Related
I want weekly totals in a month. It will not include any partial week or future weeks. Week starts from Monday to Sunday.
I have a table structure like
Date Value -- Comments
----------------------------------------------------------------------
2016-10-01 7 Ignore this because its not a whole week in a month
2016-10-05 8 Week 1
2016-10-07 5 Week 1
2016-10-11 2 Week 2
2016-10-15 1 Week 2
2016-10-17 9 Ignore this because the week is not finished yet
OUTPUT
WeekNo Total
41 13
42 3
The easier way would be to build a Tally "date" table.
you can generate it from any Tally Table like:
DECLARE #StartDate DATE = '20160101'
, #EndDate DATE = '20161231';
WITH cte AS (
SELECT DATEADD(DAY, n - 1, #StartDate) AS date
FROM tally
WHERE n - 1 <= DATEDIFF(DAY, #StartDate, #EndDate)
)
SELECT
c.date
,YEAR(c.date) AS Year
,MONTH(c.date) AS Month
,DAY(c.date) AS Month
,DATEPART(WEEK,c.date) AS Week
,CASE WHEN 7<>COUNT(c.date) OVER (PARTITION BY YEAR(c.date),MONTH(c.date),DATEPART(WEEK,c.date)) THEN 0 ELSE 1 END AS isFullWeek
FROM cte c
Then you just need to Join it to what ever query you need.
DECLARE #StartDate datetime = '2011-10-01';
DECLARE #EndDate datetime = '2016-10-31';
SELECT
CAST(DATEADD(dd, -DATEPART(dw, tblData.RecordDate) + 2, tblData.RecordDate) AS date) AS WeekStart,
CAST(DATEADD(dd, -DATEPART(dw, tblData.RecordDate) + 8, tblData.RecordDate) AS date) AS WeekEnd,
SUM(Value) AS Total
FROM tblData
WHERE (#StartDate IS NULL
OR CAST(DATEADD(dd, -DATEPART(dw, tblData.RecordDate) + 2, tblData.RecordDate) AS date) >= CAST(#StartDate AS date))
AND (#EndDate IS NULL
OR CAST(DATEADD(dd, -DATEPART(dw, tblData.RecordDate) + 8, tblData.RecordDate) AS date) <= CAST(#EndDate AS date))
AND CAST(DATEADD(dd, -DATEPART(dw, tblData.RecordDate) + 8, tblData.RecordDate) AS date) < CAST(GETDATE() AS date)
GROUP BY CAST(DATEADD(dd, -DATEPART(dw, tblData.RecordDate) + 2, tblData.RecordDate) AS date),
CAST(DATEADD(dd, -DATEPART(dw, tblData.RecordDate) + 8, tblData.RecordDate) AS date)
Create a calendar table that meets your request, like this:
create table calendarTable ([date] date, weekNro int)
go
insert into calendarTable
select dateadd(d,n,'20160101'), DATEPART(WK,dateadd(d,n,'20151231'))
from numbers where n<500
If you don't have a Numbers Table, you must create it first. like this
SET NOCOUNT ON
CREATE TABLE Numbers (n bigint PRIMARY KEY)
GO
DECLARE #numbers table(number int);
WITH numbers(number) as (
SELECT 1 AS number
UNION all
SELECT number+1 FROM numbers WHERE number<10000
)
INSERT INTO #numbers(number)
SELECT number FROM numbers OPTION(maxrecursion 10000)
INSERT INTO Numbers(n) SELECT number FROM #numbers
Then query your table joining calendar table having in mind actual date for completed week, like this:
Similar to #Kilren but translated into postgres and using generate series from https://stackoverflow.com/a/11391987/10087503 to generate the dates
DECLARE #StartDate DATE = '20160101'
, #EndDate DATE = '20161231';
WITH cte AS (
SELECT i::date AS date FROM generate_series(#StartDate,
#EndDate, '1 day'::interval) i
)
SELECT
c.date
,DATE_TRUNC('month' ,c.date) AS month_trunc
,DATE_PART('week',c.date) AS week
,CASE WHEN 7<>COUNT(c.date)
OVER (PARTITION BY DATE_TRUNC('month' ,c.date),DATE_PART('week',c.date))
THEN 0 ELSE 1 END AS is_full_week
FROM cte c
Select DATEPART(ww, date) , SUM(Case When Comments Like '%1' then Value when Comments Like '%2' then Value else Value end)
from schema.tablename
group by DATEPART(ww,date)
I'm sorry if this doesn't work, it's the only way I thought to structure it.
