Suppose I have a scala project like this:
And I symlink another folder /tmp/outside as scala/outside (outside may contain subdiretories), how can I make it appear as a source folder in intellij?
Related
I've been using CLion for a little while now, and I quite like it, except that it stores it's prject files by default in my CMake project. I am wondering if I can set a default place it stores it's project files(like compiled executables) in specific directory, per project.(So not one big folder that might interfere with other projects). The reason I want to do that is because I don't like having it in my git project(yes, I know about .gitignore) Anyone know how to do that?
Thanks!
To use a different folder for CLion building
In the CLion menu:
Build,Execution,Deployment -> Cmake -> Generation Path
Change the value to the folder path you want.
To include source code from a different folder out of current
In your CMakeLists.txt, add subdirectory like following:
add_subdirectory(<PATH_OF_YOUR_ANOTHER_CMAKE_PROJECT>)
Be aware PATH_OF_YOUR_ANOTHER_CMAKE_PROJECT can be anywhere on your computer, which does not have to be in your current project folder or one of the sub-folders.
So, something has started to act weird in my intelliJ project. I even tried removing the iml and .idea data, to no avail.
I go to Project Structure. There, I have a content root. Withing, I have three folders - one for my jar (and jni lib), one for Samples and one for Tools (just tools written to use the jar). The jar, Samples and Tools are marked blue (sources).
In the jar folder, I have my source tree (com\company\projectname\XXX), a lib folder, a folder for my JNI lib and a folder I created call 'junit', which is the focus of this question. It is marked in Project Structure in green (Tests).
Within, I have a folder structure eerily similar to my code: com\company\projectname\junit.
When I open a file in junit\com\company\xxx\junit, I have a big red underline under my package com.company.xxx.junit; line which tells me: "Package name 'com.company.xxx.junit' does not correspond to the file path 'junit.com.company.xxx.junit'.
I was under the impression that marking a folder as 'Tests' would instruct the IDE to use that as a "parent" folder, if you will, eliminating the need to prepend another folder name.
How can I separate the code from unit tests and in fact, create two junit test suites (one is for internal use, the other is a 'skeleton' for distribution), park them under one "umbrella" folder and NOT have to prepend the package names with that folder name?
Update: Project structure:
Based on your screen shot, the issue is that the junit directory is a subdirectory of another source directory, namely MyProvider. A source directory (whether a "production" source or a unit test source directory) cannot be a subdirectory of another source directory.
You need to either:
move the junit directory out of MyProvider so it is a sibling directory, or
unmark MyProvider as a source directory, create a main (or some such directory) in MyProvider, mark it as a source directory, and then move the com directory/package into main.
Option 2 would be the preferred way to deal with this as it follows a very common directory structure standard.
UPDATE (Following comment from OP)
Here's a couple of screenshot showing the configuration you desire:
I removed the .IdeaIC15 folder and started over. Working for now. Something must have gotten confused in the config, either as part of the update, or in the course of operation. I have taken a backup copy as it is now, so if this happens again, I will have something to check.
Is it possible to rename the .idea folder that's automatically created by IntelliJ or move it to a different location?
Renaming the .idea directory is not possible; IntelliJ IDEA always reads project files from the directory with that exact name, and it can't be changed.
Moving is sort of possible. The locations and content roots of modules in IntelliJ IDEA are completely independent from the location of the project itself. Because of that, you can create a project in a directory that doesn't contain any code, and set up modules with content roots pointing to the directories where the code is located.
Recently set up a multi module project in IntelliJ with the following structure:
/module1
/module2
/web-module
/sql
/lib
/a few more folders
I set up module1+2 and web-module as modules in IntelliJ so those show up, but how do you make the sql and lib folder show up in the project panel? They should be included in VCS as well, but IntelliJ ignores them. How do you add folders outside modules to a project?
Screenshot of project and explorer view:
This is not a strict answer to the question, but it worked for me so I'm posting, perhaps someone will find this useful.
If you want to add an arbitrary folder to your project (even from some different location than your projects), just add it as a module. You needn't worry about the type so much e.g. I needed to add a folder with some SQL scripts, I added it as a Java module and it's nicely visible in IntelliJ even though it has no maven structure or Java sources.
This is how to do it:
File > Project Structure > Modules
Add > New Module > ... (e.g. Java Module)
In the new module settings mark the subfolders that you want to see as 'Sources'
Voilà! :)
This is something that I typically see when creating a project from existing modules. All the modules will show in the project but not the other project related directories. These directories might be, configuration files, environment scripts or bundles of SQL scripts that don't fit neatly into an Intellij module type.
To show the rest of the project source files and directories, I create a parent module from the project root.
File->Project Structure->Modules
Create a new module using the + sign. The new module could be any type (I use java).
On the Next screen set the Content root and Module file location to the Project's root folder.
Select Finish
All of your other modules should now be submodules of the root, and your other project files should now show up.
Add and remove content roots
To add a new content root:
Go to File | Project Structure, or press Ctrl+Shift+Alt+S.
Select Modules under the Project Settings section.
Select the necessary module, and then open the Sources tab in the right-hand part of the dialog.
Click Add Content Root.
Specify the folder that you want to add as a new content root, and click OK.
source: https://www.jetbrains.com/help/idea/creating-and-managing-modules.html
I used File -> New -> Module from Existing Sources...
Then I simply select the folder and add it.
In Project view mode all directories (except the ignored ones from the settings) should show up. Of course the base folder for your multi-project has to be the folder above module1.
EDIT:
Your project should look like this (project view tree):
MY_PROJECT_ROOT (~/the/folder/to/your/project)
|- /module1
|- /module2
|- /web-module
And in this case, you should definitely see the other folders. I got a sample project set up where this is working.
EDIT 2:
From your screenshot, I assume you are missing the root directory (the project root is not as you expected). I added another screenshot. There should be a single root folder for your 3 modules. This one is missing at your screenshot. You have 3 separate folders with no common root folder. On MacOs, the project root is displayed in the window title. In my case it points to ~/devel/sandbox.
I guess you should try to create a new project in for that trunk folder. From the scratch. Then add the existing modules and you should be fine?!
It seems that MsBuild creates a folder called, "BuildType" on the build server and this folder is where the .proj file is copied. In source control I have several files that are in the same folder as the build project file. I have a workspace mapped to this location.
I would like to be able to specify explicitly which files from this workspace location should be copied to the build machine. Is this possible?
Thanks!
You cannot do this on file level but if you organize your build type folder with subfolders you can cloak the folders that you want to exclude.