I have this query:
SELECT
A.USERID
A.NAME
PVT.PHONE 'PROBABLY A CASE STATEMENT ON NULL WILL GO HERE...
PVT.ADDRESS 'ON HERE AS WELL...
FROM
USERS A
'I NEED TO CREATE A PIVOT TABLE HERE WITH THE ALIAS OF 'PVT' ON TABLE 'B'
B Contents:
UserID PHONE ADDRESS TYPE
1 444-555-2222 XXXXXXX PHONE
1 XXXXXXX 66 Nowhere NOTADDRESS
I want, on the same row, the user's phone by getting B.PHONE if TYPE = 'PHONE'.
I also want, on the same row, the user's address by getting B.ADDRESS content if TYPE = 'ADDRESS'.
As you see in the table dump above, I don't have a record matching the user ID AND TYPE = 'ADDRESS'
So I would need to show a blank or 'No address' in the main SELECT which will show the phone, but on the same row, blank or 'No address'.
I don't want to create an INNER JOIN because if there are no matching UserID's in B, the query will not return the info that I have in table A for that user.
Also, a LEFT JOIN will create two rows, which I don't want.
I think I pivoted table as alias would do it, but I don't know how to create such an alias.
Any ideas ?
How about using conditional aggregation?
SELECT A.USERID, A.NAME
B.PHONE, B.ADDRESS
FROM USERS A LEFT JOIN
(SELECT UserId, MAX(CASE WHEN TYPE = 'PHONE' THEN PHONE END) as PHONE,
MAX(CASE WHEN TYPE = 'ADDRESS' THEN ADDRESS END) as ADDRESS
FROM B
GROUP BY UserId
) B
ON B.UserId = A.UserId;
If you have to use PIVOT then you'd need the pivot in a subquery and left join to it
SELECT
A.USERID,
A.NAME,
PVT.PHONE,
PVT.[ADDRESS]
FROM
Users A
LEFT JOIN (SELECT *
FROM
(SELECT
UserID,
[Type],
(CASE [Type] WHEN 'PHONE' THEN PHONE WHEN 'ADDRESS' THEN [Address] END) Info
FROM UserInfo) AS UI
PIVOT (
MAX(Info)
FOR [Type] IN ([PHONE], [ADDRESS])
) P
) PVT ON A.UserID = PVT.UserID
This gives you pretty much the same execution plan as the conditional aggregation query, but not as easy on the eyes.
SQL Fiddle
Related
I'm just at the beginning of my SQL studies and can't figure out how to resolve the next problem.
So, there are three tables:
! given tables
The task is: "Get number of pet type per owner"
Write a query to generate the result below:
! desired output
The best result I have for the moment:
SELECT owners.OWNER_NAME, COUNT(pets.OWNER_ID) AS pets
FROM owners
JOIN pets ON owners.ID = pets.OWNER_ID
JOIN pet_type ON pets.TYPE = pet_type.ID
GROUP BY owners.OWNER_NAME;
It returns first column with owner names and second column with the sum of particular owner pets.
Will appreciate any help.
You need conditional aggregation:
SELECT
o.OWNER_NAME,
SUM(CASE WHEN t.name = 'CAT' THEN 1 ELSE 0 END) CAT,
SUM(CASE WHEN t.name = 'DOG' THEN 1 ELSE 0 END) DOG,
SUM(CASE WHEN t.name = 'SNAKE' THEN 1 ELSE 0 END) SNAKE
FROM owners o
JOIN pets p ON o.ID = p.OWNER_ID
JOIN pet_type t ON p.TYPE = t.ID
GROUP BY o.OWNER_NAME;
I use name as the name of the column describing the type in table pet_type. Change it to the actual name of the column.
Check this. To Get number of pet type per owner, this is sufficient to join only Pets table with the owners table. A DISTINCT count of Pet.Type will give your desired output.
SELECT
owners.ID,
owners.OWNER_NAME,
COUNT(DISTINCT pets.TYPE) AS Num_Pet_Type
FROM owners
INNER JOIN pets ON owners.ID = pets.OWNER_ID
GROUP BY owners.ID,owners.OWNER_NAME;
If you wants number of Pet per type, use this below script-
SELECT
owners.ID,
owners.OWNER_NAME,
pets.TYPE,
COUNT(*) AS Num_Of_Pet
FROM owners
INNER JOIN pets ON owners.ID = pets.OWNER_ID
GROUP BY owners.ID,owners.OWNER_NAME,pets.TYPE;
Here are the two table structures
I have two tables where I am trying to fetch some duplicate records based on some condition like where a.fname=b.fname and a.phone_no<>b.phone_no
But also I need to include other column 'address' which is in table 2 and introduce the same condition for duplicate checking for address as well.
