Hi all consider following as my table structure
Col1 Col2 Col3
A 1 Aa
A 2 Bb
A 1 Aa
A 4 Bb
B 2 Bb
C 1 Aa
C 5 Bb
D 3 Aa
As you can see Col3 contains distint values of Aa and Bb.
I am trying to write a query which return only rows with Col1 having value Aa and Bb (Both) or Aa(Alone).
Point is to remove those rows which have only have Bb associated with distinct Col1 value to it.
Example - For Col1 Distinct value of A should have Aa and Bb / Aa in corresponding Col3. This requirement is violated by value of B in Col1, hence result set should not have rows associated with B.
Expected output -
Col1 Col2 Col3
A 1 Aa
A 2 Bb
A 1 Aa
A 4 Bb
C 1 Aa
C 5 Bb
D 3 Aa
SELECT *
FROM TableName T
WHERE EXISTS ( SELECT 1
FROM TableName
WHERE T.Col1 = Col1
AND Col3 = 'Aa')
One other approach is to use intersect and union.
Fiddle with sample data
select * from t where col1 in (
select col1 from t where col3 = 'Aa'
intersect
select col1 from t where col3 = 'Bb'
union
select col1 from t where col3 = 'Aa')
Select table1.Col1, table1.Col2, table1.Col3
From Table1
join (SELECT Col1
,SUM(case when col3 = 'Aa' then 1 when Col3 = 'Bb' then 0 end) AS [Counting]
FROM [dbo].[Table1]
group by Col1
having SUM(case when col3 = 'Aa' then 1 when Col3 = 'Bb' then 0 end) > 0) keep on table1.Col1 = keep.Col1
Here's another option, using your values instead of a table.:
Select
T.*
From
(Select
'A' As Col1, 1 As Col2, 'Aa' As Col3
Union All
Select
'A', 2, 'Bb'
Union All
Select
'A',1,'Aa'
Union All
Select
'A',4,'Bb'
Union All
Select
'B',2,'Bb'
Union All
Select
'C',1,'Aa'
Union All
Select
'C',5,'Bb'
Union All
Select
'D',3,'Aa'
) T
Inner Join
(Select
Col1
,Sum(Case When Col3 = 'Aa' Then 1 Else 0 End) As CountAa
From
(Select
'A' As Col1, 1 As Col2, 'Aa' As Col3
Union All
Select
'A', 2, 'Bb'
Union All
Select
'A',1,'Aa'
Union All
Select
'A',4,'Bb'
Union All
Select
'B',2,'Bb'
Union All
Select
'C',1,'Aa'
Union All
Select
'C',5,'Bb'
Union All
Select
'D',3,'Aa'
) T2
Group By
Col1
) T3 On T.Col1 = T3.Col1
Where
T3.CountAa > 0
Simplified with a table, thats:
Select
T.*
From
YourTable T
Inner Join
(Select
Col1
,Sum(Case When Col3 = 'Aa' Then 1 Else 0 End) As CountAa
From
YourTable T2
Group By
Col1
) T3 On T.Col1 = T3.Col1
Where
T3.CountAa > 0
The nice thing about this method is that you can add in lots of conditions in that case statement on a more complicated data set.
Depending on what your actual data looks like, row_number() may be another possibility:
select Col1, Col2, Col3
from (
select *, i = row_number() over(partition by Col1 order by Col1, Col3)
from TableName
) a
where i > 1 or Col3 like 'Aa'
Related
Table A
Table B
Table C
Table D
Desired results
Thank you in advance for any assistance provided to achieve the desired results in this case. My goal is to stitch multiple tables together in this manner assuming my database is not able to support the use os a FULL JOIN Statement.
You can emulate a full join with union all and conditional aggregation:
select
id,
coalesce(max(case when idx = 1 then col end), '0') col1,
coalesce(max(case when idx = 2 then col end), '0') col2,
coalesce(max(case when idx = 3 then col end), '0') col3,
coalesce(max(case when idx = 4 then col end), '0') col4
from (
select id, 1 idx, col1 col from table1
union all select id, 2, col2 from table2
union all select id, 3, col3 from table3
union all select id, 4, col4 from table4
) t
group by id
order by id
UNION ALL the tables, put each column in right position. GROUP BY the result.
select id, max(col1), max(col2), max(col3), max(col4)
from
(
select id, col1, null as col2, null as col3, null as col4 from tableA
union all
select id, null, col2, null, null from tableB
union all
select id, null, null, col3, null from tableC
union all
select id, null, null, null, col4 from tableD
) dt
group by id
If you need '0' in the result instead of the null values, use COALESCE()
select id, coalesce(max(col1),'0'), ...
