I want the sum of a count IF the count is >=3. This gives me a sum of all the counts, regardless if they are <> 3:
=Sum(Iif(CountDistinct(Fields!ENCOUNTER.Value)>=3,1,0))
This produces th same result, the total number of distinct encounters:
=Sum(Iif(CountDistinct(Fields!ENCOUNTER.Value)>=3,CountDistinct(Fields!ENCOUNTER.Value),Nothing))
I want the total number of distinct encounters if there are 3 or more per person. I am grouping on person first, then encounter id.
Ex:
Person Enc
John 1
Bob 4
Sue 2
Ann 3
Total Enc>=3: 2
Based on your requirement, if there are not details rows under ENCOUNTER, you should directly compare the Fields!ENCOUNTER.Value instead of using countdistinct()
Sum(IIF(Fields!ENCOUNTER.value>=3,1,0))
If you have multiple detail rows under ENCOUNTER group level, your requirement can't be achieved because we can't use an aggregation function within an aggregation function. Which means we can't get the distinct ENCOUNTER IDs first, then calculate the total.
I found a workaround. I created another query that selects only those people with 3 or more encounters and added it to the report as a subreport
Related
hi im new to sql and trying to understand how to work with data structures. I have a table
fact.userinteraction
interactionuserkey visitdatecode
0 20220404
1 20220404
5 20220402
5 20220128
If the interaction userkey number repeats then, i want a column called number of visits. in this case, for interactionuserkey 5, there are 2 total visits since its repeated twice. for interactionuserkey 0, number of visits =1 and so on. Basically, sum duplicates in column 1 and give total count AS number of visits. How do i do this?
In sql, it's resolved using basic aggregation
select interactionuserkey, count(*)
from your_table
group by interactionuserkey
I'm trying to understand how TOTAL and Aggr work in QlikView. Could someone please explain the difference between the two examples below, and if possible please illustrate with a SQL query?
Example1:
Max({<Field1=>} Aggr(Sum({<Field2={'Value'}, Field1=>} StuffCount), Field1))
Example2:
Max({<Field1=>} TOTAL Aggr(Sum({<Field2={'Value'}, Field1=>} StuffCount), Field1))
Not sure what you mean with and SQL query in this example. Anyway, imagine you have this list of Customers (CustomerID) and Sales (Sales):
CustomerID/ Sales
Customer1 25
Customer2 20
Customer1 10
Customer1 5
Customer1 20
Customer3 30
Customer2 30
Then you want to show it on a pivot table with dimension CustomerID and two expressions:
Max(Aggr(Sum(Sales), CustomerID)) // this will show 60 for the first customer, 50 for the second and 30 for the third one
Max(TOTAL Aggr(Sum(Sales),CustomerID)) //this will show 60 in every row of your table (which is the maximum sum of sales among all customers)
So basically AGGR creates a temporal list of whatever you put in the first function input (in this case sum(Sales)) using the dimension of the second (CustomerID). Then you can perform operations on that list (such as Max, Min, Avg...). If you write TOTAL and use the expression in a pivot table, then you 'ignore' the dimensions that might be affecting the operations.
Hope it helps
TOTAL keyword is useful in charts/pivot tables. It applies the same calculation on every datapoint in the chart/pivot, with independence of dimentions.
Therefore - if you put your expression into pivot table - 1st option may display different values per cell (if the Aggr is rellevant) when the 2nd will result in same values.
Aggr function allows making double aggregations (avg of sum, max of count etc..) on different group by bases.
I have a column in PowerPivot that basically goes:
1
1
2
3
4
3
5
4
If I =AVERAGE([Column]), it's going to average all 8 values in the sample column. I just need the average of the distinct values (i.e., in the example above I want the average of (1,2,3,4,5).
Any thoughts on how to go about doing this? I tried a combination of =(DISTINCT(AVERAGE)) but it gives a formula error.
Thanks!!
Kevin
There must be a cleaner way of doing this but here is one method which uses a measure to get the sum of the values divided by the number of times it appears (to basically give the original value) then uses an iterative function to do it for each unique value.
Apologies for the uninspired measure names:
[m1] = SUM(table1[theValue]) / COUNTROWS(Table1)
[m2] = AVERAGEX(VALUES(Tables1[theValue]), [m1])
Assuming your table is caled table1 and the column is called theValue
I want the equivalent SUM and Group By as in t-SQL. But I haven't found the answer on the web.
My MDX return has some records that have the same name. I want to show the distinct name with the measure summed up just like Group by feature in SQL.
It seems like it's a common feature. Thanks.
When you define a measure in AS you can set it several different ways including count and sum.
Let's assume you have a product dimension and a fact of sales. A simple query to get the total sales by product would look like the following.
SELECT {[Measures].[ItemCount], [Measures].[SalesDollars]} ON 0,
[Products].[Products].children ON 1
FROM [CUBE]
This would give you sample output like
Product Item Count Sales Dollars
Bike 10 1000
Tire 3 650
I'm somewhat new to SQL queries, and I'm struggling with this particular problem.
Let's say I have query that returns the following 3 records (kept to one column for simplicity):
Tom
Jack
Tom
And I want to have those results grouped by the name and also include the fraction (ratio) of the occurrence of that name out of the total records returned.
So, the desired result would be (as two columns):
Tom | 2/3
Jack | 1/3
How would I go about it? Determining the numerator is pretty easy (I can just use COUNT() and GROUP BY name), but I'm having trouble translating that into a ratio out of the total rows returned.
SELECT name, COUNT(name)/(SELECT COUNT(1) FROM names) FROM names GROUP BY name;
Since the denominator is fixed, the "ratio" is directly proportional to the numerator. Unless you really need to show the denominator, it'll be a lot easier to just use something like:
select name, count(*) from your_table_name
group by name
order by count(*) desc
and you'll get the right data in the right order, but the number that's shown will be the count instead of the ratio.
If you really want that denominator, you'd do a count(*) on a non-grouped version of the same select -- but depending on how long the select takes, that could be pretty slow.