MDX return last month of every year - ssas

Question

I am trying to create a set to return the value of the last month that contains data for each year.
For example if I would put year on the rows
2011,2012,2013,2014 would all contain data for December.
2015 would contain data for June of 2015.
I can't seem to get anything but the latest month to return. I figure it is because of my tail statement, but I'm not sure how to fix it.
CREATE SET [Last Statement Month] AS
Tail(
nonempty(
Descendants(
[Date].[Calendar].currentmember
,[Date].[Calendar].[Month]
),
[Measures].[Sale Amount]
), 1);
I also tried to get the last day of each month, but when I use this with the year on the rows nothing shows up.
GENERATE(
{
Openingperiod([Date].[Calendar].[Month]):ClosingPeriod([Date].[Calendar].Month)
},
{[Date].[Calendar].CurrentMember.Lastchild}
);

Answer 1

I'm currently away from AdvWrks so unable to test. Does the following help?
CREATE SET [Last Statement Month] AS
TAIL(
NONEMPTY(
EXISTING ([Date].[Calendar].[Month].MEMBERS)
,[Measures].[Sale Amount]
)
);
(If this approach works) Performance is apparently better if EXISTING is performed last:
CREATE SET [Last Statement Month] AS
TAIL(
EXISTING
NONEMPTY(
[Date].[Calendar].[Month].MEMBERS
,[Measures].[Sale Amount]
)
);
Looks like the above isn't going to work. I've added an alternative in the following which maybe is more what you're looking for:
WITH
DYNAMIC SET [Last Statement Month] AS
Tail
(
NonEmpty
(
(EXISTING
[Date].[Calendar].[Month].MEMBERS)
,[Measures].[Internet Sales Amount]
)
)
MEMBER [Measures].[x] AS
[Last Statement Month].Item(0).Item(0).Member_Caption
MEMBER [Measures].[Lst mth with data] AS `<<<<maybe something like this helps?
Max
(
(EXISTING
[Date].[Calendar].[Month].MEMBERS)
,IIF
(
[Measures].[Internet Sales Amount] = 0
,NULL
/*,[Date].[Calendar].CurrentMember.Member_Caption*/ //<<WRONG PROPERTY USED
,[Date].[Calendar].CurrentMember.MemberValue //<<should help!!
)
)
SELECT
{[Measures].[Lst mth with data],[Measures].[x]} ON 0
,[Date].[Calendar].[Calendar Year] ON 1
FROM [Adventure Works];
Results in this:
After Edit returns this: