I have five queries and each of them will return me single column multiple row output. I want to to write a function which will contain all of these queries.
Can anyone help?
query 1:
Select Col1 as X from Table1;
query 2:
Select Col3 as Y from Table2;
From a function I want to get a table which will have columns
X, Y
How to club these queries under single function?
Add a ROW_NUMBER() to each of the queries and join them by the row number.
Depending on number of rows returned by each of the query you'd join then by inner, left or full join.
Example below assumes that two queries return the same number of rows.
WITH
CTE1
AS
(
SELECT Col1 as X, ROW_NUMBER() OVER(ORDER BY Col1) AS rn
FROM Table1
)
,CTE2
AS
(
SELECT Col3 as Y, ROW_NUMBER() OVER(ORDER BY Col3) AS rn
FROM Table2
)
SELECT
CTE1.X, CTE2.Y
FROM
CTE1
INNER JOIN CTE2 ON CTE1.rn = CTE2.rn
Use the UNION operator:
SELECT
column_1
FROM
tbl_name_1
UNION ALL
SELECT
column_1
FROM
tbl_name_2;
If there is a relation between the two tables, try using a join.
Maybe a simple inner join would be possible here?
select Col1 as X from Table1
join
on Table1.Col1_name = Table2.col3_name
Related
I have multiple SELECT queries which is ran against different tables.
The output of all the queries have the same number of rows (every query when ran individually will have the same number of rows). Is there a way I can combine the output of all these queries into a single result? (Keep out from first query and add the output of next query as a column to the output of the next query). I dont want to save these tables into database as I am just doing some validation testing.
Example:
SELECT AAA,BBB,CCC FROM Table1
SELECT Table2.DDD, Table1.AAA
FROM Table2
INNER JOIN Table1
ON Table1.AAA = Table2.AAA
I tried writing combining the query as
SELECT Table1.AAA,Table1.BBB,Table1.CCC,T1.DDD
FROM Table1,
(SELECT Table2.DDD, Table1.AAA
FROM Table2
INNER JOIN Table1
ON Table1.AAA = Table2.AAA)T1
I tried doing the above combined query, but instead of getting 11 rows as output (both queries above had result of 11 rows), I am getting 35 rows as output.
Hope the question made sense!
You'll need to specify a criteria to match each row the first query with which row of the second query.
If, for example, the column AAA is unique in both queries and you want to match rows with the same values you could do:
select a.*, b.*
from (
SELECT AAA,BBB,CCC FROM Table1
) a
full join join (
SELECT Table2.DDD, Table1.AAA
FROM Table2
INNER JOIN Table1
ON Table1.AAA = Table2.AAA
) b on b.aaa = a.aaa
If there aren't any clear matching rules, you can produce an artificial row number on each result set and use it to match rows. For example:
select
a.aaa, a.bbb, a.ccc,
b.ddd, b.aaa
from (
SELECT AAA, BBB, CCC,
row_number() over(order by aaa) as rn
FROM Table1
) a
full join join (
SELECT Table2.DDD, Table1.AAA,
row_number() over(order by table1.aaa, table2.ddd) as rn
FROM Table2
INNER JOIN Table1
ON Table1.AAA = Table2.AAA
) b on b.rn = a.rn
If you have several results and want to have all of them as additional columns you can simply use ",":
create table temp1 as select '1' as c1 from DUAL;
create table temp2 as select '2' as c2 from DUAL;
create table temp3 as select '3' as c3 from DUAL;
select a.c1, b.c2, c.c3 from temp1 a, (select c2 from temp2) b, (select c3 from temp3) c;
An alternative could also be that you want to have all the results as additional rows then you would use UNION ALL between the individual results.
I have 2 queries that return data in the form:
query 1:
column 1
a
b
c
query 2:
column 2
d
e
How can I combine the 2 queries to get output as:
column 1 column 2
a d
b e
c
The order of data in the columns does not matter.
Possibly anything with joins ?
