Table
Director DirectorId Company CompanyID Recordtime
Philip 66 AVEVA GROUP 15 1
Philip 66 AVEVA GROUP 15 1
Philip 66 BALFOUR BEATTY 36 1
Philip 66 BHP BILLITON 40 2
Philip 66 BHP BILLITON 40 2
OutPut like this
Director DirectorId Company CompanyID Count
Philip 66 AVEVA GROUP 15 1
Philip 66 AVEVA GROUP 15 1
Philip 66 BALFOUR BEATTY 36 1
Philip 66 BHP BILLITON 40 0
Philip 66 BHP BILLITON 40 0
in this table recordtime 1 has two company and recordtime 2 has one
company .i need output of count 1 in recordtime 1 count 0 in recordtime 2 because
recordtime 1 the first company is default company after all is countable this is condition
You can try something like:
select t1.*, t2.cCount from Table1 t1 join
(select Recordtime, (count(CompanyId) - 1) as cCount from (select distinct CompanyID, Recordtime from Table1) t
group by Recordtime) t2 on t1.Recordtime = t2.Recordtime
Take a look at this sample fiddle
This should work for your case:
SELECT v.director,
v.directorId,
v.company,
v.companyId,
CASE WHEN v.cnt > 1 THEN v.cnt - 1
ELSE 0 END AS cnt
FROM (SELECT t.director,
t.directorId,
t.company,
t.companyId,
COUNT(DISTINCT t.company) as cnt
FROM yourtable t
GROUP BY t.director,
t.directorId,
t.company,
t.companyId) v
Related
I would like to allocate rows from one table to another using a sort on TopLvlOrd field. The inputs are the [Orders] table and the [Defects] table. I would like to create an SQL that produces [Output]. Even after a bunch of online research I'm not sure how to do this. I'd prefer not to do a cursor, but will go there if necessary. Any ideas? Using SQL Server 2012.
Rules:
(1) Allocate by TopLvlOrd asc,
(2) Allocate one TopLvlOrd row per PegQty
[Orders]
TopLvlOrd IntOrd PegQty
========= ====== ======
67 25 3
120 25 1
111 25 1
16 25 1
127 25 1
127 65 1
127 85 1
[Defects]
DefectID IntOrd TotQty
======== ====== ======
1 25 10
2 25 10
3 25 10
4 25 10
5 25 10
6 25 10
7 25 10
8 25 10
9 25 10
10 25 10
11 65 1
12 85 2
13 85 2
[Output]
DefectID IntOrd TotQty TopLvlOrd
======== ====== ====== =========
1 25 10 16
2 25 10 67
3 25 10 67
4 25 10 67
5 25 10 111
6 25 10 120
7 25 10 127
8 25 10 NULL
9 25 10 NULL
10 25 10 NULL
11 65 1 127
12 85 2 127
13 85 2 NULL
This answers the original version of the question.
I think you want to join on an implicit sequence number, which you can add using row_number():
select d.*, o.*
from (select d.*,
row_number() over (partition by intord order by defectid) as seqnum
from defects d
) d left join
(select o.*,
row_number() over (partition by IntOrd order by TopLvlOrd) as seqnum
from orders o
) o
on d.intord = o.intord and d.seqnum = o.seqnum
Please another time make another question. Please check this query:
SELECT DefectID, IntOrd,
TotQty, TopLvlOrd, PegQty
FROM
(
SELECT B. DefectID, COALESCE (A.IntOrd, B. IntOrd) IntOrd,
B.TotQty, A. TopLvlOrd, A.PegQty FROM
(
SELECT TopLvlOrd ,IntOrd, ROW_NUMBER () OVER (PARTITION By IntOrd ORDER by
TopLvlOrd) Num, PegQty FROM Orders
) A
FULL JOIN
(
SELECT DefectID , IntOrd ,TotQty, ROW_NUMBER () OVER (PARTITION By IntOrd ORDER by
TotQty) Num FROM Orders
) B
ON A. IntOrd=B.IntOrd AND A.Num=B.Num
)C
JOIN
master.dbo.spt_values Tab
ON Tab.type='P' AND Tab.number<C.PegQty
SELECT B. DefectID, COALESCE (A.IntOrd, B. IntOrd) IntOrd,
B.TotQty, A. TopLvlOrd FROM
(
SELECT TopLvlOrd ,IntOrd , ROW_NUMBER () OVER (PARTITION By IntOrd ORDER by TopLvlOrd) Num FROM Orders
) A
FULL JOIN
(
SELECT DefectID , IntOrd ,TotQty, ROW_NUMBER () OVER (PARTITION By IntOrd ORDER by TotQty) Num FROM Orders
) B
ON A. IntOrd=B.IntOrd AND A. Num=B.Num
I am attempting to remove transactions that have been reversed from a table. the table has Account, Date, Amount and Row. If a transaction has been reversed Account will match and Amount will be inverse of each other.
