Get Distinct results of all columns based on MAX DATE of one - sql

Question

Using SQL Server 2012
I have seen a few threads about this topic but I can't find one that involves multiple joins in the query. I can't create a VIEW on this database so the joins are needed.
The Query
SELECT
p.Price
,s.Type
,s.Symbol
, MAX(d.Date) Maxed
FROM AdventDW.dbo.FactPrices p
INNER JOIN dbo.DimSecurityMaster s
ON s.SecurityID = p.SecurityID
INNER JOIN dbo.DimDateTime d
ON
p.DateTimeKey = d.DateTimeKey
GROUP BY p.Price ,
s.Type ,
s.Symbol
ORDER BY s.Symbol
The query works but does not produce distinct results. I am using Order by to validate the results, but it is not required once I get it working. I The result set looks like this.
Price Type Symbol Maxed
10.57 bfus *bbkd 3/31/1989
10.77 bfus *bbkd 2/28/1990
100.74049 cbus 001397AA6 8/2/2005
100.8161 cbus 001397AA6 7/21/2005
The result set I want is
Price Type Symbol Maxed
10.77 bfus *bbkd 2/28/1990
100.74049 cbus 001397AA6 8/2/2005
Here were a few other StackOverflow threads I tried but couldn't get t work with my specific query
How can I SELECT rows with MAX(Column value), DISTINCT by another column in SQL?
SQL Selecting distinct rows from multiple columns based on max value in one column

Answer 1

If you want data for the maximum date, use row_number() rather than group by:
SELECT ts.*
FROM (SELECT p.Price, s.Type, s.Symbol, d.Date,
ROW_NUMBER() OVER (PARTITION BY s.Type, s.Symbol
ORDER BY d.Date DESC
) as seqnum
FROM AdventDW.dbo.FactPrices p INNER JOIN
dbo.DimSecurityMaster s
ON s.SecurityID = p.SecurityID INNER JOIN
dbo.DimDateTime d
ON p.DateTimeKey = d.DateTimeKey
) ts
WHERE seqnum = 1
ORDER BY s.Symbol;

Answer 2

You should use a derived table since you really only want to group the DateTimeKey table to get the MAX date.
SELECT p.Price ,
s.Type ,
s.Symbol ,
tmp.MaxDate
FROM AdventDW.dbo.FactPrices p
INNER JOIN dbo.DimSecurityMaster s ON s.SecurityID = p.SecurityID
INNER JOIN
( SELECT MAX(d.Date) AS MaxDate ,
d.DateTimeKey
FROM dbo.DimDateTime d
GROUP BY d.DateTimeKey ) tmp ON p.DateTimeKey = tmp.DateTimeKey
ORDER BY s.Symbol;

Answer 3

/*
this is your initial select which is fine because this is base from your original criteria,
I cannot ignore this so i'll keep this in-tact. Instead from here i'll create a temp
*/
SELECT
p.Price
, s.Type
, s.Symbol
, MAX(d.Date) Maxed
INTO #tmpT
FROM AdventDW.dbo.FactPrices p
INNER JOIN dbo.DimSecurityMaster s
ON s.SecurityID = p.SecurityID
INNER JOIN dbo.DimDateTime d
ON p.DateTimeKey = d.DateTimeKey
GROUP BY p.Price ,
s.Type ,
s.Symbol
ORDER BY s.Symbol
SELECT innerTable.Price, innerTable.Symbol, innerTable.Type, innerTable.Maxed
FROM (
SELECT
ROW_NUMBER () OVER (PARTITION BY t1.Symbol, t1.Type, t1.Maxed ORDER BY t1.Maxed DESC) as row
, *
FROM #tmpT AS t1
) AS innerTable
WHERE row = 1
DROP TABLE #tmpT