object_tbl:
objId(primary key) | name
1 | A
2 | B
3 | C
document_tbl:
documentId | sourceId
1 | 2
2 | 2
3 | 1
4 | 3
5 | 3
6 | 3
objToDoc_tbl:
id | objectId | documentId
1 | 1 | 2
2 | 2 | 4
3 | 2 | 6
4 | 1 | 5
5 | 3 | 1
6 | 1 | 2
Inner join of all table
A 2 2
B 4 3
B 6 3
A 5 3
C 1 2
A 2 2
A 2
B 1
C 1
so Answer is 1(As A is only 2)
Question: - How many object are related to documents from multiple sources.
How we can write sql query for this or it can only we solved by procedure
You can join all the tables and then use having to get objects with count > 1.
with t as (
select t.name, count(distinct d.sourceid) as count
from objtodoc_tbl o
join document_tbl d on o.documentid = d.documentid
join object_tbl t on o.objectid = t.name
group by t.name
having count(distinct d.sourceid) > 1
)
select count(t.name) from t;
Related
i am working with sql from few days as beginner and stuck at a problem!
Problem:
Given A table user_email_table which columns are (id, user_id, user_id_email)
How to get all user co-related to each and every user extending himself
user_email_table
id | user_id | email_id
1 | 1 | xyz
2 | 2 | xyz2
3 | 3 | xyz3
4 | 4 | xyz4
Desired Output
id | user_id_1 | user_id_2 | user_id_1_email | user_id_2_email |
-----------------------------
1 | 1 | 2 | xyz|xyz2|
1 | 1 | 3 |xyz|xyz3|
1 | 1 | 4 |xyz|xyz4|
1 | 2 | 1 |xyz2|xyz1|
1 | 2 | 3 |xyz2|xyz3|
1 | 2 | 4 |xyz2|xyz4|
1 | 3 | 1 |xyz3|xyz1|
1 | 3 | 2 |xyz3|xyz2|
1 | 3 | 4 |xyz3|xyz4|
1 | 4 | 1 |xy4|xyz1|
1 | 4 | 2 |xyz4|xyz2|
1 | 4 | 3 |xyz4|xyz3|
Please Ignore validate data of email fields This are just for reminding to mention these columns in output-table
What SQL query can result into this table
You want a "cross join" of the table against itself excluding the self-matching rows. You can do:
select
1 as id,
a.user_id as user_id_1,
b.user_id as user_id_2,
a.email_id as user_id_1_email,
b.email_id as user_id_2_email
from user_email_table a
cross join user_email_table b
where a.user_id <> b.user_id
EDIT:
As #IMSoP points out the query can also use a common join with a join predicate and can be rephrased as:
select
1 as id,
a.user_id as user_id_1,
b.user_id as user_id_2,
a.email_id as user_id_1_email,
b.email_id as user_id_2_email
from user_email_table a
join user_email_table b on a.user_id <> b.user_id
I have a table like this
id, period, tag
1 1 A
1 2 A
1 3 B
1 4 A
1 5 A
1 6 A
2 1 A
2 2 B
2 3 B
2 4 B
2 5 B
2 6 A
I would like to add a new column with a ranking, respecting the order of the row given my column 'period' to obtain something like this
id, period, tag rank
1 1 A 1
1 2 A 1
1 3 B 2
1 4 A 3
1 5 A 3
1 6 A 3
2 1 A 1
2 2 B 2
2 3 B 2
2 4 B 2
2 5 B 2
2 6 A 3
What can I do?
I try rank and dense_rank function without any success
And another candidate for CONDITIONAL_CHANGE_EVENT()
less code, and quite effective, too ...!
