I'm stuck trying to transpose a set of rows into a table. In my stored procedure, I take a delimited string as input, and need to transpose it.
SELECT *
FROM string_split('123,4,1,0,0,5|324,2,0,0,0,4','|')
CROSS APPLY string_split(value,',')
From which I receive:
value value
123,4,1,0,0,5 123
123,4,1,0,0,5 4
123,4,1,0,0,5 1
123,4,1,0,0,5 0
123,4,1,0,0,5 0
123,4,1,0,0,5 5
324,2,0,0,0,4 324
324,2,0,0,0,4 2
324,2,0,0,0,4 0
324,2,0,0,0,4 0
324,2,0,0,0,4 0
324,2,0,0,0,4 4
The values delimited by | are client details. And within each client, there are six attributes, delimited by ,. I would like an output table of:
ClientId ClientTypeId AttrA AttrB AttrC AttrD
------------------------------------------------
123 4 0 0 0 5
324 2 0 0 0 4
What's the best way to go about this? I've been looking at PIVOT but can't make it work because it seems like I need row numbers, at least.
This answer assumes that row number function will "follow the order" of the string. If it does not you will need to write your own split that includes a row number in the resulting table. (This is asked on the official documentation page but there is no official answer given).
SELECT
MAX(CASE WHEN col = 1 THEN item ELSE null END) as ClientId,
MAX(CASE WHEN col = 2 THEN item ELSE null END) as ClientTypeId,
MAX(CASE WHEN col = 3 THEN item ELSE null END) as AttrA,
MAX(CASE WHEN col = 4 THEN item ELSE null END) as AttrB,
MAX(CASE WHEN col = 5 THEN item ELSE null END) as AttrC,
MAX(CASE WHEN col = 6 THEN item ELSE null END) as AttrD
FROM (
SELECT A.value as org, B.value as item,
ROW_NUMBER() OVER (partition by A.value) as col
FROM string_split('123,4,1,0,0,5|324,2,0,0,0,4','|') as A
CROSS APPLY string_split(A.value,',') as B
) X
GROUP BY org
You might get a message about nulls in aggregate function ignored. (I always forget which platforms care and which don't.) If you do you can replace the null with 0.
Note, this is not as fast and using a CTE to find the 5 commas in the string with CHARINDEX and then using SUBSTRING to extract the values. But I'm to lazy to write up that solution which I would need to test to get all the off by 1 issues right. Still, I suggest you do it that way if you have a big data set.
I know you already got it pretty much answered, but here you can find a PIVOT solution
select [ClientID],[ClientTypeId],[AttrA],[AttrB],[AttrC],[AttrD]
FROM
(
select case when ColumnRow = 1 then 'ClientID'
when ColumnRow = 2 then 'ClientTypeId'
when ColumnRow = 3 then 'AttrA'
when ColumnRow = 4 then 'AttrB'
when ColumnRow = 5 then 'AttrC'
when ColumnRow = 6 then 'AttrD' else null end as
ColumnRow,t.value,ColumnID from (
select ColumnID,z.value as stringsplit,b.value, cast(Row_number()
over(partition by z.value order by z.value) as
varchar(50)) as ColumnRow from (SELECT cast(Row_number() over(order by
a.value) as
varchar(50)) as ColumnID,
a.value
FROM string_split('123,4,1,0,0,5|324,2,0,0,0,4','|') a
)z
CROSS APPLY string_split(value,',') b
)t
) AS SOURCETABLE
PIVOT
(
MAX(value)
FOR ColumnRow IN ([ClientID],[ClientTypeId],[AttrA],[AttrB],[AttrC],
[AttrD])
)
AS
PivotTable
I am attempting to set values to zero if a user does not exist in one of my tables. Currently, I am using decode to count the number of users that meet a certain criteria and then display the result.
SELECT T.D_CODE,
T.C_NO,
SUM(DECODE(t.Value, 'A', 1, 0)) AS FirstValue,
SUM(DECODE(t.Value, 'B', 1, 0)) AS SecondValue,
SUM(DECODE(t.Value, 'C', 1, 0)) AS ThirdValue,
SUM(DECODE(t.Value, 'F', 1, 0)) AS LastValue
FROM Table T,
Table OtherTable S
WHERE T.T_SSN = S.SSN(+)
AND T.D_CODE = 'INF'
GROUP BY t.D_CODE,
T.C_NO;
The issue is that I have a third table (TT) that has additional values in it. If TT has a value that is not present in Table T, then I need to display that record with 0's for all of the Decode values.
Required output would look something like:
D_CODE, C_NO, FirstValue, SecondValue, ThirdValue, LastValue
INF 600 2 0 0 0
INF 501 0 0 1 0
INF 400 0 0 0 0
Where INF 400 does not exist in Table t, only in Table TT
Any suggestions?
Your problem is that you are filtering the users by T.D_CODE = 'INF' which means that any user that does not met that criteria will not come at all in the results. So, for what I understood of your question you need this:
SELECT T.D_CODE,
T.C_NO,
SUM(CASE WHEN T.D_CODE = 'INF' AND t.Value = 'A' THEN 1 ELSE 0 END) AS FirstValue,
SUM(CASE WHEN T.D_CODE = 'INF' AND t.Value = 'B' THEN 1 ELSE 0 END) AS AS SecondValue,
SUM(CASE WHEN T.D_CODE = 'INF' AND t.Value = 'C' THEN 1 ELSE 0 END) AS AS ThirdValue,
SUM(CASE WHEN T.D_CODE = 'INF' AND t.Value = 'D' THEN 1 ELSE 0 END) AS AS LastValue
FROM Table T
LEFT JOIN Table OtherTable S
ON T.T_SSN = S.SSN
LEFT JOIN AnotherTable TT
ON T.T_SSN = TT.SSN
GROUP BY t.D_CODE,
T.C_NO;
Since you didn't provide any more details about your TT table I just guessed the relation between it and the T table.
