Recursive cte to repeat several integers - sql

Question

I'd like a column of numbers:
Seven occurances of the integer 1, followed by 7 occurances of 2, followed by 7 occurances of 3 .... , followed by 7 occurances of n-1, followed by 7 occurances of n. Like so
Num
1
1
1
1
1
1
1
2
2
2
2
2
2
2
...
...
n-1
n-1
n-1
n-1
n-1
n-1
n-1
n
n
n
n
n
n
n
Unfortunately I've not progressed too far. My current attempt is the following, where n=4:
WITH
one AS
(
SELECT num = 1,
cnt = 0
UNION ALL
SELECT num = num,
cnt = cnt + 1
FROM one
WHERE cnt < 7
),
x AS
(
SELECT num,
cnt = 0
FROM one
UNION ALL
SELECT num = num + 1,
cnt = cnt + 1
FROM one
WHERE cnt < 4
)
SELECT *
FROM x

Answer 1

;WITH Numbers AS
(
SELECT n = 1
UNION ALL
SELECT n + 1
FROM Numbers
WHERE n+1 <= 10
),
se7en AS
(
SELECT n = 1
UNION ALL
SELECT n + 1
FROM se7en
WHERE n+1 <= 7
)
SELECT Numbers.n
FROM Numbers CROSS JOIN se7en

Answer 2

with x as
(select 1 as id
union all
select 2 as id
union all
select 3 as id
union all
select 4 as id
union all
select 5 as id
union all
select 6 as id
union all
select 7 as id)
select x1.* from x cross join x x1
The cross join will work in your case.

Answer 3

No need to use recursive CTE for this you can try set based approach solution try something like this. Kind of integer division.
If you have access to master database then use this.
;with cte as
(
SELECT top 1000 [7_seq] = ( ( Row_number()OVER(ORDER BY (SELECT NULL)) - 1 ) / 7 ) + 1
FROM sys.columns
)
select * from cte where [7_seq] <= #n
or use tally table to generate the numbers. I will prefer this solution
DECLARE #n INT = 10;
WITH Tally (num)
AS (
-- 1000 rows
SELECT Row_number()OVER (ORDER BY (SELECT NULL))
FROM (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) a(n)
CROSS JOIN (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) b(n)
CROSS JOIN (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) c(n)),
seq
AS (SELECT [7_seq] = ( ( Row_number()
OVER(
ORDER BY (SELECT num)) - 1 ) / 7 ) + 1
FROM Tally)
SELECT [7_seq]
FROM seq
WHERE [7_seq] <= #n

Answer 4

WITH t1 AS (SELECT 0 as num UNION ALL SELECT 0)
,t2 AS (SELECT 0 as num FROM t1 as a CROSS JOIN t1 as b)
,t3 AS (SELECT 0 as num FROM t2 as a CROSS JOIN t2 as b)
,t4 AS (SELECT 0 as num FROM t3 as a CROSS JOIN t3 as b)
,Tally (number)
AS (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) FROM t4)
SELECT t1.number
FROM Tally as t1 cross join Tally as t2
where t2.number <=7
ORDER BY t1.number;

Answer 5

You can do It in following:
DECLARE #num INT = 1,
#sub INT = 0,
#max INT = 10,
#timesToRepeat INT = 7
CREATE TABLE #Temp (num INT)
WHILE (#num < #max + 1)
BEGIN
SET #sub = 0;
WHILE (#sub < #timesToRepeat)
BEGIN
INSERT INTO #Temp
SELECT #num x
SET #sub = #sub +1
END
SET #num = #num +1
END
SELECT * FROM #Temp
DROP TABLE #Temp
Set #max variable to number what you want to reach for now It is 10 so It will return result set like:
1
1
1
1
1
1
1
2
2
2
2
2
2
2
.
.
.
10
10
10
10
10
10
10

Answer 6

DECLARE #MAX INTEGER
SET #MAX = 5;
with cte as
(SELECT 7 as num
UNION ALL
SELECT num-1 as num from cte where num>1
),cte2 AS
(SELECT #MAX as num
UNION ALL
SELECT num-1 as num from cte2 where num>1)
select C2.num from cte C1,cte2 C2 ORDER by C2.num asc
Change the value of #MAX to reflect the value of n

Answer 7

Here is a slightly different way to do it.
select null num into #a
union all
select null
union all
select null
union all
select null
union all
select null
union all
select null
union all
select null
select * into #b from
(select rn = row_number()over (order by (select null)) from sys.objects A cross join sys.objects B) A
where rn <=10
select #b.rn as numbers from #a cross join #b
order by 1