Oracle SQL: fill in dates between dates - sql

I have the following basic script, this shows me some current capacity loading in my production schedule.
select rl.duedate, rl.reservation_no resnr, qty
from gps_reservation_load rl
where rl.reservation_no in ('179459','179460','179461')
and rl.work_center_no in ('ALIN','AVD5','AVD9')
But, I want to show the DUEDATE as a date range from the sysdate to end of the year, e.g.
I have the following that gives me that range but, how can I combine the scripts to give me the result above?
select trunc(sysdate + rownum) dt
from DUAL connect by rownum < (to_date('01-JAN-2016', 'dd-mon-yyyy') - trunc(sysdate))

You just need to use outer join.
SELECT duedate_generated,reservation_no, qty, dt
from
(SELECT
trunc(sysdate + rownum) AS duedate_generated
FROM DUAL
connect by rownum < (to_date('01-JAN-2016', 'dd-mon-yyyy') - trunc(sydsate)
) d
OUTER JOIN
(select
duedate, reservation_no resnr, qty
from gps_reservation_load
where
reservation_no in ('179459','179460','179461')
and work_center_no in ('ALIN','AVD5','AVD9')
) r1
ON (d.duedate_generated = r1. due date)

Related

Lowest continuous date without break

I have a table and each record has a date. We can assume that a date range is contiguous if there's not a 3 month break. How can I find the start of the most recent contiguous date range?
For example, imagine if I had this data:
1990-5-1
1990-6-4
1990-10-28
1990-11-14
1990-12-19
1991-1-20
1991-4-30
1991-5-13
I'd like for it to return 1991-4-30 because it's the start of the most recent contiguous range of dates.
I think this does what you're looking for. Using my own table and column names as test data. This is on Oracle.
select * from (
select * from sm_ss_tickets t1 where exists (
select * from sm_ss_tickets t2 where t2.created_date between t1.created_date and t1.created_date+90 and t1.rowid <> t2.rowid
) order by created_date asc
) where rownum = 1;
Maybe something like the following would work:
WITH d1 AS (
SELECT date'1990-05-01' AS dt FROM dual
UNION ALL
SELECT date'1990-06-04' AS dt FROM dual
UNION ALL
SELECT date'1990-10-28' AS dt FROM dual
UNION ALL
SELECT date'1990-11-14' AS dt FROM dual
UNION ALL
SELECT date'1990-12-19' AS dt FROM dual
UNION ALL
SELECT date'1991-01-20' AS dt FROM dual
UNION ALL
SELECT date'1991-04-30' AS dt FROM dual
UNION ALL
SELECT date'1991-05-13' AS dt FROM dual
)
SELECT MAX(dt) FROM (
SELECT dt, LAG(dt) OVER ( ORDER BY dt ) AS prev_dt, LEAD(dt) OVER ( ORDER BY dt ) AS next_dt
FROM d1
) WHERE ( dt > ADD_MONTHS(prev_dt, 3) OR prev_dt IS NULL )
AND dt > ADD_MONTHS(next_dt, -3)
In the above, a date can only be the start of a contiguous sequence if there is no prior date within 3 months (either it is more than three months ago or it doesn't exist at all) and there is also a subsequent date within 3 months.
You can use LAG and LEAD. Find the query below. I think it works fine.
tmp_year is the table I have created. tdate is the column.
The records in the table are
28-JAN-15
27-JAN-15
26-JAN-15
25-JAN-15
12-JUL-14
11-JUL-14
10-JUL-14
09-JUL-14
24-DEC-13
23-DEC-13
22-DEC-13
21-DEC-13
15-SEP-13
07-JUN-13
27-FEB-13
19-NOV-12
11-AUG-12
Please find the query which returns 25th Jan 2015.
select max(d.tdate) from (
select c.tdate,c.next_date,c.date_diff,lag(date_diff) over( order by tdate) prev_diff from (
select b.tdate ,b.next_date,(next_date-tdate) date_diff from
(select a.tdate,lead(a.tdate) over(order by a.tdate) next_date from tmp_year a ) b ) c) d where d.date_diff<90 and d.prev_diff>=90;

