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I have to do a select query to create a view with specific criteria.
I have multiple tables which contains many many columns and lines.
However, I have extracted a value to use as my key (e.g.: id). I have 7000+ of those unique keys that I extracted from all my tables with the function UNION to avoid duplicates.
Now, I want to add a column INDICATOR_1 which will affect the value YES or NO based on criteria.
This is where I struggle.
I need to find the line in those tables that contain the id. After that, I'd like to check, always in that line, if the field XYZ contains the value 'N' (example). If yes, affect the value 'YES' to INDICATOR_1, else it's no.
In a matter of pseudo-code, what I want to do looks like this :
CASE
WHEN id = (id from table_1) AND (if table_1.xyz = 'N')
THEN 'YES'
ELSE 'NO'
END AS INDICATOR_1
I don't know if I'm clear enough, but your help will be greatly appreciated.
If I understand correctly, you want a separate indicator for each table. Something like this:
select i.*,
(case when exists (select 1
from table1 t1
where t1.id = i.id and t1.xyz = 'N'
)
then 'YES' else 'NO'
end) as indicator_1,
(case when exists (select 1
from table2 t2
where t2.id = i.id and t2.xyz = 'N'
)
then 'YES' else 'NO'
end) as indicator_2,
. . .
from (<your id list here>) i
I think you should fix this in the union, where you have all the data you need. You probably have something like:
SELECT Id
FROM table_1
UNION
SELECT Id
FROM table_2
How about selecting the information you want as well (I use distinct here to clarify):
SELECT DISTINCT Id
, CASE WHEN table_1.xyz = 'N' THEN 'N'
ELSE 'Y'
END INDICATOR_1
FROM table_1
This can lead to more records than you had, if id's can have records of both flavours exist. We can fix that with a row number in an outer query. You end up with something like:
SELECT Id
, INDICATOR_1
FROM (
SELECT Id
, INDICATOR_1
, ROW_NUMBER()OVER(PARTITION BY ID ORDER BY CASE WHEN INDICATOR_1 ='N' THEN 0 ELSE 1 END) RN
FROM (
SELECT Id
, CASE WHEN table_1.xyz = 'N' THEN 'N'
ELSE 'Y'
END INDICATOR_1
FROM table_1
UNION
...
) T
) S
WHERE S.RN = 1
You can in fact shorten that by using the inner most case expression in the ROW_NUMBER expression.
I need to write a query to produce a result to display the OLD_ACCOUNT_ID when available else NULL and the NEW_ACCOUNT_ID when available else NULL from the same table based on the conditions. I tried a query like below but this does not produce the data in separate columns as OLD and NEW. Can somebody please help.
SELECT DISTINCT
A.ACCOUNT_ID as NEW_ACCOUNT_ID,
A.ACTIVE_FLAG,A.DATA_ID
FROM Table A
WHERE DATA_SOURCE_PROVIDER_ID='X'
AND ACTIVE_FLAG='Y'
and DATA_ID= '12345678'
union
SELECT DISTINCT B.ACCOUNT_ID AS OLD_ACCOUNT_ID,
B.ACTIVE_FLAG,B.DATA_ID
FROM Table B
WHERE DATA_SOURCE_PROVIDER_ID='X'
AND ACTIVE_FLAG='N'
and DATA_ID= '12345678'
Use case
select DISTINCT
case ACTIVE_FLAG when 'Y' then ACCOUNT_ID end as NEW_ACCOUNT_ID,
case ACTIVE_FLAG when 'N' then ACCOUNT_ID end as OLD_ACCOUNT_ID,
ACTIVE_FLAG,D
DATA_ID
from Table
whene DATA_ID= '12345678';
How can I change column text Not Exists when it is empty or null ?