You can use UNION ALL to get 1 result set that has all 4 combined.
Then from that you can group by the ID.
And use conditional aggregation to pivot the COL values on the table sources.
SELECT ID
, MAX(CASE WHEN Src = 1 THEN Col ELSE '0' END) AS COL1
, MAX(CASE WHEN Src = 2 THEN Col ELSE '0' END) AS COL2
, MAX(CASE WHEN Src = 3 THEN Col ELSE '0' END) AS COL3
, MAX(CASE WHEN Src = 4 THEN Col ELSE '0' END) AS COL4
FROM
(
SELECT ID, 1 AS Src, COL1 AS Col
FROM TableA
UNION ALL
SELECT ID, 2, COL2
FROM TableB
UNION ALL
SELECT ID, 3, COL3
FROM TableC
UNION ALL
SELECT ID, 4, COL4
FROM TableD
) q
GROUP BY ID
ORDER BY ID
This will do it.
Select
coalesce(Col1, '0') as Col1,
coalesce(Col2, '0') as Col2,
coalesce(Col3, '0') as Col3,
coalesce(Col4, '0') as Col4
(
select ID from TableA union
select ID from TableB union
select ID from TableC union
select ID from TableD
) TbLID
left join TableA on TableA.ID = TbLID.ID
left join TableB on TableB.ID = TbLID.ID
left join TableC on TableC.ID = TbLID.ID
left join TableD on TableD.ID = TbLID.ID
As a part of output from my joins in SP is like :
Col1 col2
A 1
B 1
C 2
C 1
I have another table that has all the possible values in Col1 (A,B,C,D,E,F) [The values are not known and as best practice I don't want to hardcode these values. ]
Expected output in SQL is as shown below
Col1 1 2
A Yes No/Null
B Yes No
C Yes Yes
D No No
E No No
F No No
Appreciate the help I have relatively less experience in SQL and would appreciate if someone could help me understand how I can achieve this.
You can do JOIN with conditional aggregation :
with cte as (
< query >
)
select c.col1,
max(case when t1.col2 = 1 then 'Yes' end),
max(case when t1.col2 = 2 then 'Yes' end)
from cte c LEFT JOIN
table t1
on t1.col1 = c.col1
group by c.col1;
Following SQL pivot query can be used if you can use '1/0' instead of 'YES/NO'
select
*
from (
select
letters.col1, mydata.col2
from (
select 'A' as col1 union all select 'B' union all select 'C' union all select 'D' union all select 'E' union all select 'F'
) letters
left join (
select 'A' as col1, 1 as col2 union all
select 'B' as col1, 1 as col2 union all
select 'C' as col1, 2 as col2 union all
select 'C' as col1, 1 as col2
) mydata
on mydata.col1 = letters.col1
) data
PIVOT (
count( col2 )
FOR col2
IN (
[1],[2]
)
) PivotTable
WE have below data in oracle database -
col1 col2
Z1 A
Z1 B
Z2 A
Z2 C
Z3 A
Z4 D
I want count on column two in such a way that -
Ouput -
col2 count
A 3 (Z1,Z2,Z3)
B 0 (Dont count if A is already present for record)
C 0
D 1 (Z4)
Best Regards
You can use window function rank() to achieve this.
