NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSCalendarIdentifierISO8601];
[calendar setTimeZone:[NSTimeZone defaultTimeZone]];
[calendar setFirstWeekday:2];
[calendar setMinimumDaysInFirstWeek:1];
NSDateComponents *mockTodayComponents = [[NSDateComponents alloc] init];
mockTodayComponents.day = 28;
mockTodayComponents.month = 12;
mockTodayComponents.year = 2015;
NSDate *date = [calendar dateFromComponents:mockTodayComponents];
NSDateComponents *c = [calendar components:NSCalendarUnitWeekOfYear | NSCalendarUnitYearForWeekOfYear fromDate:date];
NSInteger week = [c weekOfYear];
week returns 1 instead of 53 and ofcoaurse the next year weeks enumeration wrong also because of it, what's wrong with my code or it's Apple's bug?
Your minimumDaysInFirstWeek is 1. That means that any week that has at least 1 day in the new year is the 1st week of that year. Docs
According to ISO:
There are mutually equivalent descriptions of week 01:
the week with the year's first Thursday in it (the formal ISO
definition), the week with 4 January in it, the first week with the
majority (four or more) of its days in the starting year, and the week
starting with the Monday in the period 29 December – 4 January.
I am trying to get an NSDate from a day and week post to today.
E.g. week = 2 and day = 4, which would be thursday in two weeks from now (given the week starts on Monday).
I tried a bunch of different things using NSCalendar and NSDateComponents, but nothing came close.
Searched a bit as well, but haven't found any other topic regarding my problem.
The last thing I tried was the following:
- (NSDate *)getDateForIndexPath:(NSIndexPath *)indexPath
{
int week = ((indexPath.row / 7) % 5);
int day = (indexPath.row % 7);
NSDate *referenceDate = [NSDate date];
NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
[calendar setLocale:[[NSLocale alloc] initWithLocaleIdentifier:#"es_ES"]];
[calendar setTimeZone:[NSTimeZone localTimeZone]];
NSDateComponents *dateComponents = [calendar components:(NSYearCalendarUnit|NSMonthCalendarUnit | NSWeekCalendarUnit |NSWeekdayCalendarUnit) fromDate:referenceDate];
[dateComponents setWeekday:day];
[dateComponents setWeek:dateComponents.week+(week-1)];
[dateComponents setWeek:dateComponents.week];
NSDate *followingDate = [calendar dateFromComponents:dateComponents];
NSLog(#"Week: %d - Day: %d", week, day);
NSLog(#"followingDate: %#", followingDate);
return followingDate;
}
This gave me the same date over and over again, besides the fact that it sees day 0 as sunday:
2014-04-08 00:02:33.706 TVSports[79878:60b] Week: 1 - Day: 0
2014-04-08 00:02:33.707 TVSports[79878:60b] followingDate: 2014-04-11 22:00:00 +0000
2014-04-08 00:02:33.708 TVSports[79878:60b] Week: 1 - Day: 1
2014-04-08 00:02:33.708 TVSports[79878:60b] followingDate: 2014-04-05 22:00:00 +0000
2014-04-08 00:02:33.709 TVSports[79878:60b] Week: 1 - Day: 2
2014-04-08 00:02:33.709 TVSports[79878:60b] followingDate: 2014-04-06 22:00:00 +0000
2014-04-08 00:02:33.710 TVSports[79878:60b] Week: 1 - Day: 3
2014-04-08 00:02:33.710 TVSports[79878:60b] followingDate: 2014-04-07 22:00:00 +0000
This:
NSDate *referenceDate = [NSDate date];
...
NSDateComponents *dateComponents = [calendar components:(NSYearCalendarUnit|NSMonthCalendarUnit | NSWeekCalendarUnit |NSWeekdayCalendarUnit) fromDate:referenceDate];
Returns a date components populated correctly for today because you've asked for today's date, then asked the calendar to break that down as year, month, week and weekday.
Following that, this:
[dateComponents setWeekday:day];
[dateComponents setWeek:dateComponents.week+(week-1)];
[dateComponents setWeek:dateComponents.week];
Sets the day. Then it reads the current set week and adds week-1 to it (so week 1 will be this week, week 2 will be next week, etc). It then redundantly reads the week again and sets it again.
