I have this table with two columns:
Price Date
45.00 12/06/2015 12:32:54 AM
455.98 22/06/2015 11:00:32 AM
32.00 08/07/2015 09:11:45 AM
98.00 11/07/2015 19:22:32 PM
(the date is in the format DD/MM/YYYY)
I need to get the sum of prices grouped by month and for this I need to find a code in sqlite that cut some parts of that date only getting the month (...06...)(...07...). Below is my code used for some parts of the SELECT:
SELECT SUM(CAST(price as INTEGER)) as TOTALPERMONTH FROM cart_history GROUP BY ....... ORDER BY ID
How I can grouped by some parts of that row?
Use STRFTIME function
select SUM(CAST(price as INTEGER)) as Total,
strftime('%m', dateField) as Month
From yourtable
Group by strftime('%m', dateField)
use HAVING clause.
SELECT SUM(CAST(price as INTEGER)) as TOTALPERMONTH
FROM cart_history,Date
GROUP BY Date
HAVING Date IN('your dates ')'
Related
i am trying to work with this query to produce a list of all 11 years and 12 months within the years with the sales data for each month. Any suggestions? this is my query so far.
SELECT
distinct(extract(year from date)) as year
, sum(sale_dollars) as year_sales
from `project-1-349215.Dataset.sales`
group by date
it just creates a long list of over 2000 results when i am expecting 132 max one for each month in the years.
You should change your group by statement if you have more results than you expected.
You can try:
group by YEAR(date), MONTH(date)
or
group by EXTRACT(YEAR_MONTH FROM date)
A Grouping function is for takes a subsection of the date in your case year and moth and collect all rows that fit, and sum it up,
So a s´GROUp BY date makes no sense, what so ever as you don't want the sum of every day
So make this
SELECT
extract(year from date) as year
,extract(MONTH from date) as month
, sum(sale_dollars) as year_sales
from `project-1-349215.Dataset.sales`
group by 1,2
Or you can combine both year and month
SELECT
extract(YEAR_MONTH from date) as year
, sum(sale_dollars) as year_sales
from `project-1-349215.Dataset.sales`
group by 1
customer Date location
1 25Jan2018 texas
2 15Jan2018 texas
3 12Feb2018 Boston
4 19Mar2017 Boston.
I am trying to find out count of customers group by yearmon of Date column.Date column is of text data type
eg: In jan2018 ,the count is 2
I would do something like the following:
SELECT
date_part('year', formattedDate) as Year
,date_part('month', formattedDate) as Month
,count(*) as CustomerCountByYearMonth
FROM
(SELECT to_date(Date,'DDMonYYYY') as formattedDate from <table>) as tbl1
GROUP BY
date_part('year', formattedDate)
,date_part('month', formattedDate)
Any additional formatting for dates could be done on the inner query that will allow for adjustments in case some single digit days need to be padded or a month has four letters instead of three etc.
By converting to date type, you can properly order by date type and not alphabetical etc.
Optionally:
SELECT
Year
,Month
,count(*) as CustomerCountByYearMonth
FROM
(SELECT
date_part('year', to_date(Date,'DDMonYYYY')) as Year
,date_part('month', to_date(Date,'DDMonYYYY')) as Month
FROM <table>) as tbl1
GROUP BY
Year
,Month
You shouldn't store dates in a text column...
select substring(Date, length(Date)-6), count(*)
from tablename
group by substring(Date, length(Date)-6)
I thought #Jarlh asked a good question -- what about dates like January 1? Is it 01Jan2019 or 1Jan2019? If it can be either, perhaps a regex would work.
select
substring (date from '\d+(\D{3}\d{4})') as month,
count (distinct customer)
from t
group by month
The 'distinct customer' also presupposes you may have the same customer listed in the same month, but you only want to count it once. If that's not the case, just remove 'distinct.'
And, if you wanted the output in date format:
select
to_date (substring (date from '\d+(\D{3}\d{4})'), 'monyyyy') as month,
count (distinct customer)
from t
group by month
If it is a date column, you can truncate the date:
select date_trunc('month', date) as yyyymm, count(*)
from t
group by yyyymm
order by yyyymm;
I really read that the type was date. For a string, just use string functions:
select substr(date, 3, 7) as mmmyyyy, count(*)
from t
group by mmmyyyy;
Unfortunately, ordering doesn't work in this case. You should really be storing dates using the proper type.
