I have a lists of names John, Rupert, Cassandra, Amy, and I want to get names which are not exists in table: Cassandra, Amy
How should I write such query?
My table:
+----+--------+-----------+------+
| id | name | address | tele |
+----+--------+-----------+------+
| 1 | Rupert | Somewhere | 022 |
| 2 | John | Doe | 029 |
| 3 | Donald | Armstrong | 021 |
| 4 | Bob | Gates | 022 |
+----+--------+-----------+------+
Think in sets. You add names to a the result set with UNION ALL, you remove names from the result set with EXCEPT.
select 'John'
union all
select 'Rupert'
union all
select 'Cassandra'
union all
select 'Amy'
except
select name from mytable;
Build up a list of your names to check and do a left join to the users table:
with to_check (name) as (
values
('John'), ('Rupert'), ('Cassandra'), ('Amy')
)
select tc.name as missing_name
from to_check tc
left join the_table tt on tt.name = tc.name
where tt.name is null;
SQLFiddle example: http://sqlfiddle.com/#!15/5c4f5/1
Hope your list is in form of table lets its be table b and your original table as a
now SQL query goes like it
Select name from a where name not in (select name from b);
Think this will give you solution as per my understanding. Also if further details are required please comment.
Also its more important to search for an answer as it look like its a question from a book/Class. Please try out to find solution could have got much more information like link below
How to write "not in ()" sql query using join
Related
I have a table containing pairs for matches, and the table looks like this:
|pairing_id|player1_id|player2_id|number_of_round|
| 132 | Thomas | Brian | 1 |
I try to write an sql query, which shows me all the redundant pairs, so the pairing is the same if the 2 player names are the same, but for the second time, Brian is player1 and Thomas is the player2.
So this 2 matchups are considered the same pairs, as the player names are the same:
|pairing_id|player1_id|player2_id|number_of_round|
| 132 | Thomas | Brian | 1 |
| 458 | Brian | Thomas | 4 |
I need to find all the redundant pairings in the table, but sadly I dont know how to query for this.
Can be done with EXISTS
select t1.pairing_id, t1.player1_id, t1.player2_id, t1.number_of_round
from myTable t1
where exists (select null
from myTable t2
where t2.player1_id = t1.player2_id and t2.player2_id = t1.player1_id)
order by case when t1.player1_id > t1.player2_id then t1.player2_id else t1.player1_id end
You can do it with exists:
select t.* from tablename t
where exists (
select 1 from tablename
where pairing_id <> t.pairing_id and player1_id = t.player2_id and player2_id = t.player1_id
)
I have a table that looks like that:
+----------+----------+----------+----------+--------------------------+
| Club | Role | Name | Lastname | Email |
+----------+----------+----------+----------+--------------------------+
| Porto | 1 | Peter | Pan | peter.pan#mail.com |
| Porto | 2 | Michelle | Obama | michelle.obama#mail.com |
| Monaco | 1 | Serena | Williams | serena.williams#mail.com |
| Monaco | 2 | David | Beckham | david.beckham#mail.com |
+----------+----------+----------+----------+--------------------------+
and i want to get a table like that:
+----------+-----------------+-----------------+---------------------------------+-----------------+-----------------+---------------------------------+
| Club | Role 1 Name | Role 1 Lastname | Role 1 Email | Role 2 Name | Role 2 Lastname | Role 2 Email |
+----------+-----------------+-----------------+---------------------------------+-----------------+-----------------+---------------------------------+
| Porto | Peter | Pan | peter.pan#mail.com | Michelle | Obama | michelle.obama#mail.com |
| Monaco | Serena | Williams | serena.williams#mail.com | David | Beckham | david.beckham#mail.com |
+----------+-----------------+-----------------+---------------------------------+-----------------+-----------------+---------------------------------+
where the persons with different roles in each club puts in the same row.
I would ideally like to find a way to do that in Excel, but i am not sure if its possible. If not, SQL code would also help a lot.
Here is what I could come up with for an excel formula. Hopefully it can push you in the right direction.
This formula is assuming that your first table exists at the range A1:E5 and the second table exists at the range G1:M3. It is also assuming that the second table's column names are just repeating without the Role number attached to the front of it (same as the first table). This formula is an array formula, so you have to make sure to do CTRL+SHIFT+ENTER when inputting it.
{=INDEX($A$2:$E$5,
MATCH(1,($G2=$A$2:$A$5)*((FLOOR((COLUMN() - COLUMN($H$1) ) / 3,1) + 1)=$B$2:$B$5),0),
MATCH(H$1,$A$1:$E$1,0))}
The first part is using the INDEX forumla which pulls data from the range suppled ($A$2:$E$5) based on the row and column numbers supplied by the following MATCH formulas.
The first MATCH is supplying the row number for when the result of the lookup array section is equal to 1. I am checking two conditions, the first is to check for the "Club" name ($G2=$A$2:$A$5) and the second is to check for which "Role" we are currently on ((FLOOR((COLUMN() - COLUMN($H$1) ) / 3,1) + 1). This is using the FLOOR function to round the result down to the whole number and dividing by the number of columns (3 in this case: Name, Lastname, and Email).