My query :
Select TOP 1 ISNULL(NULLIF(DR.Name,''),'Not Exists') as Name,
DR.Name as Name ,Coalesce(NullIf(rtrim(DR.Name),''),'Not Exist') as Name,
Name = case when DR.Name is null then 'Not Exists'
when DR.Name='' then 'Not Exists' else DR.Name end
from Transfer TR
join Driver DR on DR.OID=TR.DriverID
WHERE TR.TruckID=51 AND TR.Statues<>7 and TR.DateScheduled<GETDATE()
AND TR.DateScheduled>=DATEADD(DAY,-7,GETDATE()) ORDER BY TR.OID DESC
Result :
If you just need a single column, then you can use a sub-select, this way when no rows are returned by the query you will still get not exists:
SELECT Name = ISNULL(( SELECT TOP 1 NULLIF(DR.Name,'')
FROM Transfer AS TR
INNER JOIN Driver AS DR
ON DR.OID = TR.DriverID
WHERE TR.TruckID = 51
AND TR.Statues <> 7
AND TR.DateScheduled < GETDATE()
AND TR.DateScheduled >= DATEADD(DAY, -7, GETDATE())
ORDER BY TR.OID DESC), 'Not Exists');
If you need multiple columns then you could union your Not Exists record to the bottom of the query, place all this inside a subquery then select the top 1 again, ensuring that your actual value takes precedence (by adding the column SortOrder):
SELECT TOP 1 Name, SomeOtherColumn
FROM ( SELECT TOP 1
Name = NULLIF(DR.Name,''),
SomeOtherColumn,
SortOrder = 0
FROM Transfer AS TR
INNER JOIN Driver AS DR
ON DR.OID = TR.DriverID
WHERE TR.TruckID = 51
AND TR.Statues <> 7
AND TR.DateScheduled < GETDATE()
AND TR.DateScheduled >= DATEADD(DAY, -7, GETDATE())
ORDER BY TR.OID DESC
UNION ALL
SELECT 'Not Exists', NULL, 1
) AS t
ORDER BY SortOrder;
I'm not entirely sure I understand your question, but if you are trying to catch nulls and empty strings "in one go", try this:
select TOP 1
case when length(trim(coalesce(DR.Name, ''))) = 0 then
'Not Exists'
else
DR.Name
as Name
....
The coalesce catches the NULLs and sets a replacement value. The trim gets rid of any padding and the length checks if what is left is an empty string --> so this covers nulls, padded- and non-padded trivial strings.
Assuming the value has regular spaces, the following would keep your approach:
Select TOP 1 ISNULL(NULLIF(ltrim(rtrim((DR.Name))), ''), 'Not Exists') as Name,
I would probably go with the more explicit:
select top 1 (case when ltrim(rtrim((DR.Name)) = '' or DR.Name is null then 'Not Exists'
else DR.Name end) as Name
Unless you also wanted the spaces removed from Name in the output.
If you have other characters, then you can use ASCII() to find them. Something like:
select ASCII(LEFT(DR.Name, 1))
. . .
where LEFT(DR.Name, 1) NOT LIKE '[a-zA-Z0-9 ]' -- you can expand this list of allowed characters
It seems to me you are not actually looking for a way to replace an empty string with 'Not Exists', but an empty result set.
In other words: It looks like you are looking for a way to show 'Not Exists' in case your query returns no rows. If it is this what you are looking for, then first "add" a 'Not Exists' record to your result set and then show the best row, i.e. the desired row in case such a row exists, else your 'Not Exists' row.
select top 1 name
from
(
select name, tr.oid
from transfer tr
join driver dr on dr.oid=tr.driverid
where tr.truckid=51 and tr.statues<>7 and tr.datescheduled<getdate()
and tr.datescheduled>=dateadd(day,-7,getdate())
union all
select 'Not Exists', -1
)
order by oid desc;
I chose -1 for the dummy OID. It must be a value smaller than any real OID. So if you have negative values, make that value even smaller.
I have a table
create table us
(
a number
);
Now I have data like:
a
1
2
3
4
null
null
null
8
9
Now I need a single query to count null and not null values in column a
This works for Oracle and SQL Server (you might be able to get it to work on another RDBMS):
select sum(case when a is null then 1 else 0 end) count_nulls
, count(a) count_not_nulls
from us;
Or:
select count(*) - count(a), count(a) from us;
If I understood correctly you want to count all NULL and all NOT NULL in a column...
