I am working on leave management system plugin so want to show application menu under lms menu.... here i past my init file code
menu :top_menu, :leave_transactions, { :controller => 'dashboard', :action => 'index' }, :caption => 'LMS' , :if => Proc.new { User.current.logged? }
menu :application_menu, :dashboard, { :controller => 'dashboard', :action => 'index' }, :caption => 'Dashboard' , :if => Proc.new { User.current.logged? }
menu :application_menu, :leave_transactions, { :controller => 'leave_transactions', :action => 'index' }, :caption => 'Apply Leave' , :if => Proc.new { User.current.logged? }
menu :application_menu, :holiday_informations, { :controller => 'holiday_informations', :action => 'index' }, :caption => 'Holiday' , :if => Proc.new { User.current.logged? }
Its working for me but application menu display all over menu. so i want to avoid this and when I click on lms menu that time application menu display..please help me
Related
I use the AuthComponent and I want when the session expires and the user press a link or refreshes, to redirect him on the login page.
However for some actions I don't want above redirect, even if user is logged out, as they are used as an API by another application also.
For example, I want to allow the 'view' action for logged-out users, but redirect the 'index' action.
My AppController.php is:
$this->loadComponent('Auth', [
'authorize' => [
'Acl.Actions' => ['actionPath' => 'controllers/']
],
'authenticate' => [
'Form' => [
'fields' => [
'username' => 'username',
'password' => 'password'
]
]
],
'loginAction' => [
'plugin' => false,
'controller' => 'Users',
'action' => 'login'
],
'loginRedirect' => [
'controller' => 'Pages',
'action' => 'index',
'plugin' => 'Pages'
],
'logoutRedirect' => [
'plugin' => false,
'controller' => 'Users',
'action' => 'login'
],
]);
If I add below, 'index' is also working if user is logged-out, even though it should be in deny state.
MyController.php
public function beforeFilter(\Cake\Event\Event $event)
{
$this->Auth->allow('view');
The only way I managed to do what I want is to add it in the controller action as:
MyController.php
public function index()
{
if (empty($this->auth_user['username'])) {
return $this->redirect($this->Auth->logout());
}
Is there a better way to do this?
There are two types of users in the application I am developing. Users (table users.sql) for frontend users and AdminUsers (table admin_users.sql) for administration.
In CakePHP3, I solved this problem as follows with AuthComponent in AppController:
public function initialize()
{
parent::initialize();
// ...
//user login
if (!empty($this->request->params['prefix']) AND
$this->request->params['prefix'] == 'admin'
) {
$this->setAdminLogin();
}else{
$this->setUserLogin();
$this->Auth->allow();
}
// ...
}
//frontend users
public function setUserLogin()
{
$this->loadComponent('Auth', [
'authorize' => ['Controller'],
'loginAction' => [
'controller' => 'Users',
'action' => 'login'
],
'loginRedirect' => [
'controller' => 'Users',
'action' => 'edit'
],
'logoutRedirect' => [
'controller' => 'Users',
'action' => 'login'
],
'authError' => false,
'authenticate' => [
'Xety/Cake3CookieAuth.Cookie' => [
'userModel' => 'Users',
'scope' => ['Users.active' => 1],
'fields' => ['username' => 'email','password' => 'password'],
],
'Form' => [
'userModel' => 'Users',
'scope' => ['Users.active' => 1],
'fields' => ['username' => 'email','password' => 'password'],
'passwordHasher' => [
'className' => 'Fallback',
'hashers' => ['Default']
]
],
],
'storage' => ['className' => 'Session', 'key' => 'Auth.User']
]);
}
//admin users
public function setAdminLogin()
{
$this->loadComponent('Auth', [
'authorize' => ['Controller'],
'loginAction' => [
'controller' => 'AdminUsers',
'action' => 'login',
],
'loginRedirect' => [
'controller' => 'AdminHelps',
'action' => 'index'
],
'logoutRedirect' => [
'controller' => 'AdminUsers',
'action' => 'login'
],
'authError' => false,
'authenticate' => [
'Form' => [
'userModel' => 'AdminUsers',
'scope' => ['AdminUsers.active' => 1],
'fields' => ['username' => 'email','password' => 'password'],
'passwordHasher' => [
'className' => 'Fallback',
'hashers' => ['Default']
]
],
],
'storage' => ['className' => 'Session', 'key' => 'Auth.AdminUser']
]);
}
How can I do the same thing in CakePHP4 version with Authentication plugin? How can I create multiple user login?
