I am using STI and have a table Widget that a bunch of other subclasses inherit from using STI. I want a query that gets the last created of each object with a uniq type.
I have a predefined array of types I want so lets say:
types = ["type1", "type2", "type3"]
So my query would be something like: (this doesnt work)
Widget.where(type: types).uniq.reverse
My goal is to get the last of each object that matches 1 of those types..
Not 100% sure, but something like this might work (untested):
ids = Thing.where(type: types).group(:type).maximum(:id).values
last_per_type = Thing.find(ids)
Thing.select("distinct type")
By the way, type is a special variable in rails and can't be used as a column name.
Related
As far as I understand, it is not possible in Appian to dynamically construct (process) variable names, just like you would do e.g. with bash using backticks like MY_OBJECT=pv!MY_CONS_`extract(valueOfPulldown)`. Is that correct? Is there a workaround?
I have set of Appian constants, let's call them MY_CONS_FOO, MY_CONS_BAR, MY_CONS_LALA, all of which are e.g. refering to an Appian data store entity. I would like to write an Appian expression rule which populates another variable MY_OBJECT of the same type (here: data store entity), depending e.g. of the options of a pull-down menu having the possible options stored in an array MY_CONS_OPTIONS looking as follows
FOO
BAR
LALA
I could of course build a lengthy case-structure which I have to maintain in addition to MY_CONS_OPTIONS, so I am searching for a more dynanmic approach using the extract() function depending on valueOfPulldown as the chosen value of the pulldown-menu.
Edit: Here the expression-rule (in pseudo-code) I want to avoid:
if (valueOfPulldown = 'FOO') then MY_OBJECT=pv!MY_CONS_FOO
if (valueOfPulldown = 'BAR') then MY_OBJECT=pv!MY_CONS_BAR
if (valueOfPulldown = 'LALA') then MY_OBJECT=pv!MY_CONS_LALA
The goal is to be able to change the data store entity via pulldown-menu.
This can help you find what is behind your constant.
fn!typeName(fn!typeOf(cons!YOUR_CONSTANT)).
Having in mind additional details I would do as follows:
Create separate expression that will combine details into list of Dictionary like below:
Expression results (er):
{
{dd_label: "label1", dd_value: 1, cons: "cons!YOUR_CONSTANT1" }
,{dd_label: "label2", dd_value: 2, cons: "cons!YOUR_CONSTANT2" }
}
on UI for your dropdown control use er.dd_label as choiceLabels and er.dd_value as choiceValues
when user selects value on Dropdown save dropdown value to some local variable and then use it to find your const by doing:
property( index(er, wherecontains(local!dropdownselectedvalue, tointeger(er.dd_value))), "cons")
returned value of step 3 is your constant
This might not be perfect as you still have to maintain your dictionary but you can avoid long if...else statements.
As a alternative have a look on Decisions Tables in Appian https://docs.appian.com/suite/help/21.1/Appian_Decisions.html
class Seller(object):
type = ...
name = ...
cars = models.ManyToManyField(Car)
class PotentialBuyer(object):
name = ...
cars = models.ManyToManyField(Car)
class Car(object):
extra_field = ...
extra_field2 = ...
Suppose I have a relationship like this. I would like to use extra queryset modifier to get the list of cars that are already been picked out by PotentialBuyers when I fetch a seller object. I suppose the query queryset will something like this.
def markPending(self)
return self.extra(select={'pending': 'select images from PotentialBuyer as t ...'})
How can I accomplish this? Is there a better way? I could fetch the seller object and the potential object and do sets, but I'd think it would be cleaner to make it handled by the database. I am using PostgreSQL 9.5.
I think the Exists subquery expression will do what you want. Or at least it'll get you started on the right path. Docs Or you might want to use an aggregate to count the number of them.
Edit: If you need to select the full objects rather than the count, existence or a single entity, then use a Prefetch instance in prefetch_related. https://docs.djangoproject.com/en/2.0/ref/models/querysets/#django.db.models.Prefetch
Not quite the answer, but this is the solution I ended up with and I am satisfied by the performance. Perhaps someone can answer the question later :
from api.models import PotentialBuyer
potentials = PotentialBuyer.objects.filter(owner=user_id, default=True).first().cars.all()
Car.objects.filter(....).annotate(pending=Case(When(id__in=potentials, then=Value(True)), default=Value(False), output_field=BooleanField()))
I'm fairly certain after years of searching that this is not possible, but I'll ask anyway.