If that is correct:
SELECT count(*) FROM us WHERE a IS NULL
UNION ALL
SELECT count(*) FROM us WHERE a IS NOT NULL
Edited to have the full query, after reading the comments :]
SELECT COUNT(*), 'null_tally' AS narrative
FROM us
WHERE a IS NULL
UNION
SELECT COUNT(*), 'not_null_tally' AS narrative
FROM us
WHERE a IS NOT NULL;
Here is a quick and dirty version that works on Oracle :
select sum(case a when null then 1 else 0) "Null values",
sum(case a when null then 0 else 1) "Non-null values"
from us
for non nulls
select count(a)
from us
for nulls
select count(*)
from us
minus
select count(a)
from us
Hence
SELECT COUNT(A) NOT_NULLS
FROM US
UNION
SELECT COUNT(*) - COUNT(A) NULLS
FROM US
ought to do the job
Better in that the column titles come out correct.
SELECT COUNT(A) NOT_NULL, COUNT(*) - COUNT(A) NULLS
FROM US
In some testing on my system, it costs a full table scan.
As i understood your query, You just run this script and get Total Null,Total NotNull rows,
select count(*) - count(a) as 'Null', count(a) as 'Not Null' from us;
usually i use this trick
select sum(case when a is null then 0 else 1 end) as count_notnull,
sum(case when a is null then 1 else 0 end) as count_null
from tab
group by a
Just to provide yet another alternative, Postgres 9.4+ allows applying a FILTER to aggregates:
SELECT
COUNT(*) FILTER (WHERE a IS NULL) count_nulls,
COUNT(*) FILTER (WHERE a IS NOT NULL) count_not_nulls
FROM us;
SQLFiddle: http://sqlfiddle.com/#!17/80a24/5
This is little tricky. Assume the table has just one column, then the Count(1) and Count(*) will give different values.
set nocount on
declare #table1 table (empid int)
insert #table1 values (1),(2),(3),(4),(5),(6),(7),(8),(9),(10),(NULL),(11),(12),(NULL),(13),(14);
select * from #table1
select COUNT(1) as "COUNT(1)" from #table1
select COUNT(empid) "Count(empid)" from #table1
Query Results
As you can see in the image, The first result shows the table has 16 rows. out of which two rows are NULL. So when we use Count(*) the query engine counts the number of rows, So we got count result as 16. But in case of Count(empid) it counted the non-NULL-values in the column empid. So we got the result as 14.
so whenever we are using COUNT(Column) make sure we take care of NULL values as shown below.
select COUNT(isnull(empid,1)) from #table1
will count both NULL and Non-NULL values.
Note: Same thing applies even when the table is made up of more than one column. Count(1) will give total number of rows irrespective of NULL/Non-NULL values. Only when the column values are counted using Count(Column) we need to take care of NULL values.
I had a similar issue: to count all distinct values, counting null values as 1, too. A simple count doesn't work in this case, as it does not take null values into account.
Here's a snippet that works on SQL and does not involve selection of new values.
Basically, once performed the distinct, also return the row number in a new column (n) using the row_number() function, then perform a count on that column:
SELECT COUNT(n)
FROM (
SELECT *, row_number() OVER (ORDER BY [MyColumn] ASC) n
FROM (
SELECT DISTINCT [MyColumn]
FROM [MyTable]
) items
) distinctItems
Try this..
SELECT CASE
WHEN a IS NULL THEN 'Null'
ELSE 'Not Null'
END a,
Count(1)
FROM us
GROUP BY CASE
WHEN a IS NULL THEN 'Null'
ELSE 'Not Null'
END
Here are two solutions:
Select count(columnname) as countofNotNulls, count(isnull(columnname,1))-count(columnname) AS Countofnulls from table name
OR
Select count(columnname) as countofNotNulls, count(*)-count(columnname) AS Countofnulls from table name
Try
SELECT
SUM(ISNULL(a)) AS all_null,
SUM(!ISNULL(a)) AS all_not_null
FROM us;
Simple!
If you're using MS Sql Server...
SELECT COUNT(0) AS 'Null_ColumnA_Records',
(
SELECT COUNT(0)
FROM your_table
WHERE ColumnA IS NOT NULL
) AS 'NOT_Null_ColumnA_Records'
FROM your_table
WHERE ColumnA IS NULL;
I don't recomend you doing this... but here you have it (in the same table as result)
use ISNULL embedded function.
All the answers are either wrong or extremely out of date.
The simple and correct way of doing this query is using COUNT_IF function.
