SQL select statement that checks two columns and returns the value from a third [duplicate] - sql

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SQL Server Error:"SQL Server Subquery returned more than 1 value"
(2 answers)
Closed 7 years ago.
I am writing a query that accesses multiple tables in the same database. For one of the columns in the select statement, I need to return
Table1.Column4
where Table1.Column = Table3.Column1 AND
Table1.Column2 = Table4.Column1
I have it written as:
SELECT AccNum.FieldValue
FROM PersonFieldValuesVW
INNER JOIN PersonFieldValuesVW AccNum
ON AccNum.PersonId = InPerson.PersonId
INNER JOIN InPerson
ON InPerson.IncidentId = Incident.Id
WHERE AccNum.FieldDescr like '%Account Number%') as [Account Number],
This is returning the error:
Subquery returned more than 1 value. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression.
Here is the full query, any assistance would be appreciated.
SELECT DISTINCT
CaseNum as [Case Number],
ALCategoryVW.Category as [Category],
ALCategoryVW.SubCategory as [Sub Category],
InAssign.AssignToName as [Assigned To],
ReportedDate as [Open Date],
EndDate as [Closed Date], --This a placeholder for a closed date
[Status],
SiteLoc1.Descr as [Loss Location],
LocDetails as [Loss Cost Center],
SiteLoc1.Region as [Region],
SiteLoc1.SubRegion as [Sub Region],
-- SiteLoc2.Descr as [Location Description], **Need this though returning all for the location?
CASE WHEN SAR.FieldId = '604NU' and SAR.FieldValue <> 'False' THEN 'YES' ELSE 'NO' END as [SAR Required],
Summary as [Incident Summary],
Disposition as [Case Disposition],
(
SELECT AccNum.FieldValue
FROM PersonFieldValuesVW
INNER JOIN PersonFieldValuesVW AccNum ON AccNum.PersonId = InPerson.PersonId
INNER JOIN InPerson ON InPerson.IncidentId = Incident.Id
WHERE AccNum.FieldDescr like '%Account Number%'
) as [Account Number],
FORMAT(AuditItemDetail.ItemValue, '#,###') as [Potential Loss],
FORMAT(AuditItemDetail.ItemValue - AuditItemDetail.PreventedExposureAmount, '#,###') as [Actual Loss]
FROM Incident
INNER JOIN ALCategoryVW ON ALCategoryVW.IncidentId = Incident.Id
INNER JOIN InAssign ON InAssign.IncidentId = Incident.Id
INNER JOIN SiteLoc1 ON SiteLoc1.Id = Incident.LocId
INNER JOIN SiteLoc2 ON SiteLoc2.SiteLoc1Id = SiteLoc1.Id
INNER JOIN IncidentFieldValuesVW SAR ON SAR.IncidentId = Incident.Id
INNER JOIN InItem ON InItem.IncidentId = Incident.Id
INNER JOIN AuditItemDetail ON AuditItemDetail.ItemId = InItem.ItemId
INNER JOIN InPerson ON InPerson.IncidentId = Incident.Id
INNER JOIN PersonFieldValuesVW AccNum ON AccNum.PersonId = InPerson.PersonId

Answer 1

This should resolve your error, but I'm not sure it is logically correct. If you have two records being returned in the sub-select, which one is the "right" one.
SELECT DISTINCT
CaseNum as [Case Number],
ALCategoryVW.Category as [Category],
ALCategoryVW.SubCategory as [Sub Category],
InAssign.AssignToName as [Assigned To],
ReportedDate as [Open Date],
EndDate as [Closed Date], --This a placeholder for a closed date
[Status],
SiteLoc1.Descr as [Loss Location],
LocDetails as [Loss Cost Center],
SiteLoc1.Region as [Region],
SiteLoc1.SubRegion as [Sub Region],
-- SiteLoc2.Descr as [Location Description], **Need this though returning all for the location?
CASE WHEN SAR.FieldId = '604NU' and SAR.FieldValue <> 'False' THEN 'YES' ELSE 'NO' END as [SAR Required],
Summary as [Incident Summary],
Disposition as [Case Disposition],
AccNum.FieldValue,
FORMAT(AuditItemDetail.ItemValue, '#,###') as [Potential Loss],
FORMAT(AuditItemDetail.ItemValue - AuditItemDetail.PreventedExposureAmount, '#,###') as [Actual Loss]
FROM Incident
INNER JOIN ALCategoryVW ON ALCategoryVW.IncidentId = Incident.Id
INNER JOIN InAssign ON InAssign.IncidentId = Incident.Id
INNER JOIN SiteLoc1 ON SiteLoc1.Id = Incident.LocId
INNER JOIN SiteLoc2 ON SiteLoc2.SiteLoc1Id = SiteLoc1.Id
INNER JOIN IncidentFieldValuesVW SAR ON SAR.IncidentId = Incident.Id
INNER JOIN InItem ON InItem.IncidentId = Incident.Id
INNER JOIN AuditItemDetail ON AuditItemDetail.ItemId = InItem.ItemId
INNER JOIN InPerson ON InPerson.IncidentId = Incident.Id
LEFT JOIN PersonFieldValuesVW AccNum ON AccNum.PersonId = InPerson.PersonId AND AccNum.FieldDescr like '%Account Number%'
***Updated based on comment.