I have around 20,000 entries in a SQL table for which a date column is of the form
YYYY-MM-DD HH-SS. I would like to convert this format to a YYYY-MM-DD format so I can run a query on all of the entries that will count the number of entries based on
a) the month under which they fall
b) the day
I'm new to SQL and not sure if there is a way to loop through all of the entries and check based on the required criteria; and as such, would greatly appreciate any help.
I unfortunately, cannot send a screenshot of the table since the data is classified.
You don't need to change the data in the table. Most databases have year() and month() functions, so you could do:
select year(datecol), month(datecol), count(*)
from sqltable
group by year(datecol), month(datecol)
order by year(datecol), month(datecol);
If these specific functions are not available, then I'm sure your database supports something similar.
Related
I need to a value associated to a month and a user in a table. And I want to perform queries on it. I don't know if there is a column data type for this type of need. If not, should I:
Create a string field and build year-month concatenation (2017-01)
Create a int field and build year-month concatenation (201701)
Create two columns (one year and one month)
Create a date column at the beginning of the month (2017-01-01 00:00:00)
Something else?
The objective is to run queries like (pseudo-SQL):
SELECT val FROM t WHERE year_month = THIS_YEAR_MONTH and user_id='adc1-23...';
I would suggest not thinking too hard about the problem and just using the first date/time of the month. Postgres has plenty of date-specific functions -- from date_trunc() to age() to + interval -- to support dates.
You can readily convert them to the format you want, get the difference between two values, and so on.
If you phrase your query as:
where year_month = date_trunc('month', now()) and user_id = 'adc1-23...'
Then it can readily take advantage of an index on (user_id, year_month) or (year_month, user_id).
If you are interested in display values in YYYY-MM formt you can use to_char(your_datatime_colum,'YYYY-MM')
example:
SELECT to_char(now(),'YYYY-MM') as year_month
Im trying to make a small report for myself to see how my much time I get inputed in my system every day.
The goal is to have my SQL to sum up the name, Total time worked and Total NG product found for one specific day.
In this order:
1.) Sort out my data for a specific 'date'. I.E 2016-06-03
2.) Present a DISTINCT value for 'operators'
3.) SUM() all time registered at this 'date' and by this 'operator' under 'total_working_time_h'
4.) SUM() all no_of_defects registered at this 'date' and by this 'operator' under 'no_of_defects'
date, operator, total_working_time_h, no_of_defects
Currently I get the data I want by using the Query below. But now I need both the DISTINCT value of the operator and the SUM of the information. Can I use sub-queries for this or should it be done by a loop? Any other hints where I can learn more about how to solve this?
If i run the DISTINCT function I don't get the opportunity to sum my data the way I try.
SELECT date, operator, total_working_time_h, no_of_defects FROM {$table_work_hours} WHERE date = '2016-06-03' "
Without knowing the table structure or contents, the following query is only a good guess. The bits to notice and work with are sum() and GROUP BY. Actually syntax will vary a bit depending on what RDBMS you are using.
SELECT
date
,operator
,SUM(total_working_time_h) AS total_working_time_h
,SUM(no_of_defects) AS no_of_defects
FROM {$table_work_hours}
WHERE date = '2016-06-03'
GROUP BY
date
,operator
(Take out the WHERE clause or replace it with a range of dates to get results per operator per date.)
I'm not sure why you are trying to do DISTINCT. You want to know the data, no of hours, etc for a specific date.
do this....
Select Date, Operator, 'SumWorkHrs'=sum(total_working_time_h),
'SumDefects'=sum(no_ofDefects) from {$table_work_hours}
Where date='2016-06-03'
Try this:
SELECT SUM(total_working_time) as total_working_time,
SUM(no_of_defects) as no_of_defects ,
DISTINCT(operator) AS operator FROM {$table_work_hours} WHERE
date = '2016-06-03'
My question is how to properly write a SQL query for the below highlighted/bold question.
There is a table in HMO database which stores doctor's working
hours.Table has following fields
"FirstName","LastName","Date","HoursWorked". write a sql statement
which retrieves average working hours for period January-March for a
doctor with name Joe Doe.
so far i have
SELECT HoursWorked
FROM Table
WHERE DATE = (January - March) AND
SELECT AVG(HoursWorked) FROM Table WHERE FirstName="Joe",LastName="Doe"*
A few pointers as this sounds like a homework question (which we don't answer for you here, but we can try to give you some guidance).