get date range between dates

I have following table tbl in database and I have dynamic joining date 1-1-2012 and I want this date is between (Fall and spring) or (spring and summer) or (summer and fall).I want query in which i passed only joining date which return semestertime and joining date in Oracle.
Semestertime joiningDate
Fall 10-13-2011
Spring 2-1-2012
Summer 6-11-2012
Fall 10-1-2015
If I understand your question correctly:
SELECT *
FROM your_table
WHERE joiningDate between to_date (your_lower_limit_date_here, 'mm-dd-yyyy')
AND to_date (your_upper_limit_date_here, 'mm-dd-yyyy`);
What about something like that:
select 'BEFORE' term,
t."Semestertime", to_char(t."joiningDate", 'MM-DD-YYYY')
from (
select tbl.*, rownum rn from tbl where tbl."joiningDate" < to_date('1-1-2012','MM-DD-YYYY')
-- ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
-- your reference date
order by tbl."joiningDate" desc) t
where rn = 1
union all
select 'AFTER' term,
t."Semestertime", to_char(t."joiningDate", 'MM-DD-YYYY')
from (
select tbl.*, rownum rn from tbl where tbl."joiningDate" > to_date('1-1-2012','MM-DD-YYYY')
-- ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
-- your reference date
order by tbl."joiningDate" asc) t
where rn = 1
This will return the "term" before and after a given date. You will probably have to adapt such query to your specific needs. But that might be a good starting point.
For example, given your business rules, you might consider using <= instead of <. You you might require to have the result displayer a column instead of rows. Bu all of this shouldn't be too had to change.
As an alternate solution using CTE and sub-queries:
with testdata as (select to_date('1-1-2012','MM-DD-YYYY') refdate from dual)
select v.what, tbl.* from tbl join
(
select 'BEFORE' what, max(t1."joiningDate") d
from tbl t1
where t1."joiningDate" < to_date('1-1-2012','MM-DD-YYYY')
union all
select 'AFTER' what, min(t1."joiningDate") d
from tbl t1
where t1."joiningDate" > to_date('1-1-2012','MM-DD-YYYY')
) v
on tbl."joiningDate" = v.d
See http://sqlfiddle.com/#!4/c7fa5/15 for a live demo comparing those solutions.

Oracle show all dates within a range and join to another table

I am trying to run a report to show a list of all dates within the past 90 days and then join that back to another table that has a date in one column and supplemental data in another. Here is how I am getting all the dates within a range:
select trunc(sysdate-90) + rownum -1 from all_objects where rownum <=90
The problem is joining this to another table on date. If I run:
select trunc(sysdate-90) + rownum -1, t.col2 from all_objects
left join (select date, col2 from table) t on trunc(sysdate-90) + rownum -1 = t.date
where rownum <=90
Then it only displays the first record from t.col2 for all values within the date range. How do I properly join these two tables?
Thanks
A better way to get the previous 90 days is to use the dual / connect by trick:
select trunc(sysdate-level) as the_date from dual connect by level <= 90
Now, you should be able to do something like:
select the_date, t.col2
from (select trunc(sysdate-level) as the_date from dual connect by level <= 90) date_tbl
left join t on date_tbl.the_date = t.date
Don't use all_objects, this is a really bad idea in terms of performance and your DBA will want to string you up. I have no idea where this idea of using all_objects came from originally, but I wish it would die!
In order to get a list of dates, you can implement a much simpler and fast bit of SQL:
SELECT TRUNC( SYSDATE ) - ROWNUM a_date
FROM DUAL
CONNECT BY ROWNUM <= (the number of days you want)
If you want an offset, you can add that
SELECT TRUNC( SYSDATE ) - ROWNUM + (the offset) a_date
FROM DUAL
CONNECT BY ROWNUM <= (the number of days you want)
If you want a different order you can wrap if in another select and then order:
SELECT a_date
FROM (
SELECT TRUNC( SYSDATE ) - ROWNUM + (the offset)
FROM DUAL
CONNECT BY ROWNUM <= (the number of days you want)
)
ORDER BY a_date ASC
You can then embed this into your existing statement, bearing in mind that you need it in a sub-select. The reason for that is so that your ROWNUM values don't get mixed up:
SELECT t.date, t.col_2
FROM ( SELECT TRUNC( SYSDATE ) - ROWNUM a_date
FROM DUAL
CONNECT BY ROWNUM <= 90 ) date_list
LEFT JOIN table t ON date_list.a_date = t.date
ORDER BY a_date DESC