The question is whether it's possible to use a dynamic variable in an operation when you don't know the field name. For example, I have a data structure that contains a few hundred fields. The operator selects one of those fields and the program needs to know what data resides in the field from the data structure passed. So we'll say that there are 100 fields, and field50 is what the operator chose to operate on. The program would be passed in the field name (i.e. field50) in the FLDNAM variable. The program would read something like this the normal way:
/free
if field50 = 'XXX'
// do something
endif;
/end-free
The problem is that I would have to code this 100 times for every operation. For example:
/free
if fldnam = 'field1';
// do something
elseif fldnam = 'field2';
// do something
..
elseif fldnam = 'field50';
// do something
endif;
Is there any possible way of performing an operation on a field not yet known? (i.e. IF FLDNAM(pointer data) = 'XXX' then do something)
If the data structure is externally-described and you know what file it comes from, you could use the QUSLFLD API to find out the offset, length, and type of the field in the data structure, and then use substring to get the data and then use other calculations to get the value, depending on the data type.
Simple answer, no.
RPG's simply not designed for that. Few languages are.
You may want to look at scripting languages. Perl for instance, can evaluate on the fly. REXX, which comes installed on the IBM i, has an INTERPRET keyword.
REXX Reference manual
Following is a Node we having in DB
P:Person { name:"xxx", skill:"Java" }
and after awhile, we would like to change the Skill to skill array, is it possible?
P:Person { name:"xxx", skill:["Java", "Javascript"] }
Which Cypher query should I use?
If you have a single skill value in skill, then just do
MATCH (p:Person)
WHERE HAS (p.skill)
SET p.skill=[p.skill]
If there are multiple values you need to convert to an array such as P:Person { name:"xxx", skill:"Java","JavaScript" } then this should work:
MATCH (p:P)
SET p.skill= split(p.skill,",")
In fact, I think your real problem here is not how to get an array property in a node, but how to store it. Your data model is wrong in my opinion, storign data as array in neo4j is not common, since you have relations to store multiple skills (in your example).
How to create your data model
With your question, I can already see that you have one User, and one User can have 1..n skills.
I guess that one day (maybe tomorrow) you will need to know which users are able to use Java, C++, PHP, and every othre skills.
So, Here you can already see that every skill should have its own node.
What is the correct model in this case?
I think that, still with only what you said in question, you should have something like this:
(:Person{name:"Foo"})-[:KNOWS]->(:Skill{name:"Bar"})
using such a data model, you can get every Skill known by a Person using this query:
MATCH (:Person{name:"Foo"})-[:KNOWS]->(skill:Skill)
RETURN skill //or skill.name if you just want the name
and you can also get every Person who knows a Skill using this:
MATCH (:Skill{name:"Bar"})<-[:KNOWS]-(person)
RETURN person //Or person.name if you just want the name
Keep in mind
Storing array values in properties should be the last option when you are using neo4j.
If a property can be found in multiple nodes, having the same value, you can create a node to store it, then you will be able to link it the other nodes using relations, and finding every node having the property X = Y will be easier.
Suppose I have a Model Class named Anything, in Yii, and all I want is to get not the field value, but the field name, how could I do that?
Because using something like:
$anything = new Anything;
$anything->field_name;
Returns the value of that field, which is the purpose for that, still, if all you want is the string of the name of the field, how could you do that?
I tried using:
$anything->attributes;
But it just returns an array of field names, I want to try and get a specific value as a defined constant.
What I want to do is use the $_POST with specific and practical use, so I wouldn't need to use:
$_POST["Model_name"];
Instead I could use:
$_POST[Anything::model()->name][Anything::model()->field_name->name]
Which seems a lot better than "" and '' here and there. Mostly because I'm trying to set multiple fieldsets of different Models in the same formulary.
So if I could use:
$_POST[Anything::model()->name][Anything::model()->field_name->name];
and
$_POST[Something::model()->name][Something::model()->field_name->name]
and
$_POST[Godspeed::model()->name][Godspeed::model()->field_name->name]
It would save a lot of problems I might had in the future.
$strModelName = 'ModelName'; //dynamic - whatever model name you put in it
$find_id = 3;
$record = $strModelName::model()->findByPK($find_id); //it's same with ModelName::model()->findByPK(3)
foreach($record->attributes as $key=>$value){
var_dump($_POST[$strModelName][$key]); //get value corresponding to given key
}
Btw, you still need check whether the model is exist or not
http://www.yiiframework.com/forum/index.php/topic/22790-check-if-model-exists/