select col2, count(case when rn = 1 then 1 end) cnt from (
select t.*,
rank() over (partition by col1 order by case when col2 = 'A' then 1 else 2 end) rn
from table t
) group by col2;
The most general solution to your propositions where each key COL1 is counted only in the first occurrence of the key COL2 (in alphabetical order)
WITH tab AS
(
SELECT 'Z1' col1, 'A' col2 FROM dual UNION ALL
SELECT 'Z1' col1, 'B' col2 FROM dual UNION ALL
SELECT 'Z2' col1, 'A' col2 FROM dual UNION ALL
SELECT 'Z2' col1, 'C' col2 FROM dual UNION ALL
SELECT 'Z3' col1, 'A' col2 FROM dual UNION ALL
SELECT 'Z4' col1, 'D' col2 FROM dual
), tab2 as (
select COL1, COL2,
row_number() over (partition by COL1 order by COL2) as rn
from tab)
select COL1, COL2,
case when rn = 1 then 1 else 0 end is_valid
from tab2
order by 1,2
;
COL1 COL2 IS_VALID
---- ---- ----------
Z1 A 1
Z1 B 0
Z2 A 1
Z2 C 0
Z3 A 1
Z4 D 1
The rest is simple group by with a SUM on IS_VALID
select COL2, sum(is_valid) cnt from tab3 -- TAB3 is the above row source
group by COL2
order by 1
COL2 CNT
---- ----------
A 3
B 0
C 0
D 1
Thanks Guys. But I could do this way -
select count(case
when (LISTAGG(col2,'-') WITHIN GROUP (ORDER BY col2)) like '%A%' then 1
else null
end) A,
count(case
when (LISTAGG(col2,'-') WITHIN GROUP (ORDER BY col2)) = 'B' then 1
else null
end) B,
count(case
when (LISTAGG(col2,'-') WITHIN GROUP (ORDER BY col2)) = 'C' then 1
else null
end) C,
count(case
when (LISTAGG(col2,'-') WITHIN GROUP (ORDER BY col2)) = 'D' then 1
else null
end) D
from T
GROUP BY col1
Thanks for your replies
Assume your table name is table_name, One way to do it is using this:
WITH table_a AS
(
SELECT DISTINCT col1
FROM table_name
WHERE col2 = 'A'
)
SELECT col2,
SUM(CASE WHEN col1 IN (SELECT col1 FROM table_a)
THEN DECODE(col2, 'A', 1, 0)
ELSE 1 END
) count
FROM table_name
GROUP BY col2
ORDER BY col2;
Tested ok:
WITH table_name AS
(
SELECT 'Z1' col1, 'A' col2 FROM dual UNION ALL
SELECT 'Z1' col1, 'B' col2 FROM dual UNION ALL
SELECT 'Z2' col1, 'A' col2 FROM dual UNION ALL
SELECT 'Z2' col1, 'C' col2 FROM dual UNION ALL
SELECT 'Z3' col1, 'A' col2 FROM dual UNION ALL
--SELECT 'Z4' col1, 'B' col2 FROM dual UNION ALL
SELECT 'Z4' col1, 'D' col2 FROM dual
)
, table_a AS
(
SELECT DISTINCT col1
FROM table_name
WHERE col2 = 'A'
)
SELECT col2,
SUM(CASE WHEN col1 IN (SELECT col1 FROM table_a)
THEN DECODE(col2, 'A', 1, 0)
ELSE 1 END
) count
FROM table_name
GROUP BY col2
ORDER BY col2;
You want to count each record where either col2 is 'A' or no 'A' record exists for col1.
select
col2,
count(
case
when col2 = 'A' or col1 not in (select col1 from table_name where col2 = 'A') then 1
end) as cnt
from table_name
group by col2;
select col2, count(case when col2 = col3 then 'x' end) as ct
from ( select col2, min(col2) over (partition by col1) as col3
from your_table
)
group by col2
order by col2 -- if needed
;
Explanation:
There is an inner query (a.k.a. "subquery") which returns one row for each row in the original table. It returns col2 as is, and an additional (new) column, labeled col3. col3 is calculated as the "first" or min() value of col2 (in alphabetical order) for all the rows in the original table that have the same value in col1 as the current row does. This is a typical example of an analytic function; partition by col1 is similar to group by col1 but it returns all the rows in the group (all the original rows from the original table) instead of one row per group, as would an aggregate function.
To see what the inner query does by itself, select it and run it in your favorite front-end. You may add col1 to the select in the inner query - that will make what's going on in this query even clearer. You'll get the initial table, with one more column, col3, that shows the "min" col2 for each value of col1. I didn't include col1 in the subquery because I don't need it, but add it back to see what the subquery really does.
Then in the outer query I take the results from the inner query and I group by col2. For each col2 I count just how many times it is equal to the "min" value of col2 for the corresponding col1 value. That's what the case expression does in the count() function; when col2 is not equal to col3, then case returns null (by default) so the expression - and therefore the row - is not counted.
