I have a variable
var=[name1,name2]
I have a dataframe also in a list
df= [df1, df2]
How do i assign df1 to name1 and df2 to name2 and so on.
If I understand correctly, assuming the lengths of both lists are the same you just iterate over the indices of both lists and just assign them, example:
In [412]:
name1,name2 = None,None
var=[name1,name2]
df1, df2 = 1,2
df= [df1, df2]
for x in range(len(var)):
var[x] = df[x]
var
Out[412]:
[1, 2]
If your variable list is storing strings then I would not make variables from those strings (see How do I create a variable number of variables?) and instead create a dict:
In [414]:
var=['name1','name2']
df1, df2 = 1,2
df= [df1, df2]
d = dict(zip(var,df))
d
Out[414]:
{'name1': 1, 'name2': 2}
To answer your question, you can do this by:
for i in zip(var, df):
globals()[i[0]] = i[1]
And then access your variables.
But proceeding this way is bad. You're like launching a dog in your global environment. It's better to keep control about what you handle, keep your dataframe in a list or dictionary.
Related
I have a dataFrame, such that when I execute:
df.columns
I get
Index(['a', 'b', 'c'])
I need to remove Index to have columns as list of strings, and was trying:
df.columns = df.columns.tolist()
but this doesn't remove Index.
tolist() should be able to convert the Index object to a list:
df1 = df.columns.tolist()
print(df1)
or use values to convert it to an array:
df1 = df.columns.values
The columns attribute of a pandas dataframe returns an Index object, you cannot assign the list back to the df.columns (as in your original code df.columns = df.columns.tolist()), but you can assign the list to another variable.
I have a DataFrame with several columns like:
'clientes_enderecos.CEP', 'tabela_clientes.RENDA','tabela_produtos.cod_ramo', 'tabela_qar.chave', etc
I want to change the name of the columns and remove all the text neighbord a dot.
I only know the method pandas.rename({'A':'a','B':'b'})
But to name them as they are now I used:
df_tabela_clientes.columns = ["tabela_clientes." + str(col) for col in df_tabela_clientes.columns]
How could I reverse the process?
Try rename with lambda and string manipulation:
df = pd.DataFrame(columns=['clientes_enderecos.CEP', 'tabela_clientes.RENDA','tabela_produtos.cod_ramo', 'tabela_qar.chave'])
print(df)
#Empty DataFrame
#Columns: [clientes_enderecos.CEP, tabela_clientes.RENDA, tabela_produtos.cod_ramo, #tabela_qar.chave]
#Index: []
dfc = df.rename(columns=lambda x: x.split('.')[-1])
print(dfc)
#Empty DataFrame
#Columns: [CEP, RENDA, cod_ramo, chave]
#Index: []
To get rid of whats to the right of the dot you can split the columns names and choose whichever side of the dot you want.
import pandas as pd
df = pd.DataFrame(columns=['clientes_enderecos.CEP', 'tabela_clientes.RENDA','tabela_produtos.cod_ramo', 'tabela_qar.chave'])
df.columns = [name.split('.')[0] for name in df.columns] # 0: before the dot | 1:after the dot
I am wondering if anyone can help. I have a number of dataframes stored in a dictionary. I simply want to access each of these dataframes and count the values in a column in the column I have 10 letters. In the first dataframe there are 5bs and 5 as. For example the output from the count I would expect to be is a = 5 and b =5. However for each dataframe this count would be different hence I would like to store the output of these counts either into another dictionary or a separate variable.
The dictionary is called Dict and the column name in all the dataframes is called letters. I have tried to do this by accessing the keys in the dictionary but can not get it to work. A section of what I have tried is shown below.
import pandas as pd
for key in Dict:
Count=pd.value_counts(key['letters'])
Count here would ideally change with each new count output to store into a new variable
A simplified example (the actual dataframe sizes are max 5000,63) of the one of the 14 dataframes in the dictionary would be
`d = {'col1': [1, 2,3,4,5,6,7,8,9,10], 'letters': ['a','a','a','b','b','a','b','a','b','b']}
df = pd.DataFrame(data=d)`
The other dataframes are names df2,df3,df4 etc
I hope that makes sense. Any help would be much appreciated.
