I want to get records who are about reach todays date with in 2 days ProjectEnddt. i want to show Projects who are going to end with in 2 days. want to show 2 days before.
Query
SELECT ProjectEndDt
, ProjectRenewalDt
, ProjectUpgradeDt
FROM tbl_project
WHERE CONVERT(VARCHAR(10), DATEADD(DAY, 2, ProjectEndDt)) >= CONVERT(VARCHAR(10), GETDATE());
Try this:
SELECT ProjectEndDt
,ProjectRenewalDt
,ProjectUpgradeDt
FROM tbl_project
WHERE CONVERT(DATE,[ProjectEndDt]) < DATEADD(DAY, 3,CONVERT(DATE,GETDATE()))
Try this:
SELECT ProjectEndDt
,ProjectRenewalDt
,ProjectUpgradeDt
FROM tbl_project
WHERE CAST(ProjectEndDt AS DATE) < CAST(DATEADD(DAY, 3, GETDATE()) AS DATE)
Related
this is my first question here. Hopefully I´m clear enough what I´m searching for.
My problem is following:
On this analysis I want to get from the last 7 weeks, the summarized prices of each week. Its working with out any problems, but now I would like to add the weeks number of each week as alias.
In my tests I was using for example something like this:
DECLARE #week7 varchar(10)
SET #week7 = DATEPART(wk, GetDate())
One of my problems is, that I´m not allowed to work with "EXEC".
This is just an example of my analysis:
SELECT DISTINCT(
SELECT SUM(Price)
FROM tblBookingdata
WHERE(Datum BETWEEN DATEADD(wk, -7, DATEADD(DAY, 1 - DATEPART(WEEKDAY, GETDATE()), DATEDIFF(dd, 0, GETDATE()))) AND DATEADD(wk, -6, DATEADD(DAY, 1 - DATEPART(WEEKDAY, GETDATE()), DATEDIFF(dd, 0, GETDATE()))))) AS '7 weeks ago', (
SELECT SUM(Price)
FROM tblBookingdata
WHERE(Datum BETWEEN DATEADD(wk, -6, DATEADD(DAY, 1 - DATEPART(WEEKDAY, GETDATE()), DATEDIFF(dd, 0, GETDATE()))) AND DATEADD(wk, -5, DATEADD(DAY, 1 - DATEPART(WEEKDAY, GETDATE()), DATEDIFF(dd, 0, GETDATE()))))) AS '6 weeks ago'
I would like the column name to show the week number from each sub select. That the output would be for example for this week: 40 (as column name) and 900 as price summary.
So I tried to work here with DECLARE and assign #week7 for example with the current week number. But here I got stuck, due it seems like I need to work here with EXEC.
Is this only possible with "EXEC" or are there any other solutions to solve this? I was looking in the www, but currently I´m stucking a bit. Thankful for every help! :)
I think the DateDiff function is your friend here. Are you using SQL Server? This won't display a row for the week if there are zero records in that week, but this should be close to what you want.
select WeeksAgo, sum(Price) as Price from (
select
Price
,Datediff(wk, Datum, getDate()) as WeeksAgo
,Datum --not used
from
tblBookingdata
)DataByWeek
where WeeksAgo between 0 and 7 --should this be 0-6?
group by WeeksAgo
I think you're looking for something like this. The prior 7 weeks are calculated from GETDATE based on a numbers table with 1, 2, 3, ... 7. Then the booking Prices are summarized by week where the Datum is within the prior 7 weeks. This will display NULL in price_sum if there were no sales that week.
drop table if exists #tblBookingdata;
go
create table #tblBookingdata(
Datum date not null,
Price int not null);
go
;with
weeks_cte(wk) as (
select datepart(wk, dateadd(wk, w*-1, getdate()))
from (values (1),(2),(3),(4),(5),(6),(7)) v(w)),
bookings_cte(wk, price_sum) as (
select datepart(wk, Datum), sum(Price)
from #tblBookingdata
where Datum>dateadd(wk, -7, getdate())
group by datepart(wk, Datum))
select *
from weeks_cte wc
left join bookings_cte b on wc.wk=b.wk;
I know there are similar answers to this, but none of them have worked for me. I have a query with a date field in it. I want to filter the results for the next 7 days. It works if I specify the dates i.e date between '2019-07-18' AND '2019-07-25' but I need it to be more generic.
Thanks in advance!
Here are a few things I've tried:
CAST( datefield AS DATE ) > DATEADD( DAY, +7, CAST( GETDATE() AS DATE ))
WHERE GETDATE()+7
AND DATEADD(dd, -7, datefield) <= CAST(datefield AS DATETIME)
You can use logic like this:
where datefield >= dateadd(day, 1, cast(getdate() as date)) and
datefield < dateadd(day, 8, cast(getdate() as date))
This assumes you are using SQL Server (based on your syntax) and that you don't want today's data ("next 7 days").
You didnt specify what SQL you are using so this might not be fine for you.
WHERE datefield BETWEEN SYSDATE AND SYSDATE + 7
datefield between today and next 7 days
WHERE
CAST(datefield AS DATE) <= DATEADD(DAY, 7, CAST(GETDATE() AS DATE ))
AND CAST(datefield AS DATE) >= CAST(GETDATE() AS DATE )
I am trying the below query, but it's output comes last 2 weeks data, but I need only last before week data only.
select * from tablename where createddate>=DATEADD(WEEK,-2, GETDATE()) ;
Just add another condition to your WHERE clause to restrict to earlier than the week before last:
SELECT * FROM tablename
WHERE createddate >= DATEADD(WEEK,-2, GETDATE()) AND
createddate < DATEADD(WEEK,-1, GETDATE())
From one your comments I found that the week you are talking about starts from Friday, so you need to add up those gap days into your condition
SELECT * FROM tablename
WHERE createddate >= DATEADD(ww, DATEDIFF(ww, 4 ,DATEADD(WEEK, -1, GETDATE())), 4)
AND createddate < DATEADD(ww, DATEDIFF(ww, 4 ,DATEADD(WEEK, 0, GETDATE())), 4)
this code is currect answer for my quation,
select * from dbo_OrdersCompleteView1 where S2_DateTimeOrederLines between DATEADD(WEEK,-2, GETDATE()) and DATEADD(WEEK,-1,GETDATE());
I want to select all the records from [Orders] that have a [Submissiondate] less than 7 days.