SELECT
"Fname"||' '||"Lname" AS "Customer_Name",
COUNT(*) AS "Countof"
FROM "S_CONTACT" A
WHERE EXISTS (
SELECT 1
FROM "S_CONTACT" B
WHERE A."PHONE" != B."PHONE"
AND A."Fname" = B."Fname"
AND A."EMAIL"=B."EMAIL"
AND A."Lname"=B."Lname"
AND "DOB" IS NULL
)
GROUP BY "Fname","Lname","EMAIL"
HAVING count(*) >1;
The above sql gives me a list of customers with duplicate names and email.
But I do not know how to introduce the column address in this sql which is from different table t2
If you are trying to find duplicates in one table:
select c.fname, c.lname, c.email
from contacts c
group by c.fname, c.lname, c.email
having min(c.phone) <> max(c.phone);
If you want to count null as a different value, then use:
having min(c.phone) <> max(c.phone) or count(c.phone) <> count(*)
You can do the same thing on the second table:
select c.fname, c.lname, c.email
from second_table c
group by c.fname, c.lname, c.email
having min(c.address) <> max(c.address) or count(c.address) <> count(*)
If you need the results in the same result set, then use union or union all or some similar mechanism.
I have a table (Task) like this:
Task Table
and I need answer like this:
TaskResult
I am doing the first query like this:
select
StudentID, AdmissionID, EnquiryID, EnquiryDetailsID
from
Task
where
TaskUser = 0 and BranchID = 1
If I'm getting studentID then I create second query in loop for searching the student first name and last name.
elseif I'm getting EnquiryID then I create second query in loop for searching the Enquiry first name and last name.
elseif I'm getting AdmissionID then I create second query in loop for searching the Admission guys first name and last name.
elseif I'm getting EnquiryDetailsID then I create second query in loop for searching the EnquiryDetails first name and last name.
So it creates loop in a loop and I get heavy load time on the page.
I need to combine both queries into one query. So page won't be loading.
I only have two elements i.e. taskUser and BranchID.
Please help me!! Thanks in advance !!!
So - it looks like you have an oddly organized task table, and as a result, you're going to have to do mildly weird things to query right. According to your description, a row in the task table contains either a studentId, an admissionId, an enquiryId, or an enquiryDetailId. This isn't an optimal way to do this...but I understand that sometimes you have to get by with what you have.
So, to get the names, you have to join to the source of the names...and assuming they're all over the place, in related tables, you could do something like:
select
t.StudentID,t.AdmissionID,t.EnquiryID,t.EnquiryDetailsID,x.FirstName,x.LastName
from Task t inner join Student s on t.StudentId = s.Id
union all
select
t.StudentID,t.AdmissionID,t.EnquiryID,t.EnquiryDetailsID,x.FirstName,x.LastName
from Task t inner join Admission a on t.AdmissionId = a.Id
union all
select
t.StudentID,t.AdmissionID,t.EnquiryID,t.EnquiryDetailsID,x.FirstName,x.LastName
from Task t inner join Enquiry e on t.EnquiryId = e.Id
union all
select
t.StudentID,t.AdmissionID,t.EnquiryID,t.EnquiryDetailsID,x.FirstName,x.LastName
from Task t inner join EnquiryDetail d on t.EnquiryDetailId = d.Id
...or, you can accomplish the same thing kinda inside-out:
select
t.StudentID,
t.AdmissionID,
t.EnquiryID,
t.EnquiryDetailsID,
x.FirstName,
x.LastName
from
Task t
inner join
(
select 's' source, Id, FirstName, LastName from Student union all
select 'a' source, Id, FirstName, LastName from Admission union all
select 'e' source, Id, FirstName, LastName from Enquiry union all
select 'd' source, Id, FirstName, LastName from EnquiryDetail
) as x
on
( t.StudentId = x.Id and x.source = 's' )
or
( t.AdmissionId = x.Id and x.source = 'a' )
or
( t.EnquiryId = x.Id and x.source = 'e' )
or
( t.EnquiryDetailId = x.Id and x.source = 'd' )
where
t.TaskUser=0 and t.BranchID=1
Use LEFT JOIN with COALESCE like this:
--not tested
select StudentID, AdmissionID, EnquiryID, EnquiryDetailsID,
COALESCE(s.name, e.name, d.name, ed.name) as name, etc.
from Task t
left join student s on s.id = t.studentID
left join Enquiry e on e.id = t.EnquiryID
left join Admission d on d.id = t.AdmissionID
left join EnquiryDetails ed on ed.id = t.EnquiryDetailsID
where TaskUser=0 and BranchID=1
I have a SQL table consists of id, name, email,.... I have another SQL table that has id, email, emailstatus but these 2 id are different they are not related. The only thing that is common between these 2 tables are emails.
I would like to join these 2 tables bring all the info from table1 and if the email address from table 1 and table 2 are same and emailstatus is 'Bounced'. But the query that I am writing gives me more record than I expected because there are multiple rows in tbl_webhook(second table) for each row in Applicant(first table) .I want to know if applicant has EVER had an email bounce.
Query without join shows 23000 record but after join shows 42000 record that is because of duplicate how I can keep same 23000 record only add info from second table?
