I want to put a condition in my query where I have a column that should contain second position as an alphabet.
How to achieve this?
I've tried with _[A-Z]% in where clause but is not working. I've also tried [A-Z]%.
Any inputs please?
I think you want mysql query. like this
SELECT * FROM table WHERE column REGEXP '^.[A-Za-z]+$'
or sql server
select * from table where column like '_[a-zA-Z]%'
You can use regular expression matching in your query. For example:
SELECT * FROM `test` WHERE `name` REGEXP '^.[a-zA-Z].*';
That would match the name column from the test table against a regex that verifies if the second character is either a lowercase or uppercase alphabet letter.
Also see this SQL Fiddle for an example of data it does and doesn't match.
agree with #Gordon Linoff, your ('_[A-Z]%') should work.
if not work, kindly add some sample data with your question.
Declare #Table Table
(
TextCol Varchar(20)
)
Insert Into #Table(TextCol) Values
('23423cvxc43f')
,('2eD97S9')
,('sAgsdsf')
,('3Ss08008')
Select *
From #Table As t
Where t.TextCol Like '_[A-Z]%'
The use of '%[A-Z]%' suggests that you are using SQL Server. If so, you can do this using LIKE:
where col like '_[A-Z]%'
For LIKE patterns, _ represents any character. If the first character needs to be a digit:
where col like '[0-9][A-Z]%'
EDIT:
The above doesn't work in DB2. Instead:
where substr(col, 2, 1) between 'A' and 'Z'
Related
I have a table in SQL Server that stores codes. Depending on the nomenclature, some begin with 'DB_' and others with 'DBL_'. I need a way to filter the ones that start with 'DB_', since when I try to do it, it returns all the results.
CREATE TABLE CODES(Id integer PRIMARY KEY, Name Varchar(20));
INSERT INTO CODES VALUES(1,'DBL_85_RC001');
INSERT INTO CODES VALUES(2,'DBL_85_RC002');
INSERT INTO CODES VALUES(3,'DBL_85_RC003');
INSERT INTO CODES VALUES(4,'DB_20_SE_RC010');
INSERT INTO CODES VALUES(5,'DB_20_SE_RC011');
SELECT * FROM CODES where Name like 'DB_%';
The result that returns:
1|DBL_85_RC001
2|DBL_85_RC002
3|DBL_85_RC003
4|DB_20_SE_RC010
5|DB_20_SE_RC011
Expected result:
4|DB_20_SE_RC010
5|DB_20_SE_RC011
_ is a wildcard for a single character in a LIKE expression. Thus both 'DB_' and 'DBL' are LIKE 'DB_'. If you want a literal underscore you need to put it in brackets ([]):
SELECT *
FROM CODES
WHERE [Name] LIKE 'DB[_]%';
The underscore is a wildcard in SQL Server. You can escape it:
where name like 'DB$_%' escape '$'
You could also use left():
where left(name, 3) = 'DB_'
However, this is not index- and optimizer friendly.
select * from table where column like '%a|b%'
The above query matches all rows with the column having either 'a' OR 'b' as a substring.
What if I want to match the substring "a|b"?
Using the query,
select * from table where column like '%a\|b%'
yields the same result.
Can I get the complete reference for the LIKE operator in hive? The UDF manual seems insufficient.
You can use RLIKE (regular expression) : select * from table where column rlike '.*a\|b.*'
You can use select * form table where column like '%a[|]b%'
I am trying to concatenate multiple columns in a query in SQL Server 11.00.3393.
I tried the new function CONCAT() but it's not working when I use more than two columns.
So I wonder if that's the best way to solve the problem:
SELECT CONCAT(CONCAT(CONCAT(COLUMN1,COLUMN2),COLUMN3),COLUMN4) FROM myTable
I can't use COLUMN1 + COLUMN2 because of NULL values.
EDIT
If I try SELECT CONCAT('1','2','3') AS RESULT I get an error
The CONCAT function requires 2 argument(s)
Through discourse it's clear that the problem lies in using VS2010 to write the query, as it uses the canonical CONCAT() function which is limited to 2 parameters. There's probably a way to change that, but I'm not aware of it.
