Awk print different character on seperate line - awk

Question

I have been search aorund and could not find the answer... wonder if anyone can help here.
suppose I have a file contents the following:
File1:
name Joe
day Wednesday
lunch was fish
name John
dinner pie
day tuesday
lunch was noodles
name Mary
day Friday
lunch was fish pie
I wanted to grep and print only their name and what they had for lunch.
I suppose i can do
cat file1 | grep -iE 'name|lunch'
but what if i want to do a awk to just have their name and food like this output below?
Joe
fish
John
noodles
Mary
fish pie
I am aware to use awk to print, but this may require awk, is it possible for awk to lets say print $2 on one line, and print $3 on another?
Can I also output it in this format:
Person food
Joe fish
John noodles
Mary fish pie
Thanks

Answer 1

You can for example say:
$ awk '/name/ {print $2} /lunch/ {$1=$2=""; print}' file
Joe
fish
John
noodles
Mary
fish pie
Or remove the lunch was text:
awk '/name/ {print $2} /lunch/ {gsub("lunch was ",""); print}' file
To make the output in two columns:
$ awk -v OFS="\t" '/name/ {name=$2} /lunch/ {gsub("lunch was ",""); print name, $0}' a
Joe fish
John noodles
Mary fish pie

Answer 2

awk
with awk you can do it in one shot,
awk -v RS="" '{n=$2;sub(/.*lunch was\s*/,"");print n,$0}' file
Note that with this one-liner, the format of your input file should be fixed. Your data should be stored in data blocks and lunch was line should be at the end of each data block.
test with your example:
kent$ awk -v RS="" '{n=$2;sub(/.*lunch was\s*/,"");print n,$0}' file
Joe fish
John noodles
Mary fish pie
grep & sed
also you can do it in two steps, grep the values out, and merge lines
grep -Po 'name\s*\K.*|lunch was\s*\K.*' file|sed 'N;s/\n/ /'
with your input file, it outputs:
kent$ grep -Po 'name\s*\K.*|lunch was\s*\K.*' file|sed 'N;s/\n/ /'
Joe fish
John noodles
Mary fish pie