This is my query:
SELECT
A.[Id]
,A.[Application]
,A.[Loan]
,A.[Firstname]
,A.[Lastname]
,A.[Email],
,H.[Email], H.[EmailStatus] as BouncedEmail
FROM Applicant A (NOLOCK)
left outer join [tbl_Webhook] [H] (NOLOCK)
on A.Email = H.Email
and H.[event]='bounced'
this is sample of desired data:
id email name emailFromTable2 emailstatus
1 test2#yahoo.com lili test2#yahoo.com bounced
2 tesere#yahoo.com mike Null Null
3 tedfd2#yahoo.com nik tedfd2#yahoo.com bounced
4 tdfdft2#yahoo.com sam Null Null
5 tedft2#yahoo.com james tedft2#yahoo.com bounced
6 tedft2#yahoo.com San Null
Use a nested select for this type of query. I would write this as:
select id, application, load, firstname, lastname, email,
(case when BouncedEmail is not null then email end) as EmailFromTable2,
BouncedEmail
from (SELECT A.[Id], A.[Application], A.[Loan], A.[Firstname], A.[Lastname], A.[Email],
(case when exists (select 1
from tbl_WebHook h
where A.Email = H.Email and H.[event] = 'bounced'
)
then 'bounced
end) as BouncedEmail
FROM Applicant A (NOLOCK)
) a
You can also do this with cross apply, but because you only really need one column, a correlated subquery also works.
;WITH DistinctEmails
AS
(
SELECT * , rn = ROW_NUMBER() OVER (PARTITION BY [Email] ORDER BY [Email])
FROM [tbl_Webhook]
)
SELECT
A.[Id]
,A.[Application]
,A.[Loan]
,A.[Firstname]
,A.[Lastname]
,A.[Email],
,H.[Email], H.[EmailStatus] as BouncedEmail
FROM Applicant A (NOLOCK) left outer join DistinctEmails [H] (NOLOCK)
on A.Email = H.Email
WHERE H.rn = 1
and H.[event]='bounced'
i believe query below should be enough to select distinct bounced email for you, cheer :)
SELECT
A.[Id]
,A.[Application]
,A.[Loan]
,A.[Firstname]
,A.[Lastname]
,A.[Email],
,H.[Email], H.[EmailStatus] as BouncedEmail
FROM Applicant A (NOLOCK)
Inner join [tbl_Webhook] [H] (NOLOCK)
on A.Email = H.Email
and H.[EmailStatus]='bounced'
basically i just change the joining to inner join and change the 2nd table condition from event to emailstatus, if u can provide your table structure and sample data i believe i can help you up :)
I'm definitely a noob with SQL, I've been busting my head to write a complex query with the following table structure in Postgresql:
CREATE TABLE reports
(
reportid character varying(20) NOT NULL,
userid integer NOT NULL,
reporttype character varying(40) NOT NULL,
)
CREATE TABLE users
(
userid serial NOT NULL,
username character varying(20) NOT NULL,
)
The objective of the query is to fetch the amount of report types per user and display it in one column. There are three different types of reports.
A simple query with group-by will solve the problem but display it in different rows:
select count(*) as Amount,
u.username,
r.reporttype
from reports r,
users u
where r.userid=u.userid
group by u.username,r.reporttype
order by u.username
SELECT
username,
(
SELECT
COUNT(*)
FROM reports
WHERE users.userid = reports.userid && reports.reporttype = 'Type1'
) As Type1,
(
SELECT
COUNT(*)
FROM reports
WHERE users.userid = reports.userid && reports.reporttype = 'Type2'
) As Type2,
(
SELECT
COUNT(*)
FROM reports
WHERE users.userid = reports.userid && reports.reporttype = 'Type3'
) As Type3
FROM
users
WHERE
EXISTS(
SELECT
NULL
FROM
reports
WHERE
users.userid = reports.userid
)
SELECT
u.username,
COUNT(CASE r.reporttype WHEN 1 THEN 1 END) AS type1Qty,
COUNT(CASE r.reporttype WHEN 2 THEN 1 END) AS type2Qty,
COUNT(CASE r.reporttype WHEN 3 THEN 1 END) AS type3Qty
FROM reports r
INNER JOIN users u ON r.userid = u.userid
GROUP BY u.username
If your server's SQL dialect requires the ELSE branch to be present in CASE expressions, add ELSE NULL before every END.
If you're looking for the "amountof report types per user", you'll be expecting to see a number, either 1, 2 or 3 (given that there are three different types of reports) against each user. You won't be expecting the reporttype (it'll just be counted not displayed), so you don't need reporttype in either the SELECT or the GROUP BY part of the query.
Instead, use COUNT(DISTINCT r.reporttype) to count the number of different reporttypes that are used by each user.
SELECT
COUNT(DISTINCT r.reporttype) as Amount
,u.username
FROM users u
INNER JOIN reports r
ON r.userid=u.userid
GROUP BY
u.username
ORDER BY u.username