Total Count of Active Employees by Date

I have in the past written queries that give me counts by date (hires, terminations, etc...) as follows:
SELECT per.date_start AS "Date",
COUNT(peo.EMPLOYEE_NUMBER) AS "Hires"
FROM hr.per_all_people_f peo,
hr.per_periods_of_service per
WHERE per.date_start BETWEEN peo.effective_start_date AND peo.EFFECTIVE_END_DATE
AND per.date_start BETWEEN :PerStart AND :PerEnd
AND per.person_id = peo.person_id
GROUP BY per.date_start
I was now looking to create a count of active employees by date, however I am not sure how I would date the query as I use a range to determine active as such:
SELECT COUNT(peo.EMPLOYEE_NUMBER) AS "CT"
FROM hr.per_all_people_f peo
WHERE peo.current_employee_flag = 'Y'
and TRUNC(sysdate) BETWEEN peo.effective_start_date AND peo.EFFECTIVE_END_DATE
Here is a simple way to get started. This works for all the effective and end dates in your data:
select thedate,
SUM(num) over (order by thedate) as numActives
from ((select effective_start_date as thedate, 1 as num from hr.per_periods_of_service) union all
(select effective_end_date as thedate, -1 as num from hr.per_periods_of_service)
) dates
It works by adding one person for each start and subtracting one for each end (via num) and doing a cumulative sum. This might have duplicates dates, so you might also do an aggregation to eliminate those duplicates:
select thedate, max(numActives)
from (select thedate,
SUM(num) over (order by thedate) as numActives
from ((select effective_start_date as thedate, 1 as num from hr.per_periods_of_service) union all
(select effective_end_date as thedate, -1 as num from hr.per_periods_of_service)
) dates
) t
group by thedate;
If you really want all dates, then it is best to start with a calendar table, and use a simple variation on your original query:
select c.thedate, count(*) as NumActives
from calendar c left outer join
hr.per_periods_of_service pos
on c.thedate between pos.effective_start_date and pos.effective_end_date
group by c.thedate;
If you want to count all employees who were active during the entire input date range
SELECT COUNT(peo.EMPLOYEE_NUMBER) AS "CT"
FROM hr.per_all_people_f peo
WHERE peo.[EFFECTIVE_START_DATE] <= :StartDate
AND (peo.[EFFECTIVE_END_DATE] IS NULL OR peo.[EFFECTIVE_END_DATE] >= :EndDate)
Here is my example based on Gordon Linoff answer
with a little modification, because in SUBSTRACT table all records were appeared with -1 in NUM, even if no date was in END DATE = NULL.
use AdventureWorksDW2012 --using in MS SSMS for choosing DATABASE to work with
-- and may be not work in other platforms
select
t.thedate
,max(t.numActives) AS "Total Active Employees"
from (
select
dates.thedate
,SUM(dates.num) over (order by dates.thedate) as numActives
from
(
(
select
StartDate as thedate
,1 as num
from DimEmployee
)
union all
(
select
EndDate as thedate
,-1 as num
from DimEmployee
where EndDate IS NOT NULL
)
) AS dates
) AS t
group by thedate
ORDER BY thedate
worked for me, hope it will help somebody
I was able to get the results I was looking for with the following:
--Active Team Members by Date
SELECT "a_date",
COUNT(peo.EMPLOYEE_NUMBER) AS "CT"
FROM hr.per_all_people_f peo,
(SELECT DATE '2012-04-01'-1 + LEVEL AS "a_date"
FROM dual
CONNECT BY LEVEL <= DATE '2012-04-30'+2 - DATE '2012-04-01'-1
)
WHERE peo.current_employee_flag = 'Y'
AND "a_date" BETWEEN peo.effective_start_date AND peo.EFFECTIVE_END_DATE
GROUP BY "a_date"
ORDER BY "a_date"

Find missing dates using SQL

I have some dates in table over of a two years like this as a example date
01-jan-2012
02-jan-2012
04-jan-2012
05-jan-2012
06-jan-2012
07-jan-2012
09-jan-2012
11-jan-2012
.
.
.
01-DEC-2012
I think you have noticed that there a missing date of 03-jan-2012 and 08-jan-2012 and the same criteria with all dates.My Question is that is there any way in oracle to find the missing dates.Plz Help !
This will get you all missing days for one year (SQL Fiddle).
all_dates generates a list of all dates of 2012 (adjust as required), and the LEFT JOIN checking for IS NULL eliminates those dates that exist in your source-table.
WITH all_dates AS (
SELECT TO_DATE('01-jan-2012') + ROWNUM - 1 AS d
FROM dual
CONNECT BY ROWNUM <= ADD_MONTHS(TO_DATE('01-jan-2012'), 12 ) - TO_DATE('01-jan-2012')
)
SELECT all_dates.d
FROM all_dates
LEFT JOIN t ON ( t.d = all_dates.d )
WHERE t.d IS NULL
ORDER BY all_dates.d
;
Make sure to use a bind variable instead of hard-coding the date three times.
You can generate sequence of date range you needed, then use LEFT JOIN to find missed dates.
Almost the same answer as #Peter, but a very slightly different version.
select all_dates.date_ missing_dates from
(select to_date('01-Jan-14') + level - 1 date_
from dual connect by level <= 365) all_dates
left join
((select to_date('01-Jan-14') + level - 1 date_
from dual connect by level <= 365)
minus
(select to_date(round (dbms_random.value (1, 28))
|| '-'
|| round (dbms_random.value (01, 12))
|| '-'
|| round (dbms_random.value (2014, 2014)),
'DD-MM-YYYY') + level - 1 random_date_1
from dual
connect by level <= 52)) transaction_data
on all_dates.date_ = transaction_data.date_
where transaction_data.date_ is null;