An alternative:
SELECT '1'+'2'+'3'
This approach requires non-string values to be cast/converted to strings, as well as NULL handling via ISNULL() or COALESCE():
SELECT ISNULL(CAST(Col1 AS VARCHAR(50)),'')
+ COALESCE(CONVERT(VARCHAR(50),Col2),'')
SELECT CONCAT(LOWER(LAST_NAME), UPPER(LAST_NAME)
INITCAP(LAST_NAME), HIRE DATE AS ‘up_low_init_hdate’)
FROM EMPLOYEES
WHERE HIRE DATE = 1995
Try using below:
SELECT
(RTRIM(LTRIM(col_1))) + (RTRIM(LTRIM(col_2))) AS Col_newname,
col_1,
col_2
FROM
s_cols
WHERE
col_any_condition = ''
;
Blockquote
Using concatenation in Oracle SQL is very easy and interesting. But don't know much about MS-SQL.
Blockquote
Here we go for Oracle :
Syntax:
SQL> select First_name||Last_Name as Employee
from employees;
Result: EMPLOYEE
EllenAbel
SundarAnde
MozheAtkinson
Here AS: keyword used as alias.
We can concatenate with NULL values.
e.g. : columnm1||Null
Suppose any of your columns contains a NULL value then the result will show only the value of that column which has value.
You can also use literal character string in concatenation.
e.g.
select column1||' is a '||column2
from tableName;
Result: column1 is a column2.
in between literal should be encolsed in single quotation. you cna exclude numbers.
NOTE: This is only for oracle server//SQL.
for anyone dealing with Snowflake
Try using CONCAT with multiple columns like so:
SELECT
CONCAT(col1, col2, col3) AS all_string_columns_together
, CONCAT(CAST(col4 AS VARCHAR(50), col1) AS string_and_int_column
FROM table
If the fields are nullable, then you'll have to handle those nulls. Remember that null is contagious, and concat('foo', null) simply results in NULL as well:
SELECT CONCAT(ISNULL(column1, ''),ISNULL(column2,'')) etc...
Basically test each field for nullness, and replace with an empty string if so.
How to retrieve a column containing special characters including alphabets in SQL Query. i have a column like this 'abc%def'. i want to retrieve '%' based columns from that table.
Please help me in this regard.
Is abc%def the column name? or column value? Not sure what you are asking but if you mean your column name contains special character then you can escape them which would be different based on specific RDBMS you are using
SQL Server use []
select [abc%def] from tab
MySQL use backquote
select `abc%def` from tab
EDIT:
Try like below to fetch column value containing % character (Checked, it works in Ingres as well)
select * from tab where col like '%%%'
Others suggest that like '%%%' works in Ingres. So this is something special in Ingres. It does not work in other dbms.
In standard SQL you would have to declare an escape character. I think this should work in Ingres, too.
select * from mytable where str like '%!%%' escape '!';
I've got a simple nvarchar(25) column in an SQL database table. Most of the time, this field should contain alphanumeric text. However, due to operator error, there are many instances where it contains only a number. Can I do a simple search in SQL to identify these cases? That is, determine which rows in the table contain only digits in this column. As an extension, could I also search for those column values which contain only digits and a space and/or slash.
In other languages (eg. Perl, Java) a regular expression would resolve this quickly and easily. But I haven't been able to find the equivalent in SQL.
yes you can achive this by using isnumeric function available in sql sever
check more at this link : http://msdn.microsoft.com/en-us/library/aa933213(SQL.80).aspx
All the answers referred to the isnumeric function, but they are not correct, I've mentioned in a comment for all the answers the flaw in the answers. The correct solution is to use a regular expression in your where clause, which contains not like '%[^0-9]%', see the example below:
select column_name from table_name where column_name not like '%[^0-9]%'
select column_name from table_name where IsNumeric(column_name) <> 1
Numeric Only:
SELECT * FROM Table WHERE ISNUMERIC(Field) = 1
With Space:
SELECT * FROM Table WHERE Field LIKE '% %'
With Slash:
SELECT * FROM Table WHERE Field LIKE '%/%'
Combined:
SELECT * FROM Table WHERE ISNUMERIC(Field) = 1 OR Field LIKE '% %' OR Field LIKE '%/%'