The final MATCH is pulling the column number based on the header names from both tables. If you wanted to incorporate the changing names of the roles in the column headers, you could change this part to something like this:
{=INDEX($A$2:$E$5,
MATCH(1,($G2=$A$2:$A$5)*((FLOOR((COLUMN() - COLUMN($H$1) ) / 3,1) + 1)=$B$2:$B$5),0),
MOD(COLUMN() - COLUMN($H$1),3) + 3)}
I am adding 3 to the end of the mod because of the original range that was selected for table 1. The columns that we want to pull start at location 3 in the range.
If you want to do this in Oracle Sql, there's a nice approach in analytical sql.
To convert/swap rows to columns or columns to rows, we can use Pivot or Unpivot operators.
In you example use below query to covert data as you like,
select * from
(
with all_roles as
(select 1 role from dual union all
select 2 role from dual),
ddata as
(select 1 c_role, 'porto' club, 'peter' fname,'pan' lname,'peter.pan#mail.com' email from dual union all
select 2 c_role, 'porto' club, 'Michelle' fname, 'Obama' lname,'michelle.obama#mail.com' email from dual union all
select 1 c_role, 'monaco' club, 'Serena' fname, 'Williams' lname,'serena.williams#mail.com' email from dual union all
select 2 c_role, 'monaco' club, 'David' fname, 'Beckham' lname,'david.beckham#mail.com' email from dual )
(select role, club, fname,lname, email from ddata,all_roles
where all_roles.role=ddata.c_role)) all_data
pivot (
max(fname) fname,
max(lname) lname,
max(email) email
for role in ( 1 role1, 2 role2 )
)
order by club;
I have a table with column GetDup and I'd like to the duplicate records based on the value of this column. For example, if value on is 1 in GetDup, then duplicate the record once. If value in the column is 2, then duplicate the record twice and so on and the statement has to be in looping statement.
What will be a good way to write a stored procedures for this? Please help.
Input:
+--------+--------------+---------------+
| Getdup | CustomerName | CustomerAdd |
+--------+--------------+---------------+
| 1 | John | 123 SomeWhere |
| 2 | Bob | 987 SomeWhere |
+--------+--------------+---------------+
What I want:
+--------+--------------+---------------+
| Getdup | CustomerName | CustomerAdd |
+--------+--------------+---------------+
| 1 | John | 123 SomeWhere |
| 1 | John | 123 SomeWhere |
| 2 | Bob | 987 SomeWhere |
| 2 | Bob | 987 SomeWhere |
| 2 | Bob | 987 SomeWhere |
+--------+--------------+---------------+
picture of data
Answer #2 After Clarification
Number Table to the Rescue!
The number table in my example (or tally table, if you want to call it that), is both temporary and very small. To make it bigger, just add more values to z and add more CROSS JOINs. In my opinion, a number table and a calendar table are both things that should be in every database you have. They are extremely useful.
SQL Fiddle
MS SQL Server 2017 Schema Setup:
CREATE TABLE mytable ( Getdup int, CustomerName varchar(10), CustomerAdd varchar(20) ) ;
INSERT INTO mytable (Getdup, CustomerName, CustomerAdd)
VALUES (1,'John','123 SomeWhere'), (2,'Bob','987 SomeWhere')
;
Query 1:
;WITH z AS (
SELECT *
FROM ( VALUES(0),(0),(0),(0) ) v(x)
)
, numTable AS (
SELECT num
FROM (
SELECT ROW_NUMBER() OVER (ORDER BY z1.x)-1 num
FROM z z1
CROSS JOIN z z2
) s1
)
SELECT t1.Getdup, t1.CustomerName, t1.CustomerAdd
FROM mytable t1
INNER JOIN numTable ON t1.getdup >= numTable.num
ORDER BY CustomerName, CustomerAdd
Results:
| Getdup | CustomerName | CustomerAdd |
|--------|--------------|---------------|
| 2 | Bob | 987 SomeWhere |
| 2 | Bob | 987 SomeWhere |
| 2 | Bob | 987 SomeWhere |
| 1 | John | 123 SomeWhere |
| 1 | John | 123 SomeWhere |
--------------------------------------------------------------------------
ORIGINAL ANSWER
EDIT: After further clarification of the problem, this won't duplicate rows, this will only duplicate the data in a column.
Something like one of these might work.
T-SQL
SELECT replicate(mycolumn,getdup) AS x
FROM mytable
MySQL
SELECT repeat(mycolumn,getdup) AS x
FROM mytable
Oracle SQL
SELECT rpad(mycolumn,getdup*length(mycolumn),mycolumn) AS x
FROM mytable
PostgreSQL
SELECT repeat(mycolumn,getdup+1) AS x
FROM mytable
If you can provide more details for exactly what you want and what you're working with, we might be able to help you better.
NOTE 2: Depending on what you need, you may need to do some math magic. You say above if GetDup is 1 then you want one duplicate. If that means that your output should be GetDup``GetDup, then you'll want to add one in the repeat(),replicate() or rpad() functions. ie replicate(mycolumn,getdup+1). Oracle SQL will be a little different, since it uses rpad().