How to get all the dates between two dates?
I have a variable #MAXDATE which is storing the maximum date from the table. Now I want to get the all dates between #Maxdate and GETDATE() and want to store these dates in a cursor.
So far I have done as follows:
;with GetDates As
(
select DATEADD(day,1,#maxDate) as TheDate
UNION ALL
select DATEADD(day,1, TheDate) from GetDates
where TheDate < GETDATE()
)
This is working perfectly but when I am trying to store these values in a cursor
SET #DateCurSor = CURSOR FOR
SELECT TheDate
FROM GetDates
Compilation Error
Incorrect syntax near the keyword 'SET'.
How to solve this?
My first suggestion would be use your calendar table, if you don't have one, then create one. They are very useful. Your query is then as simple as:
DECLARE #MinDate DATE = '20140101',
#MaxDate DATE = '20140106';
SELECT Date
FROM dbo.Calendar
WHERE Date >= #MinDate
AND Date < #MaxDate;
If you don't want to, or can't create a calendar table you can still do this on the fly without a recursive CTE:
DECLARE #MinDate DATE = '20140101',
#MaxDate DATE = '20140106';
SELECT TOP (DATEDIFF(DAY, #MinDate, #MaxDate) + 1)
Date = DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY a.object_id) - 1, #MinDate)
FROM sys.all_objects a
CROSS JOIN sys.all_objects b;
For further reading on this see:
Generate a set or sequence without loops – part 1
Generate a set or sequence without loops – part 2
Generate a set or sequence without loops – part 3
With regard to then using this sequence of dates in a cursor, I would really recommend you find another way. There is usually a set based alternative that will perform much better.
So with your data:
date | it_cd | qty
24-04-14 | i-1 | 10
26-04-14 | i-1 | 20
To get the quantity on 28-04-2014 (which I gather is your requirement), you don't actually need any of the above, you can simply use:
SELECT TOP 1 date, it_cd, qty
FROM T
WHERE it_cd = 'i-1'
AND Date <= '20140428'
ORDER BY Date DESC;
If you don't want it for a particular item:
SELECT date, it_cd, qty
FROM ( SELECT date,
it_cd,
qty,
RowNumber = ROW_NUMBER() OVER(PARTITION BY ic_id
ORDER BY date DESC)
FROM T
WHERE Date <= '20140428'
) T
WHERE RowNumber = 1;
You can use this script to find dates between two dates. Reference taken from this Article:
DECLARE #StartDateTime DATETIME
DECLARE #EndDateTime DATETIME
SET #StartDateTime = '2015-01-01'
SET #EndDateTime = '2015-01-12';
WITH DateRange(DateData) AS
(
SELECT #StartDateTime as Date
UNION ALL
SELECT DATEADD(d,1,DateData)
FROM DateRange
WHERE DateData < #EndDateTime
)
SELECT DateData
FROM DateRange
OPTION (MAXRECURSION 0)
GO
Just saying...here is a more simple approach to this:
declare #sdate date = '2017-06-25'
, #edate date = '2017-07-24';
with dates_CTE (date) as (
select #sdate
Union ALL
select DATEADD(day, 1, date)
from dates_CTE
where date < #edate
)
select *
from dates_CTE;
Easily create a Table Value Function that will return a table with all dates.
Input dates as string
You can customize the date in the the format you like '01/01/2017' or '01-01-2017' in string formats (103,126 ...)
