This SQL produces the following:
SELECT city FROM travel_logs ORDER BY ST_Distance(travel_logs.start_point, ST_GeographyFromText('SRID=4326;POINT(101.652506 3.167610)'))
"Tshopo"
"Tshopo"
"Mongala"
"Haut-Komo"
This SQL produces the following:
SELECT city, count(*) AS count FROM travel_logs GROUP BY travel_logs.start_point, city ORDER BY ST_Distance(travel_logs.start_point, ST_GeographyFromText('SRID=4326;POINT(101.652506 3.167610)'))
"Tshopo";1
"Tshopo";1
"Mongala";1
"Haut-Komo";1
Basically, I want the result like this that groups by city and the number of times same city occurs. something like this
"Tshopo";2 <--- its summed up correctly
"Mongala";1
"Haut-Komo";1
Im not an expert on joins, subquery, would that help ? Thanks in advance.
this worked for me:
select city, count(*) as count
from
(SELECT city FROM travel_logs ORDER BY ST_Distance(travel_logs.start_point, ST_GeographyFromText('SRID=4326;POINT(101.652506 3.167610)'))
) as subquery_travel_logs_nearest group by city
Simple, plain SQL without a sub-query:
SELECT city, count(*)
FROM travel_logs
GROUP BY city
ORDER BY ST_Distance(start_point,
ST_GeographyFromText('SRID=4326;POINT(101.652506 3.167610)'));
Related
I have a table of car accident in a major city, and the structure is like:
accident_table has the following columns:
id, caseno, date_of_occurrence, street, iucr, primary_type,
description, district, community_area, year, updated_on
I want to write a query that finds the street which has the most accidents for each district(I think the street count for each street is the number of accident that happened on that street).
Here is what I have:
SELECT DISTINCT on (street)
street,
district
FROM
(
SELECT
count(street) as street_cnt,
street,
district
FROM accident_table
)
WHERE street_count = (SELECT max(street_cnt))
It did not give me syntax error, but timed out, so I guess it took too long to run.
What's wrong and how to fix it?
Thanks,
Philip
First aggregate to get the count of accidents for each street. Then use the rank() window function to rank the streets within a district by the count of accidents in them. Then only select the ones that were ranked at the top.
SELECT x.district,
x.street,
x.accidents
FROM (SELECT a.district,
a.street,
count(*) accidents,
rank() OVER (PARTITION BY a.district
ORDER BY count(*) DESC) r
FROM accident_table a
GROUP BY a.district,
a.street) x
WHERE x.r = 1;
Your code looks like Postgres. In that database, you can express this without a subquery:
SELECT DISTINCT ON (a.district)
a.district, a.street, COUNT(*) as accidents
FROM accident_table a
GROUP BY a.district, a.street
ORDER BY a.district, COUNT(*) DESC;
That said, your problem is performance, which is probably not affected by subqueries. An index on accident_table(district, street) might help performance.
I have this table data:
I want to perform an sql query which will give me the total number of distinct loan applications per city.
So for example, I would expect this output
City Wexford
Loans 1
City Waterford 1
Loans 1
City Galway
Loans 3
Any idea what kind of query I need to perform to get the count of distinct loans for each city?
I would guess, probably a COUNT (Distinct ID) with GROUP BY. Something like this:
SELECT city, COUNT(DISTINCT LoanApplicationID) as Loans
FROM tableName
GROUP BY city
Here is another approach for this question. I am adding this because using DISTINCT may cause performance issues for another example, especially for large databases. Good to keep in mind.
select city,count(LoanApplicationID) as Loans
from (
select LoanApplicationID, city
from tablename
group by LoanApplicationID, city
) t
group by city
I want to know how many items of distinct name I have in my database.
When I use:
select count(distinct name) from products
I obviously gain only number of different, distinct names I have in my
database. I was experimenting with group by, but as a total beginner I
failed. I'll appreciate any help.
Group by name and use count() to get the counts for each group
select name, count(*)
from products
group by name
select count(name) as ct, name from products group by name
SELECT NAME, COUNT(*) FROM products GROUP BY name
Looking for sql to get distinct names and count of those names from a sql table:
Structure:
id
name
other details
Do I use distinct to get each group and then count through those to get:
name1 count(name1)
name2 count(name2)
etc
Thanks
Rob.
When you want a COUNT() or a SUM(), you're using an AGGREGATE FUNCTION based on a GROUP BY clause.
As GROUP BY brings together all records with the same values specified in the GROUP BY columns, you're already getting the same effect as DISTINCT.
Except that DISTINCT doesn't allow aggregates, and GROUP BY does.
SELECT
name,
COUNT(*) AS count_of_name
FROM
yourTable
GROUP BY
name
Try :
SELECT *, COUNT(*) FROM my_table GROUP BY name
Something like this?
select name,COUNT(name) FROM Persons GROUP BY name
In the end I used:
SELECT DISTINCT `school`,COUNT(`school`) AS cat_num FROM table GROUP BY school order by cat_num DESC
I have a table of users, and in this table I have a country field telling where these people are from (i.e. "Sweden", "Italy", ...). How can I do a SQL query to get something like:
Country Number
Sweden 10
Italy 50
... ...
Users select their countries from a list I give to them, but the list is really huge so it would be great to have a SQL query that can avoid using that list, that is look in the DB and give back only those countries which are in the database, because for example I have nobody from Barbados, even if I have that option in the country select field of the signup form :)
Thanks in advance!
If the name of the country is in the Users table, try something like this:
SELECT Country, COUNT (*) AS Number
FROM Users
GROUP BY Country
ORDER BY Country
If the name of the country is in the country table, then you will have to join
SELECT Contries.CountryName, Count (*) AS Number
FROM Users
INNER JOIN Countries
ON Users.CountryId = Countries.CountryId
GROUP BY Countries.CountryName
ORDER BY Countries.CountryName
This will give what you want. But you might want to cache the result of the query. With a lot of users it's quite a heavy query.
SELECT
country,
COUNT(*)
FROM
users
GROUP BY
country
Perhaps a better idea is (assuming you don't need the counts) to do it like this:
SELECT
DISTINCT country
FROM
users
Sounds like you want something like this...?
SELECT Country, COUNT(*) AS Number
FROM Users
GROUP BY Country
This is pretty straightforward:
SELECT
Country, COUNT(*) AS 'Number'
FROM
YourTable
GROUP BY
Country
ORDER BY
Country
You just group your data by country and count the entries for each country.
Or if you want them sorted by the number of visitors, use a different ORDER BY clause:
SELECT
Country, COUNT(*) AS 'Number'
FROM
YourTable
GROUP BY
Country
ORDER BY
COUNT(*) DESC
If you want the count per country:
select country, count(*) from users group by country;
If you just want the possible values:
select distinct country from users;
SELECT BillingCountry, COUNT(*)as Invoices
FROM Invoice
GROUP BY BillingCountry
ORDER BY Invoices DESC