SELECT
COUNT_IF(a IS NULL) AS nulls,
COUNT_IF(a IS NOT NULL) AS not_nulls
FROM
us
SELECT SUM(NULLs) AS 'NULLS', SUM(NOTNULLs) AS 'NOTNULLs' FROM
(select count(*) AS 'NULLs', 0 as 'NOTNULLs' FROM us WHERE a is null
UNION select 0 as 'NULLs', count(*) AS 'NOTNULLs' FROM us WHERE a is not null) AS x
It's fugly, but it will return a single record with 2 cols indicating the count of nulls vs non nulls.
This works in T-SQL. If you're just counting the number of something and you want to include the nulls, use COALESCE instead of case.
IF OBJECT_ID('tempdb..#us') IS NOT NULL
DROP TABLE #us
CREATE TABLE #us
(
a INT NULL
);
INSERT INTO #us VALUES (1),(2),(3),(4),(NULL),(NULL),(NULL),(8),(9)
SELECT * FROM #us
SELECT CASE WHEN a IS NULL THEN 'NULL' ELSE 'NON-NULL' END AS 'NULL?',
COUNT(CASE WHEN a IS NULL THEN 'NULL' ELSE 'NON-NULL' END) AS 'Count'
FROM #us
GROUP BY CASE WHEN a IS NULL THEN 'NULL' ELSE 'NON-NULL' END
SELECT COALESCE(CAST(a AS NVARCHAR),'NULL') AS a,
COUNT(COALESCE(CAST(a AS NVARCHAR),'NULL')) AS 'Count'
FROM #us
GROUP BY COALESCE(CAST(a AS NVARCHAR),'NULL')
Building off of Alberto, I added the rollup.
SELECT [Narrative] = CASE
WHEN [Narrative] IS NULL THEN 'count_total' ELSE [Narrative] END
,[Count]=SUM([Count]) FROM (SELECT COUNT(*) [Count], 'count_nulls' AS [Narrative]
FROM [CrmDW].[CRM].[User]
WHERE [EmployeeID] IS NULL
UNION
SELECT COUNT(*), 'count_not_nulls ' AS narrative
FROM [CrmDW].[CRM].[User]
WHERE [EmployeeID] IS NOT NULL) S
GROUP BY [Narrative] WITH CUBE;
SELECT
ALL_VALUES
,COUNT(ALL_VALUES)
FROM(
SELECT
NVL2(A,'NOT NULL','NULL') AS ALL_VALUES
,NVL(A,0)
FROM US
)
GROUP BY ALL_VALUES
select count(isnull(NullableColumn,-1))
if its mysql, you can try something like this.
select
(select count(*) from TABLENAME WHERE a = 'null') as total_null,
(select count(*) from TABLENAME WHERE a != 'null') as total_not_null
FROM TABLENAME
Just in case you wanted it in a single record:
select
(select count(*) from tbl where colName is null) Nulls,
(select count(*) from tbl where colName is not null) NonNulls
;-)
for counting not null values
select count(*) from us where a is not null;
for counting null values
select count(*) from us where a is null;
I created the table in postgres 10 and both of the following worked:
select count(*) from us
and
select count(a is null) from us
In my case I wanted the "null distribution" amongst multiple columns:
SELECT
(CASE WHEN a IS NULL THEN 'NULL' ELSE 'NOT-NULL' END) AS a_null,
(CASE WHEN b IS NULL THEN 'NULL' ELSE 'NOT-NULL' END) AS b_null,
(CASE WHEN c IS NULL THEN 'NULL' ELSE 'NOT-NULL' END) AS c_null,
...
count(*)
FROM us
GROUP BY 1, 2, 3,...
ORDER BY 1, 2, 3,...
As per the '...' it is easily extendable to more columns, as many as needed
Number of elements where a is null:
select count(a) from us where a is null;
Number of elements where a is not null:
select count(a) from us where a is not null;
I have a table that has a processed_timestamp column -- if a record has been processed then that field contains the datetime it was processed, otherwise it is null.
I want to write a query that returns two rows:
NULL xx -- count of records with null timestamps
NOT NULL yy -- count of records with non-null timestamps
Is that possible?
Update: The table is quite large, so efficiency is important. I could just run two queries to calculate each total separately, but I want to avoid hitting the table twice if I can avoid it.
