I have a simple table like this
Person
id,order
1;5
2;3
3;1
4;2
5;4
I need to get previous rows using order column
For example if the id parameter is 5( order = 4) , i need to return the rows id: 2,4,3.
if the id is 2(order = 3) , i need to return the rows id 4,3
Sorry if I am struggling to make me understand
I created this request but I have so trouble to make it work
select *
from Person p
where p.id= (
Select p2.id
from Person p2
where p2.id=1 /*so should return rows [ 5,2,4,3]*/
and p2.order< p2.order
)
Desired output
id,order
5;4
2;3
4;2
3;1
Thank you very much
You just need to select all with an order less than the ID-Order:
SELECT p.id
FROM Person p
WHERE "order" < (SELECT "order"
FROM Person
WHERE ID = 5)
ORDER BY "order" desc
Demo
This matches your description:
SELECT * FROM Person
WHERE "order" <
(SELECT "order" order FROM Person WHERE id = 5)
The subselect is used to retrieve the "order" of the specified row. In the subselect I performed the subtraction to find the previous value. That is used in the where clause of the select to get the rows you want.
Related
I have a big query that brings me a lot of rows, and based on each row I use this another query as a subselect.
This subselect brings me the following result rest on Oracle:
SELECT oc3.ID_ORGAO_INTELIGENCIA,
oc3.ord,
lag(oc3.ID_ORGAO_INTELIGENCIA, 1, NULL) OVER (
ORDER BY oc3.ord) ultimo
FROM
( SELECT DISTINCT oc2.*
FROM
( SELECT oc1.ID_ORGAO_INTELIGENCIA,
oc1.ID_ORGAO_INTELIGENCIA_PAI,
oc1.SG_ORGAO_INTELIGENCIA,
rownum AS ord
FROM TB_ORGAO_INTERNO oc1
WHERE oc1.DH_EXCLUSAO IS NULL START WITH oc1.ID_ORGAO_INTELIGENCIA =
-- this is a value that come from an outer select
-- If I put the value directly, like: S.ID_ORGAO_INTELIGENCIA, it does not work... I dont know why...
(SELECT sa.ID_ORGAO_INTELIGENCIA
FROM TB_SOLICITACAO sa
WHERE sa.ID_SOLICITACAO = 1077)-- s.ID_SOLICITACAO)
CONNECT BY
PRIOR oc1.ID_ORGAO_INTELIGENCIA_PAI = oc1.ID_ORGAO_INTELIGENCIA) oc2
INNER JOIN TB_PERMISSAO pe2_ ON pe2_.ID_ORGAO_INTELIGENCIA = oc2.ID_ORGAO_INTELIGENCIA
INNER JOIN TB_USUARIO u_ ON u_.ID_USUARIO = pe2_.ID_USUARIO
WHERE pe2_.ID_STATUS_PERMISSAO = 7
AND pe2_.ID_ATRIBUICAO IN :atribuicoes
ORDER BY oc2.ord) oc3
The result:
That important value from each row is the S.ID_SOLICITACAO, because based on that value that the subquery will be started.
I need to be able to filter the results by oc3.ID_ORGAO_INTELIGENCIA where it brings me all the rows before that number.
So, If I filter by 430, only the row with 311 will return.
If I filter by 329, it will bring me the: 311 and 430.
Is there a way to achieve this result?
One option might be to use your current query as a CTE, and then filter data it returns. Something like this:
with ycq as
-- your current query
(select ...
from ...
)
select *
from ycq a
where a.ord < (select b.ord
from ycq b
where b.id_orgao_inteligencia = :par_id_orgao_inteligencia
);
I am trying to get the rows where id are not in a list.
I have email with scores with several email for each score. I know how to get the max score for each email then I want to delete other rows. I try to delete all rows that are not in the list of max score but it does not work.
SELECT *
FROM mkgaction AS a
WHERE id NOT IN (SELECT id
FROM
(SELECT *
FROM mkgaction AS b
ORDER BY `score` DESC) x
GROUP BY `score`)
The select id returns me the right list but the all request returns me no line...
Do you know why?