WITH
input(id,period,tag) AS (
SELECT 1,1,'A'
UNION ALL SELECT 1,2,'A'
UNION ALL SELECT 1,3,'B'
UNION ALL SELECT 1,4,'A'
UNION ALL SELECT 1,5,'A'
UNION ALL SELECT 1,6,'A'
UNION ALL SELECT 2,1,'A'
UNION ALL SELECT 2,2,'B'
UNION ALL SELECT 2,3,'B'
UNION ALL SELECT 2,4,'B'
UNION ALL SELECT 2,5,'B'
UNION ALL SELECT 2,6,'A'
)
SELECT
*
, CONDITIONAL_CHANGE_EVENT(tag) OVER(PARTITION BY id ORDER BY period) + 1 AS rank
FROM input;
-- out id | period | tag | rank
-- out ----+--------+-----+------
-- out 1 | 1 | A | 1
-- out 1 | 2 | A | 1
-- out 1 | 3 | B | 2
-- out 1 | 4 | A | 3
-- out 1 | 5 | A | 3
-- out 1 | 6 | A | 3
-- out 2 | 1 | A | 1
-- out 2 | 2 | B | 2
-- out 2 | 3 | B | 2
-- out 2 | 4 | B | 2
-- out 2 | 5 | B | 2
-- out 2 | 6 | A | 3
-- out (12 rows)
-- out
-- out Time: First fetch (12 rows): 14.823 ms. All rows formatted: 14.874 ms
One method is a cumulative sum based on a lag():
select t.*,
sum(case when prev_tag = tag then 0 else 1 end) over (partition by id order by period) as rank
from (select t.*, lag(tag) over (partition by id order by period) as prev_tag
from t
) t;
I have a problem with my sql join request.
I need to get lines of left table who are not referenced in right table for ME (User 1) or referenced in right table with status equal to 0 and user equal to 1.
I also need the field status of right table.
Here is my two tables :
Table left
ID | title
1 | Title 1
2 | Title 2
3 | Title 3
4 | Title 4
5 | Title 5
6 | Title 6
Table right
ID | status | user | left_id
1 | 0 | 1 | 1
2 | 0 | 50 | 1
3 | 1 | 1 | 2
4 | 0 | 50 | 2
5 | 0 | 1 | 3
6 | 1 | 50 | 3
7 | 0 | 50 | 4
8 | 1 | 50 | 5
My goal is to get this result :
left.ID | left.title | right.status | right.user
1 | Title 1 | 0 | 1
3 | Title 3 | 0 | 1
4 | Title 4 | NULL | NULL
5 | Title 5 | NULL | NULL
6 | Title 6 | NULL | NULL
Here is my request for the moment :
SELECT l.id, l.title, r.user, r.status
FROM left as l
LEFT JOIN right as r ON l.id = r.left_id
WHERE r.left_id IS NULL or (r.user = 1 AND r.status = 0)
With this request I get lines ID (left table) 1 / 3 / 6. But I also need the ID 4 / 5.
Those lines isn't displayed because another user (50) as a reference, but it's not me (1).
If someone can help me to add line 4 / 5 to my result I would be happy.
Thanks
Small improvement of the query should be sufficient:
SELECT l.id, l.title, r.user, r.status
FROM left as l
LEFT JOIN right as r ON l.id = r.left_id and r.user = 1
WHERE r.left_id IS NULL or r.status = 0
(Select t1.id, t1.title,t2.status,t2.user
from tableLeft t1
right outer join tableRight t2 on t2.left_id=t1.id
where t1.id not in
(select tt2.left_id from tableRight tt2)
)
union
(select t1.id,t1.title,t2.status,t2.user
from tableLeft t1
left join tableRight t2 on t1.id=t2.left_id
where t2.status=0 and t2.user=1
)
My question is very similar to Multiple NOT distinct only it deals with multiple columns instead of one. I have a table like so:
A B C
1 1 0
1 2 1
2 1 2
2 1 3
2 2 4
2 3 5
2 3 6
3 1 7
3 3 8
3 1 9
And the result should be:
A B C
2 1 2
2 1 3
2 3 5
2 3 6
3 1 7
3 1 9
Essentially, like the above question, removing all unique entries only where uniqueness is determined by two columns instead of one. I already tried various tweaks to the above answer but couldn't get any of them to work.
You are using SQL Server, so this is easier than in Access:
select A, B, C
from (select t.*, count(*) over (partition by A, B) as cnt
from t
) t
where cnt > 1;
This use of count(*) is as a window function. It is counting the number of rows with the same value of A and B. The final where just selects the rows that have more than one entry.
Another possible solution with EXISTS
SELECT a, b, c
FROM Table1 t
WHERE EXISTS
(
SELECT 1
FROM Table1
WHERE a = t.a
AND b = t.b
AND c <> t.c
)
It should be fast enough.