Thanks
use row_number()
select t1.col1,t2.col2 from
(
select *,row_number() over(order by col1) rn from query1
) t1 full outer join
(
select *,row_number() over(order by col2) rn from query2
) t2 on t1.rn=t2.rn
For n,m rows use full outer join
A possible solution is selecting both columns with row_number() and join them by the row_number. One must be aware to select first from the table with the higher number of rows. Example:
select
col_1,
col_2
from (
select
a.col_1,
row_number() over () rn
from a
) s1
FULL OUTER JOIN (
select
b.col_2,
row_number() over () rn
from b
) s2 on s1.rn = s2.rn
I have 2 SQL table.Table A and Table B. Both of this table have 10000 records respectively.
In Table A have 3 Column=>
ColumnA,ColumnB,ColumnC
In Table B have 3 Column=>
ColumnD,ColumnE,ColumnF
My Requirement is to select ColumnA and ColumnD with their original record(10000).
My question is how can I select only ColumnA and ColumnD.
The first problem is I cant join this two table because this two table stands as separately.
The second problem is I cant Union this two table because my requirement is to get Two column but when I union, I only get one column with combining two column.
You could create an on-the-fly join column via ROW_NUMBER, and then join on that:
WITH cte1 AS (
SELECT ColumnA, ROW_NUMBER() OVER (ORDER BY ColumnA) rn
FROM TableA
),
cte2 AS (
SELECT ColumnD, ROW_NUMBER() OVER (ORDER BY ColumnD) rn
FROM TableB
)
SELECT t1.ColumnA, t2.ColumnD
FROM cte t1
INNER JOIN cte t2
ON t1.rn = t2.rn;
Of course, this would just pair the 10K records using the arbitrary orderings in the A and D columns. If you have some specific logic for how these two columns should be paired up, then let us know. The bottom line is that you can't easily get away from the concepts of join or union to bring these two columns together.
I have tables
table1
col1 col2
a b
c d
and table2
mycol1 mycol2
e f
g h
i j
k l
I want to combine the two tables, which have no common field into one table looking like:
table 3
col1 col2 mycol1 mycol2
a b e f
c d g h
null null i j
null null k l
ie, it is like putting the two tables side by side.
I'm stuck! Please help!
Get a row number for each row in each table, then do a full join using those row numbers:
WITH CTE1 AS
(
SELECT ROW_NUMBER() OVER(ORDER BY col1) AS ROWNUM, * FROM Table1
),
CTE2 AS
(
SELECT ROW_NUMBER() OVER (ORDER BY mycol1) AS ROWNUM, * FROM Table2
)
SELECT col1, col2, mycol1, mycol2
FROM CTE1 FULL JOIN CTE2 ON CTE1.ROWNUM = CTE2.ROWNUM
This is assuming SQL Server >= 2005.
It's really good if you put in a description of why this problem needs to be solved. I'm guessing it is just to practice sql syntax?
Anyway, since the rows don't have anything connecting them, we have to create a connection. I chose the ordering of their values. Also since they have nothing connecting them that also begs the question on why you would want to put them next to each other in the first place.
Here is the complete solution: http://sqlfiddle.com/#!6/67e4c/1
The select code looks like this:
WITH rankedt1 AS
(
SELECT col1
,col2
,row_number() OVER (order by col1,col2) AS rn1
FROM table1
)
,rankedt2 AS
(
SELECT mycol1
,mycol2
,row_number() OVER (order by mycol1,mycol2) AS rn2
FROM table2
)
SELECT
col1,col2,mycol1,mycol2
FROM rankedt1
FULL OUTER JOIN rankedt2
ON rn1=rn2
Option 1: Single Query
You have to join the two tables, and if you want each row in table1 to match to only one row in table2, you have to restrict the join somehow. Calculate row numbers in each table and join on that column. Row numbers are database-specific; here is a solution for mysql:
SELECT
t1.col1, t1.col2, t2.mycol1, t2.mycol2
FROM
(SELECT col1, col2, #t1_row := t1_row + 1 AS rownum FROM table1, (SELECT #t1_row := 0) AS r1) AS t1
LEFT JOIN
(SELECT mycol1, mycol2, #t2_row := t2_row + 1 AS rownum FROM table2, (SELECT #t2_row := 0) AS r2) AS t2
ON t1.rownum = t2.rownum;
This assumes table1 is longer than table2; if table2 is longer, either use RIGHT JOIN or switch the order of the t1 and t2 sub-selects. Also note that you can specify the order of each table separately using an ORDER BY clause in the sub-selects.