In standard SQL you can use a recursive CTE:
with recursive cte as (
select t.dup, . . .
from t
union all
select cte.dup - 1, . . .
from cte
where cte.dup > 1
)
select *
from cte;
Of course, not all databases support recursive CTEs (and the recursive keyword is not used in some of them).
So, you want recursive solution :
with t as (
select Getdup, CustomerName, CustomerAdd, 0 as id
from table
union all
select Getdup, CustomerName, CustomerAdd, id + 1
from t
where id < getdup
)
insert into table (col1, col2, col3)
select Getdup, CustomerName, CustomerAdd
from t
order by getdup
option (maxrecursion 0);
Let's say I have a table in BigQuery containing 2 columns. The first column represents a name, and the second is a delimited list of values, of arbitrary length. Example:
Name | Scores
-----+-------
Bob |10;20;20
Sue |14;12;19;90
Joe |30;15
I want to transform into columns where the first is the name, and the second is a single score value, like so:
Name,Score
Bob,10
Bob,20
Bob,20
Sue,14
Sue,12
Sue,19
Sue,90
Joe,30
Joe,15
Can this be done in BigQuery alone?
Good news everyone! BigQuery can now SPLIT()!
Look at "find all two word phrases that appear in more than one row in a dataset".
There is no current way to split() a value in BigQuery to generate multiple rows from a string, but you could use a regular expression to look for the commas and find the first value. Then run a similar query to find the 2nd value, and so on. They can all be merged into only one query, using the pattern presented in the above example (UNION through commas).
Trying to rewrite Elad Ben Akoune's answer in Standart SQL, the query becomes like this;
WITH name_score AS (
SELECT Name, split(Scores,';') AS Score
FROM (
(SELECT * FROM (SELECT 'Bob' AS Name ,'10;20;20' AS Scores))
UNION ALL
(SELECT * FROM (SELECT 'Sue' AS Name ,'14;12;19;90' AS Scores))
UNION ALL
(SELECT * FROM (SELECT 'Joe' AS Name ,'30;15' AS Scores))
))
SELECT name, score
FROM name_score
CROSS JOIN UNNEST(name_score.score) AS score;
And this outputs;
+------+-------+
| name | score |
+------+-------+
| Bob | 10 |
| Bob | 20 |
| Bob | 20 |
| Sue | 14 |
| Sue | 12 |
| Sue | 19 |
| Sue | 90 |
| Joe | 30 |
| Joe | 15 |
+------+-------+
If someone is still looking for an answer
select Name,split(Scores,';') as Score
from (
# replace the inner custome select with your source table
select *
from
(select 'Bob' as Name ,'10;20;20' as Scores),
(select 'Sue' as Name ,'14;12;19;90' as Scores),
(select 'Joe' as Name ,'30;15' as Scores)
);
I've an old table like this:
user> id | name | address | comments
And now I've to create an "alias" table to allow some users to have an alias name for some reasons. I've created a new table 'user_alias' like this:
user_alias> name | user
But now I have a problem due my poor SQL level... How to join both tables to generate something like this:
1 | my_name | my_address | my_comments
1 | my_alias | my_address | my_comments
2 | other_name | other_address | other_comments
I mean, I want to make a "SELECT..." query that returns in the same format as the "user" table ALL users and ALL alias.. Something like this:
SELECT user.* FROM user LEFT JOIN user_alias ON `user`=`id`
but it doesn't work for me..
I think you need something like this:
SELECT user.*
FROM user
LEFT JOIN user_alias
ON user.name=user_alias.name
Your original query was not specific enough in the join condition.
Something like
SELECT user.name, user.address, user.comment FROM user
UNION ALL
SELECT user_alias.alias, user.address, user.comment
FROM user INNER JOIN user_alias on user.name = user_alias.name
ORDER BY name
will get you close to what you want.
You need to UNION two SELECTs together because the LEFT JOIN solution proposed by others will include only one row in the result set for users with aliases, not two as specified in your question.
But you should make the common column joining user and alias the id column, not the name column.
SELECT user.* FROM user LEFT JOIN user_alias ON user.name = user_alias.name
First of all - the query you want to build is not trivial, because you are trying to get some results spanned across more than one row. So I will offer you a proper solution in a fashion like it should be (read: in a way a database developer will do this :-).
First, you should modify your user_alias table so that it will contain id column but not the name. It is not good idea to join your tables using the name field. The reason for this is that there could be two Sarah Connors.
Then, you can get results from both tables using this query:
SELECT user.*, user_alias.*
FROM user LEFT JOIN user_alias
ON user.id=user_alias.id
This way you will get your results in such format:
id | name | address | comments | user
-------------------------------------------------------------
1 | Sarah Connor | Planet Earth | Nice woman | sarah_connor
2 | Sarah Connor | USA, NY | Mean woman | sarah_c
3 | John Connor | USA, NY | n00b | john123
In the situations when there are two or more records in user_alias table for the same person (equal id's), you will get something like this:
id | name | address | comments | user
-------------------------------------------------------------
4 | Bill Clinton | White House | President | bill
4 | Bill Clinton | White House | President | monica