My records looks like:
aid cmpyname rid imgpath
1 abc 1 ~/img/aa.jpg:~/img/bb.jpg:~/img/cc.jpg:
2 abc 1 ~/img/dd.jpg:~/img/ee.jpg:~/img/ff.jpg:
3 xyz 2 ~/img/gg.jpg:~/img/hh.jpg:~/img/ii.jpg:
4 xyz 2 ~/img/jj.jpg:~/img/kk.jpg:~/img/ll.jpg:
What I want to get is displayed below - but in a single query
cmpyname rid imgpath
abc 1 ~/img/aa.jpg:~/img/bb.jpg:~/img/cc.jpg:~/img/dd.jpg:~/img/ee.jpg:~/img/ff.jpg:
xyz 2 ~/img/gg.jpg:~/img/hh.jpg:~/img/ii.jpg:~/img/jj.jpg:~/img/kk.jpg:~/img/ll.jpg:
How can I do so? I haven't provided any relationship so please keep it in mind.
Thanks and Regards
select max(cmpyname) as cmpyname, rid,
stuff((
select imgpath
from Records t1
where t1.rid = t2.rid
order by t1.aid
for xml path(''), type).value('.', 'varchar(max)'), 1, 0, ''
) as imgpath
from Records t2
group by rid;
http://sqlfiddle.com/#!18/46822/1
select distinct rid,imgpath,rid from(
select imgpath=(select imgpath + ', ' AS 'data()'
FROM tbl_Temp
where tbl_Temp.rid=rid FOR XML PATH('') )
,id,cmpyname,rid from tbl_Temp
) as temp
Something like this:
Just paste into into an empty query window and execute. Adapt to your needs...
DECLARE #tbl TABLE(aid INT, cmpyname VARCHAR(100), rid INT, imgpath VARCHAR(1000));
INSERT INTO #tbl VALUES
(1,'abc',1,'~/img/aa.jpg:~/img/bb.jpg:~/img/cc.jpg:')
,(2,'abc',1,'~/img/dd.jpg:~/img/ee.jpg:~/img/ff.jpg:')
,(3,'xyz',2,'~/img/gg.jpg:~/img/hh.jpg:~/img/ii.jpg:')
,(4,'xyz',2,'~/img/jj.jpg:~/img/kk.jpg:~/img/ll.jpg:');
SELECT DISTINCT tbl.cmpyname
,tbl.rid
,(
SELECT '' + x.imgpath
FROM #tbl AS x
WHERE x.rid=tbl.rid
FOR XML PATH('')
) AS allPaths
FROM #tbl AS tbl
SELECT DISTINCT B.cmpyname, B.rid,
(
SELECT imgpath + '' FROM tbl1 AS A WHERE (B.rid = A.rid) FOR XML PATH('')
) AS imgpath
FROM tbl1 AS B
Related
I use the database Progress 12.2 and I want to group rows with same id
For example I have
ID Code
1 PB
1 RO
And I want :
ID Code
1 PB, RO
This is my request :
SELECT id, code FROM table WHERE table.id = 1
I tried String_agg, Group_concat ... but nothing works. Anyone has an idea ?
Regards,
You can use someting like that;
DECLARE #TBL TABLE (ID Int, Code nvarchar(5))
INSERT INTO #TBL values (1 ,'PB'),(1 ,'RO')
SELECT DISTINCT
T1.ID,
CONCAT_STRING = STUFF((
SELECT ',' + T2.Code
FROM #TBL T2
WHERE T2.ID = T1.ID
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')
FROM #TBL T1
The result will be like this;
i want join some table then concatenation columns
MyTable
-------------------------------
ID RowId LangId Caption
-------------------------------
1 1 1 ڕۆشتن
2 1 2 Go
3 1 3 اذهب
4 2 1 ئاو
5 2 2 water
6 2 3 ماء
I want join concatenation Caption column ex: for RowId 1 'ڕۆشتن - Go - اذهب'
Desired output
--------------------
RowId Caption
--------------------
1 ڕۆشتن - Go - اذهب
2 ئاو- water - ماء
I seen link but can't help me
You can use string_agg():
select rowid,
string_agg(caption, ' ') within group (order by langid) as caption
from t
group by rowid;
You can use for xml for older vresion :
select r.rowid,
stuff( (select ' - '+t.caption
from table t
where t.rowid = r.rowid
order by t.LangId
for xml path('')
), 1, 1, ''
) as Caption
from (select distinct rowid from table ) r;
You can use string_agg() for newer version SQL Server 17+ :
select t.rowid,
string_agg(t.caption, ' ') within group (order by t.langid) as caption
from table t
group by t.rowid;
You can try the following query using for xml as shown below.
SELECT DISTINCT t.RowId,
STUFF((SELECT distinct ' - ' + t1.[Caption]
FROM
(
SELECT t.[RowId],
t2.Caption
FROM [TestTable] AS t
INNER JOIN [TestTable] AS t2 ON t2.[RowId] = t.[RowId]
)
t1
WHERE t.RowId = t1.RowId
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'') CaptionList
FROM
(
SELECT t.[RowId],
por.Caption
FROM [TestTable] AS t
INNER JOIN [TestTable] AS por ON por.RowId = t.RowId
)t;
Here is the live db<>fiddle demo.
