Insert column with Max in sql - sql

Question

I did not know how to insert column with max.
Select id,MAX(salary),Min(Salary)
from C
GROUP BY id;
it is give me the all id with it is maximum
and I want just the id with maximum and minimum of salary!!

Answer 1

Several options for you that only require a single scan of the table:
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE C ( ID, SALARY ) AS
SELECT 1, 100 FROM DUAL
UNION ALL SELECT 2, 110 FROM DUAL
UNION ALL SELECT 3, 100 FROM DUAL
UNION ALL SELECT 4, 110 FROM DUAL
UNION ALL SELECT 5, 90 FROM DUAL
Query 1 - Get a single ID:
SELECT *
FROM (
SELECT ID, SALARY
FROM c
ORDER BY SALARY DESC
)
WHERE ROWNUM = 1
Results:
| ID | SALARY |
|----|--------|
| 2 | 110 |
Query 2 - Get a single ID (alternate method that will get min and max IDs):
SELECT MAX( ID ) KEEP ( DENSE_RANK LAST ORDER BY SALARY ) AS MAX_SALARY_ID,
MAX( SALARY ) AS MAX_SALARY,
MIN( ID ) KEEP ( DENSE_RANK FIRST ORDER BY SALARY ) AS MIN_SALARY_ID,
MIN( SALARY ) AS MIN_SALARY
FROM C
Results:
| MAX_SALARY_ID | MAX_SALARY | MIN_SALARY_ID | MIN_SALARY |
|---------------|------------|---------------|------------|
| 4 | 110 | 5 | 90 |
Query 3 - Get all the IDs with the maximum salary:
SELECT ID, SALARY
FROM (
SELECT ID,
SALARY,
RANK() OVER ( ORDER BY SALARY DESC ) AS RNK
FROM C
)
WHERE RNK = 1
Results:
| ID | SALARY |
|----|--------|
| 2 | 110 |
| 4 | 110 |
Query 4 - Get all IDs for min and max salary:
SELECT LISTAGG( CASE MIN_RANK WHEN 1 THEN ID END, ',' ) WITHIN GROUP ( ORDER BY ID ) AS MIN_SALARY_IDS,
MAX( CASE MIN_RANK WHEN 1 THEN SALARY END ) AS MIN_SALARY,
LISTAGG( CASE MAX_RANK WHEN 1 THEN ID END, ',' ) WITHIN GROUP ( ORDER BY ID ) AS MAX_SALARY_IDS,
MAX( CASE MAX_RANK WHEN 1 THEN SALARY END ) AS MAX_SALARY
FROM (
SELECT ID,
SALARY,
RANK() OVER ( ORDER BY SALARY ASC ) AS MIN_RANK,
RANK() OVER ( ORDER BY SALARY DESC ) AS MAX_RANK
FROM C
)
Results:
| MIN_SALARY_IDS | MIN_SALARY | MAX_SALARY_IDS | MAX_SALARY |
|----------------|------------|----------------|------------|
| 5 | 90 | 2,4 | 110 |
Query 5:
SELECT ID,
SALARY,
CASE WHEN MIN_RANK = 1 THEN 'MIN'
WHEN MAX_RANK = 1 THEN 'MAX' END AS MIN_MAX
FROM (
SELECT ID,
SALARY,
RANK() OVER ( ORDER BY SALARY ASC ) AS MIN_RANK,
RANK() OVER ( ORDER BY SALARY DESC ) AS MAX_RANK
FROM C
)
WHERE MIN_RANK = 1 OR MAX_RANK = 1
Results:
| ID | SALARY | MIN_MAX |
|----|--------|---------|
| 2 | 110 | MAX |
| 4 | 110 | MAX |
| 5 | 90 | MIN |

Answer 2

Select id,
salary
from C
where salary = (select MAX(salary)
from C)

Answer 3

you can use first_value or last_value
The FIRST_VALUE analytic function is similar to the FIRST analytic
function, allowing you to return the first result from an ordered set.
https://oracle-base.com/articles/misc/first-value-and-last-value-analytic-functions
create table C (id int, salary int);
insert into c values(1, 1);
insert into c values(2, 2);
insert into c values(3, 3);
insert into c values(4, 4);
insert into c values(5, 5);
Select distinct first_value(id) over ( order by salary desc)
from C
FIRST_VALUE(ID)OVER(ORDERBYSAL
1 5