I have a module in Yii2 containing a lot of controllers, models and views.
How can I register an asset for all views, without register it in all view one by one?
The module has init() method, you can use it for code that needs to be executed every time the module is accessed:
<?php
namespace frontend\modules\users;
use frontend\assets\UsersAsset;
use Yii;
use yii\base\Module as BaseModule;
class Module extends BaseModule
{
/**
* #inheritdoc
*/
public $controllerNamespace = 'frontend\modules\users\controllers';
/**
* #inheritdoc
*/
public function init()
{
UsersAsset::register(Yii::$app->view);
parent::init();
}
}
Don't forget to call parent implementation.
Related
When I run $ vendor/bin/behat --init
I get this:
<?php
use Behat\Behat\Context\Context;
use Behat\Gherkin\Node\PyStringNode;
use Behat\Gherkin\Node\TableNode;
/**
* Defines application features from the specific context.
*/
class FeatureContext implements Context
{
/**
* Initializes context.
*
* Every scenario gets its own context instance.
* You can also pass arbitrary arguments to the
* context constructor through behat.yml.
*/
public function __construct()
{
}
}
But the documentation show this:
<?php
// features/bootstrap/FeatureContext.php
use Behat\Behat\Context\SnippetAcceptingContext;
use Behat\Gherkin\Node\PyStringNode;
use Behat\Gherkin\Node\TableNode;
class FeatureContext implements SnippetAcceptingContext
{
/**
* Initializes context.
*/
public function __construct()
{
}
}
I'm not sure if it's because I don't a behat.yml file or it's other problem.
And it give me all the time this error:
`FeatureContext` context class not found and can not be used.
Thanks
Oskar
I'm newbie in Yii, especially Yii2. How can I create MY_Controller like CI in YII2 ? so other controllers will extend to MY_Controller.
in YII2, called as BaseController. I think in another framework have same name BaseController .
First, if you're using basic template, create BaseController.php inside component directory.
namespace app\components;
use Yii;
use yii\web\Controller;
use yii\helpers\Url;
class BaseController extends Controller
{
public function init()
{
parent::init();
}
public function _anotherMethod(){ /* your code goes here */ }
}
Next in your other controllers :
namespace app\controllers;
use Yii;
use yii\web\Controller;
use yii\web\NotFoundHttpException;
use yii\filters\VerbFilter;
use yii\helpers\Url;
use app\components\BaseController;
class YourController extends BaseController
{
public function init()
{
parent::init();
}
public function _anotherAction()
{
// your code
}
}
I hope it will help you
I can get the ID of the authenticated user like this:
Auth::user()->id = $id;
Great it works, ... but I have a load of methods which need it and I want a cleaner way of adding it to the class as a whole,so I can just reference the $id in each method. I was thinking of putting it into the constructor, but as Auth::user is a static, I am making a mess of things and don't know how to do it.
Many thanks for your help !
Laravel >= 5.3
you can't access the session or authenticated user in your controller's constructor because the middleware has not run yet.
As an alternative, you may define a Closure based middleware directly in your controller's constructor. Before using this feature, make sure that your application is running Laravel 5.3.4 or above:
class UserController extends Controller {
protected $userId;
public function __construct() {
$this->middleware(function (Request $request, $next) {
if (!\Auth::check()) {
return redirect('/login');
}
$this->userId = \Auth::id(); // you can access user id here
return $next($request);
});
}
}
Instead of using the Facade you can inject the contract for the authentication class and then set the user ID on your controller. Like #rotvulpix showed you could put this on your base controller so that all child controllers have access to the user ID too.
<?php
namespace App\Http\Controllers;
use Illuminate\Contracts\Auth\Guard;
class FooController extends Controller
{
/**
* The authenticated user ID.
*
* #var int
*/
protected $userId;
/**
* Construct the controller.
*
* #param \Illuminate\Contracts\Auth\Guard $auth
* #return void
*/
public function __construct(Guard $auth)
{
$this->userId = $auth->id();
}
}
The guard has an id() method which returns void if no user is logged in, which is a little easier than having to go through user()->id.
You can use Auth::user() in the whole application. It doesn't matter where you are. But, in response to your question, you can use the 'Controller' class present in your controllers folder. Add a constructor there and make the reference to the user ID.
<?php namespace App\Http\Controllers;
use Illuminate\Foundation\Bus\DispatchesCommands;
use Illuminate\Routing\Controller as BaseController;
use Illuminate\Foundation\Validation\ValidatesRequests;
/* Don't forget to add the reference to Auth */
use Auth;
abstract class Controller extends BaseController {
use DispatchesCommands, ValidatesRequests;
function __construct() {
$this->userID = Auth::user()?Auth::user()->id:null;
}
}
Then, in any method of any controller you can use the $this->userID variable.
In my controller(s), instead of fetchingAuth::id() in each method, I've set up an $id property in the controller's class and fetched it once in the constructor. then, in the rest of the methods i'm just refering $this->id, is it considered safe or am I doing something wrong?
Code Sample: http://pastebin.com/pvju54eh
What you could do is inject the Guard instance in your controller and then assign the currently logged in user (if there is one) to a class property:
<?php namespace App\Http\Controllers;
use Illuminate\Contracts\Auth\Guard;
class SomeController extends Controller
{
protected $auth;
protected $user;
public function __construct(Guard $auth)
{
$this->auth = $auth;
$this->user = $this->auth->user();
}
public function someMethod()
{
// Get logged in user’s ID
$userId = $this->user->id;
}
}
I do not see any major problems with this approach even though I have not seen approach used often.
Myself I find it easier to get the $request->user() in controller from Request though.
I'm new to PHPStorm and I imported an existing project in this IDE. Now I receive many warnings like
Method 'query' not found in class
I read about using PHPDoc-blocks in order to declare the origin of variables which are not defined in the current class, but I cannot get out how I should do it for this situation:
class loginModel extends Model{
public function checkLogin(){
[...]
if($this->db->query($sql)){[...]} //Warning as stated above
[...]
}
}
$this->db itself is inheritated from class Model:
class Model{
protected $db;
private function connect(){
$this->db = new PGSQL();
}
}
and therefore can access the public PGSQL method named query.Maybe not that well designed, but how could I solve these messages without downgrading their severity?
class Model{
/**
* #var PGSQL
*/
protected $db;
private function connect(){
$this->db = new PGSQL();
}
}
Docblocks work on properties too