Side note: Always use the SQL ANSI [LEFT ]JOINs style.
ALSO Note that for your current query and current fetched fields tables S and TT are totally irrelevant, unless you didn't explain it right.
I will keep this simple- I would like to know if there is a good way to select all the values in a column when it never has a null in another column. For example.
A B
----- -----
1 7
2 7
NULL 7
4 9
1 9
2 9
From the above set I would just want 9 from B and not 7 because 7 has a NULL in A. Obviously I could wrap this as a subquery and USE the IN clause etc. but this is already part of a pretty unique set and am looking to keep this efficient.
I should note that for my purposes this would only be a one-way comparison... I would only be returning values in B and examining A.
I imagine there is an easy way to do this that I am missing, but being in the thick of things I don't see it right now.
You can do something like this:
select *
from t
where t.b not in (select b from t where a is null);
If you want only distinct b values, then you can do:
select b
from t
group by b
having sum(case when a is null then 1 else 0 end) = 0;
And, finally, you could use window functions:
select a, b
from (select t.*,
sum(case when a is null then 1 else 0 end) over (partition by b) as NullCnt
from t
) t
where NullCnt = 0;
The query below will only output one column in the final result. The records are grouped by column B and test if the record is null or not. When the record is null, the value for the group will increment each time by 1. The HAVING clause filters only the group which has a value of 0.
SELECT B
FROM TableName
GROUP BY B
HAVING SUM(CASE WHEN A IS NULL THEN 1 ELSE 0 END) = 0
If you want to get all the rows from the records, you can use join.
SELECT a.*
FROM TableName a
INNER JOIN
(
SELECT B
FROM TableName
GROUP BY B
HAVING SUM(CASE WHEN A IS NULL THEN 1 ELSE 0 END) = 0
) b ON a.b = b.b
Quick one,
I have a table, with the following structure
id lid taken
1 1 0
1 1 0
1 1 1
1 1 1
1 2 1
Pretty simply so far right?
I need to query the taken/available from the lid of 1, which should return
taken available
2 2
I know I can simply do two counts and join them, but is there a more proficient way of doing this rather than two separate queries?
I was looking at the following type of format, but I can not for the life of me get it executed in SQL...
SELECT
COUNT(case taken=1) AS taken,
COUNT(case taken=0) AS available FROM table
WHERE
lid=1
Thank you SO much.
You can do this:
SELECT taken, COUNT(*) AS count
FROM table
WHERE lid = 1
GROUP BY taken
This will return two rows:
taken count
0 2
1 2
Each count corresponds to how many times that particular taken value was seen.
Your query is correct just needs juggling a bit:
SELECT
SUM(case taken WHEN 1 THEN 1 ELSE 0 END) AS taken,
SUM(case taken WHEN 1 THEN 0 ELSE 1 END) AS available FROM table
WHERE
lid=1
Alternatively you could do:
SELECT
SUM(taken) AS taken,
COUNT(id) - SUM(taken) AS available
FROM table
WHERE
lid=1
SELECT
SUM(case WHEN taken=1 THEN 1 ELSE 0 END) AS taken,
SUM(case WHEN taken=0 THEN 1 ELSE 0 END) AS available
FROM table
WHERE lid=1
Weird application of CTE's:
WITH lid AS (
SELECT DISTINCT lid FROM taken
)
, tak AS (
SELECT lid,taken , COUNT(*) AS cnt
FROM taken t0
GROUP BY lid,taken
)
SELECT l.lid
, COALESCE(a0.cnt, 0) AS available
, COALESCE(a1.cnt, 0) AS taken
FROM lid l
LEFT JOIN tak a0 ON a0.lid=l.lid AND a0.taken = 0
LEFT JOIN tak a1 ON a1.lid=l.lid AND a1.taken = 1
WHERE l.lid=1
;
I have a table with a charge/credit column:
Item | PriceVal | CostVal | CHARGE_CODE
1 5 3 CH
2 8 5 CH
1 -5 -3 CR
3 7 1 CH
4 15 10 CH
1 5 3 CH
I've got the query I need to get the NET price and cost, but I'm also interested in the NET charges. Right now I have:
SELECT Item, SUM(PriceVal), SUM(CostVal)
FROM Table
GROUP BY Item
How do I get another column with the value
COUNT(SUM(CHARGE_CODE=CH)-SUM(CHARGE_CODE=CR))
I'm at a loss.
count() is going to count one for every value thats not null, so I don't think thats exactly what you want. Take the count out and just take the
sum(case when charge_code = CH then costval else 0 end)
- sum(case when charge_code = 'CR' then costval else 0 end)
Since you have the dollar values entered as negatives in the table already, you can use the simple formula:
select
Item,
sum(PriceVal),
sum(CostVal),
sum(PriceVal-CostVal)
from Table
group by Item
I don't believe you should be subtracting the credit items as they're already negative.
If you really do want want the net count of transactions:
select
Item,
sum(PriceVal),
sum(CostVal),
sum(case when charge_code = 'CH' then 1 else 0 end) -
sum(case when charge_code = 'CR' then -1 else 0 end)
from Table
group by Item
or, if there are only two charge codes, substitute:
sum(case when charge_code = 'CH' then 1 else -1 end)
for the last column.
Not 100% sure what you want, but you can count only certain rows like this:
SELECT COUNT(IF(CHARGE_CODE=CH,1,NULL)) ...
And similarly sum certain values from certain rows like this:
SELECT SUM(IF(CHARGE_CODE=CH,PriceVal,0)) ...