Dim streamf As System.IO.Stream
Dim stringf As String
stringf = OpenFileDialog1.FileName.ToString()
streamf = OpenFileDialog1.OpenFile()
I have a file ScreenShot.png attached on the application installation path which means if user run the .exe file from Desktop it will store ScreenShot.png on his desktop and so on.
Now i need to get the full path to that ScreenShot.png file to be sent in the FAX
Dim srcBt As Byte()
Dim encodedBase64 As String
Dim filereader As New IO.FileStream(stringf, IO.FileMode.Open)
ReDim srcBt(filereader.Length)
filereader.Read(srcBt, 0, filereader.Length)
filereader.Close()
encodedBase64 = System.Convert.ToBase64String(srcBt)
So the problem part is how can i put that location of the file to the Stringf ? Because example i have force user to locate the file using OpenFileDialog and i have predefined file
This should convert any (relative) path to an absolut path:
Dim stringf_info As New System.IO.FileInfo(stringf)
stringf = stringf_info.FullName
Related
I'm writing some program in VB, and I want to create txt file with text from file in resources. You didn't understood, did you? So, it goes like this.
Dim path As String = "c:\temp\MyTest.txt"
' Create or overwrite the file.
Dim fs As FileStream = File.Create(path)
' Add text to the file.
Dim info As Byte() = New UTF8Encoding(True).GetBytes("This is some text in the file.")
fs.Write(info, 0, info.Length)
fs.Close()
is code for creating txt file with certain text. But, I need the following.
Dim fd As New FolderBrowserDialog
fd.ShowDialog()
is the only function that I have in program, and, when folder is selected, I need to create file in that folder, file's name should be config.cfg, but, text in file which is going to be created in selected folder should be text from mine txt file which is in Recources.
I've tried
Dim path As String = fd.SelectedPath
Dim fs As FileStream = File.Create(path)
' upisuje tekst u fajl
Dim info As Byte() = New UTF8Encoding(True).GetBytes(application.startuppath & "\..\..\Resources\config.cfg")
fs.Write(info, 0, info.Length)
fs.Close()
but the text I got in file is directory from where is my program debugged.
Any ideas to do this? :)
If you added a text file to your resources, then you can try something like this:
Using fbd As New FolderBrowserDialog
If fbd.ShowDialog(Me) = DialogResult.OK Then
File.WriteAllText(Path.Combine(fbd.SelectedPath, "config.cfg"), My.Resources.config)
End If
End Using
The file I added was called config, and it made a config.txt file in my resource library.
I have a .zip folder in the .exe resources and I have to move it out and then extract it to a folder. Currently I am moving the .zip out with System.IO.File.WriteAllByte and unziping it. Is there anyway to unzip straight from the resources to a folder?
Me.Cursor = Cursors.WaitCursor
'Makes the program look like it's loading.
Dim FileName As FileInfo
Dim Dir_ExtractPath As String = Me.tb_Location.Text
'This is where the FTB folders are located on the drive.
If Not System.IO.Directory.Exists("C:\Temp") Then
System.IO.Directory.CreateDirectory("C:\Temp")
End If
'Make sure there is a temp folder.
Dim Dir_Temp As String = "C:\Temp\Unleashed.zip"
'This is where the .zip file is moved to.
Dim Dir_FTBTemp As String = Dir_ExtractPath & "\updatetemp"
'This is where the .zip is extracted to.
System.IO.File.WriteAllBytes(Dir_Temp, My.Resources.Unleashed)
'This moves the .zip file from the resorces to the Temp file.
Dim UnleashedZip As ZipEntry
Using Zip As ZipFile = ZipFile.Read(Dir_Temp)
For Each UnleashedZip In Zip
UnleashedZip.Extract(Dir_FTBTemp, ExtractExistingFileAction.DoNotOverwrite)
Next
End Using
'Extracts the .zip to the temp folder.
So if you're using the Ionic library already, you could pull out your zip file resource as a stream, and plug that stream into Ionic to decompress it. Given a resource of My.Resources.Unleashed, you have two options for getting your zip file into a stream. You can load up a new MemoryStream from the bytes of the resource:
Using zipFileStream As MemoryStream = New MemoryStream(My.Resources.Unleashed)
...
End Using
Or you can use the string representation of the name of the resource to pull a stream directly from the assembly:
Dim a As Assembly = Assembly.GetExecutingAssembly()
Using zipFileStream As Stream = a.GetManifestResourceStream("My.Resources.Unleashed")
...
