I've used this site for assistance many times but never had to ask a question so finally joined...anyway, trying to set up simplecart checkout and having some trouble formatting cart output. I have my cart set to table and by default the simpleCart_items class displays the table and it's cells only as wide as they need be to fit the data. I can change this by specifying all cells(columns) as a percentage of the whole table. Unfortunately with 7 columns each only gets about 14% and this is way to much for a 1 or 2 digit quantity and not near big enough for all the characters in the item name without wrapping. What I want is a way to define a different width for each column. I have not found a way to do this even with colgroup but maybe just not doing it right. Any and all help would be appreciated!
Okay, so this may or may not help. This line is located in the simpleCart.js file. I changed it to something simple.
cartColumns : [
{ view: function(item, column){
return"<img src='"+item.get('image')+"' width='250px' height='250px'><br /><center><h3 ><span>"+item.get('name')+"</span></h3><p><a href='javascript:;' class='simpleCart_decrement'><button>-</button></a> "+item.get('quantity')+" <a href='javascript:;' class='simpleCart_increment'><button>+</button></a></p><p>$"+item.get('price')+"</p><p><a href='javascript:;' class='simpleCart_remove remove_icon'><img src='images/icon_x.png' /></a></p></center>";
},
}
],
You can change it to your own html
cartColumns : [
{ view: function(item, column){
return" YOUR HTML HERE ";
},
}
],
It MUST all be in ONE (1) LINE or else it may not work.
here are some values that are used
image = item.get('image')
name = item.get('name')
quantity = item.get('quantity')
price = item.get('price')
you can look at all the values here
http://simplecartjs.org/documentation/displaying_cart_data
but the point is that you can make a cart and display it how you want; with you own html and css. I hope this helped.
Related
See the "Collapse Rows" animated example:
That's similar to what I want to achieve.
I'd like my table to be responsive using the approach of reorganizing itself such that it shows each original row transposed (but also transpose the headers and duplicate them so that they label each row).
ag-Grid seems like a phenomenal library that has countless features, so I was surprised that the docs seem not to specify how to accomplish my goal.
Unfortunately this feature is not available out of the box.
This is actually a feature request which can be found here:
https://www.ag-grid.com/ag-grid-pipeline/
AG-3142 Allow the grid to change columns for rows (transpose rows), so the grid show each row as one column, and each column as a row
To achieve this, you would have to write a function yourself to transpose the rows into one column.
You can then leverage Grid API methods to update the column and row data accordingly.
I've created a simple plunker which does this based on a button click:
function onBtnClick() {
let newColumnDefs = [{ field: 'transposed_rows' }];
let newRowData = [];
gridOptions.api.forEachNode((node) => {
let nodeDataValues = Object.values(node.data);
nodeDataValues.forEach((val) => newRowData.push({ transposed_rows: val }));
});
gridOptions.api.setColumnDefs(newColumnDefs);
gridOptions.api.setRowData(newRowData);
}
I need to know can there be a tooltip populated with data from database to be displayed in the tooltip.
something like the tooltip should contain
name stauts
abc active
xyz active
pqr active
name and status are retrived from db
I need this tooltip onmouseover, am using CJSON decoded to render the content
i did go google but hardly did find that i would throughly understand and implement.
can anyone out there has any ideas for what am looking.
There is a extension named yii-bootstrap, which described clearly here.
For using tooltip easily in this extension, just look here.