Example Table
Account Date Amount Row
12 1/1/18 45 72 -- Case 1
12 1/2/18 50 73
12 1/2/18 -50 74
12 1/3/18 52 75
15 1/1/18 51 76 -- Case 2
15 1/2/18 51 77
15 1/2/18 -51 78
15 1/2/18 51 79
18 1/2/18 50 80 -- Case 3
18 1/2/18 50 81
18 1/2/18 -50 82
18 1/2/18 -50 83
18 1/3/18 50 84
18 1/3/18 50 85
20 1/1/18 57 88 -- Case 4
20 1/2/18 57 89
20 1/4/18 -57 90
20 1/5/18 57 91
Desired Results Table
Account Date Amount Row
12 1/1/18 45 72 -- Case 1
12 1/3/18 52 75
15 1/1/18 51 76 -- Case 2
15 1/2/18 51 79
18 1/3/18 50 84 -- Case 3
18 1/3/18 50 85
20 1/1/18 57 88 -- Case 4
20 1/5/18 57 91
Removing all instances of inverse transactions does not work when there are multiple transactions when all other columns are the same. My attempt was to count all duplicate transactions, count of all inverse duplicate transactions, subtracting those to get the number of rows I needed from each transactions group. I was going to pull the first X rows but found in most cases I want the last X rows of each group, or even a mix (the first and last in Case 2).
I either need a method of removing pairs from the original table, or working from what I have so far, a method of distinguishing which transactions to pull.
Code so far:
--adding row Numbers
with a as (
select
account a,
date d,
amount f,
row_number() over(order by account, date) r
from table),
--counting Duplicates
b as (
select a.a, a.f, Dups
from a join (
select a, f, count(*) Dups
from a
group by a.a, a.f
having count(*)>1
) b
on a.a=b.a and
b.f=a.f
where a.f>0
),
--counting inverse duplicates
c as (
select a.a, a.f, InvDups
from a join (
select a, f, count(*) InvDups
from a
group by a.a, a.f
having count(*)>1
) b
on a.a=b.a and
-b.f=a.f
where a.f>0
),
--combining c and d to get desired number of rows of each transaction group
d as (
select
b.a, b.f, dups, InvDups, Dups-InvDups TotalDups
from b join c
on b.a=c.a and
b.f=c.f
),
--getting the number of rows from the beginning of each transaction group
select d.a, d.d, d.f
from
(select
a, d, f, row_number() over (group by a, d, f) r2
from a) e
join d
on e.a=d.a and
TotalDups<=r2
You can try this.