Your output shows that the code works correctly. Apple is an American company so weekday 0 is always Sunday to them. But they're aware that Sunday isn't the first day of the week in most places so your code asks for "Sunday (day 0), this week" — not "Sunday this week if we pretend that the week started on Sunday". It says Sunday is the 11th. Allowing for timezone differences, that's correct.
Notice that NSDates do not have a time zone. An NSDate is an opaque record of a particular moment in time. How you would communicate that moment is immaterial. They log in GMT for the sake of being able to say something.
You then ask for Monday, Tuesday and Wednesday and it returns the 5th, 6th and 7th. All correct.
Side note: just use:
NSCalendar *calendar = [NSCalendar currentCalendar];
To use the current system calendar.
You can do this to get the Thursday in two weeks:
typedef NS_ENUM(NSUInteger, WeekDay){
WeekDaySunday = 1,
WeekDayModay,
WeekDayTuesday,
WeekDayWensday,
WeekDayThursday,
WeekDayFriday,
WeekDaySaturday
};
NSDate *now = [NSDate date];
NSDate *beginOfThisWeek;
NSCalendar *cal = [NSCalendar currentCalendar];
[cal setFirstWeekday:WeekDayModay];
[cal rangeOfUnit:NSWeekCalendarUnit // get the beginning of this week
startDate:&beginOfThisWeek // save the beginning to this variable
interval:NULL // we do not care for the weeks length
forDate:now];
NSDateComponents *twoWeeks = [[NSDateComponents alloc] init];
twoWeeks.week = 2;
twoWeeks.day = WeekDayThursday - WeekDaySunday -1 ; // we need the difference between thursday and the beginning of the week
NSDate *thurdayInTwoWeeks = [cal dateByAddingComponents:twoWeeks
toDate:beginOfThisWeek
options:0];
Does anyone know if there is a way to set the first day of the week on a NSCalendar, or is there a calendar that already has Monday as the first day of the week, instead of Sunday.
I'm currently working on an app that is based around a week's worth of work, and it needs to start on Monday, not Sunday. I can most likely do some work to work around this, but there will be a lot of corner cases. I'd prefer the platform do it for me.
Thanks in advance
Here's some the code that I'm using. it's saturday now, so what I would hope is that weekday would be 6, instead of 7. that would mean that Sunday would be 7 instead of rolling over to 0
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
[gregorian setFirstWeekday:0];
unsigned unitFlags = NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit | NSWeekCalendarUnit | NSWeekdayCalendarUnit;
NSDateComponents *todaysDate = [gregorian components:unitFlags fromDate:[NSDate date]];
int dayOfWeek = todaysDate.weekday;
Edit: This does not check the edge case where the beginning of the week starts in the prior month. Some updated code to cover this: https://stackoverflow.com/a/14688780/308315
In case anyone is still paying attention to this, you need to use
ordinalityOfUnit:inUnit:forDate:
and set firstWeekday to 2. (1 == Sunday and 7 == Saturday)
Here's the code:
NSCalendar *gregorian = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease];
[gregorian setFirstWeekday:2]; // Sunday == 1, Saturday == 7
NSUInteger adjustedWeekdayOrdinal = [gregorian ordinalityOfUnit:NSWeekdayCalendarUnit inUnit:NSWeekCalendarUnit forDate:[NSDate date]];
NSLog(#"Adjusted weekday ordinal: %d", adjustedWeekdayOrdinal);
Remember, the ordinals for weekdays start at 1 for the first day of the week, not zero.
Documentation link.
This code constructs a date that is set to Monday of the current week:
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDate *today = [NSDate date];
NSDate *beginningOfWeek = nil;
BOOL ok = [gregorian rangeOfUnit:NSWeekCalendarUnit startDate:&beginningOfWeek
interval:NULL forDate: today];
setFirstWeekday: on the NSCalendar object.
Sets the index of the first weekday for the receiver.
- (void)setFirstWeekday:(NSUInteger)weekday
Should do the trick.
