In WebKitGtk1 there was a function to load an html page directly from a string.
webkit_web_view_load_string ()
Requests loading of the given content with the specified mime_type ,
encoding and base_uri .
Is there an equivalent in WebKitGtk2? I would like to display an HTML page that is re-generated very often, so saving it as a file and loading this file is no option.
http://webkitgtk.org/reference/webkit2gtk/stable/WebKitWebView.html
There are few load methods e.g. webkit_web_view_load_html. Please pick up the one that suits your needs.
Related
I have a requirement wherein I need to display details of users after searching from LDAP using PUMA API.
I'm having troubling displaying the jpegPhoto of the user.
Here's what I'm doing:
First I'm querying the user by using:
PumaLocator.findUsersByAttribute(uid, user);
After that we get a User list Object.
For each user, we fetch all the attributes which is in the form of a Map.
I'm getting the following value for while retrieving the jpegPhoto:
map.get("jpegPhoto") --> [B#7a2f8a54
It seems that the Puma API returns a Binary string. Does anyone know how to display this in the portlet?
Any help would be greatly appreciated. Thank you
I think it more likely this is a byte[] array than a string.
You can probably base64 encode this binary into an encoded string and use it in an HTML image tag.
byte[] photoBytes = (byte[]) map.get("jpegPhoto");
String encodedPhoto = org.apache.commons.codec.binary.Base64.encodeBase64(photoBytes);
Then later, perhaps in a JSP (example assumes JSTL variable in scope named encodedPhoto):
<img src="data:image/jpeg;base64,${encodedPhoto}"/>
A way of doing this is to access the image through the portal service servlet instead of using your own servlet: /wps/um/secure/users/profiles/[oid]/jpegPhoto, in which you replace [oid] with the ObjectID of the user. This ID string can be obtained using IdentificationMgr.getIdentification().serialize(user.getObjectID())
The photo of the current user you can access using: /wps/um/secure/currentuser/profile/jpegPhoto
Portal is giving you data as byte array. It will never give you as URL.
You can write a servlet which will write this byte array to output stream.
Use that servlet URL as src of tag. It will start rendering on browser.
FYI, you can't print byte array to browser and expect it to treat as image.
Image or any other files has to come as a resource not as content.
I have a user that is storing a 'registered trademark' symbol in her name in our database and when we retrieve it when the database it renders correctly, but when we actually place it onto the website itself in HTML it renders with an extra 'A' symbol in front of it:
You can see above the database value compared to what is rendered in the PDF file. I can access the database value in the backend and edit it through vb code but I am really not sure how or what the code would be to do that as I don't want to remove all ASCII characters just the extra symbol being generated and rendered in the PDF.
Any idea how to do this would be great.
I think the Main-Problem is that you generate wrong HTML-Code by just inserting your Database-Result-Strings into your Website
You can encode your Database String to HTML by using the HtmlEncode-Function from HttpUtility in .NET
Here is an Example from vb.net
myEncodedString = HttpUtility.HtmlEncode(myString)
If you use "myEncodedString" inside your WebPage you'll get no additional Characters and a valid HTML-Code.
How can I create a new blank page in zen-cart without applying the template.
I want to create a page that will result only a JSON data...
Thanks in advance
Create a php file in your store directory. In that file, if you want to use ZenCart functions you can include them, like so:
<?php
include "includes/application_top.php";
set headers for mime type
set headers for not caching
YOUR CODE
echo $json;
// below is optional if you didn't create/edit session
include "includes/application_bottom.php";
I have a custom content type with 3 FileFields (plone.app.blob.field.FileField) and I want to get their url's, so i can put them on my custom view and people will be able to download these files.
However, when using Clouseau to test and debug, I call :
context.getFirst_file().absolute_url()
Where getFirst_file() is the accessor to the first file (field called 'first_file').
The url returned is 'http://foo/.../eat.00001', where 'eat.00001' is the object of my custom type that contains the file fields...
The interesting thing is, if I call:
context.getFirst_file().getContentType()
It returns 'application/pdf', which is correct since it's a pdf file.
I'm pretty lost here, any help is appreciated. Thanks in advance!
File fields do not support a absolute_url method; instead, through acquisition you inherit the method from the object itself, hence the results you see. Moreover, calling getFirst_field() will return the actual downloadable contents of the field, not the field itself which could provide such information.
Instead, you should use the at_download script appended to the object URL, followed by the field id:
First File
You can also re-use the Archetypes widget for the field, by passing the field name to the widget method:
<metal:field use-macro="python:context.widget('first_field', mode='view')">
First File
</metal:field>
This will display the file size, icon (if available), the filename and the file mime type.
In both these examples, I assumed the name of the field is 'first_field'.
Using the HTML5 File API, I wonder if I can process the content of a file on the fly.
I know I can get the content of the file when onload is called:
function fileLoaded(e)
{
alert("content is "+e.target.result);
}
but can I get the current content when onprogress is called ?
Thanks.
Seems like yes, according to the spec. The onprogress event will fill the result property of your FileReader as more data is read in. However, as Matt pointed out, if you're only interested in a portion of the file in the first place, only read that section:
var blob = file.webkitSlice|mozSlice(startByte, stopByte, contentType);
reader.readAsBinaryString(blob);
I don't think so, but look at this example which shows you how to read slices of files.