I want to select one value and retrieve it into multi rows i tried to search about this case but i didn't find the write way to sole it and
and finaly sorry for my English
try select your_value, t.* from table t
Related
I want to select rows that have more thank k values in a repeated field. (consider for example selecting user that have more than 3 email addresses)
In Standard SQL I know I can use
SELECT * FROM dataset.users
WHERE array_length(email_address) > 3
But what is the way to do this in BigQuery legacy SQL?
No need for a subquery; you should be able to filter with OMIT RECORD IF directly:
SELECT *
FROM dataset.users
OMIT RECORD IF COUNT(email_address) <= 3;
Do you mind commenting on why you want to use legacy SQL, though? If you encountered a problem with standard SQL I'd like to understand what it was so that we can fix it. Thanks!
Counting Values in a repeated field in BigQuery
BigQuery Legacy SQL
SELECT COUNT(email_address) WITHIN RECORD AS address_count
FROM [dataset.users]
If you want then to count output rows - you can use below
SELECT COUNT(1) AS rows_count
FROM (
SELECT COUNT(email_address) WITHIN RECORD AS address_count
FROM [dataset.users]
)
WHERE address_count> 3
I want to get the sequence for the id column in the tags table as
SELECT pg_get_serial_sequence(‘tags’, ‘id’);
And then I want to use the result from the above Query (the sequence) as an input to the second query. Let s say the first query is called sequence
I want to perform the second query as:
SELECT setval(**sequence**, SELECT max(id) FROM tags);
Any idea on how to do this ?
You can use ActiveRecord::Base.connection.execute("your SQL query here").
I would like to ask if it is possible to do this:
For example the search string is '009' -> (consider the digits as string)
is it possible to have a query that will return any occurrences of this on the database not considering the order.
for this example it will return
'009'
'090'
'900'
given these exists on the database. thanks!!!!
Use the Like operator.
For Example :-
SELECT Marks FROM Report WHERE Marks LIKE '%009%' OR '%090%' OR '%900%'
Split the string into individual characters, select all rows containing the first character and put them in a temporary table, then select all rows from the temporary table that contain the second character and put these in a temporary table, then select all rows from that temporary table that contain the third character.
Of course, there are probably many ways to optimize this, but I see no reason why it would not be possible to make a query like that work.
It can not be achieved in a straight forward way as there is no sort() function for a particular value like there is lower(), upper() functions.
But there is some workarounds like -
Suppose you are running query for COL A, maintain another column SORTED_A where from application level you keep the sorted value of COL A
Then when you execute query - sort the searchToken and run select query with matching sorted searchToken with the SORTED_A column
Does SQLite offer a way to search every column of a table for a searchkey?
SELECT * FROM table WHERE id LIKE ...
Selects all rows where ... was found in the column id. But instead to only search in the column id, I want to search in every column if the searchstring was found. I believe this does not work:
SELECT * FROM table WHERE * LIKE ...
Is that possible? Or what would be the next easy way?
I use Python 3 to query the SQLite database. Should I go the route to search through the dictionary after the query was executed and data returned?
A simple trick you can do is:
SELECT *
FROM table
WHERE ((col1+col2+col3+col4) LIKE '%something%')
This will select the record if any of these 4 columns contain the word "something".
No; you would have to list or concatenate every column in the query, or reorganize your database so that you have fewer columns.
SQLite has full-text search tables where you can search all columns at once, but such tables do not work efficiently with any other queries.
I could not comment on #raging-bull answer. So I had to write a new one. My problem was, that I have columns with null values and got no results because the "search string" was null.
Using coalesce I could solve that problem. Here sqlite chooses the column content, or if it is null an empty string (""). So there is an actual search string available.
SELECT *
FROM table
WHERE (coalesce(col1,"") || coalesce(col2,"") || coalesce(col3,"") || coalesce(col4,"")) LIKE '%something%')
I'm not quite sure, if I understood your question.
If you want the whole row returned, when id=searchkey, then:
select * from table where id=searchkey;
If you want to have specific columns from the row with the correct searchkey:
select col1, col2, col3 from table where id=searchkey;
If you want to search multiple columns for the "id": First narrow down which columns this could be found in - you don't want to search the whole table! Then:
select * from table where col1=searchkey or col2=searchkey or col3=searchkey;
hi in my database i am store more than 50 field with primarykey (Auto increment) i am not sure about the fields name but i wants to select the entire data in that table , i am using
SELECT * FROM tablename
i want to select all the fields except that ID but this query populate the entire table so is there is possible to unselect the particular field in the select query. Can anyone have an idea please guide me. Thanks in Advance
The * indicates that you want to select ALL fields from a given table. If you want to select only a few fields, or all but one, then you will need to specify the ones you want manually:
select field1,field2,field3 from tablename
The SQL standard does not offer an "except" notation. It would be neat if we could
select t.* -t.ID
from some_table t
/
but it is not supported.
On the other hand, SELECT * is a dangerous construct. It is always better to explicitly list the columns we want in any given situation.