I have a table called "Data". With columns: "Number" and "EntryDate".
The EntryDate is Datetime( Y-m-d h:i:s ).
I need to calculate the sum of all entries from a date ignore h:i:s, group them by the date.
Example:
Number | EntryDate
-------------------
23 | 2018-10-01 13:22:10.520
25 | 2018-10-01 11:16:09.533
So basically I need to SUM the Number from 2018-10-01.
I have tried several variations but nothing seems to work, for example:
SELECT
SUM(Number) as 'Sum',
EntryDate AS DATE
FROM Data
GROUP BY EntryDate
Use cast() function for converting datetime to date
SELECT
SUM(Number) as 'Sum', cast(EntryDate as date) AS `DATE`
FROM Data
GROUP BY cast(EntryDate as date
Your date is at the moment in the datetime format, hence if you select date within your select query, you wont really get the date, instead you would get the respective datetimes.
What you can do is Convert the EntryDate as date:
Try:
select sum(number) as 'Sum', convert(date,EntryDate) as 'Date'
from Data
group by convert(date,EntryDate)
Should work.
Go seek more information from here https://www.w3schools.com/sql/func_sqlserver_convert.asp
Cheers
I have table like this
PartID Quantity Date
12315 1 2017-01-24
51245 3 2017-01-26
12345 4 2017-02-20
12415 1 2017-02-25
..... .. ...........
I need for the report result like:
Monthly Quantity January: 4
Monthly Quantity February: 5
So in my report - every column should have the name of month and include all quantities (count) for this month. Any help would be appreciated.
I think you are looking for a query like:
select month(Date), sum(Quantity)
from table
group by month(Date)
In MS SQL :
You can use something like this:
DATENAME() function returns a specified part of a given date, as a string value.
To know more about DATENAME(), please visit https://www.w3schools.com/sql/func_sqlserver_datename.asp
CAST() function converts an expression from one data type to another data type.
To know more about CAST(), please visit https://www.w3schools.com/sql/func_sqlserver_cast.asp
SELECT
MONTH(Date) AS MonthNo,
'Monthly Quantity ' + DATENAME(MONTH, date) + ' : ' + CAST(SUM(Quantity) AS nvarchar(10)) AS Monthwise
FROM parttable
GROUP BY DATENAME(MONTH, date),
MONTH(Date)
ORDER BY MONTH(Date)
So the output will be
Two options you can have :
1) create another column and store name of month in it .
PartID Quantity Date. Month
12315 1 2017-01-24. January
51245 3 2017-01-26. January
12345 4 2017-02-20. February
12415 1 2017-02-25. February
And use below query to get the report as you needed :
Select sum(Quantity) as total_quantity, Month from table group by Month
2) by using inbuilt date and time functions of MySQL.
Select sum(Quantity) as total_quantity, Month(Date) as month from table group by Month(Date)
Which database are you using?
On SQL Server:
SELECT
DATENAME(month, Date) AS 'Month Name', SUM(Quantity)
FROM table
GROUP BY DATENAME(month, Date)
Im trying to group quantities regarding a time or period, i have the next table
SALES
SALES_DATE
SALES_ITEM
SALES_QUANTITY
The query that im doing it's
SELECT DATE,ITEM,SUM(QUANTITY)
FROM SALES
WHERE DATE BETWEEN "DATE1" AND "DATE2";
The problem is that i dont need the DATE to appear, if i look for the sales of october it should appear the sum of october without showing the date... Thank you very much for your help
Example:
What i get...
DATE ITEM SALES
2012-06-12 14152 7
2012-06-14 14152 15
2012-06-16 14157 25
What i need: query between 06-12 and 06-16
ITEM SALES
14152 22
14157 25
Thanks you very much
If you want the sum by month, you can include that in the group by expression. Here is one way:
SELECT extract(year from DATE) as yr, extract(month from date) as mon, ITEM, SUM(QUANTITY)
FROM SALES
WHERE DATE BETWEEN "DATE1" AND "DATE2"
group by extract(year from DATE), extract(month from date)
order by 1, 2
Although extract is standard SQL, not all databases support it. For instance, you might use to_char(date, 'YYYY-MM') in Oracle or datepart(month, date) in SQL Server.