Update table row with data from another table - sql

I'm quite new to sql and i need your help to solve this problem. I have 2 tables. What I want is to update a row from one table with data from another one but only if the values are different where the id is the same.
Like this:
Table A
ID DESC
1 asd
2 aaa
3 asda
Table B
ID DESC
1 asd33
2 aaa22
3 asda
And what I want is this update DESC table B with data from DESC A only if the values are different
Table B
ID DESC
1 asd
2 aaa
3 asda

UPDATE B
SET B.DESC = A.DESC
FROM TABLEB B
LEFT JOIN TABLEA A on A.ID = B.ID

Try this
Update TableB
Set TableB.desc = TableA.desc
From TableB INNER JOIN TableA ON TableB.ID = TableA.ID
Where TableB.desc NOT IN
(Select ISNULL(TableA.desc,'') From TableA)

Related

How to identify non-existing keys with reference to a table that has all mandatory keys, SQL?

I have the table 'Table01' which contains the keys that should be mandatory:
id
1
2
3
4
And I also have the table 'Table02' which contains the records to be filtered:
id
customer
weight
1
a
100
2
a
300
3
a
200
4
a
45
1
b
20
2
b
100
3
b
17
1
c
80
4
c
90
2
d
30
3
d
30
4
d
50
So I want to identify which are the mandatory id's that the table 'Table02' does not have, and in turn identify which is the 'customer' of each id's that the table 'Table02' does not have.
The resulting table should look like this:
customer
id
b
4
c
2
c
3
d
1
What I have tried so far is a 'rigth join'.
proc sql;
create table table03 as
select
b.id
from table02 a
right join table01 b
on a.id=b.id
where a.id is null;
run;
But that query is not identifying all the id's that should be mandatory.
I hope someone can help me, thank you very much.
here is one way:
select cl.customerid , a.id
from
Table1 a
cross join
( select customerid
from table2
group by customerid
) cl
where not exists ( select 1 from table2 b
where b.customerid = cl.customerid
and b.id = a.id
)
You can use an EXCEPT between two sub-selects. The first creates a matrix of all possibilities, and the except table is a selection of the extant customers.
Example:
data ids;
do id = 1 to 4; output; end;
run;
data have;
input id customer $ weight;
datalines;
1 a 100
2 a 300
3 a 200
4 a 45
1 b 20
2 b 100
3 b 17
1 c 80
4 c 90
2 d 30
3 d 30
4 d 50
run;
proc sql;
create table want(label='Customers missing some ids') as
select matrix.*
from
(select distinct have.customer, ids.id from have, ids) as matrix
except
(select customer, id from have)
;
quit;
If you are doing it in SQL server. Something like #eshirvana above posted, but also you can use with cte:
;with cte as
(
SELECT t1.id, t2.Customer
FROM Table01 t1
cross join (select distinct customer from Table02)
)
SELECT a.customer, a.id FROM cte a
LEFT JOIN Table02 b
ON a.id=b.id AND a.customer=b.customer
where b.id is null

How to join only latest date values from another table and prevent duplication

I'm trying to lookup a unique value from table b and get it into table a.
Table b stores multiple values that are changing by date.
I would like to join but only getting the values with the latest date from table b.
Table a
Unique ID
1
2
Table b
Date Unique ID Price
01/01/2019 1 100
01/02/2019 1 101
01/03/2019 1 102
01/01/2019 2 90
01/02/2019 2 91
01/03/2019 2 92
Expected result
Unique ID Price Date
1 102 01/03/2019
2 92 01/03/2019
Appreciate your help!
Have a sub-query that returns each UniqueID together with its max date. IN that result.
select * from tablename
where (UniqueID, date) in (select UniqueID, max(date)
from tablename
group by UniqueID)
You want correlated subquery :
select b.*
from tableb b
where b.date = (select max(b1.date) from tableb b1 where b1.UniqueID = b.UniqueID);
If you want to go with JOIN then you can do JOIN with subquery :
select a.UniqueID , b.Price, b.Date
from tablea a inner join
tableb b
on b.UniqueID = a.UniqueID
where b.date = (select max(b1.date) from tableb b1 where b1.UniqueID = a.UniqueID);
A correlated subquery?
select b.*
from b
where b.date = (select max(b2.date) from b b2 where b2.unique_id = b.unique_id);