I'm completely stumped. This is the query I'm executing:
SELECT * FROM [Orders] WHERE ([SubmissionDate] < #SubmissionDate)
Doesn't work.
If you mean you want rows with SubmissionDate between #SubmissionDate and #SubmissionDate - 7 days, then this is how I would implement that in Transact-SQL:
WHERE [SubmissionDate] BETWEEN DATEADD(DAY, -7, #SubmissionDate)
AND #SubmissionDate
Note that BETWEEN implies >= and <=. If you need strict inequalities, make it something like this:
WHERE [SubmissionDate] > DATEADD(DAY, -7, #SubmissionDate)
AND [SubmissionDate] < #SubmissionDate
Assuming that the sql parameter #SubmissionDate is the date (and time) now. You could use the following query that will return those [Orders] submitted within the last 7 days:
SELECT * FROM [Orders] WHERE ([SubmissionDate] >= DATEADD(DD, -7, DATEADD(dd, 0, DATEDIFF(dd, 0, #SubmissionDate))))
Two important remarks to this solution:
Time 'part' is being removed from #SubmissionDate.
As there is no 'Date To' restriction, do includes the [Orders] submitted
'today' (until the time the query is being executed).
The following code is just to get the date 'part' only of a date-time (extracted from this other SO thread).
DATEADD(dd, 0, DATEDIFF(dd, 0, #SubmissionDate))
Try this
SELECT * FROM [Orders] WHERE [submission_date] < NOW() - INTERVAL 7
DAY;
You can also try this DATEDIFF
SELECT * FROM [Orders] WHERE datediff(d,SubmissionDate,GETDATE()) > 7
where GetDate() is today's date and the d is difference in days
select datediff(d,'2012/06/23',GETDATE())
should give you 7 because it's 7 days ago
I am looking for a good SQL Statement to select all rows from the previous day from one table. The table holds one datetime column. I am using SQL Server 2005.
get today no time:
SELECT dateadd(day,datediff(day,0,GETDATE()),0)
get yestersday no time:
SELECT dateadd(day,datediff(day,1,GETDATE()),0)
query for all of rows from only yesterday:
select
*
from yourTable
WHERE YourDate >= dateadd(day,datediff(day,1,GETDATE()),0)
AND YourDate < dateadd(day,datediff(day,0,GETDATE()),0)
To get the "today" value in SQL:
convert(date, GETDATE())
To get "yesterday":
DATEADD(day, -1, convert(date, GETDATE()))
To get "today minus X days": change the -1 into -X.
So for all yesterday's rows, you get:
select * from tablename
where date >= DATEADD(day, -1, convert(date, GETDATE()))
and date < convert(date, GETDATE())
It's seems the obvious answer was missing. To get all data from a table (Ttable) where the column (DatetimeColumn) is a datetime with a timestamp the following query can be used:
SELECT * FROM Ttable
WHERE DATEDIFF(day,Ttable.DatetimeColumn ,GETDATE()) = 1 -- yesterday
This can easily be changed to today, last month, last year, etc.
SELECT * from table_name where date_field = DATE_SUB(CURRENT_DATE(),INTERVAL 1 DAY);
Its a really old thread, but here is my take on it.
Rather than 2 different clauses, one greater than and less than. I use this below syntax for selecting records from A date. If you want a date range then previous answers are the way to go.
SELECT * FROM TABLE_NAME WHERE
DATEDIFF(DAY, DATEADD(DAY, X , CURRENT_TIMESTAMP), <column_name>) = 0
In the above case X will be -1 for yesterday's records
This should do it:
WHERE `date` = CURDATE() - INTERVAL 1 DAY
Can't test it right now, but:
select * from tablename where date >= dateadd(day, datediff(day, 1, getdate()), 0) and date < dateadd(day, datediff(day, 0, getdate()), 0)
In SQL Server do like this:
where cast(columnName as date) = cast(getdate() -1 as date)
You should cast both sides of the expression to date to avoid issues with time formatting.
If you need to control interval in more detail, then you should try something like:
declare #start datetime = cast(getdate() - 1 as date)
declare #end datetime = cast(getdate() - 1 as date)
set #end = dateadd(second, 86399, #end)
Another way to tell it "Yesterday"...
Select * from TABLE
where Day(DateField) = (Day(GetDate())-1)
and Month(DateField) = (Month(GetDate()))
and Year(DateField) = (Year(getdate()))
This conceivably won't work well on January 1, as well as the first day of every month. But on the fly it's effective.
Well, its easier to cast the datetime column to date and than compare.
SELECT * FROM TABLE_NAME WHERE cast(COLUMN_NAME as date) =
dateadd(day,0, convert(date, getdate(), 105))
A simple alternative
Select GETDATE() - 1
Change 1 to go back that many number of days
PS : This gives you timestamp accuracy.
This worked a charm:
SELECT * FROM mytable WHERE date(mydate) = DATE_SUB(CURDATE(), INTERVAL 1 DAY);
subdate(now(),1) will return yesterdays timestamp
The below code will select all rows with yesterday's timestamp
Select * FROM `login` WHERE `dattime` <= subdate(now(),1) AND `dattime` > subdate(now(),2)