I use cluetip for this. Its not related to Yii but will give you some idea :
JS
function renderInfoTips(opts){
var elements=$('#'+opts.form).get(0).elements;
for(i=0; i<opts.tips.length;i++){
$(elements[opts.tips[i].field]).parent().prepend(opts.tips[i].tip);
}
var clue_opts={arrows:true,splitTitle: '|',closePosition: 'title',sticky:true,dropShadow:false,mouseOutClose:true,
onShow:function(ct, ci){
if(!$.browser.webkit) $(ct).css('top',$(ct).position().top- 30+'px');
}
}
$('#'+opts.form).find(".infotip").cluetip(clue_opts);
}
PHP
function setInfoTipsJavascript($form_id,infotips){
if (count($this->infotips) <1 ) return '';
//get all tip names
$names_csv=join(',',array_keys(infotips));
//get tips details from db
$query="select name, description from infotips where FIND_IN_SET(name ,'$names_csv')";
//run the query, in Yii you have to use InfoTipsModel , I have skipped that portion
//$infotipS , lets say this is query object
$tips=array();
while($tip=$infotipS->Assoc()){
$this->infotips[$tip['name']]['tip']="<a href='javascript:void(0)' class='infotip' title='|{$tip['description']}'> </a>";
$tips[]=$this->infotips[$tip['name']];
}
$tips=json_encode($tips);
$script="\nrenderInfoTips({\"form\":'{$form_id}', \"tips\":{$tips}});\n\n";
echo $script;
}
I am sharing this hoping this will give u some idea. Its obvious you have to : create infotips table, a model for that, and create a widget etc to fetch infotips related to your form fields . As someone suggested, if you are using Bootstrap, you have better way to do that.
I can't seem to find a way to require the filtering select input to be of a certain length. I've tried like this:
new dijit.form.FilteringSelect({
'name': 'bla',
'store': jsonRestStore,
'searchAttr': "name",
'pattern': '.{3,}',
'regExp': '.{3,}'
});
but it doesn't change a thing. I want the filtering select to only query the store, if at least 3 characters have been entered. Can't be that exotic a requirement, can it? There are thousands of items behind that store, so querying that with just 1 or 2 characters is slow.
I did a bit more searching and found this post on the dojo mailing list. To summarize, there is no way to native support in the FilteringSelect for it, but it is extremely easy to implement.
// custom min input character count to trigger search
minKeyCount: 3,
// override search method, count the input length
_startSearch: function (/*String*/key) {
if (!key || key.length < this.minKeyCount) {
this.closeDropDown();
return;
}
this.inherited(arguments);
}
Also in the API Docs, there is a searchDelay attribute, which could be helpful in minimizes the number of queries.
searchDelay
Delay in milliseconds between when user types something and we start searching based on that value
How can i add additional information to the Magento Packingslip PDF. I am using integrated label paper, so i would like to add repeat the customers delivery address at the footer and also, some details like total quantity of items in the order and the cost of the items in the order. I am currently modifying local files in: Mage/Sales/Model/Order/Pdf/ but I have only managed to change to font.
EDIT:
Okay, i have made good progress and added most of the information i need, however, i have now stumbled across a problem.. I would like to get the total weight of all items in each order and Quantity.
I am using this code in the shipment.php:
Under the foreach (This is useful in case an order has a split delivery - as you can have one order with multiple "shipments" So this is why I have the code after here:
foreach ($shipment->getAllItems() as $item){
if ($item->getOrderItem()->getParentItem()) {
continue;
...
then I have this further down:
$shippingweight=0;
$shippingweight= $item->getWeight()*$item->getQty();
$page->drawText($shippingweight . Mage::helper('sales'), $x, $y, 'UTF-8');
This is great for Row totals. But not for the whole shipment. What I need to do is have this bit of code "added up" for each item in the shipment to create the total Weight of the whole shipment. It is very important that I only have the total of the shipment - not the order as I will be splitting shipments.
Almost at the end of getPdf(...) in Mage_Sales_Model_Order_Pdf_Shipment you will find the code that inserts new pages (lines 93-94 in 1.5.0.1)
if($this->y<15)
$page = $this->newPage(....)
happening in a for-loop.
You can change the logic here to make it change page earlier to make room for your extra information and then add it before the page shift. You should also place code after the for-block if you want it to appear on the last page as well.
Note: You should not change files in app/code/code/Mage directly. Instead, you should place your changed files under app/code/local/Mage using the same folder structure. That way your changes won't accidently get overwritten in an upgrade.