(See select increment counter in mysql)
Option 2: Post-processing
Consider making two selects, and then concatenating the results with your favorite scripting language. This is a much more reasonable approach.
I'm trying to write a select query but am having trouble, probably because I'm not familiar with SQL Server (usually use MySQL).
Basically what I need to do is find the number of unique combinations of 2 columns, one a Varchar and one a Double.
There are less rows in one than another, so I've been trying to figure out the right way to do this.
Essentially pretend Table.Varchar has in it:
Table.Varchar
--------------
apple
orange
and Table.Float has in it:
Table.Float
--------------
1
2
3.
How could I write a query which returns
QueryResult
-------------
apple1
apple2
apple3
orange1
orange2
orange3
Long day at work and I think I'm just overthinking this what I've tried so far is to concat the two columns and then count but it's not working. Any ideas to better go about this?
Select T1.VarcharField + CAST(T2.FloatField as Varchar(10)) as [Concat]
from Table.Varchar T1
CROSS JOIN Table.Float T2
this way, you are generating the fields
so, then group by and use Count
select T.Concat, count(*) from
(Select T1.VarcharField + CAST(T2.FloatField as Varchar(10)) as [Concat]
from Table.Varchar T1
CROSS JOIN Table.Float T2) T
group by T.Concat order by count(*) asc
If they are in the same table:
SELECT a.Field1, b.Field2
FROM [Table] a
CROSS JOIN [Table] b
or if they are in seperate tables:
SELECT a.Field1, b.Field2
FROM [Table1] a
CROSS JOIN [Table2] b
Keep in mind that the above queries will match ALL records from the first table with ALL records from the second table, creating a cartesian product.
This will eliminate duplicates:
DECLARE #Varchar TABLE(v VARCHAR(32));
DECLARE #Float TABLE(f FLOAT);
INSERT #Varchar SELECT 'apple'
UNION ALL SELECT 'orange'
UNION ALL SELECT 'apple';
INSERT #Float SELECT 1
UNION ALL SELECT 2
UNION ALL SELECT 3;
SELECT v.v + CONVERT(VARCHAR(12), f.f)
FROM #Varchar AS v
CROSS JOIN #Float AS f
GROUP BY v.v, f.f;
A cross join is a join where each record in one table is combined with each record of the other table. Select the distinct values from the table and join them.
select x.Varchar, y.Float
from (select distinct Varchar from theTable) x
cross join (select distinct Float from theTable) y
To find the number of combinations you don't have to actually return all combinations, just count them.
select
(select count(distinct Varchar) from theTable) *
(select count(distinct Float) from theTable)
Try This
Possible Cominations.
SELECT
DISTINCT T1.VarField+CONVERT(VARCHAR(12),T2.FtField) --Get Unique Combinations
FROM Table1 T1 CROSS JOIN Table2 T2 --From all possible combinations
WHERE T1.VarField IS NOT NULL AND T2.FtField IS NOT NULL --Making code NULL Proof
and to just get the Possible Cominations Count
SELECT Count(DISTINCT T1.VarcharField + CONVERT(VARCHAR(12), T2.FloatField))
FROM Table1 T1
CROSS JOIN Table2 T2
WHERE T1.VarcharField IS NOT NULL AND T2.FloatField IS NOT NULL