Try this
CREATE FUNCTION [dbo].[DateRange_To_Table] ( #minDate_Str NVARCHAR(30), #maxDate_Str NVARCHAR(30))
RETURNS #Result TABLE(DateString NVARCHAR(30) NOT NULL, DateNameString NVARCHAR(30) NOT NULL)
AS
begin
DECLARE #minDate DATETIME, #maxDate DATETIME
SET #minDate = CONVERT(Datetime, #minDate_Str,103)
SET #maxDate = CONVERT(Datetime, #maxDate_Str,103)
INSERT INTO #Result(DateString, DateNameString )
SELECT CONVERT(NVARCHAR(10),#minDate,103), CONVERT(NVARCHAR(30),DATENAME(dw,#minDate))
WHILE #maxDate > #minDate
BEGIN
SET #minDate = (SELECT DATEADD(dd,1,#minDate))
INSERT INTO #Result(DateString, DateNameString )
SELECT CONVERT(NVARCHAR(10),#minDate,103), CONVERT(NVARCHAR(30),DATENAME(dw,#minDate))
END
return
end
To execute the function do this:
SELECT * FROM dbo.DateRange_To_Table ('01/01/2017','31/01/2017')
The output will be
01/01/2017 Sunday
02/01/2017 Monday
03/01/2017 Tuesday
04/01/2017 Wednesday
05/01/2017 Thursday
06/01/2017 Friday
07/01/2017 Saturday
08/01/2017 Sunday
09/01/2017 Monday
10/01/2017 Tuesday
11/01/2017 Wednesday
12/01/2017 Thursday
13/01/2017 Friday
14/01/2017 Saturday
15/01/2017 Sunday
16/01/2017 Monday
17/01/2017 Tuesday
18/01/2017 Wednesday
19/01/2017 Thursday
20/01/2017 Friday
21/01/2017 Saturday
22/01/2017 Sunday
23/01/2017 Monday
24/01/2017 Tuesday
25/01/2017 Wednesday
26/01/2017 Thursday
27/01/2017 Friday
28/01/2017 Saturday
29/01/2017 Sunday
30/01/2017 Monday
31/01/2017 Tuesday
This can be considered as bit tricky way as in my situation, I can't use a CTE table, so decided to join with sys.all_objects and then created row numbers and added that to start date till it reached the end date.
See the code below where I generated all dates in Jul 2018. Replace hard coded dates with your own variables (tested in SQL Server 2016):
select top (datediff(dd, '2018-06-30', '2018-07-31')) ROW_NUMBER()
over(order by a.name) as SiNo,
Dateadd(dd, ROW_NUMBER() over(order by a.name) , '2018-06-30') as Dt from sys.all_objects a
You can try this:
SET LANGUAGE SPANISH
DECLARE #startDate DATE = GETDATE() -- Your start date
DECLARE #endDate DATE = DATEADD(MONTH, 16, GETDATE()) -- Your end date
DECLARE #years INT = YEAR(#endDate) - YEAR(#startDate)
CREATE TABLE #TMP_YEARS (
[year] INT
)
-- Get all posible years between the start and end date
WHILE #years >= 0
BEGIN
INSERT INTO #TMP_YEARS
([year])
SELECT YEAR(#startDate) + #years
SET #years = #years - 1
END
;WITH [days]([day]) AS -- Posible days at a month
(
SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9 UNION ALL -- days lower than 10
SELECT 10 UNION ALL SELECT 11 UNION ALL SELECT 12 UNION ALL SELECT 13 UNION ALL SELECT 14 UNION ALL SELECT 15 UNION ALL SELECT 16 UNION ALL SELECT 17 UNION ALL SELECT 18 UNION ALL SELECT 19 UNION ALL -- days lower than 20
SELECT 20 UNION ALL SELECT 21 UNION ALL SELECT 22 UNION ALL SELECT 23 UNION ALL SELECT 24 UNION ALL SELECT 25 UNION ALL SELECT 26 UNION ALL SELECT 27 UNION ALL SELECT 28 UNION ALL SELECT 29 UNION ALL -- days lower than 30
SELECT 30 UNION ALL SELECT 31 -- days higher 30
),
[months]([month]) AS -- All months at a year
(
SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9 UNION ALL SELECT 10 UNION ALL SELECT 11 UNION ALL SELECT 12
)
SELECT CONVERT(VARCHAR, a.[year]) + '-' + REPLICATE('0', 2 - LEN(CONVERT(VARCHAR, n.[month]))) + CONVERT(VARCHAR, n.[month]) + '-' + REPLICATE('0', 2 - LEN(CONVERT(VARCHAR, d.[day]))) + CONVERT(VARCHAR, d.[day]) as [date]
