SELECT DISTINCT b.user_login
FROM wp_posts AS a JOIN wp_users AS b
WHERE a.post_author = b.ID AND a.post_type = 'tee';
This outputs what I need, it shows me the user's name.
However, I'd also like to COUNT how many times this occurred next to the user_login.
Help and explanation much appreciated.
You can do this with a GROUP BY and COUNT() aggregate:
Select b.user_login,
Count(*) As cnt
From wp_posts AS a
Join wp_users AS b On a.post_author = b.ID
Where a.post_type = 'tee'
Group By b.user_login;
It's also possible to use COUNT(DISTINCT [fieldname]). This will provide a count of unique non-null values present in [fieldname].
Related
Pretty basic SQL uses, I usually do some basic joins, and then pull data into Sheets to pivot or filter it to get what I want, but know I can do it quicker all in SQL.
For this query, I want to only return data if the c2.id count is greater than 0. I tried writing a subquery in the where clause, but feels like I need to group by task_id for this to be right...can someone help me understand what I should do and why?
select t.inserted_at::date, count (distinct c2.id), t.id, t.conversation_id
from tasks t
left join users u on u.id = t.creator_id
left join "comments" c2 on t.id = c2.task_id
left join conversations c on c.id = t.conversation_id
where u.include_in_metrics = true
and c.type = 'PROJECT_FEED'
group by 1,3,4
order by t.inserted_at::date desc;
Just add this after the group by before order by
having count(distinct c2.id)>0
i have following sql in java project:
select distinct * from drivers inner join licenses on drivers.user_id=licenses.issuer_id
inner join users on drivers.user_id=users.id
where (licenses.state='ISSUED' or drivers.status='WAITING')
and users.is_deleted=false
And result i database looks like this:
And i would like to get only one result instead of two duplicated results.
How can i do that?
Solution 1 - That's Because one of data has duplicate value write distinct keyword with only column you want like this
Select distinct id, distinct creation_date, distinct modification_date from
YourTable
Solution 2 - apply distinct only on ID and once you get id you can get all data using in query
select * from yourtable where id in (select distinct id from drivers inner join
licenses
on drivers.user_id=licenses.issuer_id
inner join users on drivers.user_id=users.id
where (licenses.state='ISSUED' or drivers.status='WAITING')
and users.is_deleted=false )
Enum fields name on select, using COALESCE for fields which value is null.
usually you dont query distinct with * (all columns), because it means if one column has the same value but the rest isn't, it will be treated as a different rows. so you have to distinct only the column you want to, then get the data
I suspect that you want left joins like this:
select *
from users u left join
drivers d
on d.user_id = u.id and d.status = 'WAITING' left join
licenses l
on d.user_id = l.issuer_id and l.state = 'ISSUED'
where u.is_deleted = false and
(d.user_id is not null or l.issuer_id is not null);
I need some help to join my tables, I used 2 tables
//table news
id_news|title|
1 |first..|
2 |second..|
//table comment
id_comment|content|id_news
1|Haha..|1
2|Hahe..|2
3|Hoho..|1
I need an output use COUNT(*) comments in id_news 1
like
id_news|title|total_comment|
1|first..|**2**|
so far my syntax like
SELECT
news.id_news,
COUNT(distinct comment.id_news)
FROM
news
inner join comment ON (comment.id_news=news.id_news)
group by
news.id_news
I think you want:
SELECT news.id_news, COUNT(*)
FROM news INNER JOIN
comment
ON comment.id_news = news.id_news
GROUP BY news.id_news;
Note the following:
The select clause uses the same column as the group by
The COUNT() is not using a distinct. In your formulation, it would always return 1, regardless of the number of comments.
If you want news items with no comments, you would use a left outer join and change the count(*) to count(comment.id_news).
Try This Query you will get the data as you want :
SELECT
news.id_news,news.title,
(select count(*) from comment group_by id_news) as total_comment
FROM
news
inner join comment ON comment.id_news=news.id_news
please can you help me before I go out of my mind. I've spent a while on this now and resorted to asking you helpful wonderful people. I have a search query:
SELECT Groups.GroupID,
Groups.GroupName,
( SELECT Sum(SiteRates.SiteMonthlySalesValue)
FROM SiteRates
WHERE InvoiceSites.SiteID = SiteRates.SiteID
) AS SumOfSiteRates,
( SELECT Count(InvoiceSites.SiteID)
FROM InvoiceSites
WHERE SiteRates.SiteID = InvoiceSites.SiteID
) AS CountOfSites
FROM (InvoiceSites
INNER JOIN (Groups
INNER JOIN SitesAndGroups
ON Groups.GroupID = SitesAndGroups.GroupID
) ON InvoiceSites.SiteID = SitesAndGroups.SiteID)
INNER JOIN SiteRates
ON InvoiceSites.SiteID = SiteRates.SiteID
GROUP BY Groups.GroupID
With the following table relationship
http://m-ls.co.uk/ExtFiles/SQL-Relationship.jpg
Without the GROUP BY entry I can get a list of the entries I want but it drills the results down by SiteID where instead I want to GROUP BY the GroupID. I know this is possible but lack the expertise to complete this.
