PIVOT over two columns - sql

Question

is there a more elegant way to implement a PIVOT on the following table - basically I am trying to count the typeid's for ever userid, as well as get the first value for each type and pivot the types and the values (using sql server 2012):
This is the expected result:
And here is what I came up with:
SELECT userid ,
MAX([1]) [1] ,
MAX([2]) [2] ,
MAX(value1) [value1] ,
MAX(value2) [value2]
FROM ( SELECT userid ,
typeid ,
FIRST_VALUE(value) OVER ( PARTITION BY userid, typeid ORDER BY testid ) [value] ,
'value' + CONVERT(VARCHAR(20), typeid) [valuepivot]
FROM dbo.test
) t PIVOT( COUNT(typeid) FOR typeid IN ( [1], [2] ) ) as pivottype
PIVOT( MAX(value) FOR [valuepivot] IN ( [value1], [value2] ) ) as pivottype2
GROUP BY userid
Table Schema:
CREATE TABLE [dbo].[Test](
PIVOT( MAX(value) FOR [valuepivot] IN ( [value1], [value2] ) ) as pivottype2
[TestID] [int] PRIMARY KEY IDENTITY(1,1) ,
[UserID] [int] NOT NULL,
[TypeID] [int] NOT NULL,
[Value] [varchar](100) NOT NULL
)
GROUP BY userid

Answer 1

I would just do this using conditional aggregation:
select userid,
sum(case when typeid = 1 then 1 else 0 end) as test1,
sum(case when typeid = 2 then 1 else 0 end) as test2,
max(case when typeid = 1 then value end) as test1,
max(case when typeid = 2 then value end) as test2
from (select t.*,
row_number() over (partition by userid, typeid order by testid) as seqnum
from test
) t
group by userid;
Whether it is simpler or not is a matter of opinion.