awk to match file 1 with file 2 and average field 7 - awk

Question

I am trying to match all the file 1 names in file 2 and average them if there is a match. The field where the match will be is $5 before the | symbol and the average is the sum of $7 that matches $4. Thank you :).
file 1
AGRN
CYP2J2
file 2
chr1 955543 955763 chr1:955543 AGRN-6|gc=75 1 2
chr1 955543 955763 chr1:955543 AGRN-6|gc=75 2 2
chr1 955543 955763 chr1:955543 AGRN-6|gc=75 3 2
chr1 957571 957852 chr1:957571 AGRN-7|gc=61.2 1 148
chr1 957571 957852 chr1:957571 AGRN-7|gc=61.2 2 149
chr1 957571 957852 chr1:957571 AGRN-7|gc=61.2 3 151
chr1 60381600 60381782 chr1:60381600 CYP2J2-1596|gc=40.7 153 274
chr1 60381600 60381782 chr1:60381600 CYP2J2-1596|gc=40.7 154 273
Desired output (tab-delimited)
chr1:955543 AGRN-6 2
chr1:957571 AGRN 149.3
chr1:60381600 CYP2J2-1596 153.5
I have tried so far:
awk '
FNR==NR{d[$0]; next;}
{
for(k in d){
pat="(^|;)"k":";
if($5 ~ pat){
print;
break;
}
}
}' file 1 file2 > output.bed
The awk does run but the output file, as of now, is 0 bytes. Thank you :).

Answer 1

The script should look like this:
test.awk
BEGIN {
FS="[ \t|]*"
}
# Read search terms from file1 into 's'
FNR==NR {
s[$0]
next
}
{
# Check if $5 matches one of the search terms
for(i in s) {
if($5 ~ i) {
# Store first two fields for later usage
a[$5]=$1
b[$5]=$2
# Add $9 to total of $9 per $5
t[$5]+=$8
# Increment count of occurences of $5
c[$5]++
next
}
}
}
END {
# Calculate average and print output for all search terms
# that has been found
for( i in t ) {
avg = t[i] / c[i]
printf("%s:%s\t%s\t%s\n", a[i], b[i], i, avg)
}
}
Call it like:
awk -f test.awk file1 file2
Btw, the third avg in your expected output is wrong. The output should look like this:
chr1:955543 AGRN-6 2
chr1:957571 AGRN-7 149.333
chr1:60381600 CYP2J2-1596 273.5