Looking for a SQL solution to the following problem
Return USER and NUMBER combination WHERE PRIORITY = MIN(PRIORITY) [NULL is equivalent to MAX(PRIORITY + 1)] ... in the case of ties in PRIORITY, break using lowest LINEITEM
FIELDS:
USER,
LINEITEM,
NUMBER,
PRIORITY
VALUES: ('X' signifies desired combination)
USER LINEITEM NUMBER PRIORITY
-------------------------------------
1 1 12345 NULL
1 2 23456 2
1 3 34567 1 X
2 1 9876 3
2 2 98765 1 X
2 3 12345 2
2 4 23456 1
3 1 23456 NULL X
3 2 12345 NULL
4 1 34567 NULL
4 2 45678 NULL
4 3 12345 1 X
4 4 12345 2
4 5 23456 1
Thanks in advance.
In response to PM 77-1,
My current method:
SELECT table1.user,table1.number
FROM table1
JOIN (
SELECT user,
CAST(MIN((COALESCE(priority,999) *
(10 ^ (5 - LEN(COALESCE(CAST(priority AS VARCHAR),'999'))))) +
lineitem) AS VARCHAR) AS selector
FROM table1 GROUP BY user
) AS table2
ON table1.user = table2.user
AND table1.lineitem = CAST(RIGHT(table2.selector, 1) AS int)
ORDER BY table1.user;
Use ROW_NUMBER:
SQL Fiddle
;WITH Cte AS(
SELECT *,
ROW_NUMBER() OVER(
PARTITION BY [User]
ORDER BY
CASE WHEN Priority IS NULL THEN 1 ELSE 0 END,
Priority,
LineItem
) AS rn
FROM tbl
)
SELECT
[User], LineItem, Number, Priority
FROM Cte
WHERE rn = 1
Related
I have this table with the following records:
table1
id ele_id_1 ele_val ele_id_2
1 2 123 1
1 1 abc 1
1 4 xyz 2
1 4 456 1
2 5 22 1
2 4 344 1
2 3 6 1
2 2 Test Name 1
2 1 Hello 1
I am trying to add position for each id when ele_id_1 and ele_id_2 is order by ASC.
Here is the output:
id ele_id_1 ele_val ele_id_2 position
1 2 123 1 2
1 1 abc 1 1
1 4 xyz 2 4
1 4 456 1 3
2 5 22 1 5
2 4 344 1 4
2 3 6 1 3
2 2 Test Name 1 2
2 1 Hello 1 1
I have 34 million rows in table1, so would like to use an efficient way of doing this.
Any idea on how I can add position with values?
I think you want row_number() used like this:
select row_number() over (partition by id
order by ele_id_1, ele_id_2
) as position
Oracle can use an index for this, on (id, ele_id_1, ele_id_2).
I should note that for your example data order by ele_id_1, ele_id_2 and order by ele_id_2, ele_id_1 produce the same result. Your question suggests that you want the first.
So, you would get
id ele_id_1 ele_val ele_id_2 position
1 1 123 2 2
1 1 abc 1 1
1 4 xyz 2 4
1 4 456 1 3
Rather than:
id ele_id_1 ele_val ele_id_2 position
1 1 123 2 3
1 1 abc 1 1
1 4 xyz 2 4
1 4 456 1 2
EDIT:
If you want to update the data, then merge is probably the best approach.
MERGE INTO <yourtable> dest
USING (select t.*,
row_number() over (partition by id
order by ele_id_1, ele_id_2
) as new_position
from <yourtable> t
) src
ON dest.id = src.id AND
dest.ele_id_1 = src.ele_id_1 AND
dest.ele_id_2 = src.ele_id_2
WHEN MATCHED THEN UPDATE
SET desc.postition = src.new_position;
Note that updating all the rows in a table is an expensive operation. Truncating the table and recreating it might be easier:
create table temp_t as
select t.*,
row_number() over (partition by id
order by ele_id_1, ele_id_2
) as new_position
from t;
truncate table t;
insert into t ( . . . )
select . . . -- all columns but position
from temp_t;
However, be very careful if you truncate the table. Be sure to back it up first!
