How do you exclude another table from a query in SQL Server? - sql

Let's assume you have the following two SQL Server tables:
t1:
|----------------------------------------------|
|name | day_planed | day_canceled | discription|
|----------------------------------------------|
|alpha| 2015-11-02 | 2015-11-01 | some |
|alpha| 2015-11-02 | 2015-10-30 | text |
|beta | 2015-11-02 | 2015-11-01 | here |
|----------------------------------------------|
t2:
|----------------------------------------------|
|name | day_planed | day_canceled | discription|
|----------------------------------------------|
|alpha| 2015-11-02 | 2015-10-30 | text |
|----------------------------------------------|
In an query of t1 I now want every entry except those of t2. I already tried something similar to
SELECT *
FROM t1 AS A
LEFT JOIN t2 as B ON (A.name = B.name
AND A.day_planed = B.day_planed
AND A.day_canceled != B.day_canceled)
Unfortunately I don't get it why it does not exclude the row from t2 in the query of t1.
A second question would be, if there is actual an easy way to make a query of t1 without t2 by just returning the row with the maximum description. I tried looking into it in SQL Server, but could only find the first identifier, which does not work for this "wonderful" implementation of sql...

There are a few ways to do it in this "wonderful" implementation.
SELECT * FROM t1
EXCEPT
SELECT * FROM t2
is one. Another is:
SELECT *
FROM t1
WHERE NOT EXISTS
( SELECT *
FROM t2
WHERE t2.name = t1.name
AND t2.day_planed = t1.day_planed
AND t2.day_canceled = t1.day_canceled
)
Or you could use LEFT JOIN and check for rows that didn't match with WHERE t2.name IS NULL after your ON clause. Like what you have but with = instead of !=
SELECT t1.*
FROM t1
LEFT JOIN t2
ON t2.name = t1.name
AND t2.day_planed = t1.day_planed
AND t2.day_canceled = t1.day_canceled
WHERE t2.name IS NULL;
If you want to check every column (including discription), go with EXCEPT.

You are just missing a where clause and a condition on discription. You also need to change != to =.
SELECT *
FROM t1 AS A
LEFT JOIN t2 as B ON (A.name = B.name
AND A.day_planed = B.day_planed
AND A.day_canceled = B.day_canceled
AND A.discription = B.discription)
WHERE B.Name IS NULL

Related

How to group total amount spend based on both ID and name

i have a table where
patientId | Units | Amount | PatientName
1234 | 1 | 20 |lisa
1111 | 5 | 10 |john
1234 | 10 | 200 |lisa
345 | 2 | 30 | xyz
i want to get ID in one column, then patient name then total amount spent by him on different items,
please note i have got patient name in the column above by doing a join on 2 tables using ID as the key
i am doing this to get this table
select t1.*,t2.name from table1 as t1 inner join table2 as t2
on t1.id = t2.id
then for adding i am trying to use the group by clause but that gives an error
please note i cannot use temp table in this, only need to do this using subquery, how to do it?
Are you looking for group by?
select t1.patientid, t2.patientname, sum(t1.amount)
from table1 t1 join
table2 t2
on t1.id = t2.id
group by t1.patientid, t2.patientname;
select t1.*,
t2.name
from table1 t1
inner join table2 t2
on t1.id = t2.id
group by t1.id, t2.name
What are table1 and table2 like? What's the error message?

What is the correct way from performance perspective to match(replace) every value in every row in temp table using SQL Server 2016 or 2017?