Output:
| A | B | C |
-------------
| 2 | 1 | 2 |
| 2 | 1 | 3 |
| 2 | 3 | 5 |
| 2 | 3 | 6 |
| 3 | 1 | 7 |
| 3 | 1 | 9 |
Here is SQLFiddle demo
I have three tables
Prospect -- holds prospect information
id
name
projectID
Sample data for Prospect
id | name | projectID
1 | p1 | 1
2 | p2 | 1
3 | p3 | 1
4 | p4 | 2
5 | p5 | 2
6 | p6 | 2
Conjoint -- holds conjoint information
id
title
projectID
Sample data
id | title | projectID
1 | color | 1
2 | size | 1
3 | qual | 1
4 | color | 2
5 | price | 2
6 | weight | 2
There is an associative table that holds the conjoint values for the prospects:
ConjointProspect
id
prospectID
conjointID
value
Sample Data
id | prospectID | conjointID | value
1 | 1 | 1 | 20
2 | 1 | 2 | 30
3 | 1 | 3 | 50
4 | 2 | 1 | 10
5 | 2 | 3 | 40
There are one or more prospects and one or more conjoints in their respective tables. A prospect may or may not have a value for each conjoint.
I'd like to have an SQL statement that will extract all conjoint values for each prospect of a given project, displaying NULL where there is no value for a value that is not present in the ConjointProspect table for a given conjoint and prospect.
Something along the lines of this for projectID = 1
prospectID | conjoint ID | value
1 | 1 | 20
1 | 2 | 30
1 | 3 | 50
2 | 1 | 10
2 | 2 | NULL
2 | 3 | 40
3 | 1 | NULL
3 | 2 | NULL
3 | 3 | NULL
I've tried using an inner join on the prospect and conjoint tables and then a left join on the ConjointProspect, but somewhere I'm getting a cartesian products for prospect/conjoint pairs that don't make any sense (to me)
SELECT p.id, p.name, c.id, c.title, cp.value
FROM prospect p
INNER JOIN conjoint c ON p.projectID = c.projectid
LEFT JOIN conjointProspect cp ON cp.prospectID = p.id
WHERE p.projectID = 2
ORDER BY p.id, c.id
prospectID | conjoint ID | value
1 | 1 | 20
1 | 2 | 30
1 | 3 | 50
1 | 1 | 20
1 | 2 | 30
1 | 3 | 50
1 | 1 | 20
1 | 2 | 30
1 | 3 | 50
2 | 1 | 10
2 | 2 | 40
2 | 1 | 10
2 | 2 | 40
2 | 1 | 10
2 | 2 | 40
3 | 1 | NULL
3 | 2 | NULL
3 | 3 | NULL
Guidance is very much appreciated!!
Then this will work for you... Prejoin a Cartesian against all prospects and elements within that project via a select as your first FROM table. Then, left join to the conjoinprospect. You can obviously change / eliminate certain columns from result, but at least all is there, in the join you want with exact results you are expecting...
SELECT
PJ.*,
CJP.Value
FROM
( SELECT
P.ID ProspectID,
P.Name,
P.ProjectID,
CJ.Title,
CJ.ID ConJointID
FROM
Prospect P,
ConJoint CJ
where
P.ProjectID = 1
AND P.ProjectID = CJ.ProjectID
ORDER BY
1, 4
) PJ
LEFT JOIN conjointProspect cjp
ON PJ.ProspectID = cjp.prospectID
AND PJ.ConjointID = cjp.conjointid
ORDER BY
PJ.ProspectID,
PJ.ConJointID
Your cartesian product is a result of joining by project Id - in your sample data there are 3 prospects with a project id of 1 and 3 conjoints with a project id of 1. Joining based on project id should then result in 9 rows of data, which is what you're getting. It looks like you really need to join via the conjointprospects table as that it what holds the mapping between prospects and conjoint.
What if you try something like:
SELECT p.id, p.name, c.id, c.title, cp.value
FROM prospect p
LEFT JOIN conjointProspect cp ON cp.prospectID = p.id
RIGHT JOIN conjoint c ON cp.conjointID = c.id
WHERE p.projectID = 2
ORDER BY p.id, c.id
Not sure if that will work, but it seems like conjointprospects needs to be at the center of your join in order to correctly map prospects to conjoints.