FROM #TMP_YEARS a
CROSS JOIN [months] n -- Join all years with all months
INNER JOIN [days] d on DAY(EOMONTH(CONVERT(VARCHAR, a.[year]) + '-' + REPLICATE('0', 2 - LEN(CONVERT(VARCHAR, n.[month]))) + CONVERT(VARCHAR, n.[month]) + '-' + CONVERT(VARCHAR, DAY(EOMONTH(CAST(CONVERT(VARCHAR, a.[year]) + '-' + CONVERT(varchar, n.[month]) + '-15' AS DATE)))))) >= d.[day] AND -- The number of the day can't be higher than the last day of the current month and the current year
CONVERT(VARCHAR, a.[year]) + '-' + REPLICATE('0', 2 - LEN(CONVERT(VARCHAR, n.[month]))) + CONVERT(VARCHAR, n.[month]) + '-' + REPLICATE('0', 2 - LEN(CONVERT(VARCHAR, d.[day]))) + CONVERT(VARCHAR, d.[day]) <= ISNULL(#endDate, GETDATE()) AND -- The current date can't be higher than the end date
CONVERT(VARCHAR, a.[year]) + '-' + REPLICATE('0', 2 - LEN(CONVERT(VARCHAR, n.[month]))) + CONVERT(VARCHAR, n.[month]) + '-' + REPLICATE('0', 2 - LEN(CONVERT(VARCHAR, d.[day]))) + CONVERT(VARCHAR, d.[day]) >= ISNULL(#startDate, GETDATE()) -- The current date should be higher than the start date
ORDER BY a.[year] ASC, n.[month] ASC, d.[day] ASC
The output will be something like this, you can format the date as you like:
2019-01-24
2019-01-25
2019-01-26
2019-01-27
2019-01-28
2019-01-29
2019-01-30
2019-01-31
2019-02-01
2019-02-02
2019-02-03
2019-02-04
2019-02-05
2019-02-06
2019-02-07
2019-02-08
2019-02-09
...
create procedure [dbo].[p_display_dates](#startdate datetime,#enddate datetime)
as
begin
declare #mxdate datetime
declare #indate datetime
create table #daterange (dater datetime)
insert into #daterange values (#startdate)
set #mxdate = (select MAX(dater) from #daterange)
while #mxdate < #enddate
begin
set #indate = dateadd(day,1,#mxdate)
insert into #daterange values (#indate)
set #mxdate = (select MAX(dater) from #daterange)
end
select * from #daterange
end
I listed dates of 2 Weeks later. You can use variable #period OR function datediff(dd, #date_start, #date_end)
declare #period INT, #date_start datetime, #date_end datetime, #i int;
set #period = 14
set #date_start = convert(date,DATEADD(D, -#period, curent_timestamp))
set #date_end = convert(date,current_timestamp)
set #i = 1
create table #datesList(dts datetime)
insert into #datesList values (#date_start)
while #i <= #period
Begin
insert into #datesList values (dateadd(d,#i,#date_start))
set #i = #i + 1
end
select cast(dts as DATE) from #datesList
Drop Table #datesList
This is the method that I would use.
DECLARE
#DateFrom DATETIME = GETDATE(),
#DateTo DATETIME = DATEADD(HOUR, -1, GETDATE() + 2); -- Add 2 days and minus one hour
-- Dates spaced a day apart
WITH MyDates (MyDate)
AS (
SELECT #DateFrom
UNION ALL
SELECT DATEADD(DAY, 1, MyDate)
FROM MyDates
WHERE MyDate < #DateTo
)
SELECT
MyDates.MyDate
, CONVERT(DATE, MyDates.MyDate) AS [MyDate in DATE format]
FROM
MyDates;
Here is a similar example, but this time the dates are spaced one hour apart to further aid understanding of how the query works:
-- Alternative example with dates spaced an hour apart
WITH MyDates (MyDate)
AS (SELECT #DateFrom
UNION ALL
SELECT DATEADD(HOUR, 1, MyDate)
FROM MyDates
WHERE MyDate < #DateTo
)
SELECT
MyDates.MyDate
FROM
MyDates;
As you can see, the query is fast, accurate and versatile.