You want to put all the things you want to return from your select first and you want to have all your search conditions at the end.
So the general format would be :
SELECT Column1,
Column2,
Column3,
FROM YourTable
WHERE Column4 = Restriction1
AND Column5 = Restriction2
The next thing you need to think about is how the dates are formatted in your database table. Hopefully they're kept in a column of type datetime or date (options will depend on the database engine you're using, eg, Microsoft SQL Server, Oracle or MySql). In reality some older databases people use can store dates in all sorts of formats which makes this much harder, but since I'm assuming it's a homework type question, lets assume it's a datetime format.
You specify restrictions by comparing columns to a value, so if you wanted all rows where the date was after midnight on the 2nd of March 2012, you would have the WHERE clause :
WHERE MyDateColumn >= '2012-03-02 00:00:00'
Note that to avoid confusion, we usually try to format dates as "Year-Month-Day Hour:Minute:Second". This is because in different countries, dates are often written in different formats and this is considered a Universal format which is understood (by computers at least) everywhere.
So you would want to combine a couple of these comparisons in your WHERE, one for dates AFTER a certain date in time AND one for dates before another point in time.
If you give this a go and see where you get to, update your question with your progress and someone will be able to help get it finished if you have problems.
If you don't have access to an actual database and need to experiment with syntax, try this site : http://sqlfiddle.com/
you already have the answer written
SELECT AVG(HoursWorked) FROM Table WHERE FirstName="Joe",LastName="Doe"*
you only need to fix the query
SELECT AVG(HoursWorked) as AVGWORKED FROM Table WHERE FirstName='Joe' AND LastName='Doe'
That query will give you the average hours worked for Joe Doe, however you only need to get between some time you add the next "AND", if you are using SQL server you can use the built in function DateFromParts(year,month,day) to create a new Date, or if you are using another Database Engine you can convert a string to a DateColumn Convert(Date,'MM/dd/yyyy')
Example
SELECT AVG(HoursWorked) as AVGWORKED FROM Table WHERE FirstName='Joe' AND LastName='Doe' AND DateColumn between DateFromParts(year,month,day) and Convert(Date,'MM/dd/yyyy')
In the example i showed both approaches (datefromparts for the initial date, and convert(date) for the ending date).
I already have a successful update query that joins tables to enter the date from the PROJECT_CLEAN table into the TABLE_PROGRESS table to show the most recent record for each evaluation unit (EU), but it keeps the date-time as a string, which I can't really do any analysis with.
I need to adjust this update query slightly to take the string version from the PROJECT_CLEAN table ("YYYY-MM-DD HH:MM:SS") and convert it to datetime (YYYY-MM-DD HH:MM:SS) in the TABLE_PROGRESS table. Here is the existing query:
UPDATE IGNORE TABLE_PROGRESS AS prog
JOIN (SELECT cast(EU AS UNSIGNED) AS eu, MAX(START_TIME) AS max, CLUSTER_COMPLETE AS complete FROM `PROJECT_CLEAN` GROUP BY EU) AS project
ON prog.EUID = project.EU
SET prog.Date_Completed = project.max
WHERE project.complete>0;
Any help will be greatly appreciated!
I figured it out. I just had to clear out the TABLE_PROGRESS table and make sure the date fields had the right format... and then the same query still worked and now the dates are no longer strings
– beck777 May 6 at 16:49
I've got a table with purchase orders stored in it. Each row has a timestamp indicating when the order was placed. I'd like to be able to create a report indicating the number of purchases each day, month, or year. I figured I would do a simple SELECT COUNT(xxx) FROM tbl_orders GROUP BY tbl_orders.purchase_time and get the value, but it turns out I can't GROUP BY a timestamp column.
Is there another way to accomplish this? I'd ideally like a flexible solution so I could use whatever timeframe I needed (hourly, monthly, weekly, etc.) Thanks for any suggestions you can give!
This does the trick without the date_trunc function (easier to read).
// 2014
select created_on::DATE from users group by created_on::DATE
// updated September 2018 (thanks to #wegry)
select created_on::DATE as co from users group by co
What we're doing here is casting the original value into a DATE rendering the time data in this value inconsequential.
Grouping by a timestamp column works fine for me here, keeping in mind that even a 1-microsecond difference will prevent two rows from being grouped together.
To group by larger time periods, group by an expression on the timestamp column that returns an appropriately truncated value. date_trunc can be useful here, as can to_char.