I should add that the query written this way assumes there are no duplicate (col1, col2) rows in the original table. If there are, then the inner subquery should select from a sub-subquery; line 3 of my code should be
from (select distinct col1, col2 from your_table)
Use the below script:
SELECT A.COL2, NVL(B.CNT, 0) AS CNT
FROM (SELECT DISTINCT COL2 FROM TET) A
LEFT JOIN (SELECT COL2, COUNT(COL2) AS CNT
FROM (SELECT SUBSTR(F, 1, INSTR(F, ',') - 1) AS COL2,
ROW_NUMBER() OVER(PARTITION BY SUBSTR(F, 1, INSTR(F, ',') - 1) ORDER BY SUBSTR(F, 1, INSTR(F, ',') - 1)) AS U
FROM (SELECT COL1,
LISTAGG(COL2, ',') WITHIN GROUP(ORDER BY COL2) || ',' AS F
FROM TET
GROUP BY COL1)) A
GROUP BY COL2) B
ON A.COL2 = B.COL2
ORDER BY A.COL2;
I have the following table;
column 1 column 2 column 3
1 2 X
1 2 X
1 2 Y
1 3 Z
1 3 X
I need to write an SQL query to get the output as;
1 2 X (because X is the maximum occurrence)
1 3 Z or X(because number of occurrence of Z or X is same)
How do i do this ?
I think i have a solution for you, try this script using the functions RANK(), ROW_NUMBER() & DENSE_RANK(), you choose the function that fits with your needs :
with temp as (
select 1 as col1, 2 AS col2, 'X' as col3 union all
select 1 as col1, 2 AS col2, 'Y' as col3 union all
select 1 as col1, 2 AS col2, 'X' as col3 union all
select 1 as col1, 3 AS col2, 'Z' as col3 union all
select 1 as col1, 3 AS col2, 'T' as col3 union all
select 1 as col1, 3 AS col2, 'Y' as col3 union all
select 1 as col1, 3 AS col2, 'Y' as col3 union all
select 1 as col1, 4 AS col2, 'Y' as col3 union all
select 1 as col1, 4 AS col2, 'W' as col3)
,temp2 AS (
select
col1
,col2
,col3
,COUNT(1) nb_occurence
,RANK() OVER(PARTITION BY col1,col2 ORDER BY COUNT(1) DESC) Ordre_RANK
,ROW_NUMBER() OVER(PARTITION BY col1,col2 ORDER BY COUNT(1) DESC) Ordre_ROW_NUMBER
,DENSE_RANK() OVER(PARTITION BY col1,col2 ORDER BY COUNT(1) DESC) Ordre_DENSE_RANK
from temp
GROUP BY
col1
,col2
,col3 )
SELECT *
FROM temp2
--WHERE Ordre_RANK = 1
--WHERE Ordre_ROW_NUMBER = 1
--WHERE Ordre_DENSE_RANK = 1
I hope this will help you.
Here is my sample table
Col1 Col2
A 1
B 1
A 1
B 2
C 3
I want to be able to select distinct records where all rows have the same value in Col1 and Col2. So my answer should be
Col1 Col2
A 1
C 3
I tried
SELECT Col1, Col2 FROM Table GROUP BY Col1, Col2
This gives me
Col1 Col2
A 1
B 1
B 2
C 3
which is not the result I am looking for. Any tips would be appreciated.
Try this out:
SELECT col1, MAX(col2) aCol2 FROM t
GROUP BY col1
HAVING COUNT(DISTINCT col2) = 1
Output:
| COL1 | ACOL2 |
|------|-------|
| A | 1 |
| C | 3 |
Fiddle here.
Basically, this makes sure that amount the different values for col2 are unique for a given col1.
Try this:
SELECT * FROM MYTABLE
GROUP BY Col1, Col2
HAVING COUNT(*)>1
For example SQLFiddle here
you can try either of the below -
select col1, col2 from
(
select 'A' Col1 , 1 Col2
from dual
union all
select 'B' , 1
from dual
union all
select 'A' ,1
from dual
union all
select 'B' ,2
from dual
)
group by col1, col2
having count(*) >1;
OR
select col1, col2
from
(
select col1, col2, row_number() over (partition by col1, col2 order by col1, col2) cnt
from
(
select 'A' Col1 , 1 Col2
from dual
union all
select 'B' , 1
from dual
union all
select 'A' ,1
from dual
union all
select 'B' ,2
from dual
)
)
where cnt>1;