You can use SQL Server recursive CTE
DECLARE
#MinDate DATE = '2020-01-01',
#MaxDate DATE = '2020-02-01';
WITH Dates(day) AS
(
SELECT CAST(#MinDate as Date) as day
UNION ALL
SELECT CAST(DATEADD(day, 1, day) as Date) as day
FROM Dates
WHERE CAST(DATEADD(day, 1, day) as Date) < #MaxDate
)
SELECT* FROM dates;
declare #start_dt as date = '1/1/2021'; -- Date from which the calendar table will be created.
declare #end_dt as date = '1/1/2022'; -- Calendar table will be created up to this date (not including).
declare #dates as table (
date_id date primary key,
date_year smallint,
date_month tinyint,
date_day tinyint,
weekday_id tinyint,
weekday_nm varchar(10),
month_nm varchar(10),
day_of_year smallint,
quarter_id tinyint,
first_day_of_month date,
last_day_of_month date,
start_dts datetime,
end_dts datetime
)
while #start_dt < #end_dt
begin
insert into #dates(
date_id, date_year, date_month, date_day,
weekday_id, weekday_nm, month_nm, day_of_year, quarter_id,
first_day_of_month, last_day_of_month,
start_dts, end_dts
)
values(
#start_dt, year(#start_dt), month(#start_dt), day(#start_dt),
datepart(weekday, #start_dt), datename(weekday, #start_dt), datename(month, #start_dt), datepart(dayofyear, #start_dt), datepart(quarter, #start_dt),
dateadd(day,-(day(#start_dt)-1),#start_dt), dateadd(day,-(day(dateadd(month,1,#start_dt))),dateadd(month,1,#start_dt)),
cast(#start_dt as datetime), dateadd(second,-1,cast(dateadd(day, 1, #start_dt) as datetime))
)
set #start_dt = dateadd(day, 1, #start_dt)
end
-- sample of the data
select
top 50 *
--into master.dbo.DimDate
from #dates d
order by date_id
DECLARE #FirstDate DATE = '2018-01-01'
DECLARE #LastDate Date = '2018-12-31'
DECLARE #tbl TABLE(ID INT IDENTITY(1,1) PRIMARY KEY,CurrDate date)
INSERT #tbl VALUES( #FirstDate)
WHILE #FirstDate < #LastDate
BEGIN
SET #FirstDate = DATEADD( day,1, #FirstDate)
INSERT #tbl VALUES( #FirstDate)
END
INSERT #tbl VALUES( #LastDate)
SELECT * FROM #tbl
I am looking for a SQL-function that gives the last 12 months with Start Date and End Date. Say you pick 10.Dec, it will give a result in:
- StartDate -- EndDate
- 2013-11-01 - 2013-11-30
- 2013-10-01 - 2013-10-31
- 2013-09-01 - 2013-09-30
and so it goes for the last 12 months.
I tried modifying an old function we had, but I got totally off and confused in the end.
ALTER FUNCTION [dbo].[Last12Months](#Date date) RETURNS TABLE
AS
Return
(
with cte as (
SELECT DATEADD(mm, DATEDIFF(mm, 01, #Date), 01) AS Start,
DATEADD(mm, DATEDIFF(mm, -12, #Date), -12) AS EndDate
union all
select Start - 1, EndDate - 1 from cte
where Start >= #Date )
select CAST(Start as DATE) StartDate, CAST(EndDate as DATE) EndDate from cte)
Runned it like this:
select * from dbo.Last12Months ('2013-12-10')
and got:
- StartDate - EndDate
- 2013-12-02 - 2013-12-20
Anyone know what to do?
Please try using CTE:
ALTER FUNCTION [dbo].[Last12Months]
(
#Date datetime
) RETURNS #tbl TABLE (Start datetime, EndDate datetime)
AS
BEGIN
WITH T AS(
SELECT
DATEADD(month, DATEDIFF(month, 0, #Date), 0) AS Start,
DATEADD(d, -DAY(DATEADD(m,1,#date)),DATEADD(m,1,#date)) AS EndDate,
12 Cnt
UNION ALL
SELECT
DATEADD(month, -1, Start),
DATEADD(d, -DAY(DATEADD(m,1,Start-1)),DATEADD(m,1,Start-1)),
Cnt-1
FROM
T
WHERE
Cnt-1>0
)
INSERT INTO #tbl
(Start, EndDate)
SELECT
Start, EndDate
FROM T
RETURN
END
This seems to do the job - whether you want to put it in a function or just wherever you need to have the data:
; With Numbers as (
select ROW_NUMBER() OVER (ORDER BY number ) as n
from master..spt_values
), Months as (
select DATEADD(month,n,'20010101') as start_date,
DATEADD(month,n,'20010131') as end_date
from Numbers
)
select * from Months
where DATEDIFF(month,start_date,GETDATE()) between 0 and 11
(Substitute any other date for GETDATE() if you want to get it based on some other date)
(On my machine, this can generate any month from January 2001 on to at least the next century - it can be adjusted if you need earlier or later dates also)
Damn, you've got to be quick on SO!
