Split row into several with SQL statement - sql

Question

I have a row in a databasetable that is on the following form:
ID | Amount | From | To
5 | 5439 | 01.01.2014 | 05.01.2014
I want to split this up to one row pr month using SQL/T-SQL:
Amount | From
5439 | 01.01.2014
5439 | 02.01.2014
5439 | 03.01.2014
5439 | 04.01.2014
5439 | 05.01.2014
I, sadly, cannot change the database source, and I want to preferrably do this in SQL as I am trying to result of this Query with an other table in Powerpivot.
Edit: Upon requests on my code, I have tried the following:
declare #counter int
set #counter = 0
WHILE #counter < 6
begin
set #counter = #counter +1
select amount, DATEADD(month, #counter, [From]) as Dato
FROM [database].[dbo].[table]
end
This however returns several databasesets.

Answer 1

You can use a tally table to generate all dates.
SQL Fiddle
;WITH E1(N) AS(
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
),
E2(N) AS(SELECT 1 FROM E1 a CROSS JOIN E1 b),
E4(N) AS(SELECT 1 FROM E2 a CROSS JOIN E2 b),
Tally(N) AS(
SELECT TOP(SELECT MAX(DATEDIFF(DAY, [From], [To])) + 1 FROM yourTable)
ROW_NUMBER() OVER(ORDER BY (SELECT NULL))
FROM E4
)
SELECT
yt.Id,
yt.Amount,
[From] = DATEADD(DAY, N-1, yt.[From])
FROM yourTable yt
CROSS JOIN Tally t
WHERE
DATEADD(DAY, N-1, yt.[From]) <= yt.[To]
Simplified explanation on Tally Table

Answer 2

You need a tally table with "running numbers". This may be a function (I posted one shortly here: https://stackoverflow.com/a/32096945/5089204) or a physical table (I posted an example here: https://stackoverflow.com/a/32474751/5089204) or a CTE to do this "on the fly" (the table example does it this way).
If you go with the posted function it could be like this:
declare #startDate DATETIME={d'2015-09-01'};
declare #EndDate DATETIME={d'2015-09-10'};
select DATEADD(DAY, Nmbr,#startDate)
from dbo.GetRunningNumbers(DATEDIFF(DAY,#startDate,#endDate)+1,0);

Answer 3

select * INTO #TEMP1 from
(values
(5 , 5439 , '01.01.2014', '05.01.2014'))t(id,amount,fromd,tod)
WITH CTE
AS
(
SELECT CAST(FROMD AS DATE) AS FROMD,amount,1 AS RN,ID FROM #TEMP1
UNION ALL
SELECT DATEADD(M,1,C.FROMD),C.amount,C.RN+1,C.ID
FROM CTE C
INNER JOIN #TEMP1 T ON T.id = C.ID AND DATEADD(M,1,c.FROMD)<=T.tod
)
SELECT * FROM CTE

Answer 4

create table t (fd date, td date)
insert into t values ('2015-01-01','2015-01-05')
WITH DATES (fd, td, Level)
AS
(
SELECT fd, td, 0 AS Level
FROM t
UNION ALL
-- Recursive member definition
SELECT DATEADD(day,level+1,e.fd),e.td,Level + 1
FROM t AS e
INNER JOIN Dates AS d ON DATEADD(day,-d.level,d.fd) = e.fd AND d.fd < d.td
)
-- Statement that executes the CTE
SELECT fd,td,level
from DATES

Answer 5

variant using recursive cte
--variable table for data sample
DECLARE #tbl AS TABLE
(
ID INT ,
Amount FLOAT ,
[From] DATE ,
[To] DATE
)
INSERT INTO #tbl
( ID, Amount, [From], [To] )
VALUES ( 5, 5439, '2014-01-01', '2014-01-05' )
--final query using recursive cte
;
WITH cte
AS ( SELECT T.ID ,
T.Amount ,
T.[From] ,
T.[To] ,
CONVERT(DATE, NULL) AS Dt ,
n = 0
FROM #tbl AS T
UNION ALL
SELECT cte.ID ,
cte.Amount ,
cte.[From] ,
cte.[To] ,
DATEADD(DAY, n, cte.[From]) ,
cte.n + 1
FROM cte
WHERE n <= DATEDIFF(day, cte.[From], cte.[To])
)
SELECT cte.ID ,
cte.Amount ,
dt AS [From]
FROM cte
WHERE cte.Dt IS NOT NULL
SQL Fiddle