SQL: Complex query with subtraction from different cells - sql

Question

I have two tables and I want to combine their data.
The first table
+------------+-----+------+-------+
| BusinessID | Lat | Long | Stars |
+------------+-----+------+-------+
| abc123 | 32 | 74 | 4.5 |
| abd123 | 32 | 75 | 4 |
| abe123 | 33 | 76 | 3 |
+------------+-----+------+-------+
The second table is:
+------------+-----+------+-------+
| BusinessID | day | time | count |
+------------+-----+------+-------+
| abc123 | 1 | 14 | 5 |
| abc123 | 1 | 15 | 6 |
| abc123 | 2 | 13 | 1 |
| abd123 | 4 | 12 | 4 |
| abd123 | 4 | 13 | 8 |
| abd123 | 5 | 11 | 2 |
+------------+-----+------+-------+
So what I want to do is find all the Businesses that are in a specific radius and have more check ins in the next hour than the current.
So the results are
+------------+
| BusinessID |
+------------+
| abd123 |
| abc123 |
+------------+
Because they have more check-ins in the next hour than the previous (6 > 5, 8 > 4)
What is more it would be helpful if the results where ordered by their difference in check-ins number. Ex. ( 8 - 4 > 6 - 5 )
SELECT *
FROM table2 t2
WHERE t2.BusinessID IN (
SELECT t1.BusinessID
FROM table1 t1
WHERE earth_box(ll_to_earth(32, 74), 4000/1.609) #> ll_to_earth(Lat, Long)
ORDER by earth_distance(ll_to_earth(32, 74), ll_to_earth(Lat, Long)), stars DESC
) AND checkin_day = 1 AND checkin_time = 14;
From the above query I can find the businesses in a radius and then find their check-ins in the specified time. Ex. 14. What I need to do now is to find the number of check-ins in the 15 hour (of the same businesses) and find if the number of the check-ins is greater than it was in the previous time.

Answer 1

I think you want something like this:
SELECT
t1.BusinessID
FROM
table1 t1
JOIN
(SELECT
*,
"count" - LAG("count") OVER (PARTITION BY BusinessID, "day" ORDER BY "time") "grow"
FROM
table2
WHERE
/* Some condition on table2 */) t2
ON t1.BusinessID = t2.BusinessID AND t2.grow > 0
WHERE
/* Some condition on table1 */
ORDER BY
t2.grow DESC;