I am using a query in oracle which gives the below result (its a kind of month-wise transaction report):
Month Total Submitted Approved
--------------------------------------
DEC-14 2 2 0
APR-15 17 12 5
SEP-14 1 1 0
FEB-15 7 4 3
JUL-15 1 1 0
JAN-15 18 4 14
MAR-15 2 1 1
OCT-14 2 (null) (null)
JUN-15 136 91 45
JUN-14 1 1 0
MAY-15 179 63 116
I want to get the result in a sorted format, like JUN-14,SEP-14,OCT-14,DEC-14,JAN-15....so on. Thanks in advance.
order by date_column desc where date_column is the column that holds the date. This will order by the date_column in descending order.
Use asc to order in ascending order.
If month data type in character format you have to use
select * from table_name
order by to_char(to_date(month,'mm/yy'),'yy') asc,to_char(to_date(month,'mm/yy'),'mm') asc
if it is in date
select * from table_name
order by to_char(month,'yy') asc,to_char(month,'mm') asc
i assumed that you were using the following for displaying month column data.
TO_char(hiredate,'mon-yy')
if you used this then it will be easy for sorting them.
select your column list from table order by source_date_column asc;
for reference use the link
Related
I'm working in Athena (SQL) and trying to extract the date, year and month from column called "createddate" which involves timestamp and its a varchar data type. I have tried bunch of queries but I am getting errors after errors. Can you please help me extracting the date, year, month, week from this createddate column?
The field "createddate" is found in the following format:
id
createddate
1
11/29/2016 10:58:02
2
12/04/2016 07:07:58
3
10/22/2018 03:47:23
4
10/22/2018 08:20:25
5
10/22/2018 08:29:26
6
10/22/2018 08:42:28
7
10/22/2018 08:46:21
8
10/22/2018 10:18:57
12
10/22/2018 22:16:46
13
10/22/2018 22:24:33
14
10/23/2018 02:55:49
15
10/23/2018 07:49:39
16
10/23/2018 09:15:57
32
10/26/2018 06:19:13
33
10/26/2018 06:21:09
34
10/26/2018 06:24:59
48
10/30/2018 19:11:41
49
10/30/2018 20:10:10
64
11/01/2018 18:06:15
65
11/01/2018 18:08:00
66
11/01/2018 18:08:37
2
12/04/2016 07:07:58
99
11/09/2018 23:52:02
100
11/09/2018 23:57:13
Here are all my attempts:
select * from table where YEAR(from_iso8601_timestamp(createddate)) = 2022
and MONTH(from_iso8601_timestamp(createddate)) = 6 limit 10
select date_format(createddate,'%m/%d/%Y %H:%m:%s') from table limit 10
select date_format(createddate,'%m/%d/%Y H:m:s') from table limit 10
select date_format(createddate,'%m/%d/%Y %H:%i:%s') from table limit 10
select date_parse(createddate, '%m/%d/%Y %H:%i%p') from table limit 10
select date_parse(createddate, ' %m/%d/%Y') from table limit 10
select cast(date_parse(createddate,'%Y-%m-%d %h24:%i:%s') as date) from table limit 10
Select CAST(date_format(date_parse(cast(createddate as varchar(10)), '%m%d%Y'), '%m/%d/%Y') AS DATE) from table limit 10
Try with this one:
WITH cte AS (
SELECT id,
DATE_PARSE(createddate, '%m/%d/%Y %H:%i:%s') AS createddate
FROM table
)
SELECT id,
createddate,
YEAR(createddate),
MONTH(createddate),
WEEK(createddate)
FROM cte
You can find the documentation relative to the employed date functions here.
First off, apologies if this has been asked elsewhere as I was unable to find any solution. The best I get is retrieving latest 1 record or 2-3 records. I'm more in search of all records (the number could be dynamic, could be 1 or 2 or maybe 50+) based on recent Datetime value. Well so basically here is the problem,
I have a table as follows,
APILoadDatetime
RowId
ProjectId
Value
2021-07-13 15:09:14.620
1
Proj-1
101
2021-07-13 15:09:14.620
2
Proj-2
81
2021-07-13 15:09:14.620
3
Proj-3
111
2021-07-13 15:09:14.620
4
Proj-4
125
2021-05-05 04:46:07.913
1
Proj-1
99
2021-05-05 04:46:07.913
2
Proj-2
69
2021-05-05 04:46:07.913
3
Proj-3
105
2021-05-05 04:46:07.913
4
Proj-4
115
...