Good use of CTEs: i've learnt a bit answering this...
alter function Last12Months(#d date) returns table
as
return(
with cte as (
select
dateadd(month, datepart(mm,#d)-13,
dateadd(year,datepart(yyyy,#d)-1900,0)
)
as start
union all
select dateadd(mm, 1, start) from cte
where start < #d)
select start, dateadd(mm, 1, start) ends from cte
where start < #d
)
go
select * from Last12Months('2014-06-04')
Removed conversion to varchar thanks to
Date serial in SQL?
This returns 13 months: from say June last year to this June, inclusive.
To return the previous 12 months, not including the current June, change the final start<#d to
where start < dateadd(month, datepart(mm,#d)-1,
dateadd(year,datepart(yyyy,#d)-1900,0))
The end is 00:00 hours on the first day of the next month.
check this,
Declare #i date='2013-12-10'
;with cte as
(Select dateadd(month,datediff(month,0,#i)-1,0) StartDate
,dateadd(day,-1,dateadd(month,datediff(month,0,#i),0)) EndDate ,1 rownum
Union all
select dateadd(month,-1,StartDate),dateadd(day,-1,StartDate),rownum+1 rownum from cte where rownum<12 )
select * from cte
#Lebowski Below script will give you start and end date of specified calendar months from today in chronological order
DECLARE #nMonths TINYINT
SET #nMonths = 60
SELECT FORMAT(DATEADD(month, n.n - #nMonths+1+ DATEDIFF(month, 0, GETDATE()) -1 ,0), 'yyyy-MM-dd') AS MonthStartDate
, FORMAT(DATEADD(dd, -1, DATEADD(month, n.n - #nMonths+1 + DATEDIFF(month, 0, GETDATE()),0)), 'yyyy-MM-dd') AS MonthEndDate
FROM (SELECT TOP(#nMonths) n = ROW_NUMBER() OVER (ORDER BY NAME)
FROM master.dbo.syscolumns) n
Sample output
MonthStartDate MonthEndDate
2011-04-01 2011-04-30
2011-05-01 2011-05-31
2011-06-01 2011-06-30
2011-07-01 2011-07-31
2011-08-01 2011-08-31
2011-09-01 2011-09-30
2011-10-01 2011-10-31
2011-11-01 2011-11-30
2011-12-01 2011-12-31
....
Try this it might help you
select top 12 *
from YourTable
where dateOf between #DateFrom and #DateTo
order by dateOf desc
I have two date for example 08/08/2013 and 11/11/2013 and I need last date of each month starting from August to November in a table so that i can iterate over the table to pick those dates individually.
I know how to pick last date for any month but i am stucked with a date range.
kindly help, it will be highly appreciated.
Note : I am using Sql 2008 and date rang could be 1 month , 2 month or 6 month or a year or max too..
You can use CTE for getting all last days of the month within the defined range
Declare #Start datetime
Declare #End datetime
Select #Start = '20130808'
Select #End = '20131111'
;With CTE as
(
Select #Start as Date,Case When DatePart(mm,#Start)<>DatePart(mm,#Start+1) then 1 else 0 end as [Last]
UNION ALL
Select Date+1,Case When DatePart(mm,Date+1)<>DatePart(mm,Date+2) then 1 else 0 end from CTE
Where Date<#End
)
Select * from CTE
where [Last]=1 OPTION ( MAXRECURSION 0 )
DECLARE #tmpTable table (LastDates DATE);
DECLARE #startDate DATE = '01/01/2012'; --1 Jan 2012
DECLARE #endDate DATE = '05/31/2012'; --31 May 2012
DECLARE #tmpEndDate DATE;
SET #startDate = DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,#startDate)+1,1));
SET #tmpEndDate = DATEADD(DAY, 1, #endDate);
WHILE (#startDate <= #tmpEndDate)
BEGIN
INSERT INTO #tmpTable (LastDates) values (DATEADD(DAY, -1, #startDate));
SET #startDate = DATEADD(MONTH, 1, #startDate);
END
SELECT [LastDates] FROM #tmpTable;
Output:
Example: 1
#startDate DATE = '01/01/2012'; --1 Jan 2012
#endDate DATE = '05/31/2012'; --31 May 2012
LastDates
----------
2012-01-31
2012-02-29
2012-03-31
2012-04-30
2012-05-31
Example: 2
#startDate DATE = '11/01/2011'; --1 Nov 2011
#endDate DATE = '03/13/2012'; --13 Mar 2012
LastDates
----------
2011-11-30
2011-12-31
2012-01-31
2012-02-29
I've created a table variable, filled it with all days between #startDate and #endDate and searched for max date in the month.