Try this:
SELECT DISTINCT RowID,
STUFF((SELECT DISTINCT Sub.caption +' - '
FROM #tab Sub
WHERE Sub.rowid = Main.rowid
FOR XML PATH('')), 1, 1, '') AS Caption
FROM #tab Main
I think this Query can perfectly fit for your case.
I have a table like
ID NAME
1 STALIN
2 MERWIN
1 AMALA
1 RAYON
i want the out as
ID NAME
1 STALIN,AMALA,RAYON
2 MERWIN
How can do this using recursive function
You can do this using XML Path
SELECT ID, NAME =
STUFF((SELECT ', ' + NAME
FROM your_table b
WHERE b.ID = a.ID
FOR XML PATH('')), 1, 2, '')
FROM your_table a
GROUP BY ID
Live Demo
Follow this link and see the case 3. it explains why to use XML path over recursive cursor.
You can use FOR XML PATH to get the result:
for example:
DECLARE #EXAMPLE TABLE (ID int, NAME nvarchar(10))
INSERT #EXAMPLE VALUES (1,'STALIN'),(2,'MERWIN'),(1,'AMALA'),(1,'RAYON')
SELECT
ID,
SUBSTRING(NAME,0,LEN(NAME)) AS NAME
FROM ( SELECT DISTINCT
T1.ID,
STUFF(( SELECT DISTINCT '' + t2.NAME + ','
FROM #EXAMPLE T2
WHERE T1.ID = T2.ID
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)')
,1,0,'') NAME
FROM #EXAMPLE t1) AS info
i have table with records :
City Name Seq
London 1
London 2
London 3
Madrid 4
London 5
Porto 6
Problem is how to get a result in string ( merge all without repeated records ).
Result : London-Madrid-London-Porto
Another option if 2012+ ... LAG()
Example
Declare #YourTable Table ([City Name] varchar(50),[Seq] int)
Insert Into #YourTable Values
('London',1)
,('London',2)
,('London',3)
,('Madrid',4)
,('London',5)
,('Porto',6)
Select Stuff((Select '-' +Value From
(
Select top 1000 Value = case when [City Name]=lag([City Name],1) over (Order By Seq) then null else [City Name] end
From #YourTable
Order By Seq
) A
For XML Path ('')),1,1,'')
Returns
London-Madrid-London-Porto
How about this?
declare #table table (CityName varchar(64), seq int)
insert into #table
values
('London',1),
('London',2),
('London',3),
('Madrid',4),
('London',5),
('Porto',6)
--find the next row that isn't the same city name (t2seq)
;with cte as(
select distinct
t.CityName
,t.seq
,min(t2.seq) as t2seq
from #table t
left join #table t2 on
t2.seq > t.seq
and t2.CityName <> t.CityName
group by
t.CityName
,t.seq),
--limit the result set to distinct list
cte2 as(
select distinct
CityName
,seq = isnull(t2seq,9999999)
from cte)
--use stuff to concat it together
select distinct
stuff(( select '-', + t2.CityName
from cte2 t2
order by seq
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')
from cte2
ID Name
1 A
1 B
1 C
2 X
2 Y
3 P
3 Q
3 R
These are the columns in a table. I want to get output like
ID Company
1 A,B,C
2 X, Y
3 P,Q,R
Restriction is that I cannot use WHILE or CURSOR. Please write a query for the same.
This query should do it - uses FOR XML PATH which is new in SQL Server 2005 - hope you are on 2005 or higher, you didn't clearly specify.....
SELECT
ID,
STUFF(CAST((SELECT ','+Name FROM dbo.YourTable t2
WHERE t2.ID = dbo.YourTable.ID
FOR XML PATH(''), TYPE) AS VARCHAR(MAX)), 1, 1, '') AS 'Company'
FROM
dbo.YourTable
GROUP BY
ID
Here's a solution using the CROSS APPLY method:
select id, sub.names
from (
select distinct id from YourTable
) a
cross apply (
select name + ', ' as [text()]
from YourTable b
where b.id = a.id
for xml path('')
) sub(names)
For 2005 version:
CREATE TABLE dbo.TEST([Type] INTEGER, [Name] NVARCHAR(100), [Qty] INTEGER)
GO
INSERT dbo.TEST VALUES(1, N'a', 5)
INSERT dbo.TEST VALUES(1, N'b', 6)
INSERT dbo.TEST VALUES(2, N'c', 44)
INSERT dbo.TEST VALUES(3, N'd', 1)
GO
select [Type],
[Description] = replace((select [Name] + ':' + cast([Qty] as varchar) as 'data()'
from TEST where [Type] = t.[Type] for xml path('')), ' ', ',')
from dbo.TEST t
group by [Type]
go
drop table dbo.TEST
You can group on the ID to get the unique values, then get the comma separated string for each using a for xml query:
select
a.ID,
substring((
select ', ' + Name
from Test1
where Test1.ID = a.ID
for xml path('')
), 3, 1000) as Company
from
TheTable a
group by
a.ID