Get records using left outer join

I have two tables as given below
Table A Table B Table C
============= ============== =========
Id Name Id AId CId Id Name
1 A 1 1 1 1 x
2 B 2 1 1 2 y
3 C 3 2 1 3 z
4 D 4 2 3 4 w
5 E 5 3 2 5 v
Now I want all the records of Table A with matching Id column CId from Table B where CId = 1.
So the output should be like below :
Id Name CId
1 A 1
2 B 1
3 C 1
4 D Null
5 E Null
Can anyone help me please?
This does what you want:
SELECT
A.Id,
A.Name,
CASE B.CId WHEN 1 THEN 1 ELSE NULL END AS CId
FROM
A LEFT JOIN B ON A.Id = B.Id
This is not about LEFT JOINing. You could as well do it with an INNER JOIN. When you don't want the 3 and 2 of column CId to appear you would still have to filter with WHERE and therefore the rows with Id 4 and 5 would not appear, which is not what you want.
EDIT:
Given this test data:
create table A (Id int, Name varchar(5));
insert into A values
(1, 'A'),
(2, 'B'),
(3, 'C'),
(4, 'D'),
(5, 'E');
create table B (Id int, AId int, CId int);
insert into B values
(1,1,1),
(2,1,1),
(3,2,1),
(4,2,3),
(5,3,2);
my query does not give a cartesian product. Read and try before downvoting. Anyway, it was not clear to me what you want to achieve, now I've joined on AId column and with this query:
SELECT DISTINCT
A.Id,
A.Name
, CASE
WHEN B.CId > 1 THEN 1
WHEN B.CId = 1 THEN 1
ELSE NULL END AS CId
FROM
A LEFT JOIN B ON A.Id = B.AId
and it also gives the right output, like the first before. If this is still not what you want, your test data is wrong or I absolutely don't get it.
Try something like this:
SELECT TableA.Id, TableA.Name, TableB.CId
FROM TableA
LEFT OUTER JOIN TableB ON TableA.Id = TableB.CId
WHERE TableB.CId = 1
Hope this helps.
Edit:
The output you desired, can be achieved if you match TableA's ID column with TableB's ID column, NOT TableB's CId column. Try below which I tested in my pc and gives thee similar output you needed.
select TableA.Id, TableA.Name, TableB.CId
from TableA
left outer join TableB on TableA.Id = TableB.Id
and TableB.CId in
(
select TableB.CId
from TableB
left outer join TableC on TableB.CId = TableC.Id
WHERE TableB.CId = 1
)
group by TableA.Id, TableA.Name, TableB.CId
Please inform if I guess it right. Check the column names.

SQL Select Statement issue - returning rows conditionally on a 2nd table

I could really use some help with the following SQL Select statement scenario:
I need to select all rows from a table conditionally depending on whether a userID has already entered data into a second table with the same ID.
Example:
Select all rows from TABLE A for idNumber where idNumber not in
TABLE B
but for each idNumber that IS in TABLE B, still return row unless a
specific userID is in that row in TABLE B.
TABLE A
========
idNumber|type|Date
1 A 01/01/01
2 A 01/01/01
3 B 01/01/01
4 B 01/01/01
5 B 01/01/01
TABLE B
========
idNumber|type|userID
1 A 0000
3 B 0000
4 B 1111
userID to exclude records for = 1111
SQL Query should return:
idNumber|type|Date
1 A 01/01/01
2 A 01/01/01
3 B 01/01/01
5 B 01/01/01
Apologies for the long winded post but i hope it makes sense.
Many thanks in advance,
ukjezza.!!
Select idNumber, type, Date
From TableA
Where Not Exists (
Select 1
From TableB
Where TableB.idNumber = TableA.idNumber
And TableB.userID = 1111
)
Another choice:
Select TableA.idNumber, TableA.type, TableA.Date
From TableA
Left Join TableB
On TableB.idNumber = TableA.idNumber
And TableB.userId = 1111
Where TableB.idNumber Is Null
Looks like a LEFT JOIN and COALESCE could take care of it:
SELECT a.*
FROM TableA as a
LEFT JOIN TableB as b
ON a.idNumber = b.idNumber
WHERE COALESCE(b.userID, -1) != 1111
select A.*
from TableA as A
left outer join TableB as B
on A.idNumber = B.idNumber
where B.idNumber is null or
B.userID <> '1111'

SQL query help

Sorry for posting this question again. I rephrased my question a little bit.
I am trying to write a query to return rows from Table-A where multiple rows found in Table-B with STATUS = 1 for each CID column from Table-A.
So in this example CID 100 has two records found in Table-B and STATUS = 1. So I want to write a query to return this row from Table-A. I know this is a weird table design. Please help.
Here are the tables with sample data.
Table-A
-----------------------------------------
AID Name CID
---------------------------------------
10 test1 100
12 test1 100
13 test2 101
14 test2 101
15 test3 102
Table-B
------------------------------------
bID AID status
-----------------------------------
1 10 1
2 12 1
3 14 1
4 15 1
Try this query:
SELECT TableA.CID
FROM TableA
JOIN TableB ON TableA.AID = TableB.AID
WHERE TableB.status = 1
GROUP BY TableA.CID
HAVING COUNT(*) > 1
It returns 100 for your example data.
Something like this?
select aid,
status
from (select aid,
count(*) as cnt
from tableA
group by aid) as aggregated
left join tableB on tableB.aid = aggregated.aid
where aggregated.cnt > 1
If your using SQL:
WITH tableBView AS
(
SELECT AID AS xxxAID
FROM [Table-B]
WHERE status = 1
GROUP BY AID
HAVING COUNT(*) > 0
)
SELECT *
FROM [Table-A]
WHERE EXISTS (SELECT * FROM tableBView WHERE xxxAID = AID)
SELECT *
FROM Table-A a
WHERE a.CID IN
(
SELECT a.CID FROM Table-A a JOIN Table-B b USING (AID)
GROUP BY a.CID
WHERE b.status = 1
HAVING count(*) > 1
)
This is a very verbose way to do it.
Selects all columns from Table-A on rows where AID match between Table-A and Table-B and more than one row with the same CID exists in Table-A:
(Btw, I wouldn't use "-" in your table/column names. Use "_" instead.)
select
derived_table.AID,
derived_table.Name,
derived_table.CID
from
(select
table_A.AID,
table_A.Name,
table_A.CID,
count(table_A.CID) c
from
Table_A
inner join Table_B on (Table_A.AID = table_B.AID)
group by table_A.CID
) derived_table
where
c > 1