I need to select records that has ID = 10,23,30 so I wrote this SQL
Select * from mytable where position(id in '10,23,30') > 0
But the problem I get additional records where ID = 1 and 2
Any ideas how to select only what I need ?
No need for position, just do IN:
Select * from mytable
where id in (10,23,30)
Use IN operator:
Select * from mytable where id in (10,23,30)
Related
I try something like
SELECT * FROM table WHERE aspect_id = (SELECT floor(random(aspect_id)::int FROM generate_series(1,8));
and I want to get several aspect_id from table.
Or I try to
SELECT * FROM table WHERE aspect_id = SELECT random_between(1,100) FROM generate_series(1,5);
But still nothing
Could you help me?
What about
SELECT * FROM atable
WHERE aspect_id BETWEEN 1 AND 100
ORDER BY random()
LIMIT 5;
My table looks something like this:
I want to retrieve all the PractitionerIdFK if they have SpecialityIdFK = 1 AND SpecialityIdFK= 2. I tried the following but it doesn't seem to work.
SELECT PractitionerSpecialities.PractitionerIdFK
FROM PractitionerSpecialities
WHERE PractitionerSpecialities.SpecialityIdFK IN (
SELECT PractitionerSpecialities.SpecialityIdFK
FROM PractitionerSpecialities
WHERE PractitionerSpecialities.SpecialityIdFK = 1
AND PractitionerSpecialities.SpecialityIdFK = 2
)
You can use GROUP BY and HAVING:
SELECT ps.PractitionerIdFK
FROM PractitionerSpecialities ps
WHERE ps.SpecialityIdFK IN (1, 2)
GROUP BY ps.PractitionerIdFK
HAVING COUNT(*) = 2; -- the size of the comparison list
This assumes that there are no duplicates in PractitionerSpecialities. If that is a possibility, then use HAVING COUNT(DISTINCT ps.SpecialityIdFK) = 2.
It can be achieved by using IN and BETWEEN operator in SQL .
SELECT PractitionerSpecialities.PractitionerIdFK
FROM PractitionerSpecialities
WHERE PractitionerSpecialities.SpecialityIdFK in (1,2)
-- You can BETWEEN Clause as well ..
SELECT PractitionerSpecialities.PractitionerIdFK
FROM PractitionerSpecialities
WHERE PractitionerSpecialities.SpecialityIdFK BETWEEN 1 AND 2
In Sub query use OR operator instead of AND .
I have a select query that returns multiple rows, and I want to check if all rows are the same. So something like this:
anything_other_than(123) in (select id from foo)
So, if select id from foo returns 111,222,123,333 the statement above is false, and if select id from foo returns 123,123,123 it's true. How can I achieve this?
A simple solution is to use the = ALL operator:
SELECT 123 = ALL (SELECT id FROM foo);
This solution also stop scanning the result as soon as the first non-matching value is found.
Another option is to use EXISTS with a where condition:
select not exists (select *
from the_table
where id <> 123);
Run this:
select count(distinct id) = 1 and count(*) > 1 from foo;
count(distinct id) will return 1 if all the rows are the same
and count(*) will return the total number of rows.
If this returns true then you have more than 1 rows and all the rows are the same.
You can use something like this -
select x, IF(x > 1, "FALSE", "TRUE") from
(SELECT count(distinct(A.id)) as x FROM foo as A) as B;
Do refer this https://www.w3schools.com/sql/func_mysql_if.asp
I have a sql query that I run against a sql server database eg.
SELECT * FROM MyTable WHERE Id = 2
This may return a number of records or may return none. If it returns none, I would like to alter my sql query to return a default record, is this possible and if so, how? If records are returned, the default record should not be returned. I cannot update the data so will need to alter the sql query for this.
Another way (you would get an empty initial rowset returned);
SELECT * FROM MyTable WHERE Id = 2
IF (##ROWCOUNT = 0)
SELECT ...
SELECT TOP 1 * FROM (
SELECT ID,1 as Flag FROM MyTable WHERE Id = 2
UNION ALL
SELECT 1,2
) qry
ORDER BY qry.Flag ASC
You can have a look to this post. It is similar to what you are asking
Return a value if no rows are found SQL
I hope that it can guide you to the correct path.
if not exists (SELECT top 1 * FROM mytable WHERE id = 2)
select * from mytable where id= 'whatever_the_default_id_is'
else
select * from mytable where id = 2
If you have to return whole rows of data (and not just a single column) and you have to create a single SQL query then do this:
Left join actual table to defaults single-row table
select
coalesce(a.col1, d.col1) as col1,
coalesce(a.col2, d.col2) as col2,
...
from (
-- your defaults record
select
default1 as col1,
default2 as col2,
...) as d
left join actual as a
on ((1 = 1) /* or any actual table "where" conditions */)
The query need to return the same number of fields, so you shouldn't do a SELECT * FROM but a SELECT value FROM if you want to return a default value.
With that in mind
SELECT value FROM MyTable WHERE Id = 2
UNION
SELECT CASE (SELECT count(*) FROM MyTable WHERE Id = 2)
WHEN 0 THEN 'defaultvalue'
END
Probably it has been asked before but I cannot find an answer.
Table Data has two columns:
Source Dest
1 2
1 2
2 1
3 1
I trying to come up with a MS Access 2003 SQL query that will return:
1 2
3 1
But all to no avail. Please help!
UPDATE: exactly, I'm trying to exclude 2,1 because 1,2 already included. I need only unique combinations where sequence doesn't matter.
For Ms Access you can try
SELECT DISTINCT
*
FROM Table1 tM
WHERE NOT EXISTS(SELECT 1 FROM Table1 t WHERE tM.Source = t.Dest AND tM.Dest = t.Source AND tm.Source > t.Source)
EDIT:
Example with table Data, which is the same...
SELECT DISTINCT
*
FROM Data tM
WHERE NOT EXISTS(SELECT 1 FROM Data t WHERE tM.Source = t.Dest AND tM.Dest = t.Source AND tm.Source > t.Source)
or (Nice and Access Formatted...)
SELECT DISTINCT *
FROM Data AS tM
WHERE (((Exists (SELECT 1 FROM Data t WHERE tM.Source = t.Dest AND tM.Dest = t.Source AND tm.Source > t.Source))=False));
your question is asked incorrectly. "unique combinations" are all of your records. but i think you mean one line per each Source. so it is:
SELECT *
FROM tab t1
WHERE t1.Dest IN
(
SELECT TOP 1 DISTINCT t2.Dest
FROM tab t2
WHERE t1.Source = t2.Source
)
SELECT t1.* FROM
(SELECT
LEAST(Source, Dest) AS min_val,
GREATEST(Source, Dest) AS max_val
FROM table_name) AS t1
GROUP BY t1.min_val, t1.max_val
Will return
1, 2
1, 3
in MySQL.
To eliminate duplicates, "select distinct" is easier than "group by":
select distinct source,dest from data;
EDIT: I see now that you're trying to get unique combinations (don't include both 1,2 and 2,1). You can do that like:
select distinct source,dest from data
minus
select dest,source from data where source < dest
The "minus" flips the order around and eliminates cases where you already have a match; the "where source < dest" keeps you from removing both (1,2) and (2,1)
Use this query :
SELECT distinct * from tabval ;