...
...
...
What I am looking to do is, write up a query which will give me all the recent data based on Datetime, so in this case, I should get the following result,
APILoadDatetime
RowId
ProjectId
Value
2021-07-13 15:09:14.620
1
Proj-1
101
2021-07-13 15:09:14.620
2
Proj-2
81
2021-07-13 15:09:14.620
3
Proj-3
111
2021-07-13 15:09:14.620
4
Proj-4
125
The RowId shows (as the name suggests) gives the number of Rows for a particular Datetime block. This will not always be 4, it's dynamic based on the data received so could be 1,2,4 or even 50+ ...
Hope I was able to convey the question properly, Thank you all for reading and Pre-Thank you to those who provide solution to this.
you can use window function row_number to find out the latest entry for each projectid:
select * from (
select * , rank() over (order by APILoadDatetime desc) rn
from tablename
) t where rn = 1
select top 1 with ties
*
from
tablename
order by
row_number() over(
partition by RowId
order by APILoadDatetime desc
);
TOP 1 works with WITH TIES here.
WITH TIES means that when ORDER BY = 1, then SELECT takes this record (because of TOP 1) and all others that have ORDER BY = 1 (because of WITH TIES).
Update #1:
If you need the last record by APILoadDatetime and several records which might have the same APILoadDatetime (as the first found), then the query is simplier:
select top 1 with ties
*
from
tablename
order by
APILoadDatetime desc;
I have the following View in PostgreSQL:
idshipment idorder quantity_order date quantity_in_shipment percent_sent
50 1 1020 1.1.16 432 42
51 1 1020 17.1.16 299 71
51 1 1020 20.1.16 144 85
51 1 1020 45.1.16 145 100
52 2 1 3.1.17 5 100
This View shows shipments per order.
For example:
idorder=1 was sent by 4 shipments:
quantity in first shipment is 432 which means 42% of order was sent
quantity in second shipment is 299 which means 71% of order was sent
quantity in third shipment is 144 which means 85% of order was sent
quantity in forth shipment is 145 which means 100% of order was sent
I need a query which will show me the first date where each order was sent above 75%. meaning each order shows only one row.
For the above data I should see:
idorder date
1 20.1.16 (cause its 85% first time above 75%)
2 3.1.17 (cause its 100% first time above 75%)
How can i do that?
You can use distinct on:
select distinct on (t.idshipment) t.*
from t
where t.percent_sent >= 75
order by t.idshipment, t.percent_sent asc;
Try something like this:
SELECT iorder, MIN("date") AS "date"
FROM your_view
WHERE percent_sent >= 75
GROUP BY iorder
use group by to get only one record per idorder and MIN() to aggregate date by selecting the earliest date
I created a table call shipment that has data like you provided:
and execute this query
SELECT s.idorder, MIN(s.date) as date
FROM shipment s
WHERE percent_sent >= 75
GROUP BY s.idorder
result:
idorder date
----------- ----------
1 2016-01-20
2 2017-03-01
I have a table which contain _id, underSubheadId, wefDate, price.
Whenever a product is created or price is edited an entry is made in this table also.
What I want is if I enter a date, I get the latest price of all distinct UnderSubheadIds before the date (or on that date if no entry found)
_id underHeadId wefDate price
1 1 2016-11-01 5
2 2 2016-11-01 50
3 1 2016-11-25 500
4 3 2016-11-01 20
5 4 2016-11-11 30
6 5 2016-11-01 40
7 3 2016-11-20 25
8 5 2016-11-15 52
If I enter 2016-11-20 as date I should get
1 5
2 50
3 25
4 30
5 52
I have achieved the result using ROW NUMBER function in SQL SERVER, but I want this result in Sqlite which don't have such function.
Also if a date like 2016-10-25(which have no entries) is entered I want the price of the date which is first.
Like for 1 we will get price as 5 as the nearest and the 1st entry is 2016-11-01.