This should get you the total number of items in your order (there might be a faster way but don't know it off the top of my head):
$quote = Mage::getModel('sales/quote')->load($order->getQuoteId());
$itemsCount = $quote->getItemsSummaryQty();
For invoice PDF
at app/code/local/Mage/Sales/Model/Order/Pdf/Items/Invoice/Default.php
add this before $lineBlock
$product = Mage::getModel('catalog/product')->loadByAttribute('sku', $this->getSku($item), array('weight'));
$lines[][] = array(
'text' => 'Weight: '. $product->getData('weight')*1 .'Kg/ea. Total: ' .$product->getData('weight')*$item->getQty() . 'Kg',
'feed' => 400
);
I use jqGrid to display data which is retrieved using NHibernate. jqGrid does paging for me, I just tell NHibernate to get "count" rows starting from "n".
Also, I would like to highlight specific record. For example, in list of employees I'd like a specific employee (id) to be shown and pre-selected in table.
The problem is that this employee may be on non-current page. E.g. I display 20 rows from 0, but "highlighted" employee is #25 and is on second page.
It is possible to pass initial page to jqGrid, so, if I somehow use NHibernate to find what page the "highlighted" employee is on, it will just navigate to that page and then I'll use .setSelection(id) method of jqGrid.
So, the problem is narrowed down to this one: given specific search query like the one below, how do I tell NHibernate to calculate the page where the "highlighted" employee is?
A sample query (simplified):
var query = Session.CreateCriteria<T>();
foreach (var sr in request.SearchFields)
query = query.Add(Expression.Like(sr.Key, "%" + sr.Value + "%"));
query.SetFirstResult((request.Page - 1) * request.Rows)
query.SetMaxResults(request.Rows)
Here, I need to alter (calculate) request.Page so that it points to the page where request.SelectedId is.
Also, one interesting thing is, if sort order is not defined, will I get the same results when I run the search query twice? I'd say that SQL Server may optimize query because order is not defined... in which case I'll only get predictable result if I pull ALL query data once, and then will programmatically in C# slice the specified portion of query results - so that no second query occur. But it will be much slower, of course.
Or, is there another way?
Pretty sure you'd have to figure out the page with another query. This would surely require you to define the column to order by. You'll need to get the order by and restriction working together to count the rows before that particular id. Once you have the number of rows before your id, you can figure what page you need to select and perform the usual paging query.
OK, so currently I do this:
var iquery = GetPagedCriteria<T>(request, true)
.SetProjection(Projections.Property("Id"));
var ids = iquery.List<Guid>();
var index = ids.IndexOf(new Guid(request.SelectedId));
if (index >= 0)
request.Page = index / request.Rows + 1;
and in jqGrid setup options
url: "${Url.Href<MyController>(c => c.JsonIndex(null))}?_SelectedId=${Id}",
// remove _SelectedId from url once loaded because we only need to find its page once
gridComplete: function() {
$("#grid").setGridParam({url: "${Url.Href<MyController>(c => c.JsonIndex(null))}"});
},
loadComplete: function() {
$("#grid").setSelection("${Id}");
}
That is, in request I lookup for index of id and set page if found (jqGrid even understands to display the appropriate page number in the pager because I return the page number to in in json data). In grid setup, I setup url to include the lookup id first, but after grid is loaded I remove it from url so that prev/next buttons work. However I always try to highlight the selected id in the grid.
And of course I always use sorting or the method won't work.
One problem still exists is that I pull all ids from db which is a bit of performance hit. If someone can tell how to find index of the id in the filtered/sorted query I'd accept the answer (since that's the real problem); if no then I'll accept my own answer ;-)
UPDATE: hm, if I sort by id initially I'll be able to use the technique like "SELECT COUNT(*) ... WHERE id < selectedid". This will eliminate the "pull ids" problem... but I'd like to sort by name initially, anyway.
UPDATE: after implemented, I've found a neat side-effect of this technique... when sorting, the active/selected item is preserved ;-) This works if _SelectedId is reset only when page is changed, not when grid is loaded.
UPDATE: here's sources that include the above technique: http://sprokhorenko.blogspot.com/2010/01/jqgrid-mvc-new-version-sources.html