Presumably -- if your query works at all -- you are using MySQL. The syntax in that database is:
delete ma
from mkgaction ma join
(select ma2.email, max(ma2.score) as max_score
from mkgaction ma2
group by ma2.email
) ma2
on ma.email = ma2.email and ma.score < ma2.max_score;
scenario 1:
I have two tables INFUSION_APP_APPOINTMENT,INFUSION_APP_NURSE_NOTES where
INFUSION_APP_NURSE_NOTES.APPOINTMENT_ID=INFUSION_APP_APPOINTMENT.ID and i want to find out the INFUSION_APP_NURSE_NOTES.ID's where INFUSION_APP_NURSE_NOTES.APPOINTMENT_ID is same.
for eg. if the INFUSION_APP_NURSE_NOTES.APPOINTMENT_ID = 1 and INFUSION_APP_NURSE_NOTES.ID is 12,15,78, then i want to display all the
INFUSION_APP_NURSE_NOTES.ID's where INFUSION_APP_NURSE_NOTES.APPOINTMENT_ID =1.
i use below script
SELECT INFUSION_APP_NURSE_NOTES.APPOINTMENT_ID,INFUSION_APP_NURSE_NOTES.ID
FROM INFUSION_APP_NURSE_NOTES
GROUP BY INFUSION_APP_NURSE_NOTES.APPOINTMENT_ID,INFUSION_APP_NURSE_NOTES.ID
HAVING COUNT(INFUSION_APP_NURSE_NOTES.APPOINTMENT_ID)>1
but it does not gives me any records.
scenario 2:
I am running below script with the intention to get the duplicate records with different INFUSION_APP_NURSE_NOTES.ID's but same INFUSION_APP_NURSE_NOTES.APPOINTMENT_ID.
SELECT INFUSION_APP_NURSE_NOTES.ID,INFUSION_APP_NURSE_NOTES.APPOINTMENT_ID,INFUSION_APP_NURSE_NOTES.TYPE
FROM INFUSION_APP_NURSE_NOTES
WHERE
EXISTS (
SELECT 1 FROM INFUSION_APP_APPOINTMENT
WHERE
INFUSION_APP_NURSE_NOTES.ENABLE=1
AND INFUSION_APP_NURSE_NOTES.APPOINTMENT_ID=INFUSION_APP_APPOINTMENT.ID
GROUP BY INFUSION_APP_NURSE_NOTES.ID
HAVING COUNT(INFUSION_APP_NURSE_NOTES.APPOINTMENT_ID)>1
)
ORDER BY INFUSION_APP_NURSE_NOTES.APPOINTMENT_ID;
but getting below error
SQL Error(164): Each GROUP BY expression must contain at least one
column that is not an outer reference
how to solve it?
i want the only row which has common APPOINTMENT_ID but different n
The question is unclear. Finding duplicates is typically performed using ranking functions like ROW_NUMBER(). This query :
SELECT *,ROW_NUMBER(PARTITION BY APPOINTMENT_ID ORDER BYID) as RN
FROM INFUSION_APP_NURSE_NOTES
WHERE
ENABLE=1
Will rank notes for the same appointment by ID and return 1, 2, 3 etc starting from the earliest note. ORDER BY ID DESC would return 1 for the latest note.
This can be used in a subquery or CTE to find the first, last or or duplicate records, eg :
with notes as (
SELECT *,ROW_NUMBER(PARTITION BY APPOINTMENT_ID ORDER BYID) as RN
FROM INFUSION_APP_NURSE_NOTES
WHERE
ENABLE=1
)
select *
from notes
where RN=1
Will return the first note per appointment while :
where RN>1
Will return only duplicates.
The question doesn't say what should be done with the duplicates though.
If the question is how to return all notes from appointments with multiple notes, a subquery can be used to return the APPOINTMENT_IDs that have more than one note. There's no need to include the INFUSION_APP_APPOINTMENT table though :
SELECT *
FROM INFUSION_APP_NURSE_NOTES
where
ENABLE=1 AND
APPOINTMENT_ID IN ( SELECT APPOINTMENT_ID
FROM INFUSION_APP_NURSE_NOTES
WHERE
ENABLE=1
group by APPOINTMENT_ID
having count(*)>1)
Try this
SELECT INFUSION_APP_NURSE_NOTES.ID,INFUSION_APP_NURSE_NOTES.APPOINTMENT_ID,INFUSION_APP_NURSE_NOTES.TYPE
FROM INFUSION_APP_NURSE_NOTES
WHERE
EXISTS (
SELECT COUNT(B.APPOINTMENT_ID), B.ID
FROM INFUSION_APP_APPOINTMENT A
INNER JOIN INFUSION_APP_NURSE_NOTES B ON B.APPOINTMENT_ID = A.ID
WHERE
B.ENABLE=1
GROUP BY B.ID
HAVING COUNT(B.APPOINTMENT_ID)>1
)
ORDER BY INFUSION_APP_NURSE_NOTES.APPOINTMENT_ID;
So I have a dataset, where I would like to order it based on strings ORDER BY FIELD(field_name, ...) after the order I wan't it to group the dataset based on another column.
I have tried with a subquery, but it seems like it ignores by ORDER BY when it gets subqueried.
