How to get number of the same members in mdx? - sql

Question

I would like to determine the number of particular weekdays (e.g. Mondays, Tuesdays, and so on....) between two dates. I thought something like the following should work, but member returns 1.
What have i done wrong?
WITH
MEMBER measures.NumberOfSameWeekDays AS
Count([Dim Date].[Day Of Week].CurrentMember)
SELECT
measures.NumberOfSameWeekDays ON COLUMNS
,[Dim Date].[Day Of Week].[Day Of Week] ON ROWS
FROM [test]
WHERE
(
[Dim Client].[Common Client UID].&[{ED8822E7-2873-4388-BC3A-CC553D939FC4}]
,
[Dim Date].[Date Int].&[20150701] : [Dim Date].[Date Int].&[20150731]
);

Answer 1

This is a proof of what is happening:
WITH
MEMBER measures.NumberOfSameWeekDays AS
Count([Date].[Day of Week].CurrentMember)
MEMBER measures.WeekDayCurrentMem AS
[Date].[Day of Week].CurrentMember.Member_Caption
SELECT
{
measures.NumberOfSameWeekDays
,measures.WeekDayCurrentMem
} ON COLUMNS
,[Date].[Day of Week].[Day of Week] ON ROWS
FROM [Adventure Works]
WHERE
[Date].[Calendar].[Date].&[20050101]
:
[Date].[Calendar].[Date].&[20050116];
Here is the result of the above:
Here is a solution to the above behaviour:
WITH
MEMBER measures.NumberOfSameWeekDays AS
Count
(
(EXISTING
[Date].[Day of Week].CurrentMember * [Date].[Calendar].[Date])
)
SELECT
{
measures.NumberOfSameWeekDays
} ON COLUMNS
,[Date].[Day of Week].[Day of Week] ON ROWS
FROM [Adventure Works]
WHERE
[Date].[Calendar].[Date].&[20050101]
:
[Date].[Calendar].[Date].&[20050131];
This returns the following:
A simplified version of Sourav's answer - although still rather complex - and potentially slow as it uses Generate which is iterative:
WITH
MEMBER Measures.CountOfDays AS
Generate
(
(EXISTING
[Date].[Date].[Date].MEMBERS)
,[Date].[Day of Week]
,ALL
).Count
SELECT
Measures.CountOfDays ON 0
,[Date].[Day of Week].[Day of Week].MEMBERS ON 1
FROM [Adventure Works]
WHERE
[Date].[Calendar].&[2005] : [Date].[Calendar].&[2006];

Answer 2

Adventure Works version:
WITH MEMBER Measures.CountOfDays AS
GENERATE
(
EXISTING [Date].[Date].[Date].MEMBERS,
EXISTING [Date].[Day of Week].[Day of Week].MEMBERS
,ALL
).COUNT
SELECT Measures.CountOfDays ON 0
,[Date].[Day of Week].[Day of Week].MEMBERS ON 1
FROM [Adventure Works]
WHERE [Date].[Calendar].&[2005]: [Date].[Calendar].&[2006]
The GENERATE part gets all the days of weeks in current context and based on whatever filter you might have.