Goal:
If a person has two candy number, number 1 should always display first. No need to display candy number 2.
If a person does not have number 1, it should display number 2 instead.
Display all data
(int)(int) (nvarchar) (int)
Id fId Name Candy Number
---------------------------------
1 12 Kimn 1
2 12 Kimn 2
3 19 Lisa 1
4 15 John 2
5 16 Maria 2
6 16 Maria 1
7 17 Mao 2
Requested result:
Id fId Name Candy Number
---------------------------------
1 12 Kimn 1
3 19 Lisa 1
4 15 John 2
6 16 Maria 1
7 17 Mao 2
Problem:
It doesn't work so well for me to display it.
Tried using case and end in where statement but the code didn't fit to the purpose.
Any idea?
select *
from
table
where
candynumber =
CASE WHEN b.MatchType = 1
THEN 1
ELSE 2
END
Thank you!
This can be using row_number() window function:
select Id, fId, Name, Candy_Number from (
select your_table.*, row_number() over(partition by fId order by Candy_Number) as rn from your_table
) t
where rn = 1
order by id
This gives one row per fId, with lower Candy_Number.
You can try this :
SELECT candyWrapper.ID,
candyWrapper.FID,
outerHardCandy.Name,
outerHardCandy.Number
FROM (SELECT innerSoftCandy.Name,
CASE
WHEN (SUM(innerSoftCandy.Number) = 3) OR (SUM(innerSoftCandy.Number) = 1) THEN 1
WHEN (SUM(innerSoftCandy.Number) = 2) THEN 2
END AS Number
FROM Candy innerSoftCandy
GROUP BY innerSoftCandy.Name
) outerHardCandy
INNER JOIN Candy candyWrapper ON (outerHardCandy.Name = candyWrapper.Name AND outerHardCandy.Number = candyWrapper.Number)
ORDER BY candyWrapper.ID
You can see this here -> http://rextester.com/BBD89608
Here is my table
UserDetail
Id UserId CourseId SubjectId TeacherCode RDate status
1 1 1 1 1 08/02/2016 Waiting
2 1 1 1 2 08/01/2016 Recceived
3 1 1 1 3 08/02/2016 Processed
4 1 1 2 1 08/03/2016 Recceived
5 1 1 2 2 08/04/2016 Processed
6 1 2 1 3 08/05/2016 Processed
7 1 2 2 1 08/06/2016 Processed
User can have multiple courses,multiple subjects.One teacher can teach multiple subject.I want to fetch all column from table, base on distinct userid,courseid and subjectid.Out of 7 row,want to show only 4 rows.
Any one record from below
Id UserId CourseId SubjectId TeacherCode RDate status
1 1 1 1 1 08/02/2016 Waiting
2 1 1 1 2 08/01/2016 Recceived
3 1 1 1 3 08/02/2016 Processed
If we pick teachercode 1,then rdate to be 08/02/2016 and status to be Waiting
neither Recceived nor Processed.
Any one from below
Id UserId CourseId SubjectId TeacherCode RDate status
4 1 1 2 1 08/03/2016 Recceived
5 1 1 2 2 08/04/2016 Processed
How to do that?
You gotta know which rows of that distincted datas you want to choose. First rows ? Last rows ?
Since for every group of distincted data would be multiple rows so you mist choose which row you want.
I assume you want the first row from every distincted group. You can do it like below:
Select first(Id) AS Id, first(UserId) AS UserId, first(CrouseId) AS CourseId, first(SubjectId) AS SubjectId, first(TeacherId) AS TescherId,first(RDate) AS RDate, first(status) as status
FROM UserDetail
Group By UserId, CourseId, SubjectId
In sql2005+, do it like below:
WITH temp AS (
SELECT *,
ROW_NUMBER() OVER(PARTITION BY UserId,CourseId,SubjectId ORDER BY Id) AS rn FROM UserDetail)
SELECT t.*
FROM temp t
WHERE t.rn = 1
Or you can do it using inner select instead of WITH:
SELECT *
FROM (SELECT *,
ROW_NUMBER() OVER(PARTITION BY UserId,CourseId,SubjectId ORDER BY Id) AS rn FROM UserDetail)
WHERE rn = 1
I am trying to select the last change value per group.