declare #tmpTable table (dates date)
declare #startDate date = '08/08/2013'
declare #endDate date = '11/11/2013'
while #startDate <= #endDate
begin
insert into #tmpTable (dates) values (#startDate)
set #startDate = DATEADD(DAY, 1, #startDate)
end
select max(dates) as [Last day] from #tmpTable as o
group by datepart(YEAR, dates), datepart(MONTH, dates)
Results:
Last day
2013-08-31
2013-09-30
2013-10-31
2013-11-11
To also get last day of November this can be used before loop:
set #endDate = DATEADD(day, -1, DATEADD(month, DATEDIFF(month, 0, #endDate) + 1, 0))
Following script demonstrates the script to find last day of previous, current and next month.
----Last Day of Previous Month
SELECT DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0))
LastDay_PreviousMonth
----Last Day of Current Month
SELECT DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE())+1,0))
LastDay_CurrentMonth
----Last Day of Next Month
SELECT DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE())+2,0))
LastDay_NextMonth
If you want to find last day of month of any day specified use following script.
--Last Day of Any Month and Year
DECLARE #dtDate DATETIME
SET #dtDate = '8/18/2007'
SELECT DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,#dtDate)+1,0))
LastDay_AnyMonth
ResultSet:
LastDay_AnyMonth
Source - SQL Server Central.
You can use a recursive CTE to do this, note the MAXRECURSION OPTION prevents an infinite loop:
DECLARE #StartDate DATE = '2013-08-08'
DECLARE #EndDate DATE = '2013-11-11'
;WITH dateCTE
AS
(
SELECT CAST(DATEADD(M, 1,DATEADD(d, DAY(#StartDate) * -1, #StartDate)) AS DATE) EndOFMonth
UNION ALL
SELECT CAST(DATEADD(M, 2,DATEADD(d, DAY(EndOFMonth) * -1, EndOFMonth)) AS DATE)
FROM dateCTE
WHERE EndOFMonth < DATEADD(d, DAY(#EndDate) * -1, #EndDate)
)
SELECT *
FROM dateCTE
OPTION (MAXRECURSION 30);
This returns
EndOFMonth
----------
2013-08-31
2013-09-30
2013-10-31
try this
the last row(where) is optional for date filtering
declare #table table
(
thisdate date
)
insert into #table values ('12/01/2013'),('05/06/2013'),('04/29/2013'),('02/20/2013')
select *,DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,thisdate)+1,0))
LastDay from #table
where thisdate between 'givendate' and 'givendate'
The Example Below is for all dates
thisdate lastday
2013-12-01 2013-12-31 23:59:59.000
2013-05-06 2013-05-31 23:59:59.000
2013-04-29 2013-04-30 23:59:59.000
2013-02-20 2013-02-28 23:59:59.000
The following CTE gives you the last day of every month from February 1900 until the middle of the 26th century (on my machine):
;with LastDaysOfMonths as (
select DATEADD(month,
ROW_NUMBER() OVER (ORDER BY so.object_id),
'19000131') as Dt
from sys.objects so,sys.objects so1
)
select * from LastDaysOfMonths
It should be easy enough to use it as part of a larger query or to filter it down to just the dates you want. You can adjust the range of years as needed by changing the constant 19000131. The only important thing to do is make sure that you use a month that has 31 days in it and always have the constant be for day 31.