Even when user is not logged in and tries to open homepage, after being redirected to login page, authError is displayed.Is there an elegant way to prevent this, without modifying Auth component? This is how I load Auth component(I am using TinyAuth as authorization adapter):
$this->loadComponent('Auth', [
'loginAction' => [
'controller' => 'Users',
'action' => 'login'
],
'loginRedirect' => [
'controller' => 'Home',
'action' => 'index'
],
'authError' => 'You dont have permissions for that action',
'authenticate' => [
'Form' => [
'fields' => [
'username' => 'email',
'password' => 'password'
],
'scope' => ['Users.active' => true],
'contain' => ['Roles']
]
],
'authorize' => [
'TinyAuth.Tiny' => [
'roleColumn' => 'role_id',
'rolesTable' => 'Roles',
'multiRole' => true,
'pivotTable' => 'roles_users',
'superAdminRole' => null,
'authorizeByPrefix' => false,
'prefixes' => [],
'allowUser' => false,
'adminPrefix' => null,
'autoClearCache' => true
]
]
]
);
According to CakePHP's documentation you can prevent the error message from being shown by setting authError to false.
Sometimes, you want to display the authorization error only after the
user has already logged-in. You can suppress this message by setting
its value to boolean false.
This should disable the error message:
if (!$this->Auth->user()) {
$this->Auth->config('authError', false);
}
the gridview if on right of the page,left is some menus,when click on page no 2，it dose not only refresh the gridview，but all page including left part are lost——a totally new page come out！help~
there is the debugging Screenshot：
my action is
public function actionList()
{
$model = new Loan();
$dataProvider = new ActiveDataProvider([
'query' => $model->find(),
'pagination' => [
'pagesize' => '1',
],
]);
return $this->renderPartial('list', ['model' => $model, 'dataProvider' => $dataProvider]);
}
my view is：
<?php
use yii\grid\GridView;
use yii\grid\SerialColumn;
use yii\helpers\Html;
use yii\helpers\Url;
use yii\widgets\LinkPager;
?>
<?=GridView::widget([
'dataProvider' => $dataProvider,
'layout'=> '{items}{pager}',
'columns' => [
['attribute' =>'loan_type','label'=>'借款类型','options' => ['width' => '80']],
['attribute' =>'amount','label'=>'金额','options' => ['width' => '80']],
['attribute' =>'rate','label'=>'还款利率','options' => ['width' => '80']],
['attribute' =>'fee','label'=>'手续费','options' => ['width' => '80']],
['attribute' =>'status','label'=>'状态','options' => ['width' => '80'] ],
['attribute' =>'comment','label'=>'审核意见','options' => ['width' => '80']],
['attribute' => 'created_at','value' =>function($model){return date('Y-m-d',strtotime($model->created_at));},'label'=>'申请时间','options' => ['width' => '150']],
[
'class' => 'yii\grid\ActionColumn',
'header' => '操作',
'template' => '{audit}',
'buttons' => [
'audit' => function ($url,$model) {
return Html::a('<span id="xxxx" class="glyphicon glyphicon-user"></span>','#',['title'=>'审核',
'onclick'=>"
$.ajax({
type: 'GET',
dataType: 'text',
url: 'http://182.92.4.87:8000/index.php?r=loan/pj', //目标地址
error: function (XMLHttpRequest, textStatus, errorThrown) {alert(XMLHttpRequest.status + ':' + XMLHttpRequest.statusText); },
success: function (page)
{
$('.ucRight').html(page);
}
});
return false;",
]);},
],
'urlCreator' => function ($action, $model, $key, $index) {
return Yii::$app->getUrlManager()->createUrl(['loan/list','id' => $model->status]);
},
'headerOptions' => ['width' => '80'],
],
],
]);
?>
The reason for your problem is that you haven't prevented the html link from directing to a new page, so your user is clicking on the link, which then loads a new page with the contents returned by the server; in this case a page of information with no layout applied. You need to add event.preventDefault() before the ajax call to stop this behaviour.
However, as #arogachev said, if you simply want to use pagination without a page refresh, then just use pjax. That is what pjax is designed for,
I have a print layout in haml for generating pdfs:
= link_to I18n.t('eda.print'), {:controller => :persons, :action => :print}, :method => '', :remote => false
Is there a way to have a javascript popup for confirmation like "are you sure?" just before executing the print method?
Non-javascript way:
= link_to I18n.t('eda.print'), {:controller => :persons, :action => :print},
:method => '', :remote => false, :data => {:confirm => 'Are you Sure ?' }
On clicking the link, it'll ask for user confirmation 'Are you Sure?' If you proceed further then respective controller -> action will be triggered.