How can I order a row into first position? - sql

Question

I have this form :
$builder
->add('restaurantsFilter1', 'entity', [
'label' => 'Commune',
'empty_value' => 'Dans toute la Narbonnaise',
'class' => 'AppBundle:City',
'choice_label' => 'name',
'query_builder' => function (EntityRepository $er) {
return $er
->createQueryBuilder('c')
->addSelect('d')
->leftJoin('c.documents', 'd')
->where('d.type = :type')
->orderBy('c.name')
->setParameter('type', Document::T_VILLAGE)
;
},
])
which is a select which displays a list of cities.
A client told me that he needed a field "Around me" which will display all cities around 20 km.
So to do so, I created a new city in my database with this name, but now I need to put it in the first position of my select.
In sql I would use something like ORDER BY (insee_code= '[specific_code_of_the_city]') but I dont know how I could that with the query builder.
Do you have an idea how I could do that with the symfony query builder ?
EDIT: That's the exact issue that How do I return rows with a specific value first?

Answer 1

You could create a hidden field and order by that.
return $er
->createQueryBuilder('c')
->addSelect('CASE
WHEN c.name = "specific_code_of_city"
THEN 0
ELSE 1
END as HIDDEN presetOrder')
->addSelect('d')
->leftJoin('c.documents', 'd')
->where('d.type = :type')
->orderBy('presetOrder', 'ASC')
->addOrderBy('c.name', 'ASC')
->setParameter('type', Document::T_VILLAGE)
;