Thanks
If you want to access both key and values when iterating over a dictionary, you should use the items function.
You could use another dictionary to store the results:
letter_counts = {}
for key, value in Dict.items():
letter_counts[key] = value["letters"].value_counts()
You could also use dictionary comprehension to do this in 1 line:
letter_counts = {key: value["letters"].value_counts() for key, value in Dict.items()}
The easiest thing is probably dictionary comprehension:
d = {'col1': [1, 2,3,4,5,6,7,8,9,10], 'letters': ['a','a','a','b','b','a','b','a','b','b']}
d2 = {'col1': [1, 2,3,4,5,6,7,8,9,10,11], 'letters': ['a','a','a','b','b','a','b','a','b','b','a']}
df = pd.DataFrame(data=d)
df2 = pd.DataFrame(d2)
df_dict = {'d': df, 'd2': df2}
new_dict = {k: v['letters'].count() for k,v in df_dict.items()}
# out
{'d': 10, 'd2': 11}
I have three Dataframes : df1, df2, df3 with the same number of "rows" but different number of "columns" and different "column" labels. I want to "merge" them in one single dataframe with the order df1,df2,df3 and keeping the original column labels.
I've read in Combine a list of pandas dataframes to one pandas dataframe that this can be done by:
df = pd.DataFrame.from_dict(map(dict,df_list))
But I cannot fully understand the code. I assume df_list is:
df_list = [df1,df2,df3]
But what is dict? A dictionary of df_list? How to get it?
I solve this by:
df = pd.concat([df1, df2], axis=1, sort=False)
df = pd.concat([df, df3], axis=1, sort=False)
Let df1, df2, and df3 are pandas.DataFrame's having the same structure but different numerical values. I want to perform:
res=if df1>1.0: (df2-df3)/(df1-1) else df3
res should have the same structure as df1, df2, and df3 have.
numpy.where() generates result as a flat array.
Edit 1:
res should have the same indices as df1, df2, and df3 have.
For example, I can access df2 as df2["instanceA"]["parameter1"]["paramter2"]. I want to access the new calculated DataFrame/Series res as res["instanceA"]["parameter1"]["paramter2"].
Actually numpy.where should work fine there. Output here is 4x2 (same as df1, df2, df3).
df1 = pd.DataFrame( np.random.randn(4,2), columns=list('xy') )
df2 = pd.DataFrame( np.random.randn(4,2), columns=list('xy') )
df3 = pd.DataFrame( np.random.randn(4,2), columns=list('xy') )
res = df3.copy()
res[:] = np.where( df1 > 1, (df2-df3)/(df1-1), df3 )
x y
0 -0.671787 -0.445276
1 -0.609351 -0.881987
2 0.324390 1.222632
3 -0.138606 0.955993
Note that this should work on both series and dataframes. The [:] is slicing syntax that preserves the index and columns. Without that res will come out as an array rather than series or dataframe.
Alternatively, for a series you could write as #Kadir does in his answer:
res = pd.Series(np.where( df1>1, (df2-df3)/(df1-1), df3 ), index=df1.index)
Or similarly for a dataframe you could write:
res = pd.DataFrame(np.where( df1>1, (df2-df3)/(df1-1), df3 ), index=df1.index,
columns=df1.columns)
Integrating the idea in this question into JohnE's answer, I have come up with this solution:
res = pd.Series(np.where( df1 > 1, (df2-df3)/(df1-1), df3 ), index=df1.index)
A better answer using DataFrames will be appreciated.
Say df is your initial dataframe and res is the new column. Use a combination of setting values and boolean indexing.
Set res to be a copy of df3:
df['res'] = df['df3']
Then adjust values for your condition.
df[df['df1']>1.0]['res'] = (df['df2'] - df['df3'])/(df['df1']-1)