This is the query I would like to group with GROUP BY setting_id
SELECT *
FROM `setting_values`
WHERE ((`owned_by_type` = 'App\\Models\\Utecca\\User' AND `owned_by_id` = 1 OR ((`owned_by_type` = 'App\\Models\\Utecca\\Agreement' AND `owned_by_id` = 1006))) OR (`owned_by_type` = 'App\\Models\\Utecca\\Employee' AND `owned_by_id` = 1)) AND `setting_values`.`deleted_at` IS NULL
ORDER BY FIELD(owned_by_type, 'App\\Models\\Utecca\\Employee', 'App\\Models\\Utecca\\Agreement', 'App\\Models\\Utecca\\User')
The order by works just fine, but I cannot get it to group it based on my order, it always selects the one with lowest primary key (id).
Here is my attempt which did not work.
SELECT * FROM (
SELECT *
FROM `setting_values`
WHERE ((`owned_by_type` = 'App\\Models\\Utecca\\User' AND `owned_by_id` = 1 OR ((`owned_by_type` = 'App\\Models\\Utecca\\Agreement' AND `owned_by_id` = 1006))) OR (`owned_by_type` = 'App\\Models\\Utecca\\Employee' AND `owned_by_id` = 1)) AND `setting_values`.`deleted_at` IS NULL
ORDER BY FIELD(owned_by_type, 'App\\Models\\Utecca\\Employee', 'App\\Models\\Utecca\\Agreement', 'App\\Models\\Utecca\\User')
) AS t
GROUP BY setting_id;
Here is some sample data
What I am trying to accomplish with this sample data is 1 row with the id 3 as the row.
The desired result set from the query should obey these rules
1 row for each setting_id
owned_by_type together with owned_by_id is filtered the following way agreement = 1006, user = 1, employee = 1.
When limiting the 1 row for each setting_idit should be done with the following priority in owned_by_type column Employee, Agreement, User
Here is a SQLFiddle with it.
Running MariaDB version 10.2.6-MariaDB
First of all, the Optimizer is free to ignore the inner ORDER BY. So, please describe further what your intent is.
Getting past that, you can use a subquery:
SELECT ...
FROM ( SELECT
...
GROUP BY ...
ORDER BY ... -- This is lost unless followed by :
LIMIT 9999999999 -- something valid; or very high (for all)
) AS x
GROUP BY ...
Perhaps you are doing groupwise max ??
I have a query which will return one row. Is there any way I can find the row index of the row I'm querying when the table is sorted?
I've tried rowid but got #582 when I was expecting row #7.
Eg:
CategoryID Name
I9GDS720K4 CatA
LPQTOR25XR CatB
EOQ215FT5_ CatC
K2OCS31WTM CatD
JV5FIYY4XC CatE
--> C_L7761O2U CatF <-- I want this row (#5)
OU3XC6T19K CatG
L9YKCYAYMG CatH
XKWMQ7HREG CatI
I've tried rowid with unexpected results:
SELECT rowid FROM Categories WHERE CategoryID = 'C_L7761O2U ORDER BY Name
EDIT: I've also tried J Cooper's suggestion (below), but the row numbers just aren't right.
using (var cmd = conn.CreateCommand()) {
cmd.CommandText = string.Format(#"SELECT (SELECT COUNT(*) FROM Recipes AS t2 WHERE t2.RecipeID <= t1.RecipeID) AS row_Num
FROM Recipes AS t1
WHERE RecipeID = 'FB3XSAXRWD'
ORDER BY Name";
cmd.Parameters.AddWithValue("#recipeId", id);
idx = Convert.ToInt32(cmd.ExecuteScalar());
Here is a way to get the row number in Sqlite:
SELECT CategoryID,
Name,
(SELECT COUNT(*)
FROM mytable AS t2
WHERE t2.Name <= t1.Name) AS row_Num
FROM mytable AS t1
ORDER BY Name, CategoryID;
Here's a funny trick you can use in Spatialite to get the order of values. If you use the count() function with a WHERE clause limiting to only values >= the current value, then the count will actually give the order. So if I have a point layer called "mypoints" with columns "value" and "val_order" then:
SELECT value, (
SELECT count(*) FROM mypoints AS my
WHERE my.value>=mypoints.value) AS val_order
FROM mypoints
ORDER BY value DESC;
Gives the descending order of the values.
I can update the "val_order" column this way:
UPDATE mypoints SET val_order = (
SELECT count(*) FROM mypoints AS my
WHERE my.value>=mypoints.value
);
What you are asking can be explained in two different ways, but I'm assuming you want to sort the resulting table and then number those rows according to the sort.
declare #resultrow int
select
#resultrow = row_number() OVER (ORDER BY Name Asc) as 'Row Number'
from Categories WHERE CategoryID = 'C_L776102U'
select #resultrow