No need to use a common table expression or anything like that - this simple query will do it:
SELECT DATEADD(d, -1, DATEADD(mm, DATEDIFF(m, 0, DATEADD(m, number, '2013-08-08')) + 1, 0)) AS EndOfMonth
FROM master.dbo.spt_values
WHERE 'P' = type
AND DATEADD(m, number, '2013-08-08') < '2013-11-11';
Although the question is about the last day which #bummi has already answered.
But here is the solution for the first date which might be helpful for someone.
Get the first dates of all the months in-between the #FromDate and #ToDate.
DECLARE #FromDate DATETIME = '2019-08-13'
DECLARE #ToDate DATETIME = '2019-11-25'
;WITH CTE
AS
(
SELECT DATEADD(DAY, -(DAY(#FromDate) - 1), #FromDate) AS FirstDateOfMonth
UNION ALL
SELECT DATEADD(MONTH, 1, FirstDateOfMonth)
FROM CTE
WHERE FirstDateOfMonth < DATEADD(DAY, -(DAY(#ToDate) - 1), #ToDate)
)
SELECT * FROM CTE
Here is the result
--Result
2019-08-01 00:00:00.000
2019-09-01 00:00:00.000
2019-10-01 00:00:00.000
2019-11-01 00:00:00.000
I need to generate either a column in a query or a temp table (not sure which one is required)
so that I can have a list of dates that are on Saturday that fall within a given date range.
This list will be used in a join to associate records with weeks.
What are my options?
Sample Input:
From: 03/01/2013
To: 04/30/2013
Results:
Week Ending
- 03/02/2013
- 03/09/2013
- 03/16/2013
- 03/23/2013
- 03/30/2013
- 04/06/2013
- 04/13/2013
- 04/20/2013
- 04/27/2013
- 05/04/2013
Current code:
create table #TBL7(YEAR INT, WEEKNUMBER INT, STARTDATE DATETIME, ENDDATE DATETIME)
begin
declare #startdate datetime
, #enddate datetime
, #ctr int
SET #startdate = CAST(2013 AS VARCHAR)+ '/01/01'
SET #enddate = CAST(2013 AS VARCHAR) + '/12/31'
SET #ctr = 0
WHILE #enddate >= #startdate
BEGIN
SET #ctr = #ctr + 1
INSERT INTO #TBL7
values(year(#startdate), #ctr, #startdate, #startdate + 6)
SET #startdate = #startdate + 7
END
end
select * from #TBL7
First, create a calendar table. Then you have a very simple query:
select [Date]
from dbo.Calendar
where DayOfWeek = 'Saturday' and [Date] between '20130301' and '20130430'
A calendar table is almost always the best approach to working with dates because you're working with data, not code, so you can see it's correct and there's no cryptic code to maintain.
This is Oracle code. Sorry I do not know how to convert this to SQL SERVER. Should not be very hard. All you need is to use proper functions in place of to_date() and to_char(), and calc the difference between start and end date, e.g. (end_date-start_date)+1:
WITH data(r, some_date) AS
(
SELECT 1 r, to_date('03/01/2013', 'MM/DD/YYYY') some_date FROM dual
UNION ALL
SELECT r+1, to_date('03/01/2013', 'MM/DD/YYYY')+r FROM data WHERE r < 61 -- (end_date-start_date)+1
)
SELECT some_date
, To_Char(some_date, 'DY') wk_day
FROM data
WHERE To_Char(some_date, 'DY') = 'SAT'
/
SOME_DATE WK_DAY
--------------------
3/2/2013 SAT
3/9/2013 SAT
3/16/2013 SAT
3/23/2013 SAT
3/30/2013 SAT
4/6/2013 SAT
4/13/2013 SAT
4/20/2013 SAT
4/27/2013 SAT
This should work:
WITH cteWeeks (WeekEnding) As
(
-- Find the Saturday of the first week.
-- Need to allow for different DATEFIRST settings:
SELECT
CASE
WHEN DatePart(dw, DateAdd(day, ##datefirst, #StartDate)) = 7 THEN #StartDate
ELSE DateAdd(day, 7 - DatePart(dw, DateAdd(day, ##datefirst, #StartDate)), #StartDate)
END
UNION ALL
SELECT
DateAdd(day, 7, WeekEnding)
FROM
cteWeeks
WHERE
WeekEnding < #EndDate
)
SELECT
WeekEnding
FROM
cteWeeks
;
http://www.sqlfiddle.com/#!3/d41d8/12095