In the script I need a counter to give the same day (in different years) a number, and when a new year begin it will start from 1 again. So when I reload my script I want a table that look like this:
Date Number
01/01/2015 1
...... ...
10/30/2015 303
10/31/2015 304
11/01/2015 305
.... ...
12/31/2015 365
01/01/2016 1
01/02/2016 2
.... ....
How can I do this?
DayNumberOfYear(date[,firstmonth])
Returns the day number of the year according to a timestamp with the first millisecond of the first day of the year containing date. The function always uses years based on 366 days.
By specifying a firstmonth between 1 and 12 (1 if omitted), the beginning of the year may be moved forward to the first day of any month. If you e.g. want to work with a fiscal year starting March 1, specify firstmonth = 3.
You could try subtracting the Date from the beginning of the year of the Date
Date-makedate(year(Date),1,1)+1 as Number
You'll need a bit more maths if leap years are going to matter in you analysis.
Related
I am using Hive .14 to analyze the following input data in timestamp format (# is irrelevant to the explanation):
#
Datetime
1
2022-03-01 00:13:08
2
2022-03-31 23:52:24
3
2022-02-28 23:32:40
and I want to get what day of the week in which each data took place (either by a number representing the day from 0 to 6, or the day itself) in, similar to the next format:
#
Day of the week
1
Tuesday or 2
2
Thursday or 4
3
Monday or 1
I have tried to use the unixtime command to transform the timestamp into an integer
like this:
select cast(from_unixtime(unix_timestamp(datetime,'yyyy-MM-dd'),'yyyyMMdd') as int) as dayint from yellowtaxi;
To later use the from_unixtime(dayint,u) query to get the day of the week in which it happened, however, this results in all the days from all the rows being equal to 20220301 and to all the days being equal to 7 when using from_unixtime(dayint,u).
What am I doing wrong, or is there an easier way to do it?
I have already tried the day_format() and the dayofweek() queries, but none of them seem to be available in my hive version.
I have sample data like this
EmployeeID Begin Date End Date Duration
168835 28/11/2017 28/11/2017 6
168835 31/10/2017 9/11/2017 32
and I want to find the leave taken by this employee month wise,so i have joined with calendar date and i want to summarise this data monthly.For e.g, he has taken leave from 31/10/2017 to 9/11/2017 for 32 hours and 6 hours in 28/11/2017. I want to exclude weekend from 31/10/2017 to 9/11/2017 period. I have used "day of week" flag to exclude the weekends, but now problem is when i roll up the data its giving me incorrect result. basically, i want to data like duration (32+6)=38 and this should be divided no of working days that is 9 in this case, so in oct month my data should be 4.22 and in nov month it should 33.77. can anyone please help me on this.Thanks in advance.
I have a date in sql which will always fall on a Monday and I'm subtracting 13 weeks to get a weekly report. I am trying to get the same 13 week report but for last year's figures as well.
At the moment, I'm using the following:
calendar_date >= TRUNC(sysdate) - 91
which is working fine.
I need the same for last year.
However, when I split this into calendar weeks, there will also be a partially complete week as it will include 1 or 2 days from the previous week. I need only whole weeks.
e.g. the dates that will be returned for last year will be 14-Feb-2015 to 16-May-2015. I need it to start on the Monday and be 16-Feb-2015. This will change each week as I am only interested in complete weeks...
I would do this:
Get the date by substracting 91 days as you're already doing.
Get the number of the day of the week with TO_CHAR(DATE,'d')
Add the number of days until the next monday to the date.
Something like this:
SELECT TO_DATE(TO_DATE('16/05/2015','DD/MM/YYYY'),'DD/MM/YYYY')-91 + MOD(7 - TO_NUMBER(TO_CHAR(TO_DATE(TO_DATE('16/05/2015','DD/MM/YYYY'),'DD/MM/RRRR')-91,'d'))+1,7) d
FROM dual
next_day - returns date of first weekday named by char.
with dates as (select to_date('16/05/2015','DD/MM/YYYY') d from dual)
select
trunc(next_day( trunc(d-91) - interval '1' second,'MONDAY'))
from dates;
I want to get next monday from calculated date. In situation when calculated date is monday i have to move back to previous week ( -1 second).
