Mysql - select with where in clause with additional condition? - conditional-statements

This is the table:
*rulestbl
| idrule | idsys | orders |
--------------------------------
|R01#1 | 1 | 1 |
|R01#1 | 2 | 1 |
|R01#2 | 1 | 2 |
|R01#2 | 3 | 2 |
|R01#2 | 4 | 2 |
|R01#3 | 2 | 3 |
|R01#3 | 1 | 3 |
|R01#3 | 5 | 3 |
|R01#4 | 1 | 4 |
|R01#4 | 4 | 4 |
|R01#4 | 5 | 4 |
--------------------------------
I want to select with 2 condition in one input array, if I want to input (idsys = 1 and idsys = 2) and "where orders" = MIN() so the output should be:
| idrule | orders |
----------------------
|R01#1 | 1 |
----------------------
anyone can help me? thanks
the result one should be elimination only "idsys with conditon 1 and 2" so the result is shoud be :
| idrule | orders |
-----------------------
|R01#1 | 1 |
|R01#3 | 3 |
-----------------------
and this is the syntax for first elimination :
SELECT idrule
FROM rulestbl
WHERE idsys IN (1, 2)
GROUP BY idrule
HAVING count(*) = 2
so next we elimination MIN(order) is 1 so the finally result is :
| idrule | orders |
------------------------
|R01#1 | 1 |
------------------------

This should work ;-)
SELECT X.IDRULE, MIN(X.ORDERS) FROM rulestbl,
(
SELECT idrule, orders
FROM rulestbl
WHERE idsys IN (1, 2)
GROUP BY idrule
HAVING count(*) = 2
) X
WHERE X.idrule = rulestbl.idrule
inside IN clause you can split your array.
Good luck

Related

Postgresql: Group rows in a row and add array

Hi i have a table like this;
+----+----------+-------------+
| id | room_id | house_id |
+----+----------+-------------+
| 1 | 1 | 1 |
| 2 | 2 | 1 |
| 3 | 3 | 1 |
| 4 | 1 | 2 |
| 5 | 2 | 2 |
| 6 | 3 | 2 |
| 7 | 1 | 3 |
| 8 | 2 | 3 |
| 9 | 3 | 3 |
+----+-------+----------------+
and i want to create a view like this
+----+----------+-------------+
| id | house_id | rooms |
+----+----------+-------------+
| 1 | 1 | [1,2,3] |
| 2 | 2 | [1,2,3] |
| 3 | 3 | [1,2,3] |
+----+-------+----------------+
i tried many ways but i cant gruop them in one line
Thanks for any help.
You can use array_agg():
select house_id, array_agg(room_id order by room_id) as rooms
from t
group by house_id;
If you want the first column to be incremental, you can use row_number():
select row_number() over (order by house_id) as id, . . .

Using LAG function with higher offset

Suppose we have the following input table
cat | value | position
------------------------
1 | A | 1
1 | B | 2
1 | C | 3
1 | D | 4
2 | C | 1
2 | B | 2
2 | A | 3
2 | D | 4
As you can see, the values A,B,C,D change position in each category, I want to track this change by adding a column change in front of each value, the output should look like this:
cat | value | position | change
---------------------------------
1 | A | 1 | NULL
1 | B | 2 | NULL
1 | C | 3 | NULL
1 | D | 4 | NULL
2 | C | 1 | 2
2 | B | 2 | 0
2 | A | 3 | -2
2 | D | 4 | 0
For example C was in position 3 in category 1 and moved to position 1 in category 2 and therefore has a change of 2. I tried inmplementing this using the LAG() function with an offset of 4 but I failed, how can I write this query.
Use lag() - with the proper partition by clause:
select
t.*,
lag(position) over(partition by value order by cat) - position change
from mytable t
You can use lag and then order by to maintain original order. Here is the demo.
select
*,
lag(position) over (partition by value order by cat) - position as change
from yourTable
order by
cat, position
output:
| cat | value | position | change |
| --- | ----- | -------- | ------ |
| 1 | A | 1 | null |
| 1 | B | 2 | null |
| 1 | C | 3 | null |
| 1 | D | 4 | null |
| 2 | C | 1 | 2 |
| 2 | B | 2 | 0 |
| 2 | A | 3 | -2 |
| 2 | D | 4 | 0 |
I think you just want lag() with the right partition by:
select t.*,
(lag(position) over (partition by value order by cat) - position) as change
from t;
Here is a db<>fiddle.