SELECT T_P.* FROM
( SELECT *, ROW_NUMBER() OVER(PARTITION BY Account, Amount ORDER BY [Row] ) RN from #MyTable WHere Amount > 0 ) T_P
LEFT JOIN
( SELECT *, ROW_NUMBER() OVER(PARTITION BY Account, Amount ORDER BY [Row] ) RN from #MyTable WHere Amount < 0 ) T_N
ON T_P.Account = T_N.Account
AND T_P.Amount = ABS(T_N.Amount)
AND T_P.RN = T_N.RN
WHERE
T_N.Account IS NULL
The following handles your three cases:
with t as (
select t.*,
row_number() over (partition by account, date, amount order by row) as seqnum
from table t
)
select t.*
from t
where not exists (select 1
from t t2
where t2.account = t.account and t2.date = t.date and
t2.amount = -t.amount and t2.seqnum = t.seqnum
);
Use This
;WITH CTE
AS
(
SELECT
[Row]
FROM YourTable YT
WHERE Amount > 0
AND EXISTS
(
SELECT 1 FROM YourTable WHERE Account = YT.Account
AND [Date] = YT.[Date]
AND (Amount+YT.Amount)=0
)
UNION ALL
SELECT
[Row]
FROM YourTable YT
WHERE Amount < 0
AND EXISTS
(
SELECT 1 FROM YourTable WHERE Account = YT.Account
AND [Date] = YT.[Date]
AND (Amount+YT.Amount)>0
)
)
SELECT * FROM YourTable
WHERE EXISTS
(
SELECT 1 FROM CTE WHERE [Row] = YourTable.[Row]
)
I have a data set that looks like:
cust city hotel_id amount
-------------------------------
A 1 252 3160
B 1 256 1893
C 2 105 2188
D 2 105 3054
E 3 370 6107
F 2 110 3160
G 2 150 1893
H 3 310 2188
I 1 252 3160
J 1 250 4000
K 3 370 5000
L 3 311 1095
Query to display the top 3 hotels by revenue (Sum of amount) for each city?
Since same hotel can be booked by other customer in same city so we need to sum the amount to find total amount.
Expected output:
city hotel_id amount
---------------------------
1 252 6320
1 250 4000
1 256 1893
2 105 5242
2 110 3160
2 150 1893
3 370 11107
3 310 2188
3 311 1095
SELECT
t.city, t.hotel_id, t.amount
FROM
(
SELECT city, hotel_id, SUM(amount) AS amount,
ROW_NUMBER() OVER (PARTITION BY city ORDER BY SUM(amount) DESC) AS rn
FROM yourTable
GROUP BY city, hotel_id
) t
WHERE t.rn <= 3
ORDER BY t.city, t.amount DESC;
Demo here:
Rextester
To get the total sum for each hotel_id you need to group by that column first, then group by the city for syntax purposes. The #tmp table here should have all of the data you need, so then you just have to select the top 3 entries for each city from there.
SELECT city, hotel_id, SUM(amount) AS 'total' INTO #tmp
FROM [table]
GROUP BY hotel_id, city
(SELECT TOP 3 *
FROM #tmp
WHERE city = 1)
UNION
(SELECT TOP 3 *
FROM #tmp
WHERE city = 2)
UNION
(SELECT TOP 3 *
FROM #tmp
WHERE city = 3)
This is the structure of my data
Name TransID Amount
Joe 123 56
Joe 124 55
Joe 125 58
Tom 126 31
Tom 127 48
I have a requirement to report from this data in the below format
Name Amount1 Amount2
Joe 56 55
Joe 58
Tom 31 48
Joe has three Amounts in the original data set but I need a fixed number of columns (two) in the view. Therefore, the third Amount for Joe is inserted as a new record in the view. Is it possible to achieve this as a stored procedure or creating a view.
Break the problems into smaller steps. These are the steps that I would take:
Use ROW_NUMBER() OVER (PARTITION BY ...):
Name TransID Amount Row_Number
Joe 123 56 1
Joe 124 55 2
Joe 125 58 3
Tom 126 31 1
Tom 127 48 2
Subtract 1.