In MySQL you could do something like
SELECT
IF(ISNULL(processed_timestamp), 'NULL', 'NOT NULL') as myfield,
COUNT(*)
FROM mytable
GROUP BY myfield
In T-SQL (MS SQL Server), this works:
SELECT
CASE WHEN Field IS NULL THEN 'NULL' ELSE 'NOT NULL' END FieldContent,
COUNT(*) FieldCount
FROM
TheTable
GROUP BY
CASE WHEN Field IS NULL THEN 'NULL' ELSE 'NOT NULL' END
Oracle:
group by nvl2(field, 'NOT NULL', 'NULL')
Try the following, it's vendor-neutral:
select
'null ' as type,
count(*) as quant
from tbl
where tmstmp is null
union all
select
'not null' as type,
count(*) as quant
from tbl
where tmstmp is not null
After having our local DB2 guru look at this, he concurs: none of the solutions presented to date (including this one) can avoid a full table scan (of the table if timestamp is not indexed, or of the indexotherwise). They all scan every record in the table exactly once.
All the CASE/IF/NVL2() solutions do a null-to-string conversion for each row, introducing unnecessary load on the DBMS. This solution does not have that problem.
Stewart,
Maybe consider this solution. It is (also!) vendor non-specific.
SELECT count([processed_timestamp]) AS notnullrows,
count(*) - count([processed_timestamp]) AS nullrows
FROM table
As for efficiency, this avoids 2x index seeks/table scans/whatever by including the results on one row. If you absolutely require 2 rows in the result, two passes over the set may be unavoidable because of unioning aggregates.
Hope this helps
If it's oracle then you can do:
select decode(field,NULL,'NULL','NOT NULL'), count(*)
from table
group by decode(field,NULL,'NULL','NOT NULL');
I'm sure that other DBs allow for similar trick.
Another MySQL method is to use the CASE operator, which can be generalised to more alternatives than IF():
SELECT CASE WHEN processed_timestamp IS NULL THEN 'NULL'
ELSE 'NOT NULL' END AS a,
COUNT(*) AS n
FROM logs
GROUP BY a
SQL Server (starting with 2012):
SELECT IIF(ISDATE(processed_timestamp) = 0, 'NULL', 'NON NULL'), COUNT(*)
FROM MyTable
GROUP BY ISDATE(processed_timestamp);
Another way in T-sql (sql-server)
select count(case when t.timestamps is null
then 1
else null end) NULLROWS,
count(case when t.timestamps is not null
then 1
else null end) NOTNULLROWS
from myTable t
If your database has an efficient COUNT(*) function for a table, you could COUNT whichever is the smaller number, and subtract.
In Oracle
SELECT COUNT(*), COUNT(TIME_STAMP_COLUMN)
FROM TABLE;
count(*) returns the count of all rows
count(column_name) returns the number of rows which are not NULL, so
SELECT COUNT(*) - COUNT(TIME_STAMP_COLUMN) NUL_COUNT,
COUNT(TIME_STAMP_COLUMN) NON_NUL_COUNT
FROM TABLE
ought to do the job.
If the column is indexed, you might end up with some sort of range scan and avoid actually reading the table.
I personally like Pax's solution, but if you absolutely require only one row returned (as I had recently), In MS SQL Server 2005/2008 you can "stack" the two queries using a CTE
with NullRows (countOf)
AS
(
SELECT count(*)
FORM table
WHERE [processed_timestamp] IS NOT NULL
)
SELECT count(*) AS nulls, countOf
FROM table, NullRows
WHERE [processed_timestamp] IS NULL
GROUP BY countOf
Hope this helps
[T-SQL]:
select [case], count(*) tally
from (
select
case when [processed_timestamp] is null then 'null'
else 'not null'
end [case]
from myTable
) a
And you can add into the case statement whatever other values you'd like to form a partition, e.g. today, yesterday, between noon and 2pm, after 6pm on a Thursday.
Select Sum(Case When processed_timestamp IS NULL
Then 1
Else 0
End) not_processed_count,
Sum(Case When processed_timestamp Is Not NULL
Then 1
Else 0
End) processed_count,
Count(1) total
From table
Edit: didn't read carefully, this one returns a single row.