I am wondering what should I use in SQL Server 2016 or 2017 (CTE, LOOP, JOINS, CURSOR, REPLACE, etc) to match (replace) every value in every row in temp table? What is the best solution from performance perspective?
Source Table
|id |id2|
| 1 | 2 |
| 2 | 1 |
| 1 | 1 |
| 2 | 2 |
Mapping Table
|id |newid|
| 1 | 3 |
| 2 | 4 |
Expected result
|id |id2|
| 3 | 4 |
| 4 | 3 |
| 3 | 3 |
| 4 | 4 |
You may join the second table to the first table twice:
WITH cte AS (
SELECT
t1.id AS id_old,
t1.id2 AS id2_old,
t2a.newid AS id_new,
t2b.newid AS id2_new
FROM table1 t1
LEFT JOIN table2 t2a
ON t1.id = t2a.id
LEFT JOIN table2 t2b
ON t1.id2 = t2b.id
)
UPDATE cte
SET
id_old = id_new,
id2_old = id2_new;
Demo
Not sure if you want just a select here, or maybe an update, or an insert into another table. In any case, the core logic I gave above should work for all these cases.
You'd need to apply joins on update query. Something like this:
Update tblA set column1 = 'something', column2 = 'something'
from actualName tblA
inner join MappingTable tblB
on tblA.ID = tblB.ID
this query will compare eachrow with ids and if matched then it will update/replace the value of the column as you desire. :)
Do the self join only
SELECT t1.id2 as id, t2.id2
FROM table1 t
INNER JOIN table2 t1 on t1.id = t.id
INNER JOIN table2 t2 on t2.id = t.id2
This may have best performance from solutions posted here if you have indexes set appropriately:
select (select [newid] from MappingTable where id = [ST].[id]) [id],
(select [newid] from MappingTable where id = [ST].[id2]) [id2]
from SourecTable [ST]

Differentiate null and empty in Postgres JOIN query

If I have tables like this:
t1:
id | name
----+------
1 | a
2 | b
3 | c
4 | d
t2:
id | value
----+-------
10 | xxx
20 | yyy
30 | zzz
t_join:
t1_id | t2_id
-------+-------
1 | 10
2 | 20
3 | 30
A SELECT query for t1.id=1 looks like:
SELECT t1.id, t1.name, t2.value FROM t1, t2,t_join WHERE t1.id=t_join.t1_id AND t2.id=t_join.t2_id AND t1.id=1;
And of course returns:
id | name | value
----+------+-------
1 | a | xxx
If I do the same thing with id=4, I get nothing.
SELECT t1.id, t1.name, t2.value FROM t1, t2,t_join WHERE t1.id=t_join.t1_id AND t2.id=t_join.t2_id AND t1.id=4;
id | name | value
----+------+-------
(0 rows)
And, if I do the same thing with a nonsense id=1234132, I also get nothing.
SELECT t1.id, t1.name, t2.value FROM t1, t2,t_join WHERE t1.id=t_join.t1_id AND t2.id=t_join.t2_id AND t1.id=1234132;
id | name | value
----+------+-------
(0 rows)
Is there a way I can differentiate between having an empty result (id=4) vs something that's null (id=1234132)? I guess I want verification that the id I'm checking exists without a separate query. Is this possible?
How about a left join:
SELECT t1.id, t1.name, t2.value
FROM t1 LEFT JOIN
t_join
ON t1.id = t_join.t1_id LEFT JOIN
t2
ON t2.id = t_join.t2_id
WHERE t1.id = 1;
If t.id is not found, you'll get no rows. If there are no matches in t2, then you'll get a NULL value.
Also, a simple rule: Never use commas in the FROM clause. Always, always use proper, explicit JOIN syntax.

Joining two sql tables with a one to many relationship, but want the max of the second table