In my opinion this settings should be dynamic according to the user locale.
Therefore one should use:
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
[gregorian setLocale:[NSLocale currentLocale]];
This will cause the calendar to set the first week day according to the user locale automatically. Unless you are developing your app for a specific purpose/user locale (or prefer to allow the user to choose this day).
I've done it like this.
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDate *today = [NSDate date];
NSDateComponents *compForWeekday = [gregorian components:(NSWeekdayCalendarUnit) fromDate:today];
NSInteger weekDayAsNumber = [compForWeekday weekday]; // The week day as number but with sunday starting as 1
weekDayAsNumber = ((weekDayAsNumber + 5) % 7) + 1; // Transforming so that monday = 1 and sunday = 7
I had trouble with a lot of the answers here. . maybe it was just me. .
Here's an answer that works for me:
- (NSDate*)firstDayOfWeek
{
NSCalendar* cal = [[NSCalendar currentCalendar] copy];
[cal setFirstWeekday:2]; //Override locale to make week start on Monday
NSDate* startOfTheWeek;
NSTimeInterval interval;
[cal rangeOfUnit:NSWeekCalendarUnit startDate:&startOfTheWeek interval:&interval forDate:self];
return startOfTheWeek;
}
- (NSDate*)lastDayOfWeek
{
NSCalendar* cal = [[NSCalendar currentCalendar] copy];
[cal setFirstWeekday:2]; //Override locale to make week start on Monday
NSDate* startOfTheWeek;
NSTimeInterval interval;
[cal rangeOfUnit:NSWeekCalendarUnit startDate:&startOfTheWeek interval:&interval forDate:self];
return [startOfTheWeek dateByAddingTimeInterval:interval - 1];
}
Update:
As pointed out (elsewhere) by #vikingosegundo, in general its best to let the local determine which day is the start of the week, however in this case the OP was asking for the start of the week to occur on Monday, hence we copy the system calendar, and override the firstWeekDay.
The problem with Kris' answer is the edge case where the beginning of the week starts in the prior month. Here's some easier code and it also checks the edge case:
// Finds the date for the first day of the week
- (NSDate *)getFirstDayOfTheWeekFromDate:(NSDate *)givenDate
{
NSCalendar *calendar = [NSCalendar currentCalendar];
// Edge case where beginning of week starts in the prior month
NSDateComponents *edgeCase = [[NSDateComponents alloc] init];
[edgeCase setMonth:2];
[edgeCase setDay:1];
[edgeCase setYear:2013];
NSDate *edgeCaseDate = [calendar dateFromComponents:edgeCase];
NSDateComponents *components = [calendar components:NSYearCalendarUnit|NSMonthCalendarUnit|NSWeekCalendarUnit|NSWeekdayCalendarUnit fromDate:edgeCaseDate];
[components setWeekday:1]; // 1 == Sunday, 7 == Saturday
[components setWeek:[components week]];
NSLog(#"Edge case date is %# and beginning of that week is %#", edgeCaseDate , [calendar dateFromComponents:components]);
// Find Sunday for the given date
components = [calendar components:NSYearCalendarUnit|NSMonthCalendarUnit|NSWeekCalendarUnit|NSWeekdayCalendarUnit fromDate:givenDate];
[components setWeekday:1]; // 1 == Sunday, 7 == Saturday
[components setWeek:[components week]];
NSLog(#"Original date is %# and beginning of week is %#", givenDate , [calendar dateFromComponents:components]);
return [calendar dateFromComponents:components];
}
I see misunderstanding in the other messages. The first weekday, whichever it is, has number 1 not 0. By default Sunday=1 as in the "Introduction to Date and Time Programming Guide for Cocoa: Calendrical Calculations":
"The weekday value for Sunday in the Gregorian calendar is 1"
For the Monday as a first workday the only remedy I have is brute force condition to fix the calculation
NSCalendar *cal=[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *comps = [cal components:NSWeekdayCalendarUnit fromDate:[NSDate date]];
// set to 7 if it's Sunday otherwise decrease weekday number
NSInteger weekday=[comps weekday]==1?7:[comps weekday]-1;
Below also covers the edge case,
- (NSDate *)getFirstDayOfTheWeekFromDate:(NSDate *)givenDate
{
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *components = [calendar components:NSYearCalendarUnit|NSMonthCalendarUnit|NSWeekCalendarUnit|NSWeekdayCalendarUnit fromDate:givenDate];
[components setWeekday:2]; // 1 == Sunday, 7 == Saturday
if([[calendar dateFromComponents:components] compare: curDate] == NSOrderedDescending) // if start is later in time than end
{
[components setWeek:[components week]-1];
}
return [calendar dateFromComponents:components];
}
You can just change .firstWeekday of the calendar.
NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSCalendarIdentifierGregorian];
calendar.firstWeekday = 2;
Then use rangeOfUnit:startDate:interval:forDate: to get the first day
NSDate *startOfWeek;
[calendar rangeOfUnit:NSCalendarUnitWeekOfYear startDate:&startOfWeek interval:nil forDate:[NSdate date]];
Try this:
NSCalendar *yourCal = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar]
[yourCal setFirstWeekday:0];
Iv found out the way to display any weekday name using nscalender..using the following code..
Just open your console from xcode menu bar to see the results.Copy Paste the following code in your viewDidLoad method to get the first day of the week
NSDate *today = [NSDate date];
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"MM/dd/yyyy :EEEE"];
NSString *dateString = [dateFormat stringFromDate:today];
NSLog(#"date: %#", dateString);
[dateFormat release];
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *components = [gregorian components:NSWeekdayCalendarUnit | NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit fromDate:today];
[components setDay:([components day]-([components weekday]-1))];
NSDate *beginningOfWeek = [gregorian dateFromComponents:components];
NSDateFormatter *dateFormat_first = [[NSDateFormatter alloc] init];
[dateFormat_first setDateFormat:#"MM/dd/yyyy :EEEE"];
NSString *dateString_first = [dateFormat_first stringFromDate:beginningOfWeek];
NSLog(#"First_date: %#", dateString_first);
The Output will be:
date: 02/11/2010 :Thursday
First_date: 02/07/2010 :Sunday
since i had run this program on 2/11/2010 u will get the desired output depending on the current date.
Similarly if u want to get the first working day of the week i.e Monday's date then just modify the code a bit:
CHANGE :[components setDay:([components day]-([components weekday]-1))];
TO
[components setDay:([components day]-([components weekday]-2))];
to get Mondays date for that week..
Similarly u can try to find the date of any of seven workdays by changing the integer -1,-2 and so on...
Hope u r question is answered..
Thanks,
Bonson Dias
The ISO 8601 calendar appears to have it's first weekday set to monday by default.
Using the Calendar nextWeekend (iOS 10 or later) and ordinality (thanks #kris-markel). I've gotten Monday as first of the week for the en_US calendar.
Here is an example of it with fallback to firstWeekday:
extension Calendar {
var firstWorkWeekday: Int {
guard #available(iOS 10.0, *) else{
return self.firstWeekday
}
guard let endOfWeekend = self.nextWeekend(startingAfter: Date())?.end else {
return self.firstWeekday
}
return self.ordinality(of: .weekday, in: .weekOfYear, for: endOfWeekend) ?? self.firstWeekday
}
}
The Swift solution (note, use .yearForWeekOfYear, not .year):
let now = Date()
let cal = Calendar.current
var weekComponents = cal.dateComponents([.yearForWeekOfYear, .weekOfYear,
.weekday], from: now)
//weekComponents.weekday = 1 // if your week starts on Sunday
weekComponents.weekday = 2 // if your week starts on Monday
cal.date(from: weekComponents) // returns date with first day of the week
… is there a calendar that already has Monday as the first day of the week, instead of Sunday.
Someday, there will be.
My simple way of doing this is to get Monday = 0, Sunday = 6:
NSDateComponents *dateComponents = [[NSCalendar currentCalendar] components:NSWeekdayCalendarUnit fromDate:[NSDate date]];
NSInteger dayNumStartingFromMonday = ([dateComponents weekday] - 2 + 7) % 7; //normal: Sunday is 1, Monday is 2
I have a problem with my function that is supposed to retrieve this week's monday's date.