This is the query for SQL SERVER which is working fine. But I want it for Sqlite which don't have ROW_NUMBER function.
select underSubHeadId,price from(
select underSubHeadId,price, ROW_NUMBER() OVER (Partition By underSubHeadId order by wefDate desc) rn from rates
where wefDate<='2016-11-19') newTable
where newTable.rn=1
Thank You
This is a little tricky, but here is one way:
select t.*
from t
where t.wefDate = (select max(t2.wefDate)
from t t2
where t2.underSubHeadId = t.underSubHeadId and
t2.wefdate <= '2016-11-20'
);
select underHeadId, max(price)
from t
where wefDate <= "2016-11-20"
group by underHead;
If data is in the following format:
SID TID Tdatetime QID QTotal
----------------------------------------
100 1 01/12/97 9:00AM 66 110
100 1 01/12/97 9:00AM 66 110
100 1 01/12/97 10:00AM 67 110
100 2 01/19/97 9:00AM 66 .
100 2 01/19/97 9:00AM 66 110
100 2 01/19/97 10:00AM 66 110
100 3 01/26/97 9:00AM 68 120
100 3 01/26/97 9:00AM 68 120
110 1 02/03/97 10:00AM 68 110
110 3 02/12/97 9:00AM 64 115
110 3 02/12/97 9:00AM 64 115
120 1 04/05/97 9:00AM 66 105
120 1 04/05/97 10:00AM 66 105
I would like to be able to write a query to sum the QTotal column for all rows and find the count of duplicate rows for the Tdatetime column.
The output would look like:
Year Total Count
97 | 1340 | 4
The third column in the result does not include the count of distinct rows in the table. And the output is grouped by the year in the TDateTime column.
The following query may help:
SELECT
'YEAR ' + CAST(sub.theYear AS VARCHAR(4)),
COUNT(sub.C),
(SELECT SUM(QTotal) FROM MyTable WHERE YEAR(Tdatetime) = sub.theYear) AS total
FROM
(SELECT
YEAR(Tdatetime) AS theYear,
COUNT(Tdatetime) AS C
FROM MyTable
GROUP BY Tdatetime, YEAR(Tdatetime)
HAVING COUNT(Tdatetime) >= 2) AS sub
This will work if you really want to group by the tDateTime column:
SELECT DISTINCT tDateTime, SUM(QTotal), Count(distinct tDateTime)
FROM Table
GROUP BY tDateTime
HAVING Count(distinct tDateTime) > 1
But your results look like you want to group by the Year in the tDateTime column. Is this correct?
If so try this:
SELECT DISTINCT YEAR (tDateTime), SUM(QTotal), Count(distinct tDateTime)
FROM Table
GROUP BY YEAR (tDateTime)
HAVING Count(distinct tDateTime) > 1
You must do SELECT from this table GROUPing by QTotal, using COUNT(subSELECT from this table WHERE QTotal is the same). If I only I had time I would write you SQL statement, but it'll take some minutes.
Something like:
select Year(Tdatetime) ,sum(QTotal), count(1) from table group by year(Tdatetime )
or full date
select Tdatetime ,sum(QTotal), count(1) from table group by year(Tdatetime)
Or your ugly syntax ( : ) )
select 'Year ' + cast(Year(tdatetime) as varchar(4))
+ '|' + cast(sum(QTotal) as varchar(31))
+ '|' + cast(count(1) as varchar(31))
from table group by year(Tdatetime )
Or do you want just the year? Sum all columns? Or just by year?
SELECT
YEar + year(Tdatetime),
SUM ( QTotal ),
(SELECT COUNT(*) FROM (
SELECT Tdatetime FROM tDateTime GROUP BY Tdatetime
HAVING COUNT(QID) > 1) C
FROM
Tdatetime t
GROUP BY
YEar + year(Tdatetime)
This is the first time I have asked a question on stackoverflow. It looks like I have lost my original ID info. I had to register to login and add comments to the question I posted.
To answer OMG Ponies question, this is a SQL Server 2008 database.
#Abe Miessler , the row with SID 120 does not contain duplicates. the first row for SID 120 shows 9:00AM in the datetime column , and the second row shows 10:00AM.
#Zafer, your query is the accepted answer. I made a few minor tweaks to get it to work. Thanks.
Thanks due to Abe Miessler and the others for your help.