Name TransID Amount RowNumberStartingWith0
Joe 123 56 0
Joe 124 55 1
Joe 125 58 2
Tom 126 31 0
Tom 127 48 1
Divide it by 2, get the result of the division and the remainder modulo 2:
Name TransID Amount Result Remainder
Joe 123 56 0 0
Joe 124 55 0 1
Joe 125 58 1 0
Tom 126 31 0 0
Tom 127 48 0 1
Drop the TransID column. The remainder is always 0 or 1, so you can pivot on it:
Name Result AmountForRemainder0 AmountForRemainder1
Joe 0 56 55
Joe 1 58
Tom 0 31 48
Now you drop the Result column and rename your columns:
Name Amount1 Amount2
Joe 56 55
Joe 58
Tom 31 48
Profit.
TRY this and let me know .Check with other sample data also.I am getting the desire output.
DECLARE #t TABLE (
NAME VARCHAR(50)
,TransID INT
,Amount INT
)
INSERT INTO #t
VALUES ('Joe',123,56)
,('Joe',124,55)
,('Joe',125,58)
,('Tom',126,31)
,('Tom',127,48)
,('Tom',128,89)
,('Tom',129,90)
,('Joe',130,68);
WITH CTE
AS (
SELECT *
,row_number() OVER (
PARTITION BY NAME ORDER BY amount
) rn
FROM #t
)
,CTE1
AS (
SELECT NAME
,(
SELECT amount
FROM cte
WHERE rn = 1
AND NAME = a.NAME
) [Amount1]
,(
SELECT amount
FROM cte
WHERE rn = 2
AND NAME = a.NAME
) [Amount2]
,rn
FROM cte A
WHERE rn = 1
UNION ALL
SELECT b.NAME
,a.amount
,isnull(c.amount, 0)
,a.rn
FROM CTE1 B
INNER JOIN CTE A ON a.NAME = b.NAME
AND a.rn % 2 <> 0
AND a.rn > 1
AND b.rn <> a.rn
OUTER APPLY (
SELECT Amount
FROM CTE C
WHERE NAME = b.NAME
AND rn % 2 = 0
AND rn > 2
) c
)
SELECT *
FROM cte1
I had a table with almost 20000 records
with columns
Id SubjectId UniqueId
1 54 1
1 58 2
1 59 3
1 60 4
2 54 5
2 58 6
2 59 7
2 60 8
2 60 9
3 54 10
3 70 11
I want to Select those Records Which Are repeating
like
result is Like
Id SubjectId UniqueId
2 60 8
2 60 9
7 54 15
7 54 18
7 54 30
Help Me how could I do this
use EXISTS()
SELECT a.*
FROM tableName a
WHERE EXISTS
(
SELECT 1
FROM tableName b
WHERE a.ID = b.ID AND
a.SubjectID = b.subjectID
GROUP BY Id, SubjectId
HAVING COUNT(*) > 1
)
SQLFiddle Demo
You can utilize analytic COUNT() since you're using SQL Server 2008
SELECT id, subjectid, uniqueid
FROM
(
SELECT id, subjectid, uniqueid,
COUNT(*) OVER (PARTITION BY id, subjectid) cnt
FROM table1
) q
WHERE cnt > 1
or another way
SELECT t.*
FROM
(
SELECT id, subjectid
FROM table1
GROUP BY id, SubjectId
HAVING COUNT(*) > 1
) q JOIN table1 t
ON q.id = t.id
AND q.subjectid = t.subjectid
Output for both queries:
| ID | SUBJECTID | UNIQUEID |
|----|-----------|----------|
| 2 | 60 | 8 |
| 2 | 60 | 9 |
| 7 | 54 | 15 |
| 7 | 54 | 18 |
| 7 | 54 | 30 |
Here is SQLFiddle demo
Try this
fetch only duplicate record
SELECT * FROM TABLE_NAME as t1 where SubjectId in (SELECT SubjectId FROM TABLE_NAME as t2 where t2.Id=t1.Id and t1.UniqueId<>t2.UniqueId) order by Id,SubjectId
Count your IDs , if greater then 1 then then select it
SELECT *
FROM table
HAVING COUNT(id) > 1