar(50)') as col1,
T.c.value('t[2]','varchar(50)') as col2 ,
T.c.value('t[3]','varchar(50)') as col3 from
(select id,cast ('<t>'+ replace(PHONE001,',','</t><t>') +'</t>'
as xml) x
from #TABLE) a cross apply x.nodes('.') t(c)
I am new to SQL
If I have a column like this
ID
00001234
00012345
00001235
00123456
I want to see a column of ID without '0' Like this
ID
1234
12345
1235
123456
How can I start? any advice?
In SQL Server you can use:
SELECT ID,
REPLACE(LTRIM(REPLACE(ID, '0', ' ') ), ' ', '0')
FROM mytable
The above can be easily adjusted to any other RDBMS you may use.
Cast it to Bigint and cast it back to varchar
Note:Assumption: RDBMS SQL SERVER, ID is of character type
SELECT * INTO #TAB FROM (
select '00001234' ID
UNION ALL
select '00012345'
UNION ALL
select '00001235'
UNION ALL
select '00123456'
)A
SELECT CAST(CAST(ID AS BIGINT) AS VARCHAR(50)) FROM #TAB
I have a table with two columns like this
col1 col2
a b
b a
c d
d a
I want to get distinct values of these two columns combined with comma separated.
Expected out put is like this
a,b,c,d
The following example concatenate row values into a variable
DECLARE #val nvarchar(max)
SELECT #val = COALESCE(#val + ',' + col1, col1)
FROM (SELECT col1
FROM dbo.twoColumns
UNION
SELECT col2
FROM dbo.twoColumns
) x
SELECT #val
Demo on SQLFiddle
try this , its very much easy i think
select group_concat(distinct(c)) as d
from
(
select col1 c from your_table
union
select col2 c from your_table
) as d
How can I convert a number to a formatted string of fixed length in SQL Server 2005 using T-SQL?
e.g.
Inputs: 5,01,007,0009,00011,01200
Result: 000005,000007,000009,0000011,001200
Looks like you want it 6 wide. Try putting your pad characters, in this case, zeros, to the left of your int/string, and then take the 6 chars on the right side of the string.
How about this?
DECLARE #i int;
SELECT #i = 1200;
SELECT RIGHT('000000'+ CAST(#i as varchar(10)), 6);
The best way I've found to do this is using the STR statement:
SELECT REPLACE(STR(123, 6), ' ', '0')
The above statement will result in 000123. It basically converts 123 to a string of 6 characters (padded with spaces), then uses REPLACE to replace the spaces with zeros.
TRY THIS
WITH t(c) AS
(
SELECT 1.99 UNION ALL
SELECT 21.34 UNION ALL
SELECT 1797.94 UNION ALL
SELECT 300.36 UNION ALL
SELECT 21.99 UNION ALL
SELECT -2.31
)
select
c,
replicate(0,4-len(replace(substring(cast(c as varchar(10)),1,charindex('.',c)-1),'-','')))+''+
replace(replace(substring(cast(c as varchar(10)),1,charindex('.',c)-1),'-',''),'','-') +''+
replace(substring(cast(c as varchar(10)),charindex('.',c),len(c)),'-','')
from t
i will still optimize it
Best way for dynamic leading zero allocation
WITH t(c) AS ( SELECT 1.99 UNION ALL
SELECT 21.34 UNION ALL SELECT
1797.94 UNION ALL SELECT 300.36 UNION ALL SELECT 21.99 UNION ALL
SELECT 2.31 ),
Final (a,b,c,d) as ( Select c,
substring(cast(c as
varchar(10)),1,charindex('.',c)-1) ,
(select max(len(substring(cast(c as
varchar(10)),1,charindex('.',c)-1)))
from t), substring(cast(c as
varchar(10)),charindex('.',c)+1,len(c))
From t group by c )
select a,
right(replicate('0',c)+''+b,4)+'.'+d
from final
declare #i int
set #i=10
print replace(str(#i),' ','0')