Semi-transposing a table in Oracle

I am having trouble semi-transposing the table below based on the 'LENGTH' column. I am using an Oracle database, sample data:
+-----------+-----------+--------+------+
| PERSON_ID | PERIOD_ID | LENGTH | FLAG |
+-----------+-----------+--------+------+
| 1 | 1 | 4 | 1 |
| 1 | 2 | 3 | 0 |
| 2 | 1 | 4 | 1 |
+-----------+-----------+--------+------+
I would like to lengthen this table based on the LENGTH row; basically duplicating the row for each value in the LENGTH column.
See the desired output table below:
+-----------+-----------+--------+------+
| PERSON_ID | PERIOD_ID | NUMBER | FLAG |
+-----------+-----------+--------+------+
| 1 | 1 | 1 | 1 |
| 1 | 1 | 2 | 1 |
| 1 | 1 | 3 | 1 |
| 1 | 1 | 4 | 1 |
| 1 | 2 | 1 | 0 |
| 1 | 2 | 2 | 0 |
| 1 | 2 | 3 | 0 |
| 2 | 1 | 1 | 1 |
| 2 | 1 | 2 | 1 |
| 2 | 1 | 3 | 1 |
| 2 | 1 | 4 | 1 |
+-----------+-----------+--------+------+
I typically work in Posgres so Oracle is new to me.
I've found some solutions using the connect by statement but they seem overly complicated, particularly when compared to the simple generate_series() command from Posgres.
A recursive CTE subtracting 1 from length until 1 is reached should work. (In Postgres too, BTW, should you need something working cross platform.)
WITH cte (person_id,
period_id,
number_,
flag)
AS
(
SELECT person_id,
period_id,
length number_,
flag
FROM elbat
UNION ALL
SELECT person_id,
period_id,
number_ - 1 number_,
flag
FROM cte
WHERE number_ > 1
)
SELECT *
FROM cte
ORDER BY person_id,
period_id,
number_;
db<>fiddle

How to select if similar field count is the maximum in the table?

I want to select from a table if row counts of similar filed is maximum depends on other columns.
As example
| user_id | team_id | isOk |
| 1 | 1 | 1 |
| 2 | 1 | 1 |
| 3 | 1 | 1 |
| 4 | 1 | 1 |
| 5 | 2 | 1 |
| 6 | 2 | 1 |
| 7 | 2 | 1 |
| 8 | 3 | 1 |
| 9 | 3 | 1 |
| 10 | 3 | 1 |
| 11 | 3 | 0 |
So i want to select team 1 and 2 because they all have 1 value at isOk Column,
i tried to use this query
SELECT Team
FROM _Table1
WHERE isOk= 1
GROUP BY Team
HAVING COUNT(*) > 3
But still i have to define a row count which can be maximum or not.
Thanks in advance.
Is this what you are looking for?
select team
from _table1
group by team
having min(isOk) = 1;

SQL Query in MANY- MANY RELATIONSHIP exactly one record with matching criteria

I have 3 like with many - many relationship
As:
TABLE 1 : select * from student;
| id | name |
| 1 | sone |
| 2 | stwo |
| 3 | sthree |
| 4 | sfour |
| 6 | ssix |
TABLE 2 : select * from course;
| id | name |
| 100 | CSE |
| 101 | ECE |
| 102 | ITI |
RELATION_SHIP TABLE : select * from student_course
| id | stu_id | cou_id |
| 1 | 1 | 101 |
| 2 | 2 | 102 |
| 3 | 2 | 100 |
| 4 | 3 | 100 |
| 5 | 3 | 101 |
| 6 | 1 | 101 |
| 1 | 6 | 101 |
I need to write a query to select a student with exactly one course 'CSE' and he should not have any other courses.
Thanks in advance
Use query:
SELECT
sc.`stu_id`,
COUNT(sc.`cou_id`) AS cnt
FROM
student_course sc
GROUP BY sc.`stu_id`
HAVING cnt = 1
AND GROUP_CONCAT(cou_id) LIKE
(SELECT
id
FROM
course
WHERE NAME = 'CSE')