End Using
Assuming you want to extract all the files to the current working directory once you have your stream then you'd do something like this:
Using zip As ZipFile = ZipFile.Read(zipFileStream)
ForEach entry As ZipEntry In zip
entry.Extract();
Next
End Using
Taking pieces from here and there, this works with 3.5 Framework on Windows 7:
Dim shObj As Object = Activator.CreateInstance(Type.GetTypeFromProgID("Shell.Application"))
Dim tmpZip As String = My.Application.Info.DirectoryPath & "\tmpzip.zip"
Using zip As Stream = Assembly.GetExecutingAssembly().GetManifestResourceStream("myProject.myfile.zip")
Dim by(zip.Length) As Byte
zip.Read(by, 0, zip.Length)
My.Computer.FileSystem.WriteAllBytes(tmpZip, by, False)
End Using
'Declare the output folder
Dim output As Object = shObj.NameSpace(("C:\destination"))
'Declare the input zip file saved above
Dim input As Object = shObj.NameSpace((tmpZip)) 'I don't know why it needs to have double parentheses, but it fails without them
output.CopyHere((input.Items), 4)
IO.File.Delete(tmpZip)
shObj = Nothing
Sources: answers here and https://www.codeproject.com/Tips/257193/Easily-Zip-Unzip-Files-using-Windows-Shell
Since we are using the shell to copy the files, it will ask the user to overwrite them if already exist.
I am trying to locate a file from a program, in VB.NET
Dim exeName As String = "explorer.exe"
Dim params As String = "/e,""c:\test"",/select,""C:\test\a.txt"""
Dim processInfo As New ProcessStartInfo(exeName, params)
Process.Start(processInfo)
It opens the containing directory "c:\" but doesn't go inside to "c:\test", I would like to have the file selected...
Dim filePath As String = "C:\test\a.txt" 'Example file
Process.Start("explorer.exe", "/select," & filePath) 'Starts explorer.exe and selects desired file
You don't need the folder path in there after the /e, try this for your params:
Dim params As String = "/e, /select,""C:\temp\file.txt"""
How I can Paste from Clipboard a file to my path? I work in VB .NET. I got filename from clipboard but don't know how to extract file from cliboard and save it to my folder.
Dim data As IDataObject = Clipboard.GetDataObject()
If data.GetDataPresent(DataFormats.FileDrop) Then
Dim files As String() = data.GetData(DataFormats.FileDrop)
End If
Can anybody help me?
Thanks in advance!
You can use the Path class to both isolate the file name and create the path of the new file to use in a file copy operation:
Dim data As IDataObject = Clipboard.GetDataObject
If data.GetDataPresent(DataFormats.FileDrop) Then
For Each s As String In data.GetData(DataFormats.FileDrop)
Dim newFile As String = Path.Combine("c:\mynewpath", Path.GetFileName(s))
File.Copy(s, newFile)
Next
End If
Example needs error checking.
You can also get the full path to the file as follows:
Dim objeto As IDataObject = Clipboard.GetDataObject
For Each data As String In objeto.GetData(DataFormats.FileDrop)
...
Dim newFile As String = Path.GetFullPath(data.ToString)
...
Next
I am working on vb.net win form. My task is display the file names from a folder onto gridview control. when user clicks process button in my UI, all the file names present in gridview, the corresponding file has to be loaded onto memory stream buffer one after another and append the titles to the content of the file and save it in hard drive with _ed as a suffix to the file name.
I am very basic programmer. I have done the following attempt and succeeded in displaying filenames onto gridview. But no idea of later part. Any suggestions please?
'Displaying files from a folder onto a gridview
Dim inqueuePath As String = "C:\Users\Desktop\INQUEUE"
Dim fileInfo() As String
Dim rowint As Integer = 0
Dim name As String
Dim directoryInfo As New System.IO.DirectoryInfo(inqueuePath)
fileInfo = System.IO.Directory.GetFiles(inqueuePath)
With Gridview1
.Columns.Add("Column 0", "FileName")
.AutoResizeColumns()
End With
For Each name In fileInfo
Gridview1.Rows.Add()
Dim filename As String = System.IO.Path.GetFileName(name)
Gridview1.Item(0, rowint).Value = filename
rowint = rowint + 1
Next
Thank you very much for spending your valuable time to read this post.
to read a file into a memorystream is quite easy, just have a look at the following example and you should be able to convert it to suite your needs:
Dim bData As Byte()
Dim br As BinaryReader = New BinaryReader(System.IO.File.OpenRead(Path))
bData = br.ReadBytes(br.BaseStream.Length)
Dim ms As MemoryStream = New MemoryStream(bData, 0, bData.Length)
ms.Write(bData, 0, bData.Length)
then just use the MemoryStream ms as you please. Just to clearify Path holds the full path and filename you want to read into your memorystream.