I have a table
MMID column is incremental
MMID GID MID Value Bundle DateEntered
1 1 1 1 2 17/8/15 05:05:04
2 1 2 2 3 16/8/15 05:05:06
3 1 3 3 2 15/8/15 05:05:07
4 1 1 0 2 18/8/15 05:05:08
5 2 2 1 1 18/8/15 05:05:05
6 2 2 2 2 18/8/15 06:06:06
7 2 4 3 1 17/8/15 06:06:06
8 2 4 3 2 18/8/15 06:06:07
Here, I want the last change 'Value' in the last 24 hour(Having Date 18th August).
From the below query, I can get that. But even if the bundle value is changed, then I get that row.
But I want only rows when 'Value' is changed, or 'Value and Bundle' are changed. But not only when Bundle is changed
Desired output
MMID GID MID Value Bundle DateEntered
4 1 1 0 2 18/8/15 05:05:08
6 2 2 2 2 18/8/15 06:06:06
The query I tried is :
select yt1.*
from Table1 yt1
left outer join Table1 yt2
on (yt1.GID = yt2.GID and yt1.MID = yt2.MID
and yt1.MMID < yt2.MMID)
where yt2.MMID is null and yt2.GID is null and yt2.MID is null and yt1.DateEntered > '2015-08-18 00:00:00' ;
The output i get from here is:
MMID GID MID Value Bundle DateEntered
4 1 1 0 2 18/8/15 05:05:08
6 2 2 2 2 18/8/15 06:06:06
8 2 4 3 2 18/8/15 06:06:07
I should not be getting the last row here.
Can anyone tell me what should I change here.
Not really following the logic of your attempt, but here is how I would get the desired results:
WITH cte AS (
SELECT *,
ROW_NUMBER() OVER (PARTITION BY GID, MID ORDER BY MMID) AS rn
FROM Table
)
, cte2 AS (
SELECT t1.* FROM cte t1
INNER JOIN cte t2
ON t1.GID=t2.GID
AND t1.MID=t2.MID
AND t1.value<>t2.value
AND t1.rn=t2.rn+1
)
SELECT *
FROM cte2
WHERE MMID=(
SELECT TOP 1 MMID
FROM cte2 c2
WHERE cte2.GID=c2.GID
AND cte2.MID=c2.MID
ORDER BY MMID DESC
)
NB: If you don't want to include the rn column in the final results, use a column list instead of SELECT *.
How do i update table structured like this:
id[pkey] | parent_id | position
1 1
2 1
3 1
4 1
5 1
6 2
7 2
8 2
9 2
10 3
11 3
12 3
...and so on
to achieve this result:
id[pkey] | parent_id | position
1 1 1
2 1 2
3 1 3
4 1 4
5 1 5
6 2 1
7 2 2
8 2 3
9 2 4
10 3 1
11 3 2
12 3 3
...and so on
I was thinking about somehow mixing
SELECT DISTINCT parent_id FROM cats AS t;
with
CREATE SEQUENCE dpos;
UPDATE cats t1 SET position = nextval('dpos') WHERE t.parent_id = t1.parent_id;
DROP SEQUENCE dpos;
although im not really experienced with postgres, and not sure how to use some kind of FOREACH. I appreciate any help
You can get the incremental number using row_number(). The question is how to assign it to a particular row. Here is one method using a join:
update cats
set position = c2.newpos
from (select c2.*, c2.ctid as c_ctid,
row_number() over (partition by c2.parent_id order by NULL) as seqnum
from cats c2
) c2
where cats.parent_id = c2.parent_id and cats.ctid = c2.c_ctid;
Use row_number function
select parent_id,
row_number() over (partition by parent_id order by parent_id) as position_id from table
Try this:
UPDATE table_name set table_name.dataID = v_table_name.rn
FROM
(
SELECT row_number() over (partition by your_primaryKey order by your_primaryKey) AS rn, id
FROM table_name
) AS v_table_name
WHERE v_table_name.your_primaryKey = v_table_name.your_primaryKey;