I've periods of time every 15 days, MOM and EOM.
What I need to check is if a date value on a date field is prior to the current period minus 1.
For example, if today is 12/29, the period is 12/31, and i need to check
if prior < 12/15
How can i get the EOM (End Of Month, i mean, the last day of the month) and the MOM (Middle of month, it's like every 15th of month) with GETDATE() function without doing a DATEADD with -15 days (because in feb will be fail, and i don't care the month)
Any help or work around will be preciated.
Thanks
If you need the value 15 then put it in your code.
If that is against your company's policies then challenge the person that made that policy. Writing 5 lines of code to replace two characters is not a good coding...
If writing the 5 lines made your application much more flexible then maybe I could understand, but you are still "hard coding" 15 into your comparisons.
Thinking in a work around, what I did it was this:
If actual day < 15 then get the month actual, convert to the first day of the month (01) and minus 1 day. I get the last day of the prior month. (EOM - 1 period)
If actual day > 15, then the prior period (MOM - 1 period) is: 15 of actual month.
It's a query with if structure.
If someone has a better answer, please answer it and I'll be accept it.
Thanks :)
Greetings SQL gurus,
I don't know if you can help me, but I will try. I have several large databases grouped by year (each year in a different database). I want to be able to compare values from a particular week from one year to the next. For example, "show me week 17 of 2008 vs. week 17 of 2002."
I have the following definition of weeks that ideally I would use:
Only 52 weeks each year and 7 days a week (that only takes 364 days),
The first day of the first week starts from January 2nd - which means we do not use January 1st data, and
In leap year, the first day of the first week ALSO starts from the January 2nd plus we skip Feb. 29.
Any ideas?
Thanks in advance.
Best to avoid creating a table because then you have to update and maintain it to get your queries to work.
DatePart('ww',[myDate]) will give you the week number. You may run into some issues though deciding which week belongs to which year - for example if Jan 1 2003 is on Wednesday does the week belong as week 52 in 2002 or week 1 in 2003? Your accounting department will have a day of the week that is your end of week (usually Sat). I usually just pick the year that has the most days in it. DatePart will always count the first week as 1 and in the case of the example above the last week as 53. You may not care that much either way. You can create queries for each year
SELECT DatePart('ww',[myDate]) as WeekNumber,myYearTable.* as WeekNumber
FROM myYearTable
and then join the queries to get your data. You'll loose a couple days at the end of the year if one table has 52 weeks and one has 53 (most will show as 53). Or you can do it by your weekending day - this always gives you Saturday which would push a late week into the following year.
(7-Weekday([myDate]))+[myDate]
then
DatePart('ww',(7-Weekday([myDate]))+[myDate])
Hope that helps
To get the week number
'to get the week number in the year
select datepart( week, datefield)
'to get the week number in the month
select (datepart(dd,datefield) -1 ) / 7 + 1
You don't need to complicate things thinking about leap years, etc. Just compare weeks mon to sun
SInce you havea a specifc defintion of when the week starts that is differnt that the standard used by the db, I think a weeks table is the solution to your problem. For each year create a table that defines the dates contained in each week and the week number. Then by joining to that table as well as the relevant other tables, you can ask for just the data for week 17.
Table structure
Date Week
20090102 1
20090103 1
etc.
I needed to create a query that shows BOTH year AND week numbers, like 2014-52. The year shows correct when you use the Datepart() formula to convert week 53 to week 52 in the previous year, but shows the wrong year for the week that was week 1 previously that should be week 52 now. It show that week as 2015-52 instead of 2014-52.
Furthermore, it sorts the data wrong if you only use only the week number, eg:
2014-1,2014-11,2014-2
To overcome this I created the following query to insert a 0 and also to check for days in week 1 that should still fall under week 52.
ActualWeek: IIf(DatePart("ww",[SomeDate],1,3)=52 And DatePart("ww",[SomeDate])=1, DatePart("yyyy",[SomeDate],1,3)-1,DatePart("yyyy",[SomeDate],1,3)) & "-" & IIf(DatePart("ww",[SomeDate],1,3)<10,"0" & DatePart("ww",[SomeDate],1,3),DatePart("ww",[SomeDate],1,3))