Date between with only the days and month - sql

Question

I have this date :
Date1 = 14/10/2015
Date2 = 01/10/2011
Date3 = 01/11/2011
I'm trying to make this req :
Date1 between date2 and date3
How can i make this without paying attention to the years (only sql (oracle)).
The req should be true.
Thanks

Answer 1

In Oracle you can get first day of month for date1 and date2 and last day of month for date3 then use between, something like:
WHERE TRUNC(date1, 'MONTH') BETWEEN TRUNC(date2, 'MONTH') AND LAST_DAY(TO_DATE(date3,'MM/DD/YYYY'))

Answer 2

As an alternative you could just cast the numeric representation of MMDD to a number, and check if this number is in a specific range.
select *
from (select to_date('14/10/2015', 'DD/MM/YYYY') as datee from dual union
select to_date('01/10/2011', 'DD/MM/YYYY') as datee from dual union
select to_date('01/11/2011', 'DD/MM/YYYY') as datee from dual)
where to_number(to_char(datee,'MMDD')) between 1014 and 1131

Answer 3

In Oracle you can use the EXTRACT function to get individual parts of the date and use that to compare:
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE TEST( Date1 ) AS
SELECT DATE '2015-01-01' FROM DUAL
UNION ALL SELECT DATE '2015-01-15' FROM DUAL
UNION ALL SELECT DATE '2015-02-01' FROM DUAL
UNION ALL SELECT DATE '2015-09-01' FROM DUAL
UNION ALL SELECT DATE '2014-01-10' FROM DUAL
UNION ALL SELECT DATE '2014-01-20' FROM DUAL
UNION ALL SELECT DATE '2014-02-02' FROM DUAL
UNION ALL SELECT DATE '2013-01-14' FROM DUAL
Query 1:
WITH Dates ( Date2, Date3 ) AS (
SELECT DATE '2015-01-10', DATE '2015-02-01' FROM DUAL
)
SELECT t.*
FROM TEST t
CROSS JOIN Dates d
WHERE ( EXTRACT( MONTH FROM Date1 ) > EXTRACT( MONTH FROM Date2 )
OR ( EXTRACT( MONTH FROM Date1 ) = EXTRACT( MONTH FROM Date2 )
AND EXTRACT( DAY FROM Date1 ) >= EXTRACT( DAY FROM Date2 )
)
)
AND ( EXTRACT( MONTH FROM Date1 ) < EXTRACT( MONTH FROM Date3 )
OR ( EXTRACT( MONTH FROM Date1 ) = EXTRACT( MONTH FROM Date3 )
AND EXTRACT( DAY FROM Date1 ) <= EXTRACT( DAY FROM Date3 )
)
)
Results:
| DATE1 |
|----------------------------|
| January, 15 2015 00:00:00 |
| February, 01 2015 00:00:00 |
| January, 10 2014 00:00:00 |
| January, 20 2014 00:00:00 |
| January, 14 2013 00:00:00 |

Answer 4

Use the DDD format string to get the number of the day of the year, i.e.:
select to_char(to_date('14/10/2015','DD/MM/YYYY'),'DDD') d1
,to_char(to_date('01/10/2011','DD/MM/YYYY'),'DDD') d2
,to_char(to_date('01/11/2011','DD/MM/YYYY'),'DDD') d3
from dual;
D1 D2 D3
=== === ===
287 274 305
with params as (
select to_date('14/10/2015','DD/MM/YYYY') d1
,to_date('01/10/2011','DD/MM/YYYY') d2
,to_date('01/11/2011','DD/MM/YYYY') d3
from dual)
select 'Yes' a from params
where to_char(d1,'DDD') between to_char(d2,'DDD') and to_char(d3,'DDD');
A
===
Yes