I am trying to join two tables one is a unique feature the seconds is readings taken on several dates that relate to the unique features. I want all of the records in the first table plus the most recent reading. I was able to get the results I was looking for before adding the shape field. By using the code
SELECT
Table1.Name, Table1.ID, Table1.Shape,
Max(Table2.DATE) as Date
FROM
Table1
LEFT OUTER JOIN
Table2 ON Table1.ID = table2.ID
GROUP BY
Table1.Name, Table1.ID, Table1.Shape
The shape field is a geometry type and I get the error
'The type "Geometry" is not comparable. It can not be use in the Group By Clause'
So I need to go about it a different way, but not sure how.
Below is a sample of the two tables and the desired results.
Table1
Name| ID |Shape
AA1 | 1 | X
BA2 | 2 | Y
CA1 | 3 | Z
CA2 | 4 | Q
Table2
ID | Date
1 | 5/27/2013
1 | 6/27/2014
2 | 5/27/2013
2 | 6/27/2014
3 | 5/27/2013
3 | 6/27/2014
My Desired Result is
Name| ID |Shape |Date
AA1 | 1 | X | 6/27/2014
BA2 | 2 | Y | 6/27/2014
CA1 | 3 | Z | 6/27/2014
CA2 | 4 | Q | Null
You can do the aggregation on Table2 in a CTE, finding the MAX(DATE) for each ID, and then join that result to Table1:
WITH AggregatedTable2(ID, MaxDate) AS
(
SELECT
ID, MAX(DATE)
FROM
Table2
GROUP BY
ID
)
SELECT
t1.ID, t1.Name, t1.Shape, t2.MaxDate
FROM
Table1 t1
LEFT JOIN
AggregatedTable2 t2 ON t1.ID = t2.ID
Try casting geometry as a varchar.
Select Table1.Name, Table1.ID, cast(Table1.Shape as varchar(1)) AS Shape, Max(Table2.DATE) as Date
FROM Table1 LEFT OUTER JOIN
Table2 ON Table1.ID = table2.ID
Group By Table1.Name, Table1.ID, cast(Table1.Shape as varchar(1))
Try this:
SELECT t1.Name
, t1.ID
, t1.Shape
, MAX(t2.Date) As Date
FROM Table1 AS t1
LEFT JOIN Table2 AS t2
ON t2.ID = t1.ID
GROUP
BY t1.Name
, t1.ID
, t1.Shape

Database to return multi-dimensional result

This is a follow-up question to my previous one.
Situation:
Table 1:
+--------------------+--------------------+
| v_id | v_name |
+--------------------+--------------------+
| 1 | v_name1 |
+--------------------+--------------------+
| etc...
Table 2:
+--------------------+--------------------+
| a_id | a_name |
+--------------------+--------------------+
| 1 | a_name1 |
+--------------------+--------------------+
| etc...
Table 3:
+--------------------+--------------------+
| v_id | a_id |
+--------------------+--------------------+
| 1 | 1 |
+--------------------+--------------------+
| 1 | 2 |
+--------------------+--------------------+
| 1 | 3 |
+--------------------+--------------------+
I want to get a join of the two tables:
SELECT t1.*, t2.a_name
FROM `table1` t1
LEFT JOIN `table_3` t3 ON t3.v_id = t1.v_id
LEFT JOIN `table_2` t2 ON t2.a_id = t3.a_id
WHERE t1.id = 1;
The result of this query will be 3 rows for the given tables, each row with the same values from Table 1, just a different a_name from Table 3.
Now, is it possible for me to make a_name an array (of 3 cells in this case)? I think that this is not possible. If it's not, how would I have to build the query so that it would return just one row, with the a_name results joined with a given 'glue' string?
EDIT
If I were to get a result in PHP, I would expect something like:
$result = array(
'v_id' => 1,
'a_name' => array('a_name1', 'a_name2', 'a_name3')
);
or
$result = array(
'v_id' => 1,
'a_name' =>'a_name1, a_name2, a_name3'), # assuming I used ', ' as the glue string
);
I believe you are looking for the GROUP_CONCAT function.
In your query it would look like this:
SELECT t1.*, GROUP_CONCAT(t2.a_name SEPARATOR ',')
FROM `table1` t1
LEFT JOIN `table_3` t3 ON t3.v_id = t1.v_id
LEFT JOIN `table_2` t2 ON t2.a_id = t3.a_id
WHERE t1.id = 1
GROUP BY [list of t1 columns here]
-- update thanks to OMG Ponies.
Use:
SELECT t1.*,
GROUP_CONCAT(DISTINCT t2.a_name SEPARATOR ',')
FROM `table1` t1
LEFT JOIN `table_3` t3 ON t3.v_id = t1.v_id
LEFT JOIN `table_2` t2 ON t2.a_id = t3.a_id
WHERE t1.id = 1
GROUP BY [list of t1 columns here]
Sean Viera's answer works as you pointed out because of the WHERE clause, and because MySQL allows for columns to be omitted from the GROUP BY. It's not a good habit - only MySQL allows this, and such queries will not port to other databases (there's lots of examples on SO).
I added the distinct in the GROUP_CONCAT - didn't think you want duplicates if any exist.