Sometimes it's a day off:
+(NSDate *) lastMondayBeforeDate:(NSDate*)timeStamp {
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *comps =
[gregorian components:NSWeekdayCalendarUnit fromDate:timeStamp];
NSInteger weekday = [comps weekday];
weekday = weekday==1 ? 6 : weekday-2;
NSTimeInterval secondsSinceMondayMidnight =
(NSUInteger) [timeStamp timeIntervalSince1970] % 60*60*24 +
weekday * 60*60*24;
NSLog(#"MONDAY's DATE-----------%#", [timeStamp dateByAddingTimeInterval:-secondsSinceMondayMidnight]);
return [timeStamp dateByAddingTimeInterval:-secondsSinceMondayMidnight];
}
Apple has code demonstrating how to do almost exactly this. They are targeting the Sunday of the week instead of Monday, but you can just add 1 in the appropriate place to adjust.
You definitely don't want to be doing things like 60*60*24 and computing seconds to adjust by. For example, days can have more or less than 24 hours due to changes in Daylight Saving Time.
I have a date picker.
After choosing a time from this I would like to get the dates of the next 64 Mondays.
How would I go about writing a method to take a date and return an NSArray of NSDates for the next 64 Mondays from that date
for e.g.
I picked time 6:45 pm from date picker then I want to fetch next 64 mondays with there time set to that time.
Example (ARC):
NSDate *pickerDate = [NSDate date];
NSLog(#"pickerDate: %#", pickerDate);
NSDateComponents *dateComponents;
NSCalendar *calendar = [NSCalendar currentCalendar];
dateComponents = [calendar components:NSWeekdayCalendarUnit fromDate:pickerDate];
NSInteger firstMondayOrdinal = 9 - [dateComponents weekday];
dateComponents = [[NSDateComponents alloc] init];
[dateComponents setDay:firstMondayOrdinal];
NSDate *firstMondayDate = [calendar dateByAddingComponents:dateComponents toDate:pickerDate options:0];
dateComponents = [[NSDateComponents alloc] init];
[dateComponents setWeek:1];
for (int i=0; i<64; i++) {
[dateComponents setWeek:i];
NSDate *mondayDate = [calendar dateByAddingComponents:dateComponents toDate:firstMondayDate options:0];
NSLog(#"week#: %i, mondayDate: %#", i, mondayDate);
}
NSLog output:
pickerDate: 2011-12-09 20:38:25 +0000
week#: 0, mondayDate: 2011-12-12 20:38:25 +0000
week#: 1, mondayDate: 2011-12-19 20:38:25 +0000
week#: 2, mondayDate: 2011-12-26 20:38:25 +0000
week#: 3, mondayDate: 2012-01-02 20:38:25 +0000
-the remaining 60 here-
Start with the NSDate from the picker, and keep adding 24*60*60 seconds to it until it's a Monday. Add the resulting date to the result. Continue adding 7*24*60*60 seconds to the last date you added and pushing the result onto the return list until you have all 64 Mondays. Here is how you tell if a NSDate falls on Monday:
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *weekdayComponents =[gregorian components:NSWeekdayCalendarUnit fromDate:dateOfInterest];
NSInteger weekday = [weekdayComponents weekday];
if (weekday == 2) ... // 2 represents Monday
EDIT: DaveDeLong pointed out a deficiency in the above algorithm: it will shift the time two times on the days of changing to daylight savings time. Instead of counting seconds manually, use this code to add a day to NSDate:
NSDate *currentDate = [NSDate date];
NSDateComponents *comps = [[NSDateComponents alloc] init];
[comps setDay:1]; // Add 1 when searching for the next Monday; add 7 when iterating 63 times
NSDate *date = [gregorian dateByAddingComponents:comps toDate:currentDate options:0];
[comps release];
You can use NSCalendar to determine what day of the week today (at the chosen time) is; bump it up to get to the next Monday, and then bump that by by 7 days 63 times to get the Mondays you seem to want.