Any help would be massively appreciated.
I think all you need to do is add groups.Name to the GROUP BY clause, however I would adopt for a slightly different approach and try to avoid the subqueries if possible. Since you have already joined to all the required tables you can just use normal aggregate functions:
SELECT Groups.GroupID,
Groups.GroupName,
SUM(SiteRates.SiteMonthlySalesValue) AS SumOfSiteRates,
COUNT(InvoiceSites.SiteID) AS CountOfSites
FROM (InvoiceSites
INNER JOIN (Groups
INNER JOIN SitesAndGroups
ON Groups.GroupID = SitesAndGroups.GroupID
) ON InvoiceSites.SiteID = SitesAndGroups.SiteID)
INNER JOIN SiteRates
ON InvoiceSites.SiteID = SiteRates.SiteID
GROUP BY Groups.GroupID, Groups.GroupName;
I think what you are looking for is something like the following:
SELECT Groups.GroupID, Groups.GroupName, SumResults.SiteID, SumResults.SumOfSiteRates, SumResults.CountOfSites
FROM Groups INNER JOIN
(
SELECT SitesAndGroups.SiteID, Sum(SiteRates.SiteMonthlySalesValue) AS SumOfSiteRates, Count(InvoiceSites.SiteID) AS CountOfSites
FROM SitesAndGroups INNER JOIN (InvoiceSites INNER JOIN SiteRates ON InvoiceSites.SiteID = SiteRates.SiteID) ON SitesAndGroups.SiteID = InvoiceSites.SiteID
GROUP BY SitesAndGroups.SiteID
) AS SumResults ON Groups.SiteID = SumResults.SiteID
This query will group your information based on the SiteID like you want. That query is referenced in the from statement linking to the Groups table to pull the group information that you want.
select
picks.`fbid`,
picks.`time`,
categories.`name` as cname,
options.`name` as oname,
users.`name`
from
picks
left join categories
on (categories.`id` = picks.`cid`)
left join options
on (options.`id` = picks.oid)
left join users
on (users.fbid = picks.`fbid`)
order by
time desc
that query returns a result that like:
my question is.... I would like to modify the query to select only DISTINCT fbid's. (perhaps the first row only sorted by time)
can someone help with this?
select
p2.fbid,
p2.time,
c.`name` as cname,
o.`name` as oname,
u.`name`
from
( select p1.fbid,
min( p1.time ) FirstTimePerID
from picks p1
group by p1.fbid ) as FirstPerID
JOIN Picks p2
on FirstPerID.fbid = p2.fbid
AND FirstPerID.FirstTimePerID = p2.time
LEFT JOIN Categories c
on p2.cid = c.id
LEFT JOIN Options o
on p2.oid = o.id
LEFT JOIN Users u
on p2.fbid = u.fbid
order by
time desc
I don't know why you originally had LEFT JOINs, as it appears that all picks must be associated with a valid category, option and user... I would then remove the left, and change them to INNER joins instead.
The first inner query grabs for each fbid, the FIRST entry time which will result in a single entity for the FBID. From that, it re-joins to the picks table for the same ID and timeslot... then continues for the rest of the category, options, users join criteria of that single entry.
2 options, you could write a group by clause.
Or you could write a nested query joined back to itself to get pertinent info.
Nested aliased table:
SELECT
n.fBids
FROM
MyTable t
INNER JOIN
(SELECT DISTINCT fBids
FROM MyTable) n
ON n.ID = t.ID
Or group by option
SELECT fBId from MyTable
GROUP BY fBID
select picks.`fbid`, picks.`time`, categories.`name` as cname,
options.`name` as oname, users.`name` from picks left join categories
on (categories.`id` = picks.`cid`) left join options on (options.`id` = picks.oid)
left join users on (users.fbid = picks.`fbid`)
order by time desc GROUP BY picks.`fbid`
select
picks.fbid,
MIN(picks.time) as first_time,
MAX(picks.time) as last_time
from
picks
group by
picks.fbid
order by
MIN(picks.time) desc
